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Math 8 Enhancement Activity.docx

23. Mar 2023โ€ขโ€ข
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Math 8 Enhancement Activity.docx

  1. Directions: Write the Rational Algebraic Expressions in simplest form. Given Solution Scratch 1.) 24๐‘š2๐‘2 36๐‘š๐‘2 = ๐Ÿ๐Ÿ๐’Ž๐’‘๐Ÿ(2๐‘š) ๐Ÿ๐Ÿ๐’Ž๐’‘๐Ÿ(3) Numerator 24๐‘š2 ๐‘3 = (2) (2) (2) (3) (m) (m) (p) (p) Denominator 36๐‘š ๐‘3 = (2) (2) (3) (3) (m) (p) (P) GCMF = (2) (2) (3) (m) (p) (p) = ๐Ÿ๐Ÿ๐’Ž๐’‘๐Ÿ = ๐Ÿ๐Ÿ๐’Ž๐’‘๐Ÿ(2๐‘š) ๐Ÿ๐Ÿ๐’Ž๐’‘๐Ÿ(3) Simplified Form = 2๐‘š 3 2.) 4๐‘๐‘2+6๐‘2๐‘ 6๐‘2+2๐‘ = ๐Ÿ๐’ƒ๐’‘(๐Ÿ๐’‘ +๐Ÿ‘๐’ƒ) ๐Ÿ๐’‘(๐Ÿ‘๐’‘ +๐Ÿ) Numerator 4๐‘๐‘2 = (2) (2) b (p) (p) 6๐‘2 ๐‘ = (2) (3) (b) (b) (p) GCMF = (2) (b) (p) = ๐Ÿ๐’ƒ๐’‘ Factored Form of the Numerator = ๐Ÿ๐’ƒ๐’‘(2p +3b) = ๐Ÿ๐’ƒ๐’‘(๐Ÿ๐’‘ +๐Ÿ‘๐’ƒ) ๐Ÿ๐’‘(๐Ÿ‘๐’‘ +๐Ÿ) Simplified Form = ๐’ƒ(๐Ÿ๐’‘ +๐Ÿ‘๐’ƒ) (๐Ÿ‘๐’‘ +๐Ÿ) Denominator 6๐‘2 = (2) (3) (p) (p) 2๐‘ = (2) (p) GCMF = (2) (p) = ๐Ÿ๐’‘ Factored Form of the Numerator = ๐Ÿ๐’‘(3p +1)
  2. Given Solution Scratch 3.) 4๐‘Ÿ2โˆ’ 9๐‘2 8๐‘Ÿ3+ 27๐‘3 = (๐Ÿ๐’“+๐Ÿ‘๐’„)(2๐‘Ÿโˆ’3๐‘) (2๐‘Ÿ+3๐‘ )( 4๐‘Ÿ2 โ€“ 6๐‘Ÿ๐‘+9๐‘2) Numerator Difference of Two Squares Formula ๐‘Ž2 โˆ’ ๐‘2 = (๐‘Ž + ๐‘)(๐‘Ž โˆ’ ๐‘) 4๐‘Ÿ2 โˆ’ 9๐‘2 = (2๐‘Ÿ + 3๐‘)(2๐‘Ÿ โˆ’ 3๐‘) (2๐‘Ÿ)(2๐‘Ÿ) (3๐‘)(3๐‘) ๐’‚ ๐’ƒ Denominator Sum of Two Cubes 8๐‘Ÿ3 + 27๐‘3 = (2๐‘Ÿ)3 + (3๐‘)3 (2r)(2๐‘Ÿ)(2๐‘Ÿ) (3๐‘)(3๐‘)(3๐‘) ๐’‡๐’Š๐’“๐’”๐’• ๐’ƒ๐’‚๐’”๐’† ๐’”๐’†๐’„๐’๐’๐’… ๐’ƒ๐’‚๐’”๐’† = (2๐‘Ÿ 3๐‘ )( ) = (2๐‘Ÿ 3๐‘ )( 2๐‘Ÿ.2๐‘Ÿ ) = (2๐‘Ÿ 3๐‘ )( 4๐‘Ÿ2 ) = (2๐‘Ÿ 3๐‘ )( 4๐‘Ÿ2 2๐‘Ÿ. 3๐‘ ) = (2๐‘Ÿ 3๐‘ )( 4๐‘Ÿ2 6๐‘Ÿ๐‘ ) = (2๐‘Ÿ 3๐‘ )( 4๐‘Ÿ2 6๐‘Ÿ๐‘ 3๐‘. 3๐‘) ) = (2๐‘Ÿ 3๐‘ )( 4๐‘Ÿ2 6๐‘Ÿ๐‘ 9๐‘2 ) = (2๐‘Ÿ + 3๐‘ )( 4๐‘Ÿ2 โ€“ 6๐‘Ÿ๐‘ + 9๐‘2 ) S O AP = (๐Ÿ๐’“+๐Ÿ‘๐’„)(2๐‘Ÿโˆ’3๐‘) (2๐‘Ÿ+3๐‘ )( 4๐‘Ÿ2 โ€“ 6๐‘Ÿ๐‘+9๐‘2) Simplified Form = 2๐‘Ÿโˆ’3๐‘ 4๐‘Ÿ2 โ€“ 6๐‘Ÿ๐‘+9๐‘2
  3. Given Solution Scratch 4.) 4๐‘‘2+2๐‘‘โˆ’ 6 2๐‘‘2+5๐‘‘+ 3 = (2๐‘‘+3)(2๐‘‘โˆ’2) (2๐‘‘+3)(๐‘‘+1) Numerator Trinomial (2๐‘‘ + 3) (2๐‘‘ โˆ’ 2) Factors of the Trinomial (2๐‘‘ + 3)(2๐‘‘ โˆ’ 2) Denominator Trinomial (2๐‘‘ + 3) (๐‘‘ + 1) Factors of the Trinomial (2๐‘‘ + 3)(๐‘‘ + 1) = (2๐‘‘+3)(2๐‘‘โˆ’2) (2๐‘‘+3)(๐‘‘+1) Simplified Form = 2๐‘‘โˆ’2 ๐‘‘+1
  4. Given Solution Scratch 5.) 2๐‘‘โˆ’ 6 6 โˆ’ 2๐‘‘ = (2๐‘‘โˆ’6) โˆ’1(2๐‘‘โˆ’6) Retain Numerator 2๐‘‘ โˆ’ 6 Change the Denominator 6 โˆ’ 2๐‘‘ a. 2๐‘‘ 6 b. 2๐‘‘ โˆ’ 6 c. โˆ’1(2๐‘‘ โˆ’ 6) = (2๐‘‘โˆ’6) โˆ’1(2๐‘‘โˆ’6) Simplified Form = 1 โˆ’1 = โˆ’1
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