XIII(XYZ) INORGANIC CHEMISTRY REVIEWTEST-6
PAPER-1
PART-A
Select the correct alternative(s). (One or More than one is/are correct) [15 × 5 = 75]
There is NEGATIVE marking. 1 mark will be deducted for eachwrong answer.
Q.32 Whichofthefollowingstatements is/are false
(A*)In[PtCl2(NH3)4]2+ complexion,thecis-formisopticallyactive,whiletrans-formisopticallyinactive
(B) In[Fe(C2O4)3]3–,geometrical isomerismdoes not exist, whileoptical isomerism exists
(C*)[Mabcd]n square planarcomplexes exhibit bothoptical as well as geometrical isomerism
(D*) In [Mabcd]n± tetrahedral complexes, optical isomerism cannot be observed
[Sol. (A) [PtCl2(NH3)4]2+  both cis and trans forms areopticallyinactive
(B) Duetoasymmetricalconfiguration,itexhibitsopticalisomerism.
(C)  Dueto plane ofsymmetrydoes not exhibit optical isomerism, but
exhibits geometrical isomerism
(D) Tetrahedralcomplex ,Asymmetricconfiguration,henceexhibits
optical isomerism]
Q.34 Saturatedsolutionof SO2 is heatedat 150°C ina closed container.Theproduct obtained is treated with
BaCl2 solution.What is/are themostsuitableobservation(s)
(A) No ppt. (B)whiteturbidity
(C) evolution of SO2 (D*) The turbiditybecomes whiteppt
[Sol. SO2  + H2O  H2SO3
3H2SO3 vessel
closed
C
150

 
 
S + 2H2SO4 + H2O
BaSO4 (white ppt.) ]
Q.36 Whichreactionis/arepossible
(A) MgCl2 + NaNO3  (B) BaSO4 + HCl 
(C*) ZnSO4 + BaS  (D*) BaCO3 + CH3COOH 
[Sol. (A) MgCl2 +2NaNO3 2Na+ + Mg2+ + 2Cl– + 
3
NO
2 (No reaction)
(B) BaSO4 + HCl  No reaction
(C) ZnSO4 + BaS  ZnS + BaSO4
(white) (white)
(D) BaCO3 + 2CH3COOH  Ba2+ + 2CH3COO– + CO2 + H2O
Insoluble (white)
(white)]

Q.38 Whichofthefollowingstructure(s)is/arenon-planar
(A) Na3B3O6 (B) I2Cl6 (C*)Sheet silicate (D)Inorganic graphite
[Sol. (A) (B)
(C)
In sheet silicates althought one 
4
4
SiO tetrahedron is linked to other threetetrahedrons but the
layer/ sheet obtained is not planar, as fourth oxygn atom is projectingawayfrom sheet.
(D)
each layer is planar as both B & N are sp2 hybridized ]
Q.40 Whichofthefollowingstatementsis/aretrue
(A*) In Ferrocyanideion, theeffective atomicnumber is 36
(B*)Chelatingligandsareatleastbidentateligands
(C*) 
]
)
NH
(
)
CN
(
CrCl
[ 2
3
2
2
and [CrCl3(NH3)3] both have d2sp3 hybridisation
(D*)As thenumberof rings incomplex increases,stabilityofcomplex (chelate)also increases
[Sol. A,B,C,D ]
Q.42 Whichofthefollowingstatementsis/aretrue
(A) Sulphide ions react with Na2[Fe(NO)(CN)5] to form a purple coloured compound
Na4[Fe(CN)5(NOS)]. In the reaction, the oxidation state of iron changes
(B*) In B2H6 vacant orbital take part in hybridisation
(C*) In B2H6, thereare only12 bondingelectrons available
(D*) Bond length of NO+ is less than in NO
[Sol. (A) Sulphideionsreact with Na2[Fe(CN)5(NO)] inalkalinemedium
Na2
)]
NO
(
)
CN
(
Fe
[ 5
II
+ S2– + 2NaOH  Na4
)]
NOS
(
)
CN
(
Fe
[ 5
II
+ 2OH–
colourless purple ]

Q.44 The correct order of energies ofd-orbitals of metal ionin a square planarcomplex is
(A) dxy = dyz = dzx > 2
2
y
x
d

= 2
z
d (B) 2
2
y
x
d

= 2
z
d > dxy = dyz = dzx
(C) 2
2
y
x
d

> 2
z
d > dxy > dyz = dzx (D*) 2
2
y
x
d

> dxy > 2
z
d > dzx = dyz
[Sol. D]
Q.45 Which statement(s) is/are correct regarding the dI– I in 
3
I ?
(A) bothareidentical (B)bothare different
(C*) It depends upon the cation attached. (D*) It can't be predicted from its formula.
[Sol. In 

3
4 I
NH ; the I–I bond lengths are not equal. while in Ph4As+ 
3
I , the I–I bond lengths are equal.
In 

3
4 I
NH different I– Ibond lengths are attributed due tothe polarization effects from the cation ]
PAPER-2
PART-B
MATCH THE COLUMN [3 × 10 = 30]
There is NEGATIVE marking. 0.5 Marks will be deducted for each wrongmatch.
INSTRUCTIONS:
Column-Iand column-IIcontainsfour entries each. Entries ofcolumn-Iareto bematchedwith some
entriesofcolumn-II.Oneormorethanoneentriesofcolumn-Imayhavethematchingwiththesameentries
ofcolumn-IIandoneentryofcolumn-Imayhaveoneormorethanonematchingwithentriesofcolumn-II.
Q.8 List I List II
(A) Colourless gas evolvedon addition (P) –
2
3
2O
S
of dil. H2SO4
(B)White ppt. on addition ofAgNO3 (Q) S2–
(C) Black ppt. obtained when HgCl2 is added (R) –
2
NO
in little amount
(D)The ppt. obtained on addition ofAgNO3 (S) –
2
3CO
CH
followed by NH3 solution
[Ans. (A) P,Q,S; (B) P,R,S; (C) Q; (D) Q]

[Sol. (A)
(B)
(C)
(D) Ag2SisinsolubleinNH3 solution ]