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Tecnológico De Estudios Superiores
De Jilotepec

Calculo Vectorial
Ángulos Que Se Forman En Dos
Líneas Rectas Parametrizadas
Wendy Herrera Santillán
Brenda Cuevas Trejo
Israel Cruz Jasso
EJERCICIO 1.
   X1= 4-t   X2=5+2s     FORMULAS
                          L1(L2)=||L1|| ||L2||COSƟ
   y2=1+3s   y1=3+2t
                          Ɵ=arc cos [L1(L2)/||L1||||L2||]
   z2=5-6s   z1= -2-2t


PROCEDIMIENTO:

   X=X2+T(X2-X1)
X2=4                             L1= ( 5,1,2)
X2-X1=-1:.X1=5
   Y1=3
Y2-Y1=2:.Y1=1
   Z1=0
 Z2-Z1=-2:.Z=2
   X2= 5 + 2S
X2=5
                 L2= ( 3,-2.11)
X2-X1 = 2
X1= 3
   Y2= 1 + 3S
Y2= 1
Y2 – Y1= 3
Y1= -2
   Z2= 5 – 6S
Z2=5
Z2 – Z1= -6
Z1=11
   PRODUCTO PUNTO
L1= ( 5,1,2)
L2= ( 3.-2,11)
15 – 2 + 22
= 35
||L1|| = 5.47
||L2|| = 11.57
Ɵ arc cos [ 35 / (5.47) (11.57)
= 56 25’



                                  56° 25´
EJERCICIO 2.
X – 4 / 2 = X + 5 / 7 = 2 – 1/ -1
X + 3/ -2 = Y – 9 = Z / 4
   X= X2 + T ( X2 - X1)
   Y= Y2 + T ( YZ – Y1)
   Z= Z2 + T (Z2 – Z1)
DESPEJANDO:
   T= X – X2 / X2 – X1
   T= Y – Y2/ Y2 – Y1
   T= Z – Z2/ Z2 – Z1
L1=
X2 = 1
X2 - X1 = 2
:. X1= -1
   Y2 = -5
Y2 – Y1 = 7
:. Y1= -12
   Z2 = 1
Z2 – Z1= -1
:. Z1= 2      L1= ( -1,-12,2)
  L2=
 X2 = -3

X2 – X1 = -2
:. X1= -1
 Y2 = 9

Y2 – Y1 = 1
               L2 = ( -1,8,-4)
:. Y1 = 8
 Z2= 0

Z2 – Z1= 4
:. Z1= -4
   PRODUCTO PUNTO:
   (-1,-12,2)
   (-1,8,-4)
= -103
   Arc cos Ɵ [ - 103 / ( 12.20) (9) ]
||L1||= 12.20
||L2||= 9
Ɵ= 159 43’


                                         Ɵ= 159 43’

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Ejercicios de calculo

  • 1. Tecnológico De Estudios Superiores De Jilotepec Calculo Vectorial Ángulos Que Se Forman En Dos Líneas Rectas Parametrizadas Wendy Herrera Santillán Brenda Cuevas Trejo Israel Cruz Jasso
  • 2. EJERCICIO 1.  X1= 4-t X2=5+2s FORMULAS L1(L2)=||L1|| ||L2||COSƟ  y2=1+3s y1=3+2t Ɵ=arc cos [L1(L2)/||L1||||L2||]  z2=5-6s z1= -2-2t PROCEDIMIENTO:  X=X2+T(X2-X1) X2=4 L1= ( 5,1,2) X2-X1=-1:.X1=5  Y1=3 Y2-Y1=2:.Y1=1  Z1=0 Z2-Z1=-2:.Z=2
  • 3. X2= 5 + 2S X2=5 L2= ( 3,-2.11) X2-X1 = 2 X1= 3  Y2= 1 + 3S Y2= 1 Y2 – Y1= 3 Y1= -2  Z2= 5 – 6S Z2=5 Z2 – Z1= -6 Z1=11
  • 4. PRODUCTO PUNTO L1= ( 5,1,2) L2= ( 3.-2,11) 15 – 2 + 22 = 35 ||L1|| = 5.47 ||L2|| = 11.57 Ɵ arc cos [ 35 / (5.47) (11.57) = 56 25’ 56° 25´
  • 5. EJERCICIO 2. X – 4 / 2 = X + 5 / 7 = 2 – 1/ -1 X + 3/ -2 = Y – 9 = Z / 4  X= X2 + T ( X2 - X1)  Y= Y2 + T ( YZ – Y1)  Z= Z2 + T (Z2 – Z1) DESPEJANDO:  T= X – X2 / X2 – X1  T= Y – Y2/ Y2 – Y1  T= Z – Z2/ Z2 – Z1 L1= X2 = 1 X2 - X1 = 2 :. X1= -1
  • 6. Y2 = -5 Y2 – Y1 = 7 :. Y1= -12  Z2 = 1 Z2 – Z1= -1 :. Z1= 2 L1= ( -1,-12,2)
  • 7.  L2=  X2 = -3 X2 – X1 = -2 :. X1= -1  Y2 = 9 Y2 – Y1 = 1 L2 = ( -1,8,-4) :. Y1 = 8  Z2= 0 Z2 – Z1= 4 :. Z1= -4
  • 8. PRODUCTO PUNTO:  (-1,-12,2)  (-1,8,-4) = -103  Arc cos Ɵ [ - 103 / ( 12.20) (9) ] ||L1||= 12.20 ||L2||= 9 Ɵ= 159 43’ Ɵ= 159 43’