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Name the domain and range for the relation shown in each graph D = {x | x is a real number} D = {x | x is a real number} R = {y | y ≥ 0} R = {y | y ≥ -2} Lesson 2 Contents
In a linear equation, each term is either a constant or the product of a constant and (the first power of) a single variable. Which of these represent linear functions? linear nonlinear linear nonlinear Example 2-1a
Slope-intercept form 	   y = mx + b  	f(x) = mx + b m is the slope of the line b is the y-intercept What are the slope and y-intercept of the line                   ? Slope = 3 y-intercept = -9 Example 2-1d
The graph of a linear equation is a line. Graph the line                    y-intercept = -9 Slope = 3 Slope = ΔyΔx Example 2-1d
Standardform  Ax + By = C  ,[object Object]
 A is positive
A and B are not both zero3x + 5y = -2 is in standard form Example 2-1d
Write the equation in standard form. Identify A, B, and C.  Ax + By = C Simplified? 2      2      2 Example 2-3c
Write the equation in standard form. Identify A, B, and C.  Ax + By = C Simplified? Example 2-3a
Write the equation in standard form. Identify A, B, and C.  Ax + By = C -3                        (-3) Simplified? Example 2-3b
Find the x- and y- intercepts of  -2x + y – 4 = 0 x-intercept -2x + 0 – 4 = 0 -2x – 4 = 0 -2x = 4 x = -2 The x-intercept is -2 	(-2, 0) y-intercept -2(0) + y – 4 = 0 0 + y – 4 = 0 y – 4 = 0 y = 4 The y-intercept is 4 	(0, 4) Example 2-4b
(0, 4) (–2, 0) Graph -2x + y – 4 = 0 x-intercept : –2 y-intercept: 4 Example 2-4c
Slope 	m = vertical change	       Horizontal change 	m = ΔyΔx 	m = rise		run Any two points on a line can be used to determine its slope.

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Alg2 lesson 2.2 and 2.3

  • 1. Name the domain and range for the relation shown in each graph D = {x | x is a real number} D = {x | x is a real number} R = {y | y ≥ 0} R = {y | y ≥ -2} Lesson 2 Contents
  • 2. In a linear equation, each term is either a constant or the product of a constant and (the first power of) a single variable. Which of these represent linear functions? linear nonlinear linear nonlinear Example 2-1a
  • 3. Slope-intercept form y = mx + b f(x) = mx + b m is the slope of the line b is the y-intercept What are the slope and y-intercept of the line ? Slope = 3 y-intercept = -9 Example 2-1d
  • 4. The graph of a linear equation is a line. Graph the line y-intercept = -9 Slope = 3 Slope = ΔyΔx Example 2-1d
  • 5.
  • 6. A is positive
  • 7. A and B are not both zero3x + 5y = -2 is in standard form Example 2-1d
  • 8. Write the equation in standard form. Identify A, B, and C. Ax + By = C Simplified? 2 2 2 Example 2-3c
  • 9. Write the equation in standard form. Identify A, B, and C. Ax + By = C Simplified? Example 2-3a
  • 10. Write the equation in standard form. Identify A, B, and C. Ax + By = C -3 (-3) Simplified? Example 2-3b
  • 11. Find the x- and y- intercepts of -2x + y – 4 = 0 x-intercept -2x + 0 – 4 = 0 -2x – 4 = 0 -2x = 4 x = -2 The x-intercept is -2 (-2, 0) y-intercept -2(0) + y – 4 = 0 0 + y – 4 = 0 y – 4 = 0 y = 4 The y-intercept is 4 (0, 4) Example 2-4b
  • 12. (0, 4) (–2, 0) Graph -2x + y – 4 = 0 x-intercept : –2 y-intercept: 4 Example 2-4c
  • 13. Slope m = vertical change Horizontal change m = ΔyΔx m = rise run Any two points on a line can be used to determine its slope.
  • 14. Find the slope of a line passing through (-3,5) & (2,1)
  • 15. Classification of lines by slope Positive slope Zero slope Negative slope Undefined slope
  • 16. Graph x = 1 Graph y = 3
  • 17. Parallel lines have equal slopes. Perpendicular lines have slopes that are opposite reciprocals.
  • 18. Graph the line that passes through (2, 1) that is parallel to the graph of 4x – 2y = 10 4x – 2y =10 -2y = -4x + 10 -2 -2 -2 y = 2x – 5 m = 2 , b = -5 Parallel slope = 2
  • 19. Graph the line that passes through (2, 1) that is perpendicular to the graph of 4x – 2y = 10 4x – 2y =10 -2y = -4x + 10 -2 -2 -2 y = 2x – 5 m = 2 , b = -5 Perpendicular slope = -1/2