1. As the resistance increases the
voltage will decrease

2. V1 = I 1 R1

3. In example One, if R1 = 10 Ω , R2 = 20 Ω and I = 10A
VR1 = 10 A x 10 Ω = 100 V drop
VR2 = 10 A x 20 Ω = 200 V drop

5. V t = VR1 + V R2
= 100 + 200
= 300 V

7. Vt = V1 + V2 + V3

10. R=V/I
= 300 ÷ 10
= 30 Ω

11. So Vt = ( I R1 ) + ( I R2 ) + ( I R3 )
= (10 x 10) + (10 x 20) + ( 10 x 30)
= 100 + 200 + 300
= 600 V