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Dynamics of Continuous Structures
Maged Mostafa
#WikiCourses
http://WikiCourses.WikiSpaces.com
Vibration of Continuous
Structures
Dynamics of Continuous Structures
Maged Mostafa
#WikiCourses
http://WikiCourses.WikiSpaces.com
Beam Vibration
Dynamics of Continuous Structures
Maged Mostafa
#WikiCourses
http://WikiCourses.WikiSpaces.com
Course Contents
 SDOF
 M-DOF
 Cables/String
 Bars
 Shafts
• Beams
• Vibration Attenuation
• FEM for Vibration
• Plates
• Aeroelasticity
Dynamics of Continuous Structures
Maged Mostafa
#WikiCourses
http://WikiCourses.WikiSpaces.com
Beam Vibration
• The beam element is the most famous
structural element as it presents a lot of
realistic structural elements
• It bears loads normal to its longitudinal
axis
• It resists deformations by inducing bending
stresses
Dynamics of Continuous Structures
Maged Mostafa
#WikiCourses
http://WikiCourses.WikiSpaces.com
Bending vibrations of a beam
2
2
),(
)(),(
aboutinertia
ofmomentareasect.-cross)(
modulusYoungs
)(stiffnessbending
x
txw
xEItxM
z
xI
E
xEI






Next sum forces in they- direction (up, down)
Sum moments about the pointQ
Use the moment given from
stenght of materials
Assume sides do not bend
(no shear deformation)
f (x,t)
w (x,t)
x
dx A(x)= h1h2
h1
h2
M(x,t)+Mx(x,t)dx
M(x,t)
V(x,t)
V(x,t)+Vx(x,t)dx
f(x,t)
w(x,t)
x x +dx
·Q
Dynamics of Continuous Structures
Maged Mostafa
#WikiCourses
http://WikiCourses.WikiSpaces.com
Summing forces and moments
0)(
2
),(),(
),(
),(
0
2
),(
),(
),(),(
),(
),(
),(
)(),(),(
),(
),(
2
2
2


































dx
txf
x
txV
dxtxVdx
x
txM
dx
dxtxf
dxdx
x
txV
txVtxMdx
x
txM
txM
t
txw
dxxAdxtxftxVdx
x
txV
txV













0
Dynamics of Continuous Structures
Maged Mostafa
#WikiCourses
http://WikiCourses.WikiSpaces.com
A
EI
c
x
txw
c
t
txw
txf
x
txw
xEI
xt
txw
xA
t
txw
dxxAdxtxfdx
x
txM
x
txM
txV




























,0
),(),(
),(
),(
)(
),(
)(
),(
)(),(
),(
),(
),(
4
4
2
2
2
2
2
2
2
2
2
2
2
2
2
Substitute into force balance equation yields:
Dividing by dx and substituting for M yields
Assume constant stiffness to get:
Dynamics of Continuous Structures
Maged Mostafa
#WikiCourses
http://WikiCourses.WikiSpaces.com
Boundary conditions (4)
0forceshear
0momentbending
endFree
2
2
2
2








x
w
EI
x
x
w
EI






0slope
0deflection
endfixed)(orClamped


x
w
w


0momentbending
0deflection
endsupported)simply(orPinned
2
2


x
w
EI
w


0forceshear
0slope
endSliding
2
2








x
w
EI
x
x
w






Dynamics of Continuous Structures
Maged Mostafa
#WikiCourses
http://WikiCourses.WikiSpaces.com
Solution of the time equation:
)()0,(),()0,(
:conditionsinitialTwo
cossin)(
0)()(
)(
)(
)(
)(
00
2
22
xwxwxwxw
tBtAtT
tTtT
tT
tT
xX
xX
c
t











Dynamics of Continuous Structures
Maged Mostafa
#WikiCourses
http://WikiCourses.WikiSpaces.com
Spatial equation (BVP)
xaxaxaxaxX
AexX
EI
A
c
xX
c
xX
x





coshsinhcossin)(
:getto)(Let
Define
.0)()(
4321
22
4
2
















Apply boundary conditions to get 3
constants and the characteristic equation
Dynamics of Continuous Structures
Maged Mostafa
#WikiCourses
http://WikiCourses.WikiSpaces.com
Example: compute the mode shapes and
natural frequencies for a clamped-pinned
beam.
0)coshsinhcossin(
0)(
0coshsinhcossin
0)(
andend,pinnedAt the
0)(0)0(
00)0(
and0endfixedAt
4321
2
4321
31
42
















aaaa
XEI
aaaa
X
x
aaX
aaX
x
Dynamics of Continuous Structures
Maged Mostafa
#WikiCourses
http://WikiCourses.WikiSpaces.com


  






tanhtan
0)det(,
0
0
0
0
coshsinhcossin
coshsinhcossin
00
1010
4
3
2
1
2222








































BB
a
a
a
a
B
0a0a
a
The 4 boundary conditions in the 4 constants can be
written as the matrix equation:
The characteristic equation
Dynamics of Continuous Structures
Maged Mostafa
#WikiCourses
http://WikiCourses.WikiSpaces.com
Solve numerically to obtain solution to
transcendental equation
4
)14(
5
493361.16351768.13
210176.10068583.7926602.3
54
321









n
n
n


Next solve Ba=0 for 3 of the constants:
Dynamics of Continuous Structures
Maged Mostafa
#WikiCourses
http://WikiCourses.WikiSpaces.com
Solving for the eigenfunctions:

















xxxxaxX
aa
aa
aa
aa
B
nnnn
nn
nn
nn
nn
nn
nnnn












coscosh)sin(sinh
sinsinh
coscosh
)()(
sinsinh
coscosh
:yieldsSolving
equationfourth)(orthirdthefrom
0)cos(cosh)sinsinh(
equationsecondthefrom
equationfirstthefrom
:4ththeofin termsconstants3yields
4
43
43
42
31
0a
Dynamics of Continuous Structures
Maged Mostafa
#WikiCourses
http://WikiCourses.WikiSpaces.com
Mode shapes
X ,n x .
cosh n cos n
sinh n sin n
sinh .n x sin .n x cosh .n x cos .n x
0 0.2 0.4 0.6 0.8 1
2
1.5
1
0.5
0.5
1
1.5
X ,3.926602 x
X ,7.068583 x
X ,10.210176 x
x
Mode 1
Mode 2
Mode 3
Note zero slope
Non zero slope
Dynamics of Continuous Structures
Maged Mostafa
#WikiCourses
http://WikiCourses.WikiSpaces.com
Summary of the Euler-Bernoulli
Beam
• Uniform along its span and slender
• Linear, homogenous, isotropic elastic
material without axial loads
• Plane sections remain plane
• Plane of symmetry is plane of vibration so
that rotation & translation decoupled
• Rotary inertia and shear deformation
neglected
Dynamics of Continuous Structures
Maged Mostafa
#WikiCourses
http://WikiCourses.WikiSpaces.com
Homework
• Get an expression for  for the cases of a
uniform Euler-Bernoulli beam with BC’s as
follows:
– Clamped-Clamped
– Pinned-Pinned
– Clamped-Free
– Free-Free

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05 continuous beams

  • 1. Dynamics of Continuous Structures Maged Mostafa #WikiCourses http://WikiCourses.WikiSpaces.com Vibration of Continuous Structures
  • 2. Dynamics of Continuous Structures Maged Mostafa #WikiCourses http://WikiCourses.WikiSpaces.com Beam Vibration
  • 3. Dynamics of Continuous Structures Maged Mostafa #WikiCourses http://WikiCourses.WikiSpaces.com Course Contents  SDOF  M-DOF  Cables/String  Bars  Shafts • Beams • Vibration Attenuation • FEM for Vibration • Plates • Aeroelasticity
  • 4. Dynamics of Continuous Structures Maged Mostafa #WikiCourses http://WikiCourses.WikiSpaces.com Beam Vibration • The beam element is the most famous structural element as it presents a lot of realistic structural elements • It bears loads normal to its longitudinal axis • It resists deformations by inducing bending stresses
  • 5. Dynamics of Continuous Structures Maged Mostafa #WikiCourses http://WikiCourses.WikiSpaces.com Bending vibrations of a beam 2 2 ),( )(),( aboutinertia ofmomentareasect.-cross)( modulusYoungs )(stiffnessbending x txw xEItxM z xI E xEI       Next sum forces in they- direction (up, down) Sum moments about the pointQ Use the moment given from stenght of materials Assume sides do not bend (no shear deformation) f (x,t) w (x,t) x dx A(x)= h1h2 h1 h2 M(x,t)+Mx(x,t)dx M(x,t) V(x,t) V(x,t)+Vx(x,t)dx f(x,t) w(x,t) x x +dx ·Q
  • 6. Dynamics of Continuous Structures Maged Mostafa #WikiCourses http://WikiCourses.WikiSpaces.com Summing forces and moments 0)( 2 ),(),( ),( ),( 0 2 ),( ),( ),(),( ),( ),( ),( )(),(),( ),( ),( 2 2 2                                   dx txf x txV dxtxVdx x txM dx dxtxf dxdx x txV txVtxMdx x txM txM t txw dxxAdxtxftxVdx x txV txV              0
  • 7. Dynamics of Continuous Structures Maged Mostafa #WikiCourses http://WikiCourses.WikiSpaces.com A EI c x txw c t txw txf x txw xEI xt txw xA t txw dxxAdxtxfdx x txM x txM txV                             ,0 ),(),( ),( ),( )( ),( )( ),( )(),( ),( ),( ),( 4 4 2 2 2 2 2 2 2 2 2 2 2 2 2 Substitute into force balance equation yields: Dividing by dx and substituting for M yields Assume constant stiffness to get:
  • 8. Dynamics of Continuous Structures Maged Mostafa #WikiCourses http://WikiCourses.WikiSpaces.com Boundary conditions (4) 0forceshear 0momentbending endFree 2 2 2 2         x w EI x x w EI       0slope 0deflection endfixed)(orClamped   x w w   0momentbending 0deflection endsupported)simply(orPinned 2 2   x w EI w   0forceshear 0slope endSliding 2 2         x w EI x x w      
  • 9. Dynamics of Continuous Structures Maged Mostafa #WikiCourses http://WikiCourses.WikiSpaces.com Solution of the time equation: )()0,(),()0,( :conditionsinitialTwo cossin)( 0)()( )( )( )( )( 00 2 22 xwxwxwxw tBtAtT tTtT tT tT xX xX c t           
  • 10. Dynamics of Continuous Structures Maged Mostafa #WikiCourses http://WikiCourses.WikiSpaces.com Spatial equation (BVP) xaxaxaxaxX AexX EI A c xX c xX x      coshsinhcossin)( :getto)(Let Define .0)()( 4321 22 4 2                 Apply boundary conditions to get 3 constants and the characteristic equation
  • 11. Dynamics of Continuous Structures Maged Mostafa #WikiCourses http://WikiCourses.WikiSpaces.com Example: compute the mode shapes and natural frequencies for a clamped-pinned beam. 0)coshsinhcossin( 0)( 0coshsinhcossin 0)( andend,pinnedAt the 0)(0)0( 00)0( and0endfixedAt 4321 2 4321 31 42                 aaaa XEI aaaa X x aaX aaX x
  • 12. Dynamics of Continuous Structures Maged Mostafa #WikiCourses http://WikiCourses.WikiSpaces.com            tanhtan 0)det(, 0 0 0 0 coshsinhcossin coshsinhcossin 00 1010 4 3 2 1 2222                                         BB a a a a B 0a0a a The 4 boundary conditions in the 4 constants can be written as the matrix equation: The characteristic equation
  • 13. Dynamics of Continuous Structures Maged Mostafa #WikiCourses http://WikiCourses.WikiSpaces.com Solve numerically to obtain solution to transcendental equation 4 )14( 5 493361.16351768.13 210176.10068583.7926602.3 54 321          n n n   Next solve Ba=0 for 3 of the constants:
  • 14. Dynamics of Continuous Structures Maged Mostafa #WikiCourses http://WikiCourses.WikiSpaces.com Solving for the eigenfunctions:                  xxxxaxX aa aa aa aa B nnnn nn nn nn nn nn nnnn             coscosh)sin(sinh sinsinh coscosh )()( sinsinh coscosh :yieldsSolving equationfourth)(orthirdthefrom 0)cos(cosh)sinsinh( equationsecondthefrom equationfirstthefrom :4ththeofin termsconstants3yields 4 43 43 42 31 0a
  • 15. Dynamics of Continuous Structures Maged Mostafa #WikiCourses http://WikiCourses.WikiSpaces.com Mode shapes X ,n x . cosh n cos n sinh n sin n sinh .n x sin .n x cosh .n x cos .n x 0 0.2 0.4 0.6 0.8 1 2 1.5 1 0.5 0.5 1 1.5 X ,3.926602 x X ,7.068583 x X ,10.210176 x x Mode 1 Mode 2 Mode 3 Note zero slope Non zero slope
  • 16. Dynamics of Continuous Structures Maged Mostafa #WikiCourses http://WikiCourses.WikiSpaces.com Summary of the Euler-Bernoulli Beam • Uniform along its span and slender • Linear, homogenous, isotropic elastic material without axial loads • Plane sections remain plane • Plane of symmetry is plane of vibration so that rotation & translation decoupled • Rotary inertia and shear deformation neglected
  • 17. Dynamics of Continuous Structures Maged Mostafa #WikiCourses http://WikiCourses.WikiSpaces.com Homework • Get an expression for  for the cases of a uniform Euler-Bernoulli beam with BC’s as follows: – Clamped-Clamped – Pinned-Pinned – Clamped-Free – Free-Free