8. Proof of the Perpendicular Bisector Theorem Given: Prove: Show ∆ ACP ≅ ∆ BCP CA = CB ∠ APC ≅ ∠ CPB Reflexive property of congruence ∆ ACP ≅ ∆ BCP SAS Postulate CPCTC CA = CB Definition of Congruence Plan: bisects bisects
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10. Prove the Perpendicular Bisector Theorem Converse Given : C is equidistant from A and B Prove : C is on the perpendicular bisector of Plan Show ∆ APC ≅ ∆ BPC Draw