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1. rc rl-rlc

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1. rc rl-rlc

  1. 1. Prepared by Md. Amirul Islam Lecturer Department of Applied Physics & Electronics Bangabandhu Sheikh Mujibur Rahman Science & Technology University, Gopalganj – 8100
  2. 2. A circuit containing a series combination of a resistor and a capacitor is called an RC circuit. Maximum current of the circuit, I0 = Ɛ 𝐑 [When, t = 0, Maximum current flows] Maximum Charge on Capacitor, Q = CƐ [When t = tf = 5τ] Reference: Physics II by Robert Resnick and David Halliday, Topic – 28.4, Page – 883
  3. 3. Expression of Charge q(t), voltage VC and current I during charging phase of an RC circuit: The voltage across a capacitor cannot change instantaneously. Reference: Physics II by Robert Resnick and David Halliday, Topic – 28.4, Page – 883 By applying KVL, We get, Current through the circuit is the time rate of change of the charge on the capacitor plates. So, I = 𝐝𝐪 𝐝𝐭 Putting this value of I and after rearranging, we get,
  4. 4. Reference: Physics II by Robert Resnick and David Halliday, Topic – 28.4, Page – 883 This is the equation of charge stored in a capacitor. Voltage across the capacitor is, VC = q(t) / C Equation of instantaneous current can be obtained by differentiating the equation of charge,
  5. 5. Reference: Physics II by Robert Resnick and David Halliday, Topic – 28.4, Page – 883 Graph: Time vs Charge (or voltage) The charge is zero at t = 0 and approaches the maximum value CƐ as t → ∞ . The current I has its maximum value at t = 0 and decays exponentially to zero as t → ∞. From the graph, we observe that after 5 Graph: Current vs Time
  6. 6. Expression of Charge q(t), voltage VC and current I during discharging phase of an RC circuit: Reference: Physics II by Robert Resnick and David Halliday, Topic – 28.4, Page – 885 By applying KVL in clockwise direction, we get, Now, I = 𝐝𝐪 𝐝𝐭 . Again, when t=0 then q = Q and when t=t then q = q
  7. 7. Reference: Physics II by Robert Resnick and David Halliday, Topic – 28.4, Page – 885 This is the equation of charge remaining in the capacitor. The equation of current can be obtained by differentiating this equation.
  8. 8. Reference: Circuit Analysis by Robert Boylestad, Figure– 10.24 & 10.39, Page – 395 Figure: Charging – discharging network Here, VC – Voltage across capacitor iC – Circuit current VR – Voltage across resistor Figure: Charging – discharging cycles
  9. 9. Math. Problem: Find the mathematical expressions for the transient behavior of vC, iC, and vR for the circuit of Figure when the switch is moved to position 1. b. How much time must pass before it can be assumed, for all practical purposes, that iC ≈ 0 A and vC ≈ E volts? c. When the switch is placed to position 2, find the mathematical expressions for the transient behavior of vC, iC, and vR Reference: Circuit Analysis by Robert Boylestad, , Example – 10.5, Page – 393
  10. 10. Math. Problem: An uncharged capacitor and a resistor are connected in series to a battery, as shown in Figure. If C = 5μF and Ɛ = 12V, R = 0.8 MΩ, find the time constant of the circuit, the maximum charge on the capacitor, the maximum current in the circuit, and the charge and current as functions of time. Reference: Physics II by Robert Resnick and David Halliday, Example– 28.11, Page – 887 Time constant, τ = RC = 4s Maximum charge, Q = CƐ = 60 μC Maximum Current, I0 = Ɛ R = 15 μA
  11. 11. A circuit containing a series combination of a resistor and an inductor is called an RL circuit. an inductor in a circuit opposes changes in the current through that circuit. Reference: Physics II by Robert Resnick and David Halliday, Quick Quiz– 32.1, Page – 1018 When switch S is closed at t = 0. The current in the circuit begins to increase, and a back emf that opposes the increasing current is induced in the inductor. The back emf is, VL = – L diL dt In R-L circuits, the energy is stored in the form of a magnetic field established by the current through the coil.
  12. 12. Expression of transient current iL for the storage cycle of an RL circuit: Reference: Physics II by Robert Resnick and David Halliday, Quick Quiz– 32.1, Page – 1018 Here, VL = – L diL dt and VR = iL R By applying KVL we get, E – VR – VL = 0 or, E – iL R – L diL dt = 0 Let, E R – iL = x then, diL dt = – dx dt Now, x + L R dx dt = 0 or, dx x = – R L dt
  13. 13. Reference: Physics II by Robert Resnick and David Halliday, Quick Quiz– 32.1, Page – 1018 By integrating within the limit (x0 to x) and (0 to t), ln x x𝟎 = – R L t or, x = x0 e –Rt/L When t = 0, current iL = 0 thus, x = x0 = E R When t = t, current = iL thus, x = E R – iL Now, E R – iL = E R e –Rt/L or, iL = E R ( 1 – e –Rt/L )
  14. 14. For RL circuit time constant, τ = L R Reference: Physics II by Robert Resnick and David Halliday, Quick Quiz– 32.1, Page – 1019 Thus the equation of current, iL = E R ( 1 – e –t/τ ) When t → ∞ current reaches final value or steady state value and then, iL = E R . That is, the inductor acts as a short circuit. Physically, τ is the time it takes the current in the circuit to reach ( 1 – e –1 ) = 0.637 or 63.7% of its final value E R . Figure: Storage Cycle T𝐡𝐞 𝐞𝐪𝐮𝐚𝐭𝐢𝐨𝐧 𝐨𝐟 𝐕𝐨𝐥𝐭𝐚𝐠𝐞 𝐚𝐜𝐫𝐨𝐬𝐬 𝐢𝐧𝐝𝐮𝐜𝐭𝐨𝐫, VL = E R e –t/τ T𝐡𝐞 𝐞𝐪𝐮𝐚𝐭𝐢𝐨𝐧 𝐨𝐟 𝐕𝐨𝐥𝐭𝐚𝐠𝐞 𝐚𝐜𝐫𝐨𝐬𝐬 𝐫𝐞𝐬𝐢𝐬𝐭𝐨𝐫, VR = E R (1 – e –t/τ )
  15. 15. Find the mathematical expressions for the transient behavior of iL and vL for the circuit of figure after closing of the switch. Reference: Circuit Analysis by Robert Boylestad, Example– 12.4, Page – 484
  16. 16. The switch in figure is thrown closed at t = 0 (a) Find the time constant of the circuit. (b) Calculate the current in the circuit at t = 2 ms Reference: Physics II by Robert Resnick and David Halliday, Example– 32.3, Page – 1021
  17. 17. RL Circuit – decay Phase: Reference: Physics II by Robert Resnick and David Halliday, Problem – 18, Page – 1036, 1020 At the instant S2 is closed, S1 is opened, the battery is no longer part of the circuit. Stored magnetic energy inside the inductor starts to decay. By applying KVL now, – iL R – L diL dt = 0 or, diL iL = – R L dt After integrating within the limit (i0 to iL) and (0 to t) we get, ln iL – ln i0 = – R L t or, iL = i0 e – Rt/L = i0 e – t/τ = E R e – t/τ So the current through the inductor decrease according to this equation.
  18. 18. A circuit containing a series combination of a resistor, an inductor and a capacitor is called an RLC circuit. Let, the capacitor has an initial charge Qmax. Thus energy is stored in the capacitor and inductor. When the switch is closed, the resistor causes transformation to internal energy. The rate of energy transformation is: Reference: Physics II by Robert Resnick and David Halliday, Topic – 32.6, Page – 1031 The negative sign indicates that the energy of the circuit is decreasing in time.
  19. 19. Reference: Physics II by Robert Resnick and David Halliday, Topic – 32.6, Page – 1031 This energy is equal to the energy of capacitor and inductor. Thus, Solution of this equation is, ωd is the angular frequency at which the circuit oscillates.
  20. 20. Reference: Physics II by Robert Resnick and David Halliday, Topic – 32.6, Page – 1031 A plot of the charge versus time for the damped oscillator is shown in Figure. the value of the charge on the capacitor undergoes a damped harmonic oscillation. When R << 4L/C , second term of ωd can be neglected. Then ωd = 1/ LC and we get un-damped oscillation i.e. pure sinusoidal wave. The circuit where no resistance is present, the LC circuit is called tank circuit and we can get pure sinusoidal wave form this circuit.

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