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SYLLABUS                            Annexure ‘E’
                                MATHEMATICS(041)
                                  SA-II (2012-13)
               Second Term                                              Marks: 90
               UNITS                                                    MARKS
         II    ALGEBRA                                                  16
         III   GEOMETRY (Contd.)                                        38
         V     MENSURATION (Contd.)                                     18
         VI    STATISTICS AND PROBABILITY                               18
               TOTAL                                                    90

The Question Paper will include value based question(s)
             To the extent of 3-5 marks.

   The Problem Solving Assessment will be conducted for all students of class IX in Jan
    – Feb 2013 and the details are available in a separate circular.
   The `Problem Solving Assessment’ (CBSE-PSA) will be counted towards FA-4 which
    is 10% of total assessments of Class IX. This assessment will also be carried forward
    towards the FA-4 in Class X. This score will be reflected in one Language (English
    or Hindi), Mathematics, Science and Social Science w.e.f the session 2012-2013 for
    Class IX and 2013 – 14 for Class X.
   The same score will be reflected in FA-4 for class IX and Class X.
    The students will have the option to improve their PSA Score in Class X, as they can
    sit for the test with Class IX students of the Session 2013-2014 in January –
    February 2014. The best scores will be reflected in the final certificate in case of
    those applying for improvement.
   The schools which have already planned their time table and other details regarding
    FA-4 will take the best scores of FA-3 and FA-4 to count towards the total 10%, now
    available for FA-3 and FA-4 taken together.




                                          64
65
66
Design of Question Paper
                            Mathematics (047)
                                 Class IX
                            S. A. –II (2012-13)

Type of Question     Marks per question     Total no. of Questions    Total Marks

      M.C.Q                   1                       8                    8
       SA-I                   2                       6                   12
      SA-II                   3                      10                   30
        LA                    4                      10                   40
                TOTAL                                34                   90



The Question Paper will include value based question(s)
              to the extent of 3-5 marks

The Question Paper will not have any choice(s) in any of
                   the questions.



                                  Weightage
  S.No.   Unit No.    Topic                                          Weightage

  1       II          Algebra (contd.) 3+4                        16
                      [Linear equations in two variables]
  2       III         Geometry (contd.) 1+2+4                     38
                      [Quadrilaterals,Area,Circles,Constructions]

  3       V           Mensuration 1+3+4                              18

  4       VI          Statistics & Probability 2+3                   18

  Total                                                              90




                                       67
Sample Questions
                                               Mathematics (047)
                                                    Class IX
                                               S. A. –II (2012-13)

M.C.Q.          1 Mark

     1. If in a quadrilateral, diagonals are equal, then it cannot be a :
        (A) Square       (B) Parallelogram     (C) Rhombus (D) Rectangle
     2. If in a sphere, volume and surface area are numerically equal, then radius will be :
        (A) 1            (B) 3        (C) 2          (D) 4

SA-I            2 Marks

     3. In a     ABC, E is the mid-point of median AD. Show that ar (BED) = 1 ar (ABC)
                                                                                4
     4. Find the mode of 14, 25, 14, 26, 27, 16, 14, 18, 22, 25,26, 30, 14, 25, 22.

SA-II           3 Marks

     5. The slant height and base diameter of a conical tomb are 25 m and 14m respectively. Find the cost of
        white – washing its curved surface at the rate of.
     6. In a survey, 1000 families with two children were selected randomly and the following data were
        recorded :

        No. of girls in the family             2                   1                   0

        No. of families                        320                 460                 220


        Find the probability of a family, chosen at random, having (i) 2 girls (ii) 1 girl (iii) less than 1 girl.
     7. Draw graphs of 3x+2y=0 and 2x-3y=0. What is the point of intersection of the two lines representing
        the above equation.

LA      – 4 Marks

     8. A 44m x 11m sheet is roled along length to form a cylinder. Find the volume of the cylinder.
     9. Two parallel lines l and m are intersected by a transversal p as shown in the figure. Show that the
        quadrilateral formed by the bisectors of interior angles is a rectangle.




                                                     P
                                                          68
P                 A   S
                                                            l
                                 B                 D

                                                            m
                             Q        C              R



 10. Cost of 7 pens and 8 pencils is Rs. 87 and cost of 6 pens and 4 pencils is Rs. 66. Write linear equations
     representing the above data and draw its graph. Also find the cost of 1 pen and 1 pencil from the
     graph.

                                               ANSWER KEY
1. (C)                                                                           1M
2. (B)                                                                           1M
3. Median of a triangle divides it into two triangles of equal area
                                                                         A
     In     ABC, AD is median                                                              1 M
                                                                                           2

       . ar (ABD) = ½ ar (ABC) (i)                                                         Fig 1 M
      . .                                                                    E                  2
             In    ABD, BE is median

                                                                B            D         C
       . ar (BED) = ½ ar (ABD)
      . .                                                                                  1M
                  = ¼ ar (ABC) using (i)                                                   2

4. Number 14 occurs most frequently i.e. 4 times                                           1 M

     so mode = 14                                                                          1 M

5. l = slant height = 25 m, r = radius = 7 m

     Area of curved surface of conical tomb = ᴫ rl                                         1 M
                                                                                 2
                   = 22 x 7x25
                      7
                   = 550 m2                                                                1 M
     Cost of white mash @ Rs. 410 per 100 m2 = 550 x 410                                   1 M
                                                       100
                                               = Rs. 2255/-                                1 M
                                                                                 2


                                                       69
6. (i)         Prob of 2 girls in the family           = p(2) = 320        =    8                  1 M
                                                                1000           25

               Prob of 1 girl in the family            = p(1) = 460 =          23                  1 M
                                                                1000           50
               Prob of less than 1 girls in the family = p(0) = 220                 =   11         1 M
                                                                1000                    50

7. 3x + 2y = 0
   Y = - 3x
         2

                                                                                        Y
                    x       0         2          -2
                                                                                                2 x – 3y = 0
                    Y       0        -3           3

                        Graph                                  3x+2y=0

                   2x – 3y = 0                        1M
                                                                                            O
                                                                      l
                        Y = 2x                                        x                                        x
                            3
                                x         0        3       6
                                Y         0        2       4

                               Graph                                      1M            Yl
                        Point of intersection (o, o)

8. Area of sheet                 =             44 x 11 m2
    Height of cylinder           =            length of sheet = 44 m                               1M
         Area of cylinder        =            2 ᴫ rh = 2. 22 r. 44 = 44x11                         1M
                                                           7
               r=7 m                                                                               ½M
                 4
            Vol. of cylinder     =            ᴫ r2 h
                                 =       22 . 7 . 7 . 44                                           ½M
                                         7 4 4
                                 =       1547 m3
                                           2
                                 =       773.5 m3                                                  1M
9.       PAC =   ACR             (alternate angle)
         1 PAC = 1
         2        2
           BAC = ACD                                                                               ½M


                                                                 70
But they are alternate angles for lines AB and DC with AC as transversal


        So      AB ǁ DC                                                            1M
        Similarly BC ǁ AD                                                          ½M
           ABCD is a parallelogram
           Also PAC + CAS = 180˚                                   (linear pair)
             1 PAC + 1 CAS = 90˚                                                   1M
             2        2
            BAC +   CAD = 90˚
                     BAD = 90˚                                                     ½M
        ABCD is a parallelogram with            A= 90˚

           ABCD is a rectangle                                                     ½M
10.     Let cost of 1 pen            = Rs. x
           cost of 1 pencil          = Rs. y
        7x + 8y = 87                                                                           6x +

4y = 66 or 2x + 3y =33                                             ½

        7x + 8y = 87
                                                                       Y
        Y = 87 – 7x
              8
                 x       3       9
                 Y       7       3

        Graph                        1½M

        3x + 2y = 33
        y = 33 – 3x
                2                                                                  (9.3)
             x       9       5
             Y       3       9                           Xl                                X


Point of intersection is ( 9, 3) i.e.          1½ M
Cost of 1 Pen           = Rs. 9                                        Yl
Cost of 1 Pencil        = Rs. 3                ½M




                                                         71
VALUE BASED QUESTION

                                                                                                4 Marks
Shimpi, a class IX student received cash award of Rs. 10,000/- (Ten thousand) in the singing competition.
Her father advised her to made a budget plan for spending this amount. She made following plan :


        Sl.                       Head                  Amount
       No.
      1       Donation in temple                             200
      2       Tuition fee to needy child                     100
      3       Welfare of senior citizens                     500
      4       Welfare of street children                     800
      5       Saving in bank                               4000
      6       Books for family library                     2000
      7       Picnic for family                            1000
      8       Gift to grand parents                        1100
      9       Tea party to friends                           300
              Total                                       10000


Make a pie chart for the above data.
From above answer the following question :

   1. Which mathematical concepts have been covered in this?
   2. How will you rate her budget plan? In your opinion which head has been given (i) more than it
      deserved and (ii) less than it deserved?
   3. Which values are depicted in her plan?




                                                   72
Marking scheme Value BasedQuestion


Sl.                 Head                        Amount    Central angle
No.
1   Donation in temple                              200            7.2
2   Tuition fee to needy child                      100            3.6
3   Welfare of Senior Citizen                       500           18.0
4   Welfare of street children                      800           28.8
5   Saving in bank                                 4000          144.0
6   Books for family library                       2000           72.0
7   Picnic for family                              1000           36.0
8   Gift to grand parents                          1100           39.6
9   Tea party to friends                            300           10.8
    Total                                         10000          360.0




                                           73

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Mathematics s-a-ii-class-ix-2012-13

  • 1. SYLLABUS Annexure ‘E’ MATHEMATICS(041) SA-II (2012-13) Second Term Marks: 90 UNITS MARKS II ALGEBRA 16 III GEOMETRY (Contd.) 38 V MENSURATION (Contd.) 18 VI STATISTICS AND PROBABILITY 18 TOTAL 90 The Question Paper will include value based question(s) To the extent of 3-5 marks.  The Problem Solving Assessment will be conducted for all students of class IX in Jan – Feb 2013 and the details are available in a separate circular.  The `Problem Solving Assessment’ (CBSE-PSA) will be counted towards FA-4 which is 10% of total assessments of Class IX. This assessment will also be carried forward towards the FA-4 in Class X. This score will be reflected in one Language (English or Hindi), Mathematics, Science and Social Science w.e.f the session 2012-2013 for Class IX and 2013 – 14 for Class X.  The same score will be reflected in FA-4 for class IX and Class X. The students will have the option to improve their PSA Score in Class X, as they can sit for the test with Class IX students of the Session 2013-2014 in January – February 2014. The best scores will be reflected in the final certificate in case of those applying for improvement.  The schools which have already planned their time table and other details regarding FA-4 will take the best scores of FA-3 and FA-4 to count towards the total 10%, now available for FA-3 and FA-4 taken together. 64
  • 2. 65
  • 3. 66
  • 4. Design of Question Paper Mathematics (047) Class IX S. A. –II (2012-13) Type of Question Marks per question Total no. of Questions Total Marks M.C.Q 1 8 8 SA-I 2 6 12 SA-II 3 10 30 LA 4 10 40 TOTAL 34 90 The Question Paper will include value based question(s) to the extent of 3-5 marks The Question Paper will not have any choice(s) in any of the questions. Weightage S.No. Unit No. Topic Weightage 1 II Algebra (contd.) 3+4 16 [Linear equations in two variables] 2 III Geometry (contd.) 1+2+4 38 [Quadrilaterals,Area,Circles,Constructions] 3 V Mensuration 1+3+4 18 4 VI Statistics & Probability 2+3 18 Total 90 67
  • 5. Sample Questions Mathematics (047) Class IX S. A. –II (2012-13) M.C.Q. 1 Mark 1. If in a quadrilateral, diagonals are equal, then it cannot be a : (A) Square (B) Parallelogram (C) Rhombus (D) Rectangle 2. If in a sphere, volume and surface area are numerically equal, then radius will be : (A) 1 (B) 3 (C) 2 (D) 4 SA-I 2 Marks 3. In a ABC, E is the mid-point of median AD. Show that ar (BED) = 1 ar (ABC) 4 4. Find the mode of 14, 25, 14, 26, 27, 16, 14, 18, 22, 25,26, 30, 14, 25, 22. SA-II 3 Marks 5. The slant height and base diameter of a conical tomb are 25 m and 14m respectively. Find the cost of white – washing its curved surface at the rate of. 6. In a survey, 1000 families with two children were selected randomly and the following data were recorded : No. of girls in the family 2 1 0 No. of families 320 460 220 Find the probability of a family, chosen at random, having (i) 2 girls (ii) 1 girl (iii) less than 1 girl. 7. Draw graphs of 3x+2y=0 and 2x-3y=0. What is the point of intersection of the two lines representing the above equation. LA – 4 Marks 8. A 44m x 11m sheet is roled along length to form a cylinder. Find the volume of the cylinder. 9. Two parallel lines l and m are intersected by a transversal p as shown in the figure. Show that the quadrilateral formed by the bisectors of interior angles is a rectangle. P 68
  • 6. P A S l B D m Q C R 10. Cost of 7 pens and 8 pencils is Rs. 87 and cost of 6 pens and 4 pencils is Rs. 66. Write linear equations representing the above data and draw its graph. Also find the cost of 1 pen and 1 pencil from the graph. ANSWER KEY 1. (C) 1M 2. (B) 1M 3. Median of a triangle divides it into two triangles of equal area A In ABC, AD is median 1 M 2 . ar (ABD) = ½ ar (ABC) (i) Fig 1 M . . E 2 In ABD, BE is median B D C . ar (BED) = ½ ar (ABD) . . 1M = ¼ ar (ABC) using (i) 2 4. Number 14 occurs most frequently i.e. 4 times 1 M so mode = 14 1 M 5. l = slant height = 25 m, r = radius = 7 m Area of curved surface of conical tomb = ᴫ rl 1 M 2 = 22 x 7x25 7 = 550 m2 1 M Cost of white mash @ Rs. 410 per 100 m2 = 550 x 410 1 M 100 = Rs. 2255/- 1 M 2 69
  • 7. 6. (i) Prob of 2 girls in the family = p(2) = 320 = 8 1 M 1000 25 Prob of 1 girl in the family = p(1) = 460 = 23 1 M 1000 50 Prob of less than 1 girls in the family = p(0) = 220 = 11 1 M 1000 50 7. 3x + 2y = 0 Y = - 3x 2 Y x 0 2 -2 2 x – 3y = 0 Y 0 -3 3 Graph 3x+2y=0 2x – 3y = 0 1M O l Y = 2x x x 3 x 0 3 6 Y 0 2 4 Graph 1M Yl Point of intersection (o, o) 8. Area of sheet = 44 x 11 m2 Height of cylinder = length of sheet = 44 m 1M Area of cylinder = 2 ᴫ rh = 2. 22 r. 44 = 44x11 1M 7 r=7 m ½M 4 Vol. of cylinder = ᴫ r2 h = 22 . 7 . 7 . 44 ½M 7 4 4 = 1547 m3 2 = 773.5 m3 1M 9. PAC = ACR (alternate angle) 1 PAC = 1 2 2 BAC = ACD ½M 70
  • 8. But they are alternate angles for lines AB and DC with AC as transversal So AB ǁ DC 1M Similarly BC ǁ AD ½M ABCD is a parallelogram Also PAC + CAS = 180˚ (linear pair) 1 PAC + 1 CAS = 90˚ 1M 2 2 BAC + CAD = 90˚ BAD = 90˚ ½M ABCD is a parallelogram with A= 90˚ ABCD is a rectangle ½M 10. Let cost of 1 pen = Rs. x cost of 1 pencil = Rs. y 7x + 8y = 87 6x + 4y = 66 or 2x + 3y =33 ½ 7x + 8y = 87 Y Y = 87 – 7x 8 x 3 9 Y 7 3 Graph 1½M 3x + 2y = 33 y = 33 – 3x 2 (9.3) x 9 5 Y 3 9 Xl X Point of intersection is ( 9, 3) i.e. 1½ M Cost of 1 Pen = Rs. 9 Yl Cost of 1 Pencil = Rs. 3 ½M 71
  • 9. VALUE BASED QUESTION 4 Marks Shimpi, a class IX student received cash award of Rs. 10,000/- (Ten thousand) in the singing competition. Her father advised her to made a budget plan for spending this amount. She made following plan : Sl. Head Amount No. 1 Donation in temple 200 2 Tuition fee to needy child 100 3 Welfare of senior citizens 500 4 Welfare of street children 800 5 Saving in bank 4000 6 Books for family library 2000 7 Picnic for family 1000 8 Gift to grand parents 1100 9 Tea party to friends 300 Total 10000 Make a pie chart for the above data. From above answer the following question : 1. Which mathematical concepts have been covered in this? 2. How will you rate her budget plan? In your opinion which head has been given (i) more than it deserved and (ii) less than it deserved? 3. Which values are depicted in her plan? 72
  • 10. Marking scheme Value BasedQuestion Sl. Head Amount Central angle No. 1 Donation in temple 200 7.2 2 Tuition fee to needy child 100 3.6 3 Welfare of Senior Citizen 500 18.0 4 Welfare of street children 800 28.8 5 Saving in bank 4000 144.0 6 Books for family library 2000 72.0 7 Picnic for family 1000 36.0 8 Gift to grand parents 1100 39.6 9 Tea party to friends 300 10.8 Total 10000 360.0 73