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Stoichiometry
You already know... In a balanced equation the coefficients are MOLES.  2H 2  + O 2  -> 2H 2 O  2 moles Hydrogen, 1 mole Oxygen, 2 moles H 2 O How to Calculate Molar Mass: H 2 O = H 2 x 1.01 =  2.02  O 1 x 16.00 =  16.00 18.02 g/mol   1 mole of anything is 22.42 L examples: 1 mole water = 22.42 L 1 mole H 2 SO 4  = 22.42 L 1 mole acetic acid = 22.42 L
Before the Math ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
The Math ,[object Object],[object Object],[object Object],[object Object]
Finding Moles (this is going to be the first step in all the other types of problems) ,[object Object],[object Object],[object Object],[object Object],= .67 mol O 2 1.34 mol H 2 O 2  (from the problem) 1 mol O 2  (from equation) 2 mol H 2 O 2  (from equation)
Finding Liters ,[object Object],[object Object],[object Object],[object Object],=  4.8 L H 2 O 2 2.4 L O 2 1 mol O 2 2 mol H 2 O 2 22.42 L H 2 O 2 22.42 L O 2 1 mol O 2 1 mol H 2 O 2
Finding Grams ,[object Object],[object Object],[object Object],[object Object],[object Object],=  7.02 g H 2 O 2 3.7 g H 2 O 1 mol H 2 O 2 mol H 2 O 2 34.02 g H 2 O 2 18.02 g H 2 O 2 mol H 2 O 1 mol H 2 O 2
Grams to Liters? The mole allows for any calculation. ,[object Object],[object Object],[object Object],=  1.87 L H 2 O 2 1.5 g H 2 O 1 mol H 2 O 2 mol H 2 O 2 22.42 L H 2 O 2 18.02 g H 2 O 2 mol H 2 O 1 mol H 2 O 2

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Stoichiometry

  • 2. You already know... In a balanced equation the coefficients are MOLES. 2H 2 + O 2 -> 2H 2 O 2 moles Hydrogen, 1 mole Oxygen, 2 moles H 2 O How to Calculate Molar Mass: H 2 O = H 2 x 1.01 = 2.02 O 1 x 16.00 = 16.00 18.02 g/mol 1 mole of anything is 22.42 L examples: 1 mole water = 22.42 L 1 mole H 2 SO 4 = 22.42 L 1 mole acetic acid = 22.42 L
  • 3.
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  • 7.
  • 8.