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Paradox

                         魏澤人

                     國立東華大學應用數學學系


                       2013-04-13




魏澤人 (國立東華大學應用數學學系)       Paradox    2013-04-13   1 / 30
1


Proof.

                       1        −1
                           =
                      −1        1
                         1     −1
                           =
                        −1      1
                      √      √
                         1     −1
                      √    = √
                        −1     1
                     √ √     √ √
                      1 1 =   −1 −1
                        1 = −1




魏澤人 (國立東華大學應用數學學系)         Paradox    2013-04-13   2 / 30
2




Proof.
                               6           3    3
            −1 = (−1)3 = (−1) 2 = ((−1)2 ) 2 = 1 2 = 1




魏澤人 (國立東華大學應用數學學系)            Paradox                    2013-04-13   3 / 30
3




    任何一個人的團體,所有人頭髮數量一定一樣多。
    假設所有 n 個人的團體,都必然每個人有相同數量頭髮。
    考慮一個 n + 1 人團體,編號為 1, 2, . . . , n + 1
    1, 2, . . . , n 每個人頭髮數量相同。
    2, . . . , n, n + 1 每個人頭髮數量相同
    所以 1, 2, . . . , n, n + 1 每個人的頭髮都相同




魏澤人 (國立東華大學應用數學學系)          Paradox          2013-04-13   4 / 30
4

證明 a = b for every a, b ∈ N
對 max (a, b) 做數學歸納法
case max (a, b) = 0: a = 0 = b, done.
設
                         max (a, b) = n ⇒ a = b
成立。
當 max (a, b) = n + 1 時,

                           max (a, b) = n + 1
                     ⇒ max (a − 1, b − 1) = n
                     ⇒        a−1=b−1
                     ⇒            a=b



魏澤人 (國立東華大學應用數學學系)               Paradox          2013-04-13   5 / 30
5




    1   設 BC 中點 D
    2   設 ∠A 平分線及 BC 中垂線交於O (否則 AB = AC )
    3   做 OR⊥AB, OQ⊥AC
    4   由 AAS, RAO ∼ QAO
                   =
    5   由 SAS, ODB ∼ ODC
                   =
    6   所以       ∼ QOC
             ROB =
    7   得 AB = AC
魏澤人 (國立東華大學應用數學學系)         Paradox          2013-04-13   6 / 30
Braess’s Paradox




Without ——————-
Total 4000 cars.
                         A
Route Start->A->END: 100 + 45
                         B
Route Start->B->END: 100 + 45
Best solution is A = B = 2000, Time = 2000 + 45 = 65.
                                       100




魏澤人 (國立東華大學應用數學學系)               Paradox                2013-04-13   7 / 30
Braess’s Paradox




Without ——————-
Total 4000 cars.
                         A
Route Start->A->END: 100 + 45
                         B
Route Start->B->END: 100 + 45
Best solution is A = B = 2000, Time = 2000 + 45 = 65.
                                       100




魏澤人 (國立東華大學應用數學學系)               Paradox                2013-04-13   7 / 30
Braess’s Paradox




With —————–
Total 4000 cars.
                   X
Route Start->A: 100 < 45
                   X
Route B->END: 100 < 45
Best solution is 100 + 4000 = 80.
                 4000
                        100




魏澤人 (國立東華大學應用數學學系)                  Paradox   2013-04-13   8 / 30
Zeno’s paradoxes




   Achilles and the tortoise
   The dichotomy paradox
   The arrow paradox




魏澤人 (國立東華大學應用數學學系)             Paradox   2013-04-13   9 / 30
Zeno’s paradoxes




   Achilles and the tortoise
   The dichotomy paradox
   The arrow paradox




魏澤人 (國立東華大學應用數學學系)             Paradox   2013-04-13   9 / 30
Zeno’s paradoxes




   Achilles and the tortoise
   The dichotomy paradox
   The arrow paradox




魏澤人 (國立東華大學應用數學學系)             Paradox   2013-04-13   9 / 30
Zeno’s paradoxes




   Achilles and the tortoise
   The dichotomy paradox
   The arrow paradox




魏澤人 (國立東華大學應用數學學系)             Paradox   2013-04-13   9 / 30
Thomson’s Lamp



  time    Status
  2:00      on
  3:00      off
  3:30      on
  3:45      off
 3:52.5     on
    ...
  4:00      ?




魏澤人 (國立東華大學應用數學學系)   Paradox   2013-04-13   10 / 30
Infinite




    Hilbert’s paradox of the Grand Hotel
    Squares and Natural numbers
    Balls and vase problem




魏澤人 (國立東華大學應用數學學系)                Paradox   2013-04-13   11 / 30
Infinite




    Hilbert’s paradox of the Grand Hotel
    Squares and Natural numbers
    Balls and vase problem




魏澤人 (國立東華大學應用數學學系)                Paradox   2013-04-13   11 / 30
Infinite




    Hilbert’s paradox of the Grand Hotel
    Squares and Natural numbers
    Balls and vase problem




魏澤人 (國立東華大學應用數學學系)                Paradox   2013-04-13   11 / 30
玫瑰小木




中午前 1 分鐘,放 10 個球到花瓶中,然後拿出一個。
中午前1/2分鐘,放 10 個球到花瓶中,然後拿出一個。
中午前1/4分鐘,放 10 個球到花瓶中,然後拿出一個。
...
中午時,花瓶有幾顆球?




魏澤人 (國立東華大學應用數學學系)   Paradox   2013-04-13   12 / 30
玫瑰小木




球編號 1, 2, 3, ...
中午前 1 分鐘,放 1-10號球到花瓶中,然後拿出 1 號。
中午前1/2分鐘,放 11-20 個球到花瓶中,然後拿出 2 號。
中午前1/4分鐘,放 21-30 個球到花瓶中,然後拿出 3 號。
...
中午時,花瓶有幾顆球?




魏澤人 (國立東華大學應用數學學系)   Paradox        2013-04-13   13 / 30
Banach–Tarski paradox




魏澤人 (國立東華大學應用數學學系)      Paradox   2013-04-13   14 / 30
Voter’s Paradox




2                  2
3   think A > B,   3   think B > C , then A > C ?
      Voter 1: A > B > C
      Voter 2: B > C > A
      Voter 3: C > A > B




魏澤人 (國立東華大學應用數學學系)                     Paradox      2013-04-13   15 / 30
Voter’s Paradox




2                  2
3   think A > B,   3   think B > C , then A > C ?
      Voter 1: A > B > C
      Voter 2: B > C > A
      Voter 3: C > A > B




魏澤人 (國立東華大學應用數學學系)                     Paradox      2013-04-13   15 / 30
Arrow’s Paradox



It is impossible to satisfies
     Universal Domain : Contain all possible choices.
     Irrelevant Alternatives - An individual preference stated in binary
     terms shouldn’t affect his ordering of other preferences
     Pareto Optimality : If every one votes the same way, the society is
     decisive.
          Monotonicity+Non-imposition
     Nondictatorship : More than one person’s vote should be used.




魏澤人 (國立東華大學應用數學學系)                  Paradox                     2013-04-13   16 / 30
Arrow’s Paradox



It is impossible to satisfies
     Universal Domain : Contain all possible choices.
     Irrelevant Alternatives - An individual preference stated in binary
     terms shouldn’t affect his ordering of other preferences
     Pareto Optimality : If every one votes the same way, the society is
     decisive.
          Monotonicity+Non-imposition
     Nondictatorship : More than one person’s vote should be used.




魏澤人 (國立東華大學應用數學學系)                  Paradox                     2013-04-13   16 / 30
Arrow’s Paradox



It is impossible to satisfies
     Universal Domain : Contain all possible choices.
     Irrelevant Alternatives - An individual preference stated in binary
     terms shouldn’t affect his ordering of other preferences
     Pareto Optimality : If every one votes the same way, the society is
     decisive.
          Monotonicity+Non-imposition
     Nondictatorship : More than one person’s vote should be used.




魏澤人 (國立東華大學應用數學學系)                  Paradox                     2013-04-13   16 / 30
Arrow’s Paradox



It is impossible to satisfies
     Universal Domain : Contain all possible choices.
     Irrelevant Alternatives - An individual preference stated in binary
     terms shouldn’t affect his ordering of other preferences
     Pareto Optimality : If every one votes the same way, the society is
     decisive.
          Monotonicity+Non-imposition
     Nondictatorship : More than one person’s vote should be used.




魏澤人 (國立東華大學應用數學學系)                  Paradox                     2013-04-13   16 / 30
Arrow’s Paradox



It is impossible to satisfies
     Universal Domain : Contain all possible choices.
     Irrelevant Alternatives - An individual preference stated in binary
     terms shouldn’t affect his ordering of other preferences
     Pareto Optimality : If every one votes the same way, the society is
     decisive.
          Monotonicity+Non-imposition
     Nondictatorship : More than one person’s vote should be used.




魏澤人 (國立東華大學應用數學學系)                  Paradox                     2013-04-13   16 / 30
錢包



A和B兩人進行一場賭博。
賭法是:由第三者計算A、B二君錢包裡面的錢,錢少者可以贏走錢多
者的錢。
A對於這場賭博的想法為:若B君的錢比我少,我可能輸掉我現有的
錢。但若B君的錢比我多,我贏了,就會得到多於我現有的錢。我能夠
贏的錢比輸的錢多,所以這場賭博對我有利。
而B的想法也是如此。
二人想法的邏輯都正確,但若認為二人的想法都正確,又將做出這場賭
博對A、B二人都有利的錯誤結論。這顯然是一個悖論。




魏澤人 (國立東華大學應用數學學系)   Paradox   2013-04-13   17 / 30
信封




兩個外觀一樣的信封,都放了錢,一個裡面的金額是另外一個的兩倍。
你隨機的拿起了一個,然後給你一個機會來交換,你是否要交換?




魏澤人 (國立東華大學應用數學學系)   Paradox   2013-04-13   18 / 30
Barber Paradox



   There is a town with just one male barber.
   Every man in the town keeps himself clean-shaven
       some by shaving themselves
       some by attending the barber.
   The barber shaves all and only those men who do not shave
   themselves.
       seems reasonable.
   Does the barber shave himself?




魏澤人 (國立東華大學應用數學學系)               Paradox                 2013-04-13   19 / 30
Barber Paradox



   There is a town with just one male barber.
   Every man in the town keeps himself clean-shaven
       some by shaving themselves
       some by attending the barber.
   The barber shaves all and only those men who do not shave
   themselves.
       seems reasonable.
   Does the barber shave himself?




魏澤人 (國立東華大學應用數學學系)               Paradox                 2013-04-13   19 / 30
Barber Paradox



   There is a town with just one male barber.
   Every man in the town keeps himself clean-shaven
       some by shaving themselves
       some by attending the barber.
   The barber shaves all and only those men who do not shave
   themselves.
       seems reasonable.
   Does the barber shave himself?




魏澤人 (國立東華大學應用數學學系)               Paradox                 2013-04-13   19 / 30
Barber Paradox



   There is a town with just one male barber.
   Every man in the town keeps himself clean-shaven
       some by shaving themselves
       some by attending the barber.
   The barber shaves all and only those men who do not shave
   themselves.
       seems reasonable.
   Does the barber shave himself?




魏澤人 (國立東華大學應用數學學系)               Paradox                 2013-04-13   19 / 30
Barber Paradox




   The situation presented is in fact impossible:
       If the he does not shave himself, he must shave himself.
       If he does shave himself, he should not shave himself.
   Barber Paradox = Russell’s Paradox {x |x ∈ x }.
       Solution: modern set theory, ZFC.
       ZFC is the foundation of modern mathematics.




魏澤人 (國立東華大學應用數學學系)                Paradox                         2013-04-13   20 / 30
Barber Paradox




   The situation presented is in fact impossible:
       If the he does not shave himself, he must shave himself.
       If he does shave himself, he should not shave himself.
   Barber Paradox = Russell’s Paradox {x |x ∈ x }.
       Solution: modern set theory, ZFC.
       ZFC is the foundation of modern mathematics.




魏澤人 (國立東華大學應用數學學系)                Paradox                         2013-04-13   20 / 30
Liar’s Paradox




    Epimenides paradox: A Cretan says: "All Cretans are liars".
    Liar paradox: "This sentence is false." or "Is the answer to this
    question no?"
    Godel’s incomplete theorem: “This sentence can not be proved”.
        The sentence is true and can not be proved.
        No formal system is complete.
        Huge impact.




魏澤人 (國立東華大學應用數學學系)                 Paradox                     2013-04-13   21 / 30
Liar’s Paradox




    Epimenides paradox: A Cretan says: "All Cretans are liars".
    Liar paradox: "This sentence is false." or "Is the answer to this
    question no?"
    Godel’s incomplete theorem: “This sentence can not be proved”.
        The sentence is true and can not be proved.
        No formal system is complete.
        Huge impact.




魏澤人 (國立東華大學應用數學學系)                 Paradox                     2013-04-13   21 / 30
Self Reference Paradoxes



   Berry paradox: "the first number not nameable in under ten words".
       computability and complexity implication.
   Curry’s paradox: "If this sentence is true, the world will end in a
   week."
       logic and philosophy interests.
   Grelling-Nelson paradox: "heterological" := "not applicable to itself".
   Yablo’s paradox. A self reference paradoxes without self reference.




魏澤人 (國立東華大學應用數學學系)                 Paradox                    2013-04-13   22 / 30
Self Reference Paradoxes



   Berry paradox: "the first number not nameable in under ten words".
       computability and complexity implication.
   Curry’s paradox: "If this sentence is true, the world will end in a
   week."
       logic and philosophy interests.
   Grelling-Nelson paradox: "heterological" := "not applicable to itself".
   Yablo’s paradox. A self reference paradoxes without self reference.




魏澤人 (國立東華大學應用數學學系)                 Paradox                    2013-04-13   22 / 30
Self Reference Paradoxes



   Berry paradox: "the first number not nameable in under ten words".
       computability and complexity implication.
   Curry’s paradox: "If this sentence is true, the world will end in a
   week."
       logic and philosophy interests.
   Grelling-Nelson paradox: "heterological" := "not applicable to itself".
   Yablo’s paradox. A self reference paradoxes without self reference.




魏澤人 (國立東華大學應用數學學系)                 Paradox                    2013-04-13   22 / 30
Self Reference Paradoxes



   Berry paradox: "the first number not nameable in under ten words".
       computability and complexity implication.
   Curry’s paradox: "If this sentence is true, the world will end in a
   week."
       logic and philosophy interests.
   Grelling-Nelson paradox: "heterological" := "not applicable to itself".
   Yablo’s paradox. A self reference paradoxes without self reference.




魏澤人 (國立東華大學應用數學學系)                 Paradox                    2013-04-13   22 / 30
More Self Reference Paradoxes




   Opposite Day: "It is opposite day today."
   Paradox of the Court: A law student agrees to pay his teacher after
   winning his first case.
   Quine’s paradox: "Yields a falsehood when appended to its own
   quotation" yields a falsehood when appended to its own quotation.
   Richard’s paradox:




魏澤人 (國立東華大學應用數學學系)              Paradox                    2013-04-13   23 / 30
聖彼得堡




擲硬幣,若第一次擲出正面,你就賺1元。若第一次擲出反面,那就要
再擲一次,若第二次擲的是正面,你便賺2元。若第二次擲出反面,那
就要擲第三次,若第三次擲的是正面,你便賺2*2元. . . . . . 如此類推,即
可能擲一次遊戲便結束,也可能反覆擲沒完沒了。問題是,你最多肯付
多少錢參加這個遊戲?




魏澤人 (國立東華大學應用數學學系)   Paradox      2013-04-13   24 / 30
Penney Ante




   HHH         TTT
   HHT         TTH
   HTH         THT
   HTT         THH




魏澤人 (國立東華大學應用數學學系)   Paradox   2013-04-13   25 / 30
Simpson’s Paradox




                   Men                       Women
 Dept A   250/500, 50% accepted        9/10, 90% accepted
 Dept B     1/10, 10% accepted       100/500, 20% accepted
 Totals      251/510 accepted           109/510 accepted




魏澤人 (國立東華大學應用數學學系)                Paradox                    2013-04-13   26 / 30
Simpson’s Paradox




                 Treatment A     Treatment B
     Both       78% (273/350)   83% (289/350)
 Small Stones    93% (81/87)    87% (234/270)
 Large Stones   73% (192/263)    69% (55/80)




魏澤人 (國立東華大學應用數學學系)              Paradox         2013-04-13   27 / 30
UC Berkeley 1973




         Applicants   % admitted
  Men      8442          44%
 Women     4321          35%




魏澤人 (國立東華大學應用數學學系)            Paradox   2013-04-13   28 / 30
UC Berkeley 1973




 Major   Men    %    Women    %
  A      825   62%    108    82%
  B      560   63%    25     68%
  C      325   37%    593    34%
  D      417   33%    375    35%
  E      191   28%    393    24%
  F      272    6%    341    7%




魏澤人 (國立東華大學應用數學學系)           Paradox   2013-04-13   29 / 30
Related Paradox




   Low birth weight paradox
   Batting average




魏澤人 (國立東華大學應用數學學系)            Paradox   2013-04-13   30 / 30

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Imo talk2

  • 1. Paradox 魏澤人 國立東華大學應用數學學系 2013-04-13 魏澤人 (國立東華大學應用數學學系) Paradox 2013-04-13 1 / 30
  • 2. 1 Proof. 1 −1 = −1 1 1 −1 = −1 1 √ √ 1 −1 √ = √ −1 1 √ √ √ √ 1 1 = −1 −1 1 = −1 魏澤人 (國立東華大學應用數學學系) Paradox 2013-04-13 2 / 30
  • 3. 2 Proof. 6 3 3 −1 = (−1)3 = (−1) 2 = ((−1)2 ) 2 = 1 2 = 1 魏澤人 (國立東華大學應用數學學系) Paradox 2013-04-13 3 / 30
  • 4. 3 任何一個人的團體,所有人頭髮數量一定一樣多。 假設所有 n 個人的團體,都必然每個人有相同數量頭髮。 考慮一個 n + 1 人團體,編號為 1, 2, . . . , n + 1 1, 2, . . . , n 每個人頭髮數量相同。 2, . . . , n, n + 1 每個人頭髮數量相同 所以 1, 2, . . . , n, n + 1 每個人的頭髮都相同 魏澤人 (國立東華大學應用數學學系) Paradox 2013-04-13 4 / 30
  • 5. 4 證明 a = b for every a, b ∈ N 對 max (a, b) 做數學歸納法 case max (a, b) = 0: a = 0 = b, done. 設 max (a, b) = n ⇒ a = b 成立。 當 max (a, b) = n + 1 時, max (a, b) = n + 1 ⇒ max (a − 1, b − 1) = n ⇒ a−1=b−1 ⇒ a=b 魏澤人 (國立東華大學應用數學學系) Paradox 2013-04-13 5 / 30
  • 6. 5 1 設 BC 中點 D 2 設 ∠A 平分線及 BC 中垂線交於O (否則 AB = AC ) 3 做 OR⊥AB, OQ⊥AC 4 由 AAS, RAO ∼ QAO = 5 由 SAS, ODB ∼ ODC = 6 所以 ∼ QOC ROB = 7 得 AB = AC 魏澤人 (國立東華大學應用數學學系) Paradox 2013-04-13 6 / 30
  • 7. Braess’s Paradox Without ——————- Total 4000 cars. A Route Start->A->END: 100 + 45 B Route Start->B->END: 100 + 45 Best solution is A = B = 2000, Time = 2000 + 45 = 65. 100 魏澤人 (國立東華大學應用數學學系) Paradox 2013-04-13 7 / 30
  • 8. Braess’s Paradox Without ——————- Total 4000 cars. A Route Start->A->END: 100 + 45 B Route Start->B->END: 100 + 45 Best solution is A = B = 2000, Time = 2000 + 45 = 65. 100 魏澤人 (國立東華大學應用數學學系) Paradox 2013-04-13 7 / 30
  • 9. Braess’s Paradox With —————– Total 4000 cars. X Route Start->A: 100 < 45 X Route B->END: 100 < 45 Best solution is 100 + 4000 = 80. 4000 100 魏澤人 (國立東華大學應用數學學系) Paradox 2013-04-13 8 / 30
  • 10. Zeno’s paradoxes Achilles and the tortoise The dichotomy paradox The arrow paradox 魏澤人 (國立東華大學應用數學學系) Paradox 2013-04-13 9 / 30
  • 11. Zeno’s paradoxes Achilles and the tortoise The dichotomy paradox The arrow paradox 魏澤人 (國立東華大學應用數學學系) Paradox 2013-04-13 9 / 30
  • 12. Zeno’s paradoxes Achilles and the tortoise The dichotomy paradox The arrow paradox 魏澤人 (國立東華大學應用數學學系) Paradox 2013-04-13 9 / 30
  • 13. Zeno’s paradoxes Achilles and the tortoise The dichotomy paradox The arrow paradox 魏澤人 (國立東華大學應用數學學系) Paradox 2013-04-13 9 / 30
  • 14. Thomson’s Lamp time Status 2:00 on 3:00 off 3:30 on 3:45 off 3:52.5 on ... 4:00 ? 魏澤人 (國立東華大學應用數學學系) Paradox 2013-04-13 10 / 30
  • 15. Infinite Hilbert’s paradox of the Grand Hotel Squares and Natural numbers Balls and vase problem 魏澤人 (國立東華大學應用數學學系) Paradox 2013-04-13 11 / 30
  • 16. Infinite Hilbert’s paradox of the Grand Hotel Squares and Natural numbers Balls and vase problem 魏澤人 (國立東華大學應用數學學系) Paradox 2013-04-13 11 / 30
  • 17. Infinite Hilbert’s paradox of the Grand Hotel Squares and Natural numbers Balls and vase problem 魏澤人 (國立東華大學應用數學學系) Paradox 2013-04-13 11 / 30
  • 18. 玫瑰小木 中午前 1 分鐘,放 10 個球到花瓶中,然後拿出一個。 中午前1/2分鐘,放 10 個球到花瓶中,然後拿出一個。 中午前1/4分鐘,放 10 個球到花瓶中,然後拿出一個。 ... 中午時,花瓶有幾顆球? 魏澤人 (國立東華大學應用數學學系) Paradox 2013-04-13 12 / 30
  • 19. 玫瑰小木 球編號 1, 2, 3, ... 中午前 1 分鐘,放 1-10號球到花瓶中,然後拿出 1 號。 中午前1/2分鐘,放 11-20 個球到花瓶中,然後拿出 2 號。 中午前1/4分鐘,放 21-30 個球到花瓶中,然後拿出 3 號。 ... 中午時,花瓶有幾顆球? 魏澤人 (國立東華大學應用數學學系) Paradox 2013-04-13 13 / 30
  • 21. Voter’s Paradox 2 2 3 think A > B, 3 think B > C , then A > C ? Voter 1: A > B > C Voter 2: B > C > A Voter 3: C > A > B 魏澤人 (國立東華大學應用數學學系) Paradox 2013-04-13 15 / 30
  • 22. Voter’s Paradox 2 2 3 think A > B, 3 think B > C , then A > C ? Voter 1: A > B > C Voter 2: B > C > A Voter 3: C > A > B 魏澤人 (國立東華大學應用數學學系) Paradox 2013-04-13 15 / 30
  • 23. Arrow’s Paradox It is impossible to satisfies Universal Domain : Contain all possible choices. Irrelevant Alternatives - An individual preference stated in binary terms shouldn’t affect his ordering of other preferences Pareto Optimality : If every one votes the same way, the society is decisive. Monotonicity+Non-imposition Nondictatorship : More than one person’s vote should be used. 魏澤人 (國立東華大學應用數學學系) Paradox 2013-04-13 16 / 30
  • 24. Arrow’s Paradox It is impossible to satisfies Universal Domain : Contain all possible choices. Irrelevant Alternatives - An individual preference stated in binary terms shouldn’t affect his ordering of other preferences Pareto Optimality : If every one votes the same way, the society is decisive. Monotonicity+Non-imposition Nondictatorship : More than one person’s vote should be used. 魏澤人 (國立東華大學應用數學學系) Paradox 2013-04-13 16 / 30
  • 25. Arrow’s Paradox It is impossible to satisfies Universal Domain : Contain all possible choices. Irrelevant Alternatives - An individual preference stated in binary terms shouldn’t affect his ordering of other preferences Pareto Optimality : If every one votes the same way, the society is decisive. Monotonicity+Non-imposition Nondictatorship : More than one person’s vote should be used. 魏澤人 (國立東華大學應用數學學系) Paradox 2013-04-13 16 / 30
  • 26. Arrow’s Paradox It is impossible to satisfies Universal Domain : Contain all possible choices. Irrelevant Alternatives - An individual preference stated in binary terms shouldn’t affect his ordering of other preferences Pareto Optimality : If every one votes the same way, the society is decisive. Monotonicity+Non-imposition Nondictatorship : More than one person’s vote should be used. 魏澤人 (國立東華大學應用數學學系) Paradox 2013-04-13 16 / 30
  • 27. Arrow’s Paradox It is impossible to satisfies Universal Domain : Contain all possible choices. Irrelevant Alternatives - An individual preference stated in binary terms shouldn’t affect his ordering of other preferences Pareto Optimality : If every one votes the same way, the society is decisive. Monotonicity+Non-imposition Nondictatorship : More than one person’s vote should be used. 魏澤人 (國立東華大學應用數學學系) Paradox 2013-04-13 16 / 30
  • 30. Barber Paradox There is a town with just one male barber. Every man in the town keeps himself clean-shaven some by shaving themselves some by attending the barber. The barber shaves all and only those men who do not shave themselves. seems reasonable. Does the barber shave himself? 魏澤人 (國立東華大學應用數學學系) Paradox 2013-04-13 19 / 30
  • 31. Barber Paradox There is a town with just one male barber. Every man in the town keeps himself clean-shaven some by shaving themselves some by attending the barber. The barber shaves all and only those men who do not shave themselves. seems reasonable. Does the barber shave himself? 魏澤人 (國立東華大學應用數學學系) Paradox 2013-04-13 19 / 30
  • 32. Barber Paradox There is a town with just one male barber. Every man in the town keeps himself clean-shaven some by shaving themselves some by attending the barber. The barber shaves all and only those men who do not shave themselves. seems reasonable. Does the barber shave himself? 魏澤人 (國立東華大學應用數學學系) Paradox 2013-04-13 19 / 30
  • 33. Barber Paradox There is a town with just one male barber. Every man in the town keeps himself clean-shaven some by shaving themselves some by attending the barber. The barber shaves all and only those men who do not shave themselves. seems reasonable. Does the barber shave himself? 魏澤人 (國立東華大學應用數學學系) Paradox 2013-04-13 19 / 30
  • 34. Barber Paradox The situation presented is in fact impossible: If the he does not shave himself, he must shave himself. If he does shave himself, he should not shave himself. Barber Paradox = Russell’s Paradox {x |x ∈ x }. Solution: modern set theory, ZFC. ZFC is the foundation of modern mathematics. 魏澤人 (國立東華大學應用數學學系) Paradox 2013-04-13 20 / 30
  • 35. Barber Paradox The situation presented is in fact impossible: If the he does not shave himself, he must shave himself. If he does shave himself, he should not shave himself. Barber Paradox = Russell’s Paradox {x |x ∈ x }. Solution: modern set theory, ZFC. ZFC is the foundation of modern mathematics. 魏澤人 (國立東華大學應用數學學系) Paradox 2013-04-13 20 / 30
  • 36. Liar’s Paradox Epimenides paradox: A Cretan says: "All Cretans are liars". Liar paradox: "This sentence is false." or "Is the answer to this question no?" Godel’s incomplete theorem: “This sentence can not be proved”. The sentence is true and can not be proved. No formal system is complete. Huge impact. 魏澤人 (國立東華大學應用數學學系) Paradox 2013-04-13 21 / 30
  • 37. Liar’s Paradox Epimenides paradox: A Cretan says: "All Cretans are liars". Liar paradox: "This sentence is false." or "Is the answer to this question no?" Godel’s incomplete theorem: “This sentence can not be proved”. The sentence is true and can not be proved. No formal system is complete. Huge impact. 魏澤人 (國立東華大學應用數學學系) Paradox 2013-04-13 21 / 30
  • 38. Self Reference Paradoxes Berry paradox: "the first number not nameable in under ten words". computability and complexity implication. Curry’s paradox: "If this sentence is true, the world will end in a week." logic and philosophy interests. Grelling-Nelson paradox: "heterological" := "not applicable to itself". Yablo’s paradox. A self reference paradoxes without self reference. 魏澤人 (國立東華大學應用數學學系) Paradox 2013-04-13 22 / 30
  • 39. Self Reference Paradoxes Berry paradox: "the first number not nameable in under ten words". computability and complexity implication. Curry’s paradox: "If this sentence is true, the world will end in a week." logic and philosophy interests. Grelling-Nelson paradox: "heterological" := "not applicable to itself". Yablo’s paradox. A self reference paradoxes without self reference. 魏澤人 (國立東華大學應用數學學系) Paradox 2013-04-13 22 / 30
  • 40. Self Reference Paradoxes Berry paradox: "the first number not nameable in under ten words". computability and complexity implication. Curry’s paradox: "If this sentence is true, the world will end in a week." logic and philosophy interests. Grelling-Nelson paradox: "heterological" := "not applicable to itself". Yablo’s paradox. A self reference paradoxes without self reference. 魏澤人 (國立東華大學應用數學學系) Paradox 2013-04-13 22 / 30
  • 41. Self Reference Paradoxes Berry paradox: "the first number not nameable in under ten words". computability and complexity implication. Curry’s paradox: "If this sentence is true, the world will end in a week." logic and philosophy interests. Grelling-Nelson paradox: "heterological" := "not applicable to itself". Yablo’s paradox. A self reference paradoxes without self reference. 魏澤人 (國立東華大學應用數學學系) Paradox 2013-04-13 22 / 30
  • 42. More Self Reference Paradoxes Opposite Day: "It is opposite day today." Paradox of the Court: A law student agrees to pay his teacher after winning his first case. Quine’s paradox: "Yields a falsehood when appended to its own quotation" yields a falsehood when appended to its own quotation. Richard’s paradox: 魏澤人 (國立東華大學應用數學學系) Paradox 2013-04-13 23 / 30
  • 43. 聖彼得堡 擲硬幣,若第一次擲出正面,你就賺1元。若第一次擲出反面,那就要 再擲一次,若第二次擲的是正面,你便賺2元。若第二次擲出反面,那 就要擲第三次,若第三次擲的是正面,你便賺2*2元. . . . . . 如此類推,即 可能擲一次遊戲便結束,也可能反覆擲沒完沒了。問題是,你最多肯付 多少錢參加這個遊戲? 魏澤人 (國立東華大學應用數學學系) Paradox 2013-04-13 24 / 30
  • 44. Penney Ante HHH TTT HHT TTH HTH THT HTT THH 魏澤人 (國立東華大學應用數學學系) Paradox 2013-04-13 25 / 30
  • 45. Simpson’s Paradox Men Women Dept A 250/500, 50% accepted 9/10, 90% accepted Dept B 1/10, 10% accepted 100/500, 20% accepted Totals 251/510 accepted 109/510 accepted 魏澤人 (國立東華大學應用數學學系) Paradox 2013-04-13 26 / 30
  • 46. Simpson’s Paradox Treatment A Treatment B Both 78% (273/350) 83% (289/350) Small Stones 93% (81/87) 87% (234/270) Large Stones 73% (192/263) 69% (55/80) 魏澤人 (國立東華大學應用數學學系) Paradox 2013-04-13 27 / 30
  • 47. UC Berkeley 1973 Applicants % admitted Men 8442 44% Women 4321 35% 魏澤人 (國立東華大學應用數學學系) Paradox 2013-04-13 28 / 30
  • 48. UC Berkeley 1973 Major Men % Women % A 825 62% 108 82% B 560 63% 25 68% C 325 37% 593 34% D 417 33% 375 35% E 191 28% 393 24% F 272 6% 341 7% 魏澤人 (國立東華大學應用數學學系) Paradox 2013-04-13 29 / 30
  • 49. Related Paradox Low birth weight paradox Batting average 魏澤人 (國立東華大學應用數學學系) Paradox 2013-04-13 30 / 30