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# Law of conservation of momentum harsh.pptx

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### Law of conservation of momentum harsh.pptx

1. 1. . . Date- 06/12/2022 Subject-Science Duration-35min Class-9th Branch – Physics Period – 2nd
2. 2. . . Date- 06/12/2022 Subject-Science Duration-35min Class-9th Branch – Physics Period – 2nd
3. 3. . . Date- 06/12/2022 Subject-Science Duration-35min Class-9th Branch – Physics Period – 2nd
4. 4. . . Date- 06/12/2022 Subject-Science Duration-35min Class-9th Branch – Physics Period – 2nd
5. 5. . . Date- 06/12/2022 Subject-Science Duration-35min Class-9th Branch – Physics Period – 2nd Why the gas particles ejected?
6. 6. Law of conservation of momentum. . Date- 06/12/2022 Subject-Science Duration-35min Class-9th Branch – Physics Period – 2nd
7. 7. Law of conservation of momentum For two or more bodies in an isolated system acting upon each other, their total momentum remains constant unless an external force is applied. i.e., P initial = P final ⟹ m1u1+m2u2= m1v1+m2v2 Date- 06/12/2022 Subject-Science Duration-35min Class-9th Branch – Physics Period – 2nd
8. 8. Law of conservation of momentum . Date- 06/12/2022 Subject-Science Duration-35min Class-9th Branch – Physics Period – 2nd
9. 9. Law of conservation of momentum Newton’s cradle • Used to demonstrates the conservation of momentum. • Sphere at the end lifted and released leads to pushes the last sphere upwards. Date- 06/12/2022 Subject-Science Duration-35min Class-9th Branch – Physics Period – 2nd
10. 10. Questions related to law of conservation of momentum Ques1.Calculate the recoil velocity of a gun having mass equal to 5 kg, if a bullet of 25 g acquires the velocity of 500 ms-1 after firing from the gun. Date- 06/12/2022 Subject-Science Duration-35min Class-9th Branch – Physics Period – 2nd Topic : Conservation of momentum Solution: Given, Bullet;m1=25g=0.025kg, u1=0ms-1 ,v1=500ms-1 , Gun; m2 =5kg ,u2=0ms-1 , v2 =? From Law of the conservation of momentum, P initial = P final ⟹ m1u1+m2u2= m1v1+m2v2
11. 11. Questions related to law of conservation of momentum Ques1.Calculate the recoil velocity of a gun having mass equal to 5 kg, if a bullet of 25 g acquires the velocity of 500 ms-1 after firing from the gun. Date- 06/12/2022 Subject-Science Duration-35min Class-9th Branch – Physics Period – 2nd Topic : Conservation of momentum ⟹ m1u1+m2u2= m1v1+m2v2 ⟹ m1X 0+m2X 0= m1v1+m2v2 ⟹ m1u1+m2u2= m1v1+m2v2 ⟹0=12.5+5 v2 ⟹v2=−12.55=−2.5ms-1 The negative (- ve) sign shows that the gun moves in the opposite direction of the bullet.
12. 12. Questions related to law of conservation of momentum Q2. There are cars with masses of 4 kg and 10 kg respectively that are at rest. The car has a mass of 10 kg and moves towards the east with a velocity of 5 m.s-1. Find the velocity of the car with a mass of 4 kg with respect to the ground. Date- 06/12/2022 Subject-Science Duration-35min Class-9th Branch – Physics Period – 2nd Topic : Conservation of momentum Solution: Given, m1 = 4 kg m2 = 10 kg v1 = ? v2 = 5 m.s-1 P initial = m1u1+m2u2 = 0, (u1 = 0, u2 = 0) P final = p1 + p2 = m1v1+m2v2
13. 13. Questions related to law of conservation of momentum Q2. There are cars with masses of 4 kg and 10 kg respectively that are at rest. The car has a mass of 10 kg and moves towards the east with a velocity of 5 m.s-1. Find the velocity of the car with a mass of 4 kg with respect to the ground. Date- 06/12/2022 Subject-Science Duration-35min Class-9th Branch – Physics Period – 2nd Topic : Conservation of momentum Solution: P final = m1.v1 + m2.v2 = (4 kg).(v1) + (10 kg).(5 m.s-1) We know from the law of conservation of momentum that, P initial = P final ⟹0=4 kg.v1+50 kg.m.s-1 ⟹ v1 = -1.25 m.s-1 m1u1+m2u2= m1v1+m2v2
14. 14. Questions related to law of conservation of momentum Q3.Why does the gun recoil when bullet is fired? Date- 06/12/2022 Subject-Science Duration-35mi Class-9th Branch – Physics Period – 2nd Topic : Conservation of momentum I. What are the two objects here? Ans : Gun and bullet. II. What is the initial velocity of gun and bullet? Ans :Initial velocity of gun and bullet is zero.
15. 15. Questions related to law of conservation of momentum Q3.Why does the gun recoil when bullet is fired? Date- 06/12/2022 Subject-Science Duration-35mi Class-9th Branch – Physics Period – 2nd Topic : Conservation of momentum III. Taking the mass of gun=m1, mass of bullet =m2, find the final velocity of the gun if bullet moves with velocity v1, After fired .(apply law of conservation of momentum) Ans: By law of conservation of momentum, initial momentum= final momentum. P initial = P final ⟹ m1u1+m2u2= m1v1+m2v2 ⟹ m1 X 0+m2 X 0 = m1v1+m2v2 ⟹ 0 = m1v1+m2v2 ⟹ v1 = -m2v2 /m1
16. 16. Evaluation According to law of conservation of momentum, Initial________ = final __________________ Date- 06/12/2022 Subject-Science Duration-35min Class-9th Branch – Physics Period – 2nd Topic : Conservation of momentum
17. 17. Evaluation According to law of conservation of momentum, Initial momentum = final momentum Date- 06/12/2022 Subject-Science Duration-35min Class-9th Branch – Physics Period – 2nd Topic : Conservation of momentum
18. 18. Conservation of momentum in elastic collision Elastic collision :elastic collision is the collision in which there is no net loss in kinetic energy. Date- 06/12/2022 Subject-Science Duration-35min Class-9th Branch – Physics Period – 2nd Topic : Conservation of momentum
19. 19. Objective : Conservation of momentum in elastic collision . Date- 06/12/2022 Subject-Science Duration-35min Class-9th Branch – Physics Period – 2nd Topic : Conservation of momentum
20. 20. Link- https://www.physicsclassroom.com/Physics- Interactives/Momentum-and-Collisions/Collision- Carts/Collision-Carts-Interactive . Date- 06/12/2022 Subject-Science Duration-35min Class-9th Branch – Physics Period – 2nd Topic : Conservation of momentum
21. 21. Steps of the experiment. • Step1. Select the mass of object 1. • Step 2.Select the initial velocity of the object • Step3. Select the mass of object 2 • Step4. Select the initial velocity of object 2. • Step5. Select elastic collision. • Step6. Click on the start button. Date- 06/12/2022 Subject-Science Duration-35min Class-9th Branch – Physics Period – 2nd Topic : Conservation of momentum
22. 22. Observation table Table Date- 06/12/2022 Subject-Science Duration-35min Class-9th Branch – Physics Period – 2nd Topic : Conservation of momentum Before collision After collision Mass of object1= 2kg u1= 5m/s v1=2m/s Mass of object 2= 2 kg u2= 2m/s v2= 5m/s Momentum mv 10+4 4+10
23. 23. Ques. What do you observe from the observation table? Ans. Initial momentum= final momentum Date- 06/12/2022 Subject-Science Duration-35min Class-9th Branch – Physics Period – 2nd Topic : Conservation of momentum
24. 24. Result As there is no external force acting on two bodies, the total momentum of the system remains conserved. Date- 06/12/2022 Subject-Science Duration-35min Class-9th Branch – Physics Period – 2nd Topic : Conservation of momentum
25. 25. Evaluation Ques 1.Calculate the recoil velocity of a gun having mass equal to 2kg, if a bullet of 0.5 kg acquires the velocity of 500 ms−1 after firing from the gun. Date- 06/12/2022 Subject-Science Duration-35min Class-9th Branch – Physics Period – 2nd Topic : Conservation of momentum
26. 26. Summary
27. 27. Home work Ques 1. Calculate the recoil velocity of a gun having a mass equal to 12 kg, if a bullet of 5 kg acquires the velocity of 5ms−1 after firing from the gun. Date- 06/12/2022 Subject-Science Duration-35min Class-9th Branch – Physics Period – 2nd Topic : Conservation of momentum