The document provides instructions for finding the equation of a line given points on the line or the gradient. It explains that the equation is y = mx + c, where m is the gradient and c is the y-intercept. An example finds the equation of a line with gradient -2 passing through the point (-1, 3). A second example finds the equation of a line through the points (4, 9) and (6, -1).

1. Finding Equation of any Line 11.

2. Finding Equation of any Line 0 y x A (x , y) B (x 1 , y 1 ) Take the points A and B shown in the diagram. To find the gradient we have: NB y = mx + c is simply a variation on this with point (0 , c) substituted

3. Copy the following: To find the equation of any line if we know at least one point on that line we use: This is the most important formula in this outcome

6. Heinemann, p.11, Ex 1G, Q2, 3 & 4