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Joy A. Awoniyi, PharmD.
 PGY1 Pharmacy Practice Resident
   Miami VA Healthcare System

For The FAMU COPPS Class of 2013
Objectives
• To emphasize the importance of calculations
• To review important calculation concepts related to
     •   Patient Parameters
     •   Measurements
     •   Concentrations
     •   Electrolyte Solutions
     •   Clinical Laboratory Tests
     •   IV infusions flow rates
     •   Parenteral Nutrition

• To practice using the reviewed calculation concepts
• To review important pharmacokinetic concepts

                                     1
WHY SHOULD YOU CARE?


         • You can’t escape it

         • You need it to pass the NAPLEX

         • It can be applied to any
           pharmacy-related specialty

         • It may save your patient’s money

         • It may save your patient’s life
           (and your license)



           2
PATIENT
PARAMETERS
 Important Calculation Concepts




               3
BSA and IBW
• Body Surface Area (BSA), m2
  • BSA = Weight (kg)0.425 x Height (cm)0.725 x 0.007184

  • BSA =             cm ´ kg
                       3600
• Ideal Body Weight, kg
  • Males: 50 +( 2.3 x inches greater 60)
  • Females: 45.5 + (2.3 x inches greater than 60)

                               4
BODY MASS INDEX (BMI)
• Measure of body fat to help categorize patients and
  assess risk of morbidity for certain diseases

• BMI = weight(kg) ÷ [height (m)2]

   BMI                           Classification

   < 18.5                        Underweight

   18.5 to <25                   Normal

   25 to <30                     Overweight

   >30                           Obese

                             5
Creatinine Clearance (CrCl)
• Formula used to estimate renal function
• Not useful when renal function is fluctuating rapidly
• Used in the dosing of several medications
  • Tamiflu, Antibiotics, Low-molecular weight heparins

                              CrCl (mL/min)   Interpretation

(140 - Age) ´ IBW             60 to 90
                              30 to < 60
                                              Mild renal impairment
                                              Moderate Renal impairment

       72´ SCr                15 to <30       Severe Renal impairment
 Multiply by 0.85 if female   < 15            Kidney failure



                                     6
EXAMPLE

        Mack “Big Mack” Donald
          is a 55 year old man
       recently admitted to your
       service after choking on a
         Zebra Cake. He is 6’2”
            and 980 pounds.
        Calculate his BSA and
                 BMI.

   7
EXAMPLE
    Body Surface Area                            Body Mass Index
• Height in centimeters: 6’2” = 74           • Height in meters = 1.88 m
  inches
   • 74 inches x 2.54 cm/inch =              • Answer: 126
     187.96 cm
                                             • How do we classify Big Mack’s
• Weight in kilograms: 980 lbs                 BMI?
   • 980 lbs x 1 kg/2.2lbs = 445.45 kg         • Underweight
                                               • Normal
• Answer: 4.82                                 • Overweight
                                               • Obese


                                         8
EXAMPLE
        Mack had a DVT during
        admission. The doctors
          wish to start him on
        Enoxaparin (Lovenox), a
       renally dosed medication.
             His SCr is 2.3.
        Calculate his IBW and
        Creatinine Clearance


   9
EXAMPLE
  Ideal Body Weight             Creatinine Clearance

• Inches over 60               • Use IBW of 82.2kg
  • 74 – 60 = 14 inches
                               • Answer: 42.19 mL/min
• IBW = 50kg + 2.3 (14)          • Dose of Lovenox is
                                   50% if CrCl is less
• Answer: 82.2 kg                  than 30 mL/min



                          10
MEASUREMENTS
  Important Calculation Concepts




                11
The Basics Of
                   Measurement
• Irrelevant information is often given

• Fundamental information is often left
  out
  • How many grams are in a kilogram?
  • How many milliliters are in a fluid ounce?

• Start each problem by assessing
  what you know and what you want to
  know

• Double check!
                                       12
EXAMPLE
 A cough syrup contains 10mg of dextromethorphan per 5
 mL. Your pharmacy has 6 bottles left in stock. Each bottle
   contains 120mL of the syrup. How many grams of the
                 drug are in one bottle?

• What information is irrelevant?
• What fundamental information do you need to know to
  complete this problem?
• What do you know?
• What do you want to know?
                             13
EXAMPLE
 A cough syrup contains 10mg of dextromethorphan per 5
 mL. Your pharmacy has 6 bottles left in stock. Each bottle
   contains 120mL of the syrup. How many grams of the
                 drug are in one bottle?




              120mL/ 1           1            0.24 grams/ 1
10mg/5mL
                bottle      gram/1000mg            bottle




                            14
Specific Gravity
          Definition                            Equations
• A ratio of the weight of any        • Grams = mL x SG
  substance in relation to the
  weight of an equal volume of        • mL = Grams ÷ SG
  water
                                      • SG = Grams ÷ mL
• Water is used because 1g of           • Do not confuse with density or
  water is equal to 1mL                   concentration
  • If SG > 1 the substance is
    heavier than water
  • If SG < 1 the substance is
    lighter

                                 15
EXAMPLE
    There is 10 grams of glycerin in a 500mL solution.
    300 mL of glycerin weighs 165 grams. What is the
               specific gravity of glycerin?

• Specific Gravity = grams / mL
   • 10 g / 500mL ?
   • 165 g/ 300mL ?

• Think of SG as a conversion factor
   • 10 grams of glycerin does not EQUAL 500 mL of
     glycerin
   • 165 grams of Glycerin EQUALS 300 mL of glycerin
                            16
EXAMPLE
 There is 10 grams of glycerin in a 500mL solution.
 300 mL of glycerin weighs 165 grams. What is the
            specific gravity of glycerin?




 165                  300
                                            0.55
grams                 mL

                         17
EXAMPLE
   What is the weight, in grams of a 2 fluid ounces of a
          liquid with a specific gravity of 1.118?

• Grams = mL x SG



                 30mL/                             67.08
 2 fl oz                         1.118
                 1 fl oz                           grams




                            18
DOUBLE CHECK
• DOES THE ANSWER MAKE
  SENSE?
• If the SG is 1.118, the substance is
  • Heavier than water?
  • Lighter than water?

• 2 fluid ounces of water (60mL) = 60
  grams
• The answer is 67.08 grams which is
  > 60 grams
• Any answer below 60 would be
  WRONG

                                 19
CONCENTRATIONS
   Important Calculation Concepts




                 20
PERCENTAGE
PREPARATIONS
  Weight in volume
  • Amount of grams in 100mL of solution


  Volume in volume
  • Amount of mL in 100mL of solution



  Weight in weight
  • Amount of grams in 100 grams of substance




               21
EXAMPLE
         Weight in Volume
   How many grams of dextrose are required to prepare
              4000 mL of a 5% solution?

• 5% Dextrose by definition means 5 grams in 100mL



                       5
4000mL              grams/              200 grams
                    100mL

                          22
ALLIGATION

• Alligation is a method of solving
  problems that involves the mixing
  of solutions or substances with
  different percentage strengths

• Alligation alternate is a method
  to calculate the number of parts
  of two or more components of
  different strengths mixed to
  prepare a desired strength.

                           23
EXAMPLE
              ALLIGATION
  What is the percentage of zinc oxide in an ointment
 prepared by mixing 200 grams of a 10% ointment, 50
   grams of a 20% ointment, and 100 grams of a 5%
                      ointment
             0.10 x   200 g   = 20 grams
             0.20 x   50 g    = 10 grams
             0.05 x   100 g   = 5 grams
                      350 g     35 grams

35 grams ÷ 350 grams = 0.10 x 100% = 10%
                         24
EXAMPLE
   ALLIGATION ALTERNATE
 A pharmacist needs to prepare 50 mL of 3% hydrogen
 peroxide solution. He has 30% and 1.5% solutions in
     stock. How many mL of each should he use?
                                    • A– C =Y
 Percent    Percent   Proportions
Available   Desired    required     • C–B=X
   A                      X
                                    • X and Y are
              C                       proportions of A and
                                      B (respectively)
   B                      Y
                                      needed for the
                                      entire preparation
                         25
EXAMPLE
  ALLIGATION ALTERNATE
A pharmacist needs to prepare 50 mL of 3% hydrogen
peroxide solution. He has 30% and 1.5% solutions in
    stock. How many mL of each should he use?

 Percent    Percent   Proportions
Available   Desired    required     • 1.5 parts of 30%
  30%                        1.5
                                    • 27 parts of 1.5%
              3%
                                    • Total Parts: 28.5
  1.5%                       27


                        26
EXAMPLE
     ALLIGATION ALTERNATE
   A pharmacist needs to prepare 50 mL of 3% hydrogen
   peroxide solution. He has 30% and 1.5% solutions in
       stock. How many mL of each should he use?
• We need 1.5 of all 28.5 parts to contain 30% Hydrogen
  peroxide
 • 1.5/28.5 = x/50mL
 • X = 2.63mL of 30%
• We need 27 parts of all 28.5 parts to contain 3% Hydrogen
  peroxide
 • 27/28.5 = x/50mL
 • X = 47.37mL of 1.5%
                               27
ELECTROLYTE
 SOLUTIONS
 Important Calculation Concepts




               28
MILLIEQUIVALENTS
• Unit of measure related to the total number of ionic
  charges in a solution
  • Measures the chemical activity of an electrolyte
    relative to 1mg of hydrogen

• 1 mEq represents the milligrams equal to its
  equivalent weight, taking into account the valency

        mg ´ valence                   mEq ´ Molecular.Weight
 mEq =                            mg =
       Molecular.Weight                       Valence


                             29
MILLIEQUIVALENTS

   Ion        Abbr.    Valence   Atomic   Milliequivalent
                                 Weight        weight

Aluminum       Al3+      3         27           9

Magnesium     Mg2+       2         24           12

 Sodium        Na+       1         23           23

Bicarbonate   HCO32-     2         60          ???




                         30
EXAMPLE
   What is the concentration, in milligrams per milliliter, of a
          solution containing 2mEq of NaCl per mL?
• Molecular weight of Sodium = 23
                             2mEq ´ 58.3
• Molecular weight of Chloride = 35.5
                                 1



• Molecular weight of Sodium chloride = 58.5

• Valency = 1 (Na+, Cl+)
     mEq´ Molecular.Weight       2mEq ´ 58.5
mg =
           Valence                   1
                                 31
MOLARITY
• Millimoles
  • 1 mol = molecular weight in grams, therefore…
  • mmol = molecular weight in milligrams

• Molarity is the number of mmols in a solution
  How many milligrams would 3 mmol of monobasic
       sodium phosphate (MW = 138) weigh?


                       138 mg/
3 mmol                                         414 mg
                       1 mmol
                            32
OSMOLARITY
• mOsmoles represent the number of particles in a
  solution when the substance dissociates
  • NaCl = 2 mOsmol
  • CaCl2 = 3 mOsmol
  • Anhydrous dextrose = 1 mOsmol

• Osmolality is the milliosmoles of solute in a solution

                             1mmol
        mOsmol = mg ´
                      Molecular.Weight(mg)
                             33
CLINICAL
LABORATORY TESTS
    Important Calculation Concepts




                  34
CALCIUM-ALBUMIN
• Almost 50% of calcium is bound to plasma proteins

• If levels of proteins are low, then the serum calcium
  may be inaccurate

• If albumin is low, calcium will appear to be low, when it
  levels are actually within normal limits
  • Correct levels when Albumin is less than 4 g/dL

• Corrected Ca2+ = Ca2+ + 0.8 [4 – albumin(g/dL)]



                              35
SODIUM-GLUCOSE
• In patients with hyperglycemia, glucose does not enter
  the cell, causing a shift of fluid from intracellular to
  extracellular

• The shift of fluid dilutes the concentration of sodium in
  the extracellular fluid

• This type of hyponatremia (translational) does not need
  to be treated, instead control of glucose levels is
  indicated

• Corrected Na+ = Na+ + 0.016(Serum Glucose – 100)
                              36
INFUSION FLOW
    RATES
  Important Calculation Concepts




                37
EXAMPLE
     A physician orders 2 liters of D5W to be administered
   over 8 hours. The IV administration set in your pharmacy
   delivers 10 drops/mL. How many drops per minute should
                  the patient be set to receive?




2 Liters/    1000mL/       1 hour/     10 drops/    42 drops/
8hours        1 Liter      60 min        1mL           min




                             38
TOTAL PARENTERAL
    NUTRITION
   Important Calculation Concepts




                 39
TOTAL PARENTERAL
           NUTRUTION
• Provides a patient with all
  nutritional requirements

• Composition:
  • Fluids
  • Carbohydrates (Dextrose)
  • Protein (Amino acids)
  • Fats
  • Vitamins, minerals, trace
    elements
  • Electrolytes
                                40
TPN HIGHLIGHTS
• Fluid Requirements:
  • Generally 30 – 40 mL/kg/day
  • Calculated: 1500 mL + 20mL (kg over 20)

• Protein Requirements
  • Ambulatory: 0.8 – 1 g/kg/day
  • Hospitalized: 1.2 – 2 g/kg/day

• Non-Protein Requirements (Total Energy Expenditure)
  • Male: 66.47 + 13.75(kg) + 5.0(cm) – 6.76 (yrs)
  • Female: 655.1 + 9.6(kg) + 1.85(cm) – 4.68(yrs)
  • Multiply by 1.2 if confined to a bed, and 1.3 if out of bed

                                 41
TPN HIGHLIGHTS
                     Component            Units
• Each TPN
  component          Dextrose             3.4 kcal per gram
  provides a defined Amino Acids          4 kcal per gram
  amount of calories
                     Lipids               9 kcal per gram
• COMMIT THESE
                     10% lipid emulsion   1.1 kcal per mL
  TO MEMORY!!

                     20% lipid emulsion 2 kcal per mL



                           42
PHARMACOKINETICS
    Important Calculation Concepts




                  43
PHARMACOKINETCS

• Pharmacokinetics describes what happens to a drug
  or substance inside of the body



         Absorption             Distribution


         Metabolism              Excretion

                           44
FIRST-ORDER KINETICS
• The amount of drug given is proportional to the change
  in concentration
  • The change in drug concentration with respect to time will
    create a rate constant (k)


       dC
  -k =
       dt

• C = C0e-kt

                               45
HALF-LIFE
• The half-life (t1/2) is the time required for the
  concentration of the drug to decrease by one-half


  • t1/2 = 0.693/k (k is the rate constant)



   A patient is receiving an antibiotic for the treatment of a
  respiratory infection. The initial concentration of the drug
  was 17.9mg/L. The drug has an elimination half-life of 2
   hours. How much of the drug is present after 8 hours?
                                  46
EXAMPLE
   A patient is receiving an antibiotic for the treatment of a
  respiratory infection. The initial concentration of the drug
  was 17.9mg/L. The drug has an elimination half-life of 2
   hours. How much of the drug is present after 8 hours?

• C = C0e-kt SOLVE FOR “C”

• t1/2 = 0.693/k (k is the rate constant)
  • 2h = 0.693/k
  • k = 0.347h-1

• C = 17.90e-0.347(8) = 1.11mg/L

                               47
QUESTIONS?




    48
THANK YOU!

• Joy A. Awoniyi

• Email your questions, comments or concerns to
  Joy.awoniyi@va.gov




                        49

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Basic Pharmacy Calculations and Pharmacokinetes

  • 1. Joy A. Awoniyi, PharmD. PGY1 Pharmacy Practice Resident Miami VA Healthcare System For The FAMU COPPS Class of 2013
  • 2. Objectives • To emphasize the importance of calculations • To review important calculation concepts related to • Patient Parameters • Measurements • Concentrations • Electrolyte Solutions • Clinical Laboratory Tests • IV infusions flow rates • Parenteral Nutrition • To practice using the reviewed calculation concepts • To review important pharmacokinetic concepts 1
  • 3. WHY SHOULD YOU CARE? • You can’t escape it • You need it to pass the NAPLEX • It can be applied to any pharmacy-related specialty • It may save your patient’s money • It may save your patient’s life (and your license) 2
  • 5. BSA and IBW • Body Surface Area (BSA), m2 • BSA = Weight (kg)0.425 x Height (cm)0.725 x 0.007184 • BSA = cm ´ kg 3600 • Ideal Body Weight, kg • Males: 50 +( 2.3 x inches greater 60) • Females: 45.5 + (2.3 x inches greater than 60) 4
  • 6. BODY MASS INDEX (BMI) • Measure of body fat to help categorize patients and assess risk of morbidity for certain diseases • BMI = weight(kg) ÷ [height (m)2] BMI Classification < 18.5 Underweight 18.5 to <25 Normal 25 to <30 Overweight >30 Obese 5
  • 7. Creatinine Clearance (CrCl) • Formula used to estimate renal function • Not useful when renal function is fluctuating rapidly • Used in the dosing of several medications • Tamiflu, Antibiotics, Low-molecular weight heparins CrCl (mL/min) Interpretation (140 - Age) ´ IBW 60 to 90 30 to < 60 Mild renal impairment Moderate Renal impairment 72´ SCr 15 to <30 Severe Renal impairment Multiply by 0.85 if female < 15 Kidney failure 6
  • 8. EXAMPLE Mack “Big Mack” Donald is a 55 year old man recently admitted to your service after choking on a Zebra Cake. He is 6’2” and 980 pounds. Calculate his BSA and BMI. 7
  • 9. EXAMPLE Body Surface Area Body Mass Index • Height in centimeters: 6’2” = 74 • Height in meters = 1.88 m inches • 74 inches x 2.54 cm/inch = • Answer: 126 187.96 cm • How do we classify Big Mack’s • Weight in kilograms: 980 lbs BMI? • 980 lbs x 1 kg/2.2lbs = 445.45 kg • Underweight • Normal • Answer: 4.82 • Overweight • Obese 8
  • 10. EXAMPLE Mack had a DVT during admission. The doctors wish to start him on Enoxaparin (Lovenox), a renally dosed medication. His SCr is 2.3. Calculate his IBW and Creatinine Clearance 9
  • 11. EXAMPLE Ideal Body Weight Creatinine Clearance • Inches over 60 • Use IBW of 82.2kg • 74 – 60 = 14 inches • Answer: 42.19 mL/min • IBW = 50kg + 2.3 (14) • Dose of Lovenox is 50% if CrCl is less • Answer: 82.2 kg than 30 mL/min 10
  • 12. MEASUREMENTS Important Calculation Concepts 11
  • 13. The Basics Of Measurement • Irrelevant information is often given • Fundamental information is often left out • How many grams are in a kilogram? • How many milliliters are in a fluid ounce? • Start each problem by assessing what you know and what you want to know • Double check! 12
  • 14. EXAMPLE A cough syrup contains 10mg of dextromethorphan per 5 mL. Your pharmacy has 6 bottles left in stock. Each bottle contains 120mL of the syrup. How many grams of the drug are in one bottle? • What information is irrelevant? • What fundamental information do you need to know to complete this problem? • What do you know? • What do you want to know? 13
  • 15. EXAMPLE A cough syrup contains 10mg of dextromethorphan per 5 mL. Your pharmacy has 6 bottles left in stock. Each bottle contains 120mL of the syrup. How many grams of the drug are in one bottle? 120mL/ 1 1 0.24 grams/ 1 10mg/5mL bottle gram/1000mg bottle 14
  • 16. Specific Gravity Definition Equations • A ratio of the weight of any • Grams = mL x SG substance in relation to the weight of an equal volume of • mL = Grams ÷ SG water • SG = Grams ÷ mL • Water is used because 1g of • Do not confuse with density or water is equal to 1mL concentration • If SG > 1 the substance is heavier than water • If SG < 1 the substance is lighter 15
  • 17. EXAMPLE There is 10 grams of glycerin in a 500mL solution. 300 mL of glycerin weighs 165 grams. What is the specific gravity of glycerin? • Specific Gravity = grams / mL • 10 g / 500mL ? • 165 g/ 300mL ? • Think of SG as a conversion factor • 10 grams of glycerin does not EQUAL 500 mL of glycerin • 165 grams of Glycerin EQUALS 300 mL of glycerin 16
  • 18. EXAMPLE There is 10 grams of glycerin in a 500mL solution. 300 mL of glycerin weighs 165 grams. What is the specific gravity of glycerin? 165 300 0.55 grams mL 17
  • 19. EXAMPLE What is the weight, in grams of a 2 fluid ounces of a liquid with a specific gravity of 1.118? • Grams = mL x SG 30mL/ 67.08 2 fl oz 1.118 1 fl oz grams 18
  • 20. DOUBLE CHECK • DOES THE ANSWER MAKE SENSE? • If the SG is 1.118, the substance is • Heavier than water? • Lighter than water? • 2 fluid ounces of water (60mL) = 60 grams • The answer is 67.08 grams which is > 60 grams • Any answer below 60 would be WRONG 19
  • 21. CONCENTRATIONS Important Calculation Concepts 20
  • 22. PERCENTAGE PREPARATIONS Weight in volume • Amount of grams in 100mL of solution Volume in volume • Amount of mL in 100mL of solution Weight in weight • Amount of grams in 100 grams of substance 21
  • 23. EXAMPLE Weight in Volume How many grams of dextrose are required to prepare 4000 mL of a 5% solution? • 5% Dextrose by definition means 5 grams in 100mL 5 4000mL grams/ 200 grams 100mL 22
  • 24. ALLIGATION • Alligation is a method of solving problems that involves the mixing of solutions or substances with different percentage strengths • Alligation alternate is a method to calculate the number of parts of two or more components of different strengths mixed to prepare a desired strength. 23
  • 25. EXAMPLE ALLIGATION What is the percentage of zinc oxide in an ointment prepared by mixing 200 grams of a 10% ointment, 50 grams of a 20% ointment, and 100 grams of a 5% ointment 0.10 x 200 g = 20 grams 0.20 x 50 g = 10 grams 0.05 x 100 g = 5 grams 350 g 35 grams 35 grams ÷ 350 grams = 0.10 x 100% = 10% 24
  • 26. EXAMPLE ALLIGATION ALTERNATE A pharmacist needs to prepare 50 mL of 3% hydrogen peroxide solution. He has 30% and 1.5% solutions in stock. How many mL of each should he use? • A– C =Y Percent Percent Proportions Available Desired required • C–B=X A X • X and Y are C proportions of A and B (respectively) B Y needed for the entire preparation 25
  • 27. EXAMPLE ALLIGATION ALTERNATE A pharmacist needs to prepare 50 mL of 3% hydrogen peroxide solution. He has 30% and 1.5% solutions in stock. How many mL of each should he use? Percent Percent Proportions Available Desired required • 1.5 parts of 30% 30% 1.5 • 27 parts of 1.5% 3% • Total Parts: 28.5 1.5% 27 26
  • 28. EXAMPLE ALLIGATION ALTERNATE A pharmacist needs to prepare 50 mL of 3% hydrogen peroxide solution. He has 30% and 1.5% solutions in stock. How many mL of each should he use? • We need 1.5 of all 28.5 parts to contain 30% Hydrogen peroxide • 1.5/28.5 = x/50mL • X = 2.63mL of 30% • We need 27 parts of all 28.5 parts to contain 3% Hydrogen peroxide • 27/28.5 = x/50mL • X = 47.37mL of 1.5% 27
  • 29. ELECTROLYTE SOLUTIONS Important Calculation Concepts 28
  • 30. MILLIEQUIVALENTS • Unit of measure related to the total number of ionic charges in a solution • Measures the chemical activity of an electrolyte relative to 1mg of hydrogen • 1 mEq represents the milligrams equal to its equivalent weight, taking into account the valency mg ´ valence mEq ´ Molecular.Weight mEq = mg = Molecular.Weight Valence 29
  • 31. MILLIEQUIVALENTS Ion Abbr. Valence Atomic Milliequivalent Weight weight Aluminum Al3+ 3 27 9 Magnesium Mg2+ 2 24 12 Sodium Na+ 1 23 23 Bicarbonate HCO32- 2 60 ??? 30
  • 32. EXAMPLE What is the concentration, in milligrams per milliliter, of a solution containing 2mEq of NaCl per mL? • Molecular weight of Sodium = 23 2mEq ´ 58.3 • Molecular weight of Chloride = 35.5 1 • Molecular weight of Sodium chloride = 58.5 • Valency = 1 (Na+, Cl+) mEq´ Molecular.Weight 2mEq ´ 58.5 mg = Valence 1 31
  • 33. MOLARITY • Millimoles • 1 mol = molecular weight in grams, therefore… • mmol = molecular weight in milligrams • Molarity is the number of mmols in a solution How many milligrams would 3 mmol of monobasic sodium phosphate (MW = 138) weigh? 138 mg/ 3 mmol 414 mg 1 mmol 32
  • 34. OSMOLARITY • mOsmoles represent the number of particles in a solution when the substance dissociates • NaCl = 2 mOsmol • CaCl2 = 3 mOsmol • Anhydrous dextrose = 1 mOsmol • Osmolality is the milliosmoles of solute in a solution 1mmol mOsmol = mg ´ Molecular.Weight(mg) 33
  • 35. CLINICAL LABORATORY TESTS Important Calculation Concepts 34
  • 36. CALCIUM-ALBUMIN • Almost 50% of calcium is bound to plasma proteins • If levels of proteins are low, then the serum calcium may be inaccurate • If albumin is low, calcium will appear to be low, when it levels are actually within normal limits • Correct levels when Albumin is less than 4 g/dL • Corrected Ca2+ = Ca2+ + 0.8 [4 – albumin(g/dL)] 35
  • 37. SODIUM-GLUCOSE • In patients with hyperglycemia, glucose does not enter the cell, causing a shift of fluid from intracellular to extracellular • The shift of fluid dilutes the concentration of sodium in the extracellular fluid • This type of hyponatremia (translational) does not need to be treated, instead control of glucose levels is indicated • Corrected Na+ = Na+ + 0.016(Serum Glucose – 100) 36
  • 38. INFUSION FLOW RATES Important Calculation Concepts 37
  • 39. EXAMPLE A physician orders 2 liters of D5W to be administered over 8 hours. The IV administration set in your pharmacy delivers 10 drops/mL. How many drops per minute should the patient be set to receive? 2 Liters/ 1000mL/ 1 hour/ 10 drops/ 42 drops/ 8hours 1 Liter 60 min 1mL min 38
  • 40. TOTAL PARENTERAL NUTRITION Important Calculation Concepts 39
  • 41. TOTAL PARENTERAL NUTRUTION • Provides a patient with all nutritional requirements • Composition: • Fluids • Carbohydrates (Dextrose) • Protein (Amino acids) • Fats • Vitamins, minerals, trace elements • Electrolytes 40
  • 42. TPN HIGHLIGHTS • Fluid Requirements: • Generally 30 – 40 mL/kg/day • Calculated: 1500 mL + 20mL (kg over 20) • Protein Requirements • Ambulatory: 0.8 – 1 g/kg/day • Hospitalized: 1.2 – 2 g/kg/day • Non-Protein Requirements (Total Energy Expenditure) • Male: 66.47 + 13.75(kg) + 5.0(cm) – 6.76 (yrs) • Female: 655.1 + 9.6(kg) + 1.85(cm) – 4.68(yrs) • Multiply by 1.2 if confined to a bed, and 1.3 if out of bed 41
  • 43. TPN HIGHLIGHTS Component Units • Each TPN component Dextrose 3.4 kcal per gram provides a defined Amino Acids 4 kcal per gram amount of calories Lipids 9 kcal per gram • COMMIT THESE 10% lipid emulsion 1.1 kcal per mL TO MEMORY!! 20% lipid emulsion 2 kcal per mL 42
  • 44. PHARMACOKINETICS Important Calculation Concepts 43
  • 45. PHARMACOKINETCS • Pharmacokinetics describes what happens to a drug or substance inside of the body Absorption Distribution Metabolism Excretion 44
  • 46. FIRST-ORDER KINETICS • The amount of drug given is proportional to the change in concentration • The change in drug concentration with respect to time will create a rate constant (k) dC -k = dt • C = C0e-kt 45
  • 47. HALF-LIFE • The half-life (t1/2) is the time required for the concentration of the drug to decrease by one-half • t1/2 = 0.693/k (k is the rate constant) A patient is receiving an antibiotic for the treatment of a respiratory infection. The initial concentration of the drug was 17.9mg/L. The drug has an elimination half-life of 2 hours. How much of the drug is present after 8 hours? 46
  • 48. EXAMPLE A patient is receiving an antibiotic for the treatment of a respiratory infection. The initial concentration of the drug was 17.9mg/L. The drug has an elimination half-life of 2 hours. How much of the drug is present after 8 hours? • C = C0e-kt SOLVE FOR “C” • t1/2 = 0.693/k (k is the rate constant) • 2h = 0.693/k • k = 0.347h-1 • C = 17.90e-0.347(8) = 1.11mg/L 47
  • 50. THANK YOU! • Joy A. Awoniyi • Email your questions, comments or concerns to Joy.awoniyi@va.gov 49