Project in programming

Submitted by:
Ken M. Sahashi
BM10203

http://eglobiotraining.com/

#include <iostream> case 3: cout<< "Excellent!n";
#include <cstdio> break;
using namespace std; case 2: cout<< "Masterful!n";
int main() break;
{ case 1: cout<< "Incredible!n";
int number; break;
cout<< "Enter a number between 1 and 5: default: cout<< "Too large!n";
"; }
cin>> number; cout<< "nn";
switch (number) system ("pause");
{ return 0;
case 0: cout<< "Too small, sorry!"; }
break;
case 5: cout<< "Good job!n";
break;
case 4: cout<< "Nice Pick!n";
break;

 This programming accepts a number between 1
and 5 . If the user enters a right number the
programming will show an output according
to its number.


#include <iostream> cout<< " Enter the width : ";
#include <cstdio> cin>>wid;
using namespace std; area=len*wid;
int main() per=(2*len)+(2*wid);
{ switch (ch)
intch, len , wid , area , per ; {
balik: case 1 : cout<< " The Area is : " <<
system ("cls"); area <<endl;break;
cout<< " ***** Area - Perimeter case 2 : cout<< " The perimeter is : "
Program ******* <<per<<endl;break;
"<<endl<<"tt(Rectangle)"<<en default: gotobalik;
dl; }
cout<< "n [1] Area n [2] Perimeter
nnnnn " <<endl; system ("pause");
cout<< "Enter your choice here : " ; return 0;
cin>>ch; }
cout<< " Enter the length : ";
cin>>len;


This programming computes for the area or
perimeter of a given rectangle given that the
user will input its length and width. After the
programming accepts the values for
dimensions of the rectangle, the programming
lets the user choose if the programming will
compute for its perimeter or area. Then the
programming will compute for whatever the
user chose and then prints the computed value.
Lastly the programming will ask the user to
press any key to end the programming.


#include "iostream" ";
using namespace std; cin >> x;
int main ()
{ int rem , x; switch (x)
balik: {
system ("cls"); case 1: cout<< "Your birthstone is
cout << "[1] January "<<endl;; Garnet "<<endl;break;
cout << "[2] February "<<endl; case 2: cout<< "Your birthstone is
cout << "[3] March "<<endl; Amethyst "<<endl;break;
cout << "[4] April "<<endl; case 3: cout<< "Your birthstone is
cout << "[5] May "<<endl; Aquamarine "<<endl;break;
cout << "[6] June "<<endl; case 4: cout<< "Your birthstone is
cout << "[7] July "<<endl; Diamond "<<endl;break;
cout << "[8] August "<<endl; case 5: cout<< "Your birthstone is
cout << "[9] September "<<endl; Shamrock "<<endl;break;
cout << "[10] October "<<endl; case 6: cout<< "Your birthstone is
cout << "[11] November "<<endl; Alexandrite "<<endl;break;
cout << "[12] December case 7: cout<< "Your birthstone is
"<<endl<<endl; Ruby "<<
cout << "Enter the number of month :

 Amethyst "<<endl;break;
case 3: cout<< "Your birthstone is Aquamarine "<<endl;break;
case 4: cout<< "Your birthstone is Diamond "<<endl;break;
case 5: cout<< "Your birthstone is Shamrock "<<endl;break;
case 6: cout<< "Your birthstone is Alexandrite "<<endl;break;
case 7: cout<< "Your birthstone is Ruby "<<endl;break;
case 8: cout<< "Your birthstone is Peridot "<<endl;break;
case 9: cout<< "Your birthstone is Sapphire "<<endl;break;
case 10: cout<< "Your birthstone is Rose Zircon "<<endl;break;
case 11: cout<< "Your birthstone is Topaz "<<endl;break;
case 12: cout<< "Your birthstone is Blue Zircon "<<endl;break;
default:system ("cls"); cout<< "Invalid Input!!"<<endl;goto
balik;break;
}
system ("pause");
return 0;
}


This programming will
display the equivalent
birthstone of each month
using switch statement.


#include "iostream.h"
using namespace std;
int main ()
{
system ("cls");
for (int x = 1 ; x <= 10 ; x++ )
{
switch ( x )
{
case 1: cout<< " One "<<endl;break;
case 2: cout<< " two "<<endl;break;
case 3: cout<< " three"<<endl;break;
case 4: cout<< " four "<<endl;break;
case 5: cout<< " five "<<endl;break;
case 6: cout<< " six "<<endl;break;
case 7: cout<< " seven "<<endl;break;
case 8: cout<< " eight "<<endl;break;
case 9: cout<< " nine "<<endl;break;
default: cout<< " ten "<<endl;break;
}

system ("pause");
return 0;
}

 This programming allows the user to input a
number from 1 to 10. If the user input a right
number,the programming will run correctly
and it will display the equivalent of the
number in words.


int main ()
{ int rem , x;
system ("cls")
cout << "Enter an integer : ";
cin >> x;
rem=x%2;
switch (rem)
{
case 1: cout<< " Odd "<<endl;break;
default: cout<< " even "<<endl;break;
}

system ("pause");
return 0;
}


 This programming allows the user to enter a
integer number in which it will also display if it
is even or odd after executing the indicated
operation in the programming. We all know
that the number is even if it’s remainder is 0
and odd if it’s remainder is 1.


#include <iostream> fact+=1;
#include <conio.h> }
using namespace std; }
int main() if(fact>0)
{ cout<<"COMPOSITE!";
intnum, ctr=2, fact=0; else
system ("cls"); cout<<"PRIME!";
cout<<"Enter a number: "; }
cin>>num; cout<< "n";
{ system ("pause");
for (;ctr<num;ctr++) return 0;
{ }
if(num%ctr==0) http://eglobiotraining.com/

 This programming allows the user to input a
number. This number will be test if it’s a
PRIME or COMPOSITE.


int main ()
{
system ("cls");
for (int x = 1 ; x <= 10 ; x++ )
cout << x << "t" << x*x<< endl;
system ("pause");
return 0;
}

In this programming,the user is allowed to
enter a number from 1 to 10 and once he/she
enters the number the programming will
execute the operation in which it will displays
the square of the number inputted by the user.


int main ()
{
system ("cls");
for (int x = 1 ; x <= 10 ; x++ )
{for( y=1 ; <=10 ; y++)
{cout <<"#"<< endl;
}
cout << "t";
}
system ("pause");
return 0;
}


 This programming draw a ten by ten sharp
symbol box using the for loop.


Octal is : "
#include <iostream> <<oct<<dec<<endl<<end
using namespace std; l;
int main() cout<< "Do you wish to try
again [Y/N]? : ";
{ intdec;charch;
cin>>ch;
do
}while (toupper(ch)== 'Y');
{
system ("pause");
system ("cls");
return 0;
cout<< "Enter a decimal: ";
}
cin>>dec;
cout<< " THe number in


This programming converts the user’s input of decimal
number system into octal number system. The first step
in this programming is to ask the user to input an
integer of base 10(decimal). Next, the programming
will compute the value of the base 10 into base 8 or
octal number system. After the programming has
computed the value of base 10 integer to octal, now it
will output or print the answer of conversion of
decimal to octal. Then the programming will ask the
user if he/she wants to try again. The programming
accepts only Y for yes and N for a no. Lastly the
programming asks the user to press any key to end the
programming.


#include "iostream" }
#include "conio.h" cout<< "Trip Executed !!!
using namespace std; "<<endl<<endl;
int main () system ("pause");
{ return 0;
charch = 'a'; }
system ("cls");
while (ch !='q')
{
cin>>ch;


This programming accepts any character
such as alphanumeric and special
characters(symbols and the like). After
the input of the user, the programming
will now test the entered character. If the
programming reads the letter q or Q the
programming will end and outputs
“PROGRAM EXECUTED”.


This powerpoint is saved at
http://www.slideshare.net/

This project is submitted to:
Prof. Erwin Globio


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