Solving Absolute Value Equations and Inequalities.ppt

Warm-Up:
Describe the similarities and differences between
equations and inequalities.
Name:
Date:
Period:
Topic: Solving Absolute Value Equations & Inequalities
Essential Question: What is the process needed to solve
absolute value equations and inequalities?
Home-Learning #2 Review
Quiz #7:
Recall :
Absolute value | x | : is the distance
between x and 0. If | x | = 8, then
– 8 and 8 is a solution of the
equation ; or | x |  8, then any
number between 8 and 8 is a
solution of the inequality.
Absolute Value (of x)
• Symbol lxl
• The distance x is from 0 on the number line.
• Always positive
• Ex: l-3l=3
-4 -3 -2 -1 0 1 2
You can solve some absolute-value
equations using mental math. For
instance, you learned that the equation
| x | 3 has two solutions: 3 and 3.
To solve absolute-value equations, you
can use the fact that the expression inside
the absolute value symbols can be either
positive or negative.
Recall:
Solving an Absolute-Value Equation:
Solve | x  2 |  5 Solve | 2x  7 |  5  4
Solving an Absolute-Value Equation
| 7  2 |  | 5 |  5 | 3  2 |  | 5 |  5
Solve | x  2 |  5
The expression x  2 can be equal to 5 or 5.
x  2 IS POSITIVE
| x  2 |  5
x  2  5
x  7 x  3
x  2 IS NEGATIVE
| x  2 |  5
x  2  5
The equation has two solutions: 7 and –3.
CHECK
Answer ::
Solve | 2x  7 |  5  4
2x  7 IS POSITIVE
| 2x  7 |  5  4
| 2x  7 |  9
2x  7  +9
2x  16
2x  7 IS NEGATIVE
| 2x  7 |  5  4
| 2x  7 |  9
2x  7  9
2x  2
x  1
Isolate the absolute value expression on one side of the equation.
Isolate the absolute value expression on one side of the equation.
SOLUTION
2x  7 IS POSITIVE
2x  7  +9
2x  7 IS NEGATIVE
2x  7  9
2x  7 IS POSITIVE
| 2x  7 |  5  4
| 2x  7 |  9
2x  7  +9
2x  16
2x  7 IS NEGATIVE
| 2x  7 |  5  4
| 2x  7 |  9
2x  7  9
2x  2
TWO SOLUTIONS
x  8
x  1
Answer ::
Solve the following Absolute-Value Equation:
Practice:
1) Solve 6x-3 = 15
2) Solve 2x + 7 -3 = 8
1) Solve 6x-3 = 15
6x-3 = 15 or 6x-3 = -15
6x = 18 or 6x = -12
x = 3 or x = -2
* Plug in answers to check your solutions!
Answer ::
2) Solve 2x + 7 -3 = 8
Get the abs. value part by itself first!
2x+7 = 11
Now split into 2 parts.
2x+7 = 11 or 2x+7 = -11
2x = 4 or 2x = -18
x = 2 or x = -9
Check the solutions.
Answer ::
***Important NOTE***
3 2x + 9 +12 = 10
- 12 - 12
3 2x + 9 = - 2
3 3
2x + 9 = - 2
3
What about this absolute value equation? 3x – 6 – 5 = – 7
Solving Absolute Value Equations and Inequalities.ppt
Solving an Absolute Value Inequality:
● Step 1: Rewrite the inequality as a conjunction or a
disjunction.
● If you have a you are working with a
conjunction or an ‘and’ statement.
Remember: “Less thand”
● If you have a you are working with a
disjunction or an ‘or’ statement.
Remember: “Greator”
● Step 2: In the second equation you must negate the
right hand side and reverse the direction of the
inequality sign.
● Solve as a compound inequality.
or
 
or
 
Ex: “and” inequality
• Becomes an “and” problem
21
9
4 

x
-3 7 8
4x – 9 ≤ 21
+ 9 + 9
4x ≤ 30
x ≤ 7.5
4 4
4x – 9 ≥ -21
+ 9 + 9
4x ≥ -12
x ≥ -3
4 4
Positive Negative
|2x + 1| > 7
This is an ‘or’
statement.
(Greator).
3
-4
Ex: “or” inequality
2x + 1 > 7 or 2x + 1 < - 7
– 1 - 1 – 1 - 1
2x > 6 2x < - 8
2 2 2 2
x > 3
In the 2nd
inequality, reverse
the inequality sign
and negate the
right side value.
Solve | x  4 | < 3 and graph the solution.
Solving Absolute Value Inequalities:
Solve | 2x  1 | 3  6 and graph the solution.
Solve | x  4 | < 3
x  4 IS POSITIVE x  4 IS NEGATIVE
| x  4 |  3
x  4  3
x  7
| x  4 |  3
x  4  3
x  1
Reverse
inequality symbol.

This can be written as 1  x  7.
The solution is all real numbers greater than 1 and less than 7.
Answer ::
Solve | 2x  1 | 3  6 and graph the solution.
| 2x  1 |  3  6
| 2x  1 |  9
2x  1  +9
x  4
2x  8
| 2x  1 | 3  6
| 2x  1 |  9
2x  1  9
2x  10
x  5
2x + 1 IS POSITIVE 2x + 1 IS NEGATIVE
 6  5  4  3  2  1 0 1 2 3 4 5 6
The solution is all real numbers greater than or equal
to 4 or less than or equal to  5. This can be written as the
compound inequality x   5 or x  4.
Reverse
inequality
symbol.
Answer ::
11
3
2
3 


x
3)
Solve and graph the following
Absolute-Value Inequalities:
4) |x -5| < 3
Solve & graph.
• Get absolute value by itself first.
• Becomes an “or” problem
11
3
2
3 


x
8
2
3 

x
8
2
3
or
8
2
3 



 x
x
6
3
or
10
3 

 x
x
2
or
3
10


 x
x
-2 3 4
Answer ::
3)
4) |x -5|< 3
x -5< 3 and x -5< 3
x -5< 3 and x -5> -3
x < 8 and x > 2
2 < x < 8
This is an ‘and’ statement.
(Less thand).
Rewrite.
In the 2nd inequality, reverse the
inequality sign and negate the
right side value.
Solve each inequality.
Graph the solution.
8
2
Answer ::
Solve and Graph
5) 4m - 5 > 7 or 4m - 5 < - 9
6) 3 < x - 2 < 7
7) |y – 3| > 1
8) |p + 2| + 4 < 10
9) |3t - 2| + 6 = 2
Home-Learning #3:
• Page 211 - 212 (18, 26,36, 40, 64)
1 von 24

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Solving Absolute Value Equations and Inequalities.ppt

  • 1. Warm-Up: Describe the similarities and differences between equations and inequalities. Name: Date: Period: Topic: Solving Absolute Value Equations & Inequalities Essential Question: What is the process needed to solve absolute value equations and inequalities?
  • 4. Recall : Absolute value | x | : is the distance between x and 0. If | x | = 8, then – 8 and 8 is a solution of the equation ; or | x |  8, then any number between 8 and 8 is a solution of the inequality.
  • 5. Absolute Value (of x) • Symbol lxl • The distance x is from 0 on the number line. • Always positive • Ex: l-3l=3 -4 -3 -2 -1 0 1 2 You can solve some absolute-value equations using mental math. For instance, you learned that the equation | x | 3 has two solutions: 3 and 3. To solve absolute-value equations, you can use the fact that the expression inside the absolute value symbols can be either positive or negative. Recall:
  • 6. Solving an Absolute-Value Equation: Solve | x  2 |  5 Solve | 2x  7 |  5  4
  • 7. Solving an Absolute-Value Equation | 7  2 |  | 5 |  5 | 3  2 |  | 5 |  5 Solve | x  2 |  5 The expression x  2 can be equal to 5 or 5. x  2 IS POSITIVE | x  2 |  5 x  2  5 x  7 x  3 x  2 IS NEGATIVE | x  2 |  5 x  2  5 The equation has two solutions: 7 and –3. CHECK Answer ::
  • 8. Solve | 2x  7 |  5  4 2x  7 IS POSITIVE | 2x  7 |  5  4 | 2x  7 |  9 2x  7  +9 2x  16 2x  7 IS NEGATIVE | 2x  7 |  5  4 | 2x  7 |  9 2x  7  9 2x  2 x  1 Isolate the absolute value expression on one side of the equation. Isolate the absolute value expression on one side of the equation. SOLUTION 2x  7 IS POSITIVE 2x  7  +9 2x  7 IS NEGATIVE 2x  7  9 2x  7 IS POSITIVE | 2x  7 |  5  4 | 2x  7 |  9 2x  7  +9 2x  16 2x  7 IS NEGATIVE | 2x  7 |  5  4 | 2x  7 |  9 2x  7  9 2x  2 TWO SOLUTIONS x  8 x  1 Answer ::
  • 9. Solve the following Absolute-Value Equation: Practice: 1) Solve 6x-3 = 15 2) Solve 2x + 7 -3 = 8
  • 10. 1) Solve 6x-3 = 15 6x-3 = 15 or 6x-3 = -15 6x = 18 or 6x = -12 x = 3 or x = -2 * Plug in answers to check your solutions! Answer ::
  • 11. 2) Solve 2x + 7 -3 = 8 Get the abs. value part by itself first! 2x+7 = 11 Now split into 2 parts. 2x+7 = 11 or 2x+7 = -11 2x = 4 or 2x = -18 x = 2 or x = -9 Check the solutions. Answer ::
  • 12. ***Important NOTE*** 3 2x + 9 +12 = 10 - 12 - 12 3 2x + 9 = - 2 3 3 2x + 9 = - 2 3 What about this absolute value equation? 3x – 6 – 5 = – 7
  • 14. Solving an Absolute Value Inequality: ● Step 1: Rewrite the inequality as a conjunction or a disjunction. ● If you have a you are working with a conjunction or an ‘and’ statement. Remember: “Less thand” ● If you have a you are working with a disjunction or an ‘or’ statement. Remember: “Greator” ● Step 2: In the second equation you must negate the right hand side and reverse the direction of the inequality sign. ● Solve as a compound inequality. or   or  
  • 15. Ex: “and” inequality • Becomes an “and” problem 21 9 4   x -3 7 8 4x – 9 ≤ 21 + 9 + 9 4x ≤ 30 x ≤ 7.5 4 4 4x – 9 ≥ -21 + 9 + 9 4x ≥ -12 x ≥ -3 4 4 Positive Negative
  • 16. |2x + 1| > 7 This is an ‘or’ statement. (Greator). 3 -4 Ex: “or” inequality 2x + 1 > 7 or 2x + 1 < - 7 – 1 - 1 – 1 - 1 2x > 6 2x < - 8 2 2 2 2 x > 3 In the 2nd inequality, reverse the inequality sign and negate the right side value.
  • 17. Solve | x  4 | < 3 and graph the solution. Solving Absolute Value Inequalities: Solve | 2x  1 | 3  6 and graph the solution.
  • 18. Solve | x  4 | < 3 x  4 IS POSITIVE x  4 IS NEGATIVE | x  4 |  3 x  4  3 x  7 | x  4 |  3 x  4  3 x  1 Reverse inequality symbol.  This can be written as 1  x  7. The solution is all real numbers greater than 1 and less than 7. Answer ::
  • 19. Solve | 2x  1 | 3  6 and graph the solution. | 2x  1 |  3  6 | 2x  1 |  9 2x  1  +9 x  4 2x  8 | 2x  1 | 3  6 | 2x  1 |  9 2x  1  9 2x  10 x  5 2x + 1 IS POSITIVE 2x + 1 IS NEGATIVE  6  5  4  3  2  1 0 1 2 3 4 5 6 The solution is all real numbers greater than or equal to 4 or less than or equal to  5. This can be written as the compound inequality x   5 or x  4. Reverse inequality symbol. Answer ::
  • 20. 11 3 2 3    x 3) Solve and graph the following Absolute-Value Inequalities: 4) |x -5| < 3
  • 21. Solve & graph. • Get absolute value by itself first. • Becomes an “or” problem 11 3 2 3    x 8 2 3   x 8 2 3 or 8 2 3      x x 6 3 or 10 3    x x 2 or 3 10    x x -2 3 4 Answer :: 3)
  • 22. 4) |x -5|< 3 x -5< 3 and x -5< 3 x -5< 3 and x -5> -3 x < 8 and x > 2 2 < x < 8 This is an ‘and’ statement. (Less thand). Rewrite. In the 2nd inequality, reverse the inequality sign and negate the right side value. Solve each inequality. Graph the solution. 8 2 Answer ::
  • 23. Solve and Graph 5) 4m - 5 > 7 or 4m - 5 < - 9 6) 3 < x - 2 < 7 7) |y – 3| > 1 8) |p + 2| + 4 < 10 9) |3t - 2| + 6 = 2
  • 24. Home-Learning #3: • Page 211 - 212 (18, 26,36, 40, 64)