Class : XII (NUCLEUS)
Time : 3 hour Max. Marks : 60
INSTRUCTIONS
1. The question paper contain pages and 3-parts. Part-A contains 6 objective question , Part-B contains 2
questions of "Match theColumn" type and Part-C contains 4 subjective type questions.All questions are
compulsory. Please ensure that the Question Paper you have received contains all the QUESTIONS
and Pages. If you found some mistake like missing questions or pages then contact immediately to
the Invigilator.
PART-A
(i) Q.1 to Q.6 have One or More than one is / are correct alternative(s) and carry 4 marks each.
There is NEGATIVE marking. 1 mark will be deducted for eachwrong answer.
PART-B
(iii) Q.1 to Q.2 are"Match the Column" typewhich mayhave oneor more than onematching options and
carry8 marks foreach question. 2 marks will be awarded for each correct match within a question.
ThereisNONEGATIVEmarking.Markswillbeawardedonlyifallthecorrectalternativesareselected.
PART-C
(iv) Q.1 to Q.4 are "Subjective" questions. There is NO NEGATIVE marking. Marks will be awarded
onlyifall the correct bubbles are filled in yourOMR sheet.
2. Indicate the correctanswer for each question byfillingappropriate bubble(s) inyour answer sheet.
3. Use onlyHB pencil fordarkeningthe bubble(s).
4. Use ofCalculator, LogTable, SlideRule and Mobile is not allowed.
5. Theanswer(s)ofthequestionsmustbemarked byshadingthecirclesagainst thequestionbydarkHBpencil
only.
PART TEST-2
PART-B
For example if Correct
match for (A) is P, Q; for
(B) is P, R; for (C) is P
and for (D) is S then the
correct method for filling
thebubbleis
P Q R S
(A)
(B)
(C)
(D)
PART-C
Ensure that all columns
(4 before decimal and 2
after decimal) are filled.
Answer having blank
column willbe treated as
incorrect. Insert leading
zero(s) if required after
rounding the result to 2
decimalplaces.
e.g. 86 should befilled as
0086.00
.
.
.
.
.
.
.
.
.
.
PART-A
For example if only 'B'
choice is correct then,
the correct method for
fillingthebubbleis
A B C D
Forexampleifonly'B&
D' choices are correct
then, the correct method
forfillingthebubblesis
A B C D
The answer of the
question in any other
manner (such as putting
, cross , or partial
shading etc.) will be
treated as wrong.

Class - XII Physics Part Test - 2
PARTA
Select the correct alternative(s) (choose one or more than one)
Q.1 Auniformlychargedthinnonconductingshellofradius RischargedwithQunitsofcharge.Theescape
velocityof aparticle of charge –qand mass m from surfaceof conductor is
(A)
R
4
Qq
0


(B*)
mR
2
Qq
0


(C)
mR
Qq
0

(D)
mR
4
Qq
0


[Sol: Vescape = R
·
g
2 eff
geff =
m
qE
where E = 2
0 R
Q
4
1


Vescape = R
·
R
4
Q
·
m
q
2 2
0


 =
mR
2
Qq
0

 (B) ]
Q.2 Atesttubeoflengthlisimmersedinverticallyintoavesselcontainingmercuryof
density(m).Itis immersedinsuchawayso thatits closedendjust touches the
mercurylevel.Mercurywasfoundtorisetoaheightxinthetubeasshown.The
pressureatAis (HereAtmospheric pressure is equal to l length of mercury):
(A) (l – x) mg (B)xmg
(C*) (2l – x) mg (D) (l – 2x) mg
[Sol: Patm = P0 = lg
P = P0 + lg – xg = (2l-x)g
(C) ]
Q.3 Anadiabatic containeris dividedintotwoequal parts, withanidealgas atpressurePand temperatureT
at oneside and vacuum onthe other side. Onmaking a hole in the separating wall
(A) work done bygas will be nRT
(B*)changeininternal energyofgas will bezero
(C*) internal energydepends on temperature of gas
(D*) work done bygas is zero
[Sol: Thethermodynamicprocess will befree-expansionin nature.
Hence dw = 0
since d = 0, dU also is zero
(B), (C), (D) ]
Q.4 Figure shows a network of capacitors and resistances.
Potentials ofsomeof thepoints are given. Then
(A*) potential at M = 2.6 V
(B*) Potential at N = –1.6 V
(C*) Charge across 2f capacitor is 8.4 C
(D) Charge across 2f capacitor is 4.2 C

[Sol: 2i1 + 3(i1 + i2 – i3) + 4(i1 + i2) – 10 = 6
i2 + 2i3 = 3
2(i1 + i2 – i3) – 6i3 = 0
solving(A,B, C) ]
Q.5 As aliquidof densityflows throughthe tubeshownbelow in astreamlines way
(A) volume rate of flow reduces from a1 to a2
(B) volume rate of flow increases from a1 to a2
(C*) h is a measure of pressure difference atAand B
(D*) pressure atAhas to be more than that at B by hg
[Sol: Rateofflowremains constant
C, D ]
Q.6 Twolargeblackplanesurfaces aremaintained at constant temperatureT1 &T2
(T1 >T2) & placed in vacuume. Two thin black plates are placed between the
twosurfacesandisparalleltothese.Aftersometimesteadyconditionareobtained.
By what factor () is the steady heat flow reduced due to presence of black
plates?
(A)  =
2
1
(B*)  =
3
1
(C)  = 1 (D)  = 0
[Sol: Q = (T1
4 – T3
4)
= (T3
4 – T4
4)
= (T4
4 – T2
4)
3Q = (T1
4 – T2
4) = Q0
Q =
3
Q0
]
PART B
Match the column
Q.1 In the circuit shown in figure, there are three identical capacitor C1,C2,
C3 each having capacitance 'C'. The switch 'S' is kept closed to point–1
for long time, then at timet = 0 switch'S' is shifted to position–2 from
position–1
ColumnI Column II
(A) Final charge on capacitor C1 (P)
2
CV
3
2
(B) Work done byBatteryhaving emf V2 = V (Q)
2
CV
3
4

(C) Final charge on capacitor C2 (R) CV
3
2
(D)Amount ofheat produced inthe circuit after (S)
3
CV
shifting the switch 'S' from (1) to (2)
[Ans: (A)  S; (B)  P; (C)  R; (D)  P]
[Sol: Initial charge on C1 = CV
KVL 
C
CV
q1 
+
C
q1
+
C
q1
= V
q1 – CV + 2q1 = CV
3q1 = 2CV q1 =
3
CV
2
Final charge on C1 = |q1 – CV| =
3
CV
2
– CV =
3
CV
work done by battery (V2) = q1 × V =
3
CV
2
× V =
3
CV
2 2
final charge on C2 =
3
CV
2
Ui =
2
1
CV2 Uf =
2
1
9
iV
4 2
× 2 +
2
1
9
CV2
= 






18
1
18
8
CV2 = 2
CV2
 H =
3
CV
2 2
]
Q.2 Match the following. (Here gas is ideal, P = pressure, V = volume,  = ratio of molar specific heat at
constant pressure&constant volume)
ColumnI ColumnII
(A)AdiabaticBulkmodulus ofgas (P) –
V
P
(B)Slope ofP–V graph inisothermal (Q)
1
2


process
(C) Degreeof freedom (R) P
(D) Molar heat capacityat constant pressure (S) 1



divided by R
[Sol: (A) PV = C
dP
d
PV = 0





 V
dP
dV
V
·
P 1
= 0

 dPV
PdV 
 = 0
Bulk modulus = –
V
/
dV
dP
= P (R)
(B) PdV + VdP = 0 Slope =
dV
dP
=
V
P
 (P)
(C)  = 1 +
f
2
 f =
1
2


(Q)
(D)
  1
R
1
R
R
CP







 (S) ]
PART C
Q.1 Asampleofmonoatomicidealgasoccupies5.00Latatmosphericpressure
and temperature 300 K (pointA). It is heated at constant volume to 3.00
atm (point B)then it is allowedto expand isothermallyto 1.00 atm (point
C) and at last compressed isobaricallyto its original state. If the gas is
monoatomicthencalculatethetotal amountofheat(injoules)giventothe
gas during whole cycle. (Here R = 8.30 Joule/mole0K; Patm = 105Pa;
1L = 10–3 m3; ln3 = 1.1) [Ans: 650 Joules]
[Sol: A 

 
Isochoric B 

 
Isothermal C 

 
Isobaric A
P1 = P0 = 105 Pa P2 = 3P0 P3 = P0 P4 = P0
V1 = V0= 5 x 10-3 m3 V2 = V0 V3 = 3V0 V4 = V0
T1 = T0 = 300 K T2 = 3T0 T3 = 3T0 T4 = T0
T1 = T4 = T0  U
 = 0
 Q
 = W
 = areaABCA= (Area under BC curve) - (Area under CAcurve)
= (nRT0) ln 







2
3
V
V
- P0 (V3 - V
V4) = 3P0V0ln 3 - 2 P0V0
= P0Vo (3ln 3 - 2) = 650J Q

 = 650J]
Q.2 Inthecircuit shown in figureswitch 'S'is closedforlongtime, then at time
t = 0 it is again opened. Find the charge on capacitor (in C) at time t = 6s
(here e–1 = 0.37) [Ans: 7.4C]
[Sol: At node X
2
0
X
4
30
X 


X – 30 + 2X = 0
3X = 30
 X = 10
At nodeY
4
0
Y
2
30
Y 


= 0
2Y – 60 + Y
3Y = 60
Y = 20
Potential differenceacross capacitor

= Y – X = 20 – 10 = 10
q0 = CV = 2 × 10 = 20 C
When switch S is open charge on capacitor at t = t
Req = 3W q = q0
q
Re
C
t
e

q = 20 3
2
6
e 

= 0.37 × 20 = 7.4
q = 7.4 C ]
Q.3 ArodoflengthL=1mwiththermallyinsulatedlateralsurfacehasuniformcross-section.Thecoefficient
ofthermalconductivityofthematerialoftherod varieswithtemperatureas K 
T
1
.Theendsoftherod
are maintained at temperature T1 = 200C & T2 = 800C. Find the temperature (in0C) at the mid point of
rod.
[Ans: 400C]
[Sol:
dx
dT
kA
dt
dQ


=
dx
dT
A
T
C

dx
CA
dQ
= 

T
dT

1
0
0x
C =
80
20
T
ln

C0
1 = –ln4 ..........(1)
Similarly
2
/
1
0
0x
C =
T
20
T
ln

C0½ = –ln
20
T
(2)
 Dividing2=
20
T
ln
4
ln
2
20
T






= 4 
20
T
= 2  T = 400C ]
Q.4 Fiveidentical largeconductingplates each ofareaAareplaced parallel
to each other at separation 'd'. Plates 1 & 3 are connected by thin
conductingwire&plate2&5areconnectedbyanotherthinconducting
wire.Thejunctionof plate1&3and plate-4areconnectedbyabattery
having emf'V'(as showninfigure). The system is in steadystate. Now
Plate-1ismovedupwardslowlysothatitcomeincontactwithPlate2.
Calculatethe amount ofwork done (in J) bybatteryduringmotion of
plate-1. (Here
d
A
0

= 20F, V = 10 volts)
[Sol: C = d
/
A
0


When 4 and5 are not connected the equivalent Ckt diagram
Cleft =
3
C
5
Charge given by batteryq1 = Ceff · V =
3
CV
5
When 4 & 5 are connected, the equivalent ckt diagram
Ceq = 2C
q2 = 2CV
work done by battery = V 





 CV
3
5
CV
2
=
3
CV
× V =
3
1
CV2
=
3
1
× 20 × 100
=
3
2000
J = 666.67 J ]