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Communication System
Ass. Prof. Ibrar Ullah
BSc (Electrical Engineering)
UET Peshawar
MSc (Communication & Electronics Engineering)
UET Peshawar

PhD (In Progress) Electronics Engineering
(Specialization in Wireless Communication)
MAJU Islamabad

E-Mail: ibrar@cecos.edu.pk
Ph: 03339051548 (0830 to 1300 hrs)

1
Chapter-4 Amplitude Modulation
Ā 
1. Bandwidth and baseband
2. Amplitude modulation
3Ā QuadratureĀ amplitudeĀ modulation
4. SingleĀ sideĀ bandĀ Modulation
5. VestigialĀ sideĀ bandĀ Modulation

2
Baseband and carrier Communication
ā€¢
ā€¢
ā€¢

The bandwidth B represents a measure of frequency range.
It is typically measured in Hz with 1 Hz = 1/sec.
The bandwidth of a signal indicates the frequency range in which the
signalā€˜s Fourier transform has a power above a certain threshold
(typically half of the maximum power)

ā€¢ Often the frequency f = Ļ‰ / 2Ļ€ is used instead of the angular frequency
Ļ‰.
3
Baseband and carrier Communication
ā€¢ The term baseband designates a frequency range starting
at 0 Hz
ā€¢ Example of a baseband signal spectrum:

ā€¢ In baseband communication baseband signals are sent
without any shift in the range of frequencies
ā€¢ Any communication that uses modulation of a highfrequency carrier signal is called carrier communication
4
Amplitude Modulation (DSB)
ā€¢Amplitude modulation (AM)Ā variesĀ theĀ amplitudeĀ ofĀ aĀ carrierĀ 
signalĀ Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā accordingĀ toĀ aĀ modulatingĀ signalĀ m(t).
A cos( wct + Īø c )
ā€¢Ā TheĀ modulatedĀ signalĀ is m(t ) cos( wct )

5
Amplitude Modulation (DSB) contā€¦

Frequency-Shifting Property of Fourier transform:

6
Amplitude Modulation (DSB) contā€¦
ā€¢Ā ThisĀ typeĀ ofĀ modulationĀ shiftsĀ theĀ spectrumĀ ofĀ m(t)Ā toĀ theĀ carrierĀ 
frequency.
If

m(t ) ā‡” M ( w)
1
m(t ) cos wc t ā‡” [ M ( w + wc ) + M ( w āˆ’ wc )]
2

7
Amplitude Modulation (DSB) contā€¦
m(t ) cos wc t ā‡”

1
[ M (w + wc ) + M ( w āˆ’ wc )]
2

ā€¢ThisĀ modulationĀ shiftsĀ theĀ frequencyĀ spectrumĀ toĀ theĀ rightĀ andĀ theĀ 
leftĀ byĀ  wc
wc
ā€¢Ā TheĀ modulatedĀ signalĀ isĀ composedĀ ofĀ twoĀ parts,Ā aboveĀ Ā Ā Ā Ā andĀ 
belowĀ  wc
wc
ā€“Ā Ā theĀ upper sideband (USB)Ā containingĀ theĀ frequenciesĀ |w|Ā >Ā |Ā Ā Ā Ā Ā |
wc
ā€“Ā Ā theĀ lower sideband (LSB)Ā containingĀ theĀ frequenciesĀ Ā |w|Ā <Ā |Ā Ā Ā Ā Ā |
ā€¢TheĀ modulatedĀ signalĀ inĀ thisĀ schemeĀ doesĀ notĀ haveĀ aĀ discreteĀ 
wc
componentĀ ofĀ theĀ carrierĀ frequencyĀ Ā Ā Ā Ā Ā forĀ thisĀ reasonĀ thisĀ isĀ calledĀ 
double-sidebandĀ suppressedĀ carrierĀ (DSB-SC)Ā modulationĀ Ā 

8
Amplitude Modulation (DSB) contā€¦
BĀ Ā Ā VsĀ  wc

ā€¢IfĀ theĀ bandwidthĀ ofĀ theĀ originalĀ signalĀ m(t)Ā isĀ 2Ā Ā Ā B,Ā thenĀ theĀ 
Ļ€
Ļ€
bandwidthĀ ofĀ theĀ modulatedĀ signalĀ willĀ beĀ 4Ā Ā B,Ā consistingĀ of
wc
ā€“Ā Ā theĀ upper sideband (USB)Ā containingĀ theĀ frequenciesĀ |w|Ā >Ā |Ā Ā Ā Ā Ā |
wc
ā€“Ā Ā theĀ lower sideband (LSB)Ā containingĀ theĀ frequenciesĀ Ā |w|Ā <Ā |Ā Ā Ā Ā Ā |

ToĀ avoidĀ overlapĀ ofĀ theĀ twoĀ spectralĀ parts,Ā wc >Ā 2Ļ€BĀ mustĀ beĀ fulfilled
(ifĀ Ļ‰cĀ Ā <Ā 2Ļ€BĀ ,Ā theĀ informationĀ ofĀ m(t)Ā willĀ beĀ partlyĀ lostĀ inĀ theĀ processĀ ofĀ 
modulation)Ā 

9
Amplitude Modulation (DSB) contā€¦

10
Amplitude Modulation (DSB) contā€¦

SpectrumĀ 

Spectrum of the DSB-SC signal m(t)cos10,000t
1
cos Ī± cos Ī² = cos(Ī± + Ī² ) + cos(Ī± āˆ’ Ī² )
2

11
Amplitude Modulation (DSB) contā€¦

SpectrumĀ 

Spectrum of the DSB-SC signal m(t)cos10,000t

12
Amplitude Modulation (DSB) contā€¦

SpectrumĀ 

Spectrum of the DSB-SC signal m(t)cos10,000t

13
Modulation / Demodulation
Modulation

Demodulation

14
Demodulation
ā€¢Ā Ā Ā TheĀ processĀ ofĀ receivingĀ theĀ originalĀ signalĀ fromĀ theĀ modulatedĀ 
signalĀ isĀ calledĀ demodulation.
ā€¢Ā Ā Ā DemodulationĀ isĀ similarĀ toĀ modulationĀ andĀ canĀ beĀ performedĀ byĀ 
multiplying theĀ modulatedĀ signalĀ againĀ withĀ theĀ carrierĀ signal cos( w t )
c

The resulting signal

e(t ) = m(t ) cos w t = 1 [ m(t ) + m(t ) cos(2 w t )]
2
2

c

c

It has the Fourier transform

E ( w) = 1 M ( w) + 1 [ M ( w + 2 w ) + M ( w āˆ’ 2 w )]
2
4
c

c

15
Demodulation

16
Modulators
Multiplier modulators:
ā€¢ModulationĀ isĀ achievedĀ directlyĀ byĀ multiplyingĀ m(t)Ā byĀ Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā t
cos wc
usingĀ anĀ analogĀ multiplier.
ā€¢TheĀ outputĀ isĀ proportionalĀ toĀ theĀ productĀ ofĀ twoĀ inputĀ signals.
ā€¢DifficultĀ toĀ maintainĀ linearityĀ andĀ areĀ expansive.Ā 
Better to avoid
Better to avoid

17
Modulators (contā€¦)
Nonlinear modulators:
Modulation is achieved by using nonlinear devices such as
semiconductor diode or a transistor
NL: Two identical
NL: Two identical
nonlinear elements
nonlinear elements

Let output characteristics of NL be approximated by the power series as:

Where x(t) and y(t) are input & output

18
Modulators (contā€¦)

Changing inputs

Gives:
19
Modulators (contā€¦)

ā€¢Spectrum m(t) is centered at the origin, while of m(t)coswct is centered at
+-wc
ā€¢The signal is ready for transmission but we do not need the m(t) part of z(t)
ā€¢Z(t) is passed through a band-pass filter tuned to wc , the signal m(t) is
suppressed while 4bm(t)coswct passed unharmed.

20
Modulators (contā€¦)
Summary nonlinear modulator:
ā€¢Two inputs m(t) and coswct
ā€¢The summer output does not contain one of the input coswct
ā€¢Circuits which have this characteristic are called balanced circuits.
ā€¢The previous circuitry is an example of balanced modulators.
This circuit is balanced to only one input carrier, the other input m(t) still appear at the
This circuit is balanced to only one input carrier, the other input m(t) still appear at the
filter input, which must reject itā€¦ā€¦.for that reason ititis called aasingle balanced modulator
filter input, which must reject itā€¦ā€¦.for that reason is called single balanced modulator

21
Modulators (contā€¦)
Modulation through any periodic signal:
Modulated signal can not only be obtained by a pure sinusoid but by
any periodic signal.of fundamental frequency wc. E.g:

Trigonometric Fourier series
Trigonometric Fourier series

Spectrum of the modulated signal is the spectrum M(w) shifted to
If we pass this modulated signal through band-pass filter of
bandwidth 2B tuned to wc

22
Modulators (contā€¦)
Modulation through any periodic signal:
Modulated signal can not only be obtained by a pure sinusoid but by
any periodic signal.of fundamental frequency wc. E.g:

Trigonometric Fourier series
Trigonometric Fourier series

Spectrum of the modulated signal is the spectrum M(w) shifted to
If we pass this modulated signal through band-pass filter of
bandwidth 2B tuned to wc

23
Switching Modulators
Multiplication operation of modulation can be replaced by switching
operation. If we a periodic signal having Fourier series as:
carrier
Modulated signal
Now consider a periodic square pulse train with Fourier series as

1 2ļ£«
1
1
1
ļ£¶
w(t ) = + ļ£¬ cos w t āˆ’ cos 3w t + cos 5w t āˆ’ cos 7 w t + .... ļ£·
2 Ļ€ļ£­
3
5
7
ļ£ø
c

c

c

From example 2.8
From example 2.8

c

24
Switching Modulators
The modulated signal m(t)w(t) is given by

25
Switching Modulators
Modulated signal m(t)w(t) consists of the component m(t) plus infinite
numbers of modulated signals with carrier frequencies w ,3w ,5w ,.....
c

c

c

The spectrum of m(t)w(t) consists of M(w) and M(w) shifted to
Ā± w ,Ā±3w ,Ā±5w ,.....
c

c

c

As we are interested in modulated component m(t ) cos w t only. To
separate this component from others we pass m(t)w(t) through a
bandpass filter of bandwidth 2BHz, centered at Ā± w
c

c

gives the required modulated signal

2 m(t ) cos w t
Ļ€
c

Therefore the multiplication of a signal by a square pulse train is is
reality a switching operation means turning off and on signal m(t)
periodically and can be accomplished by switching element
26
controlled by w(t)
Switching Modulators
Diode bridge modulator:
Consider the following electronic switch circuit driven by A cos w t to produce
the switching action
c

D ,D
1

2

andD 3 , D 4

are matched pairs

When terminal c is positive with respect to d, all the diodes conduct, terminal
a & b are effectively shortened.
During the next half cycle d is positive with respect to c, all the diodes open,
terminal a & b are open.
27
Switching Modulators
Therefore the the circuit act as a desired electronic switch, where the terminal a
& b open and close periodically with the carrier frequency f c . When A cos wct
is applied across the terminal ab
To obtain m(t)w(t) we may place terminal ab in series or in parallel as:

Series-bridge diode modulator

Shunt-bridge diode modulator

Switching on and off m(t) for each cycle of the carrier, resulting in the
switched signal m(t)w(t) and passing through bandpass filter gives the
desired signal:
28
Switching Modulators
Ring modulator:
Consider the following circuit

During the positive half cycle of the carrier D1 & D3
conduct and D2 & D4 are open, hence terminal a is
connected to c & b to d
During the negative half cycle of the carrier D1 & D3 are
open and D2 & D4 conduct, hence terminal a is connected
to d & b to c
Output is proportional to m(t) during positive cycle &
-m(t) during negative cycle

29
Switching Modulators
The Fourier series of bipolar square wave is given by:
Example 2.8 p-52
Example 2.8 p-52

Gives modulated signal as:

Filtering this signal to bandpass filter tuned to wc gives the
required modulated signal:

In this circuit there are two inputs m(t) and coswcct,the input of the final
In this circuit there are two inputs m(t) and cosw t, the input of the final
bandpass filter does not contain either of the inputsā€¦ā€¦
bandpass filter does not contain either of the inputsā€¦ā€¦
this circuit is an example of double balanced modulator
this circuit is an example of double balanced modulator

30
Problem 4.2-4

31
Problem 4.2-4

32
Problem 4.2-4

At point b

At point c
33
Problem 4.2-4
The minimum value of wc is

to avoid overlapping

Will not work

34
Problem 4.2-4

This may be verified that the identity for
contains
a term
when n is odd. This is not true when n is
even. Hence, the system works for a carrier
only
when n is odd.

35
Example 4.2
Frequency mixer or converter:
Frequency mixer or converter is used to change the carrier frequency of the
modulated signal m(t)coswct to some other frequency wl
Can be achieved by multiplying m(t)coswct by
where

or

36
Example 4.2
In both cases the filter tuned to Wl will pass the term m(t)coswlt and suppress
the other term and giving the required output

m(t)coswct

(the carrier frequency is translated to wl from wc)

Frequency mixing or frequency conversion is also known as heterodyning.
All the modulators discussed previously can be used for frequency mixing.
Frequency selected as
Frequency selected as

operation called up-conversion
operation called down-conversion
37
Amplitude Modulation (AM)
For DSB-SC a receiver must generate a carrier in frequency and phase synchronism
with the carrier at the transmitter.
Problem:
Transmitter and receiver may be located thousands of miles away, this call for a
sophisticated receiver and could be costly.
Solution:
Transmit a carrier Acoswct along with the modulated signal m(t)coswct so no
need to generate a carrier at the receiver.

38
Amplitude Modulation (AM)
This type of modulation is called amplitude modulation and denoted by Ļ• (t )
and is given by:
AM

It has the Fourier spectrum

The spectrum of Ļ• (t ) is the same as m(t)coswct plus two additional impulses atĀ± wc
AM

ā€¢DSB-SC signal m(t)coswct and AM signal
A+m(t) as modulating signal instead of m(t)

are identical with

ā€¢To sketch Ļ• (t ) ,we sketch A+m(t) & -(A+m(t) ) and fill in between the carrier
frequency.
AM

39
Amplitude Modulation (AM)
As we sketch A+m(t) & -(A+m(t) ):
Consider two cases:

A + m(t ) ā‰„ 0 and

A + m(t ) ā‰¤ 0

40
Amplitude Modulation (AM)
For simple envelope detection for AM signal is:

A = 0, also satisfies the condition. In this case there is no need to add carrier,
because the envelope of DSB-SC signal m(t)coswct is m(t)
Such a DSB-SC signal can be detected by envelope detection

Assume

for all t

Let mp is the peak amplitude (positive or negative) of m(t)
Then
Hence the condition is equivalent to
Thus the minimum carrier amplitude required for the envelope detection is mp
41
Amplitude Modulation (AM)
We define the modulation index

Āµ

as:
A = carrier amplitude
mp = constant of m(t)

As A is the carrier amplitude and there is no
upper bound on A,

This is the condition for the viability of demodulation of Am signal by an
envelope detector
42
Example 4.4 p-164

ā‡’

43
Amplitude Modulation (AM)
Sideband and carrier power:
There is a disadvantage of envelope detection in terms of power waste, as the
carrier term does not contain any information

The carrier power Pc is given by
The sideband power Ps is given
by
Hence the power efficiency
is given by:

Ī·

44
Amplitude Modulation (AM)
For the special case of tone modulation:

m(t ) = ĀµA cos wmt

and

Hence
With condition
Thus under best condition only one third of the transmitted power is used for
carrying message, for practical signals the efficiency is even worst

45
Generation of AM signals
ā€¢ Am signals can be generated by any DSB-SC modulators.
ā€¢ The input should be A + m(t) instead of just m(t).
ā€¢ The modulating circuit do not have to be balanced because there is no need to
suppress the carrier

Switching action is provided by aasingle diode
Switching action is provided by single diode
and controlled by c cos wc t with
and controlled by
with

46
Generation of AM signals

The diode opens and short periodically with
The diode opens and short periodically with
multiplying the input signal by w(t).
multiplying the input signal by w(t).

infect
infect

The voltage across bb / is:

47
Demodulation of AM Signals
The AM signal can be demodulated coherently by a locally generated carrier. E.g.

[[ A + m(t )] cos wct ] cos wct

No benefit of sending carrier on the channel
No benefit of sending carrier on the channel

There are two well known methods of demodulation of AM signals:
1) Rectifier detection 2) Envelope detection

Rectifier detector:
AM signal is applied to a diode and resistor circuit, the negative part of the the
AM wave will be suppressed.
The output across the resistor is the half wave rectified version of the AM signal
means multiplying AM with w(t).
48
Rectifier Detector

The rectified output VR

{[

]}

vR = A + m(t ) cos w t w(t )
c
ļ£®1 2 ļ£«
1
1
ļ£¶ļ£¹
= [ A + m(t )] cos w t ļ£Æ + ļ£¬ cos w t āˆ’ cos 3w t + cos 5w t āˆ’ ...ļ£·ļ£ŗ
c ļ£°2 Ļ€ ļ£­
c 3
c 5
c
ļ£øļ£»

=

1
[ A + m(t )] + otherTerms
Ļ€

49
Rectifier Detector (contā€¦)

50
Envelope Detector
In an envelope detector, the output follows the envelope of the modulated signal.
The following circuit act as an envelope detector:

ā€¢ During the positive cycle of the input signal, the diode conducts and the
capacitor C charges up to the peak voltage of the input signal.
ā€¢When input signal falls below this peak value, the diode is cut off. (because the
diode voltage which is nearly the peak voltage is greater than the input signal
voltage causing the diode to open ).
ā€¢At this stage the capacitor discharge at the slew rate (with a time constant RC)
ā€¢ during the next positive cycle the process repeats.

51
Envelope Detector (contā€¦)

During each positive cycle the capacitor charges up to the peak voltage of the
input signal and then decays slowly until the next positive cycle.
This behavior of the capacitor makes output voltage Vc(t) follow the envelope of
the input signal.
Capacitor discharges during each positive peaks causes a ripple signal of
frequency wc at the output

52
Envelope Detector (contā€¦)
The ripple can be reduced by increasing the time constant RC so the capacitor
discharges very little between positive peaks of the input signals
Making RC too large, makes capacitor voltage impossible to follow the envelope.

Conditions:
RC should be large compared to 1/wc, but should be small compared to 1 2Ļ€B
Where B is the highest frequency in m(t)

Also requires

a condition which is necessary for well defined envelope.

53
Envelope Detector (contā€¦)
The envelope detector output is

with a ripple of frequency w c

The DC term A can be blocked by a capacitor or a simple RC high pass filter, and
the ripple may be reduced further by another low-pass RC filter.

54
Quadrature Amplitude Modulation
The DSB signals of AM require twice the bandwidth required for the baseband
signal!
Idea: Try to send two signals m1(t) and m2(t) simultaneously by modulating them
with two carrier signals of same frequency but shifted in phase by ā€“Ļ€/2
The combined signal is

m1 (t ) + m2 (t ) = m1 (t ) cos wc t + m2 (t ) sin wc t

55
Quadrature Amplitude Modulation (contā€¦)
Both modulated signals occupy the same band
ā€¢ At the receiver the two baseband signals can be separated by using a second
carrier that is shifted in phase by ā€“Ļ€/2
ā€¢ The first signal m1(t) can be detected by a multiplication with 2cos(Ļ‰ct) followed
by a low-pass filter

The second signal x2(t) can be detected accordingly by a multiplication with
sin(Ļ‰ct) followed by a low-pass filter
56
Quadrature Amplitude Modulation
(contā€¦)
ā€¢ Thus, two baseband signals, each of bandwidth B, can be simultaneously
transmitted over a channel with bandwidth 2B
ā€¢ This principle is called quadrature amplitude modulation (QAM), because
the carrier frequencies are in phase quadrature.

57
Amplitude Modulation (Single Sideband SSB)
ā€¢ The DSB spectrum has two sidebands: USB and LSB
ā€¢ Both USB and LSB contain complete information of the baseband
signal.
ā€¢ A scheme in which only one sideband is transmitted is known as
single-sideband ( SSB) transmission.
ā€¢ In SSB transmission the required bandwidth is half compared to DSB
signal.
ā€¢ An SSB signal can be coherently (synchronously) demodulated. E.g.
For example multiplying USB signal by cos wc t shifts its spectrum to
the left and right by wc
58
Single Sideband SSB (cont..)

Low pass filtering will give the required baseband signal at the
receiver.
59
Single Sideband SSB (cont..)
Time domain representation of SSB signals:

Ļ• SSB (t ) = m(t ) cos wct Ā± mh (t ) sin wc t
mh (t ) Hilbert Transform of m(t)
Hilbert Transform of m(t)

Ļ€
and delays the phase of each component by 2
and delays the phase of each component by

Where minus sign applies to USB and the plus sign applies to LSB

60
Example 4.7 p-174
Tone Modulation:
Find Ļ• SSB (t ) for a simple case of tone modulation, that is, when the
modulating signal is a sinusoid m(t ) = cos wmt
Solution:

Ļ• SSB (t ) = m(t ) cos wc t Ā± mh (t ) sin wc t

61
Example 4.7 p-174
Hence

62
Example 4.7 p-174

63
Generation of SSB Signals
Two methods are generally used to generate SSB signals.
1) Sharp cutoff filters
2) Phase shifting networks
Selective Filtering Method:
ā€¢ In this method the DSB-SC signal is passed through a sharp cutoff
filter to eliminate the undesired sideband.
ā€¢ To obtain USB , the filter should pass all components above wc,
attenuated and completely suppress all components below wc
ā€¢ Such an operation requires an ideal filter that is practically not
possible.
64
Generation of SSB Signals
ā€¢ This method of generating SSB signal can be used when there is
some separation between the passband and stopband.
ā€¢ In some application this can be achieved e.g. voice signals
Voice signals spectrum shows little power content at the
origin. Thus filtering the unwanted sideband is relatively
easy.

Tests have shown that frequency components
Tests have shown that frequency components
below 300Hz are not important.
below 300Hz are not important.

600Hz transition region around the cutoff
600Hz transition region around the cutoff
frequency w cc, ,makes filtering easy and
frequency w makes filtering easy and
minimize the channel interference
minimize the channel interference
65
Generation of SSB Signals(contā€¦)
Phase-Shift Method:
The basis of this method is the following equation

Ļ• SSB (t ) = m(t ) cos wc t Ā± mh (t ) sin wc t

66
Generation of SSB Signals(contā€¦)

67

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communication system Chapter 4

  • 1. Communication System Ass. Prof. Ibrar Ullah BSc (Electrical Engineering) UET Peshawar MSc (Communication & Electronics Engineering) UET Peshawar PhD (In Progress) Electronics Engineering (Specialization in Wireless Communication) MAJU Islamabad E-Mail: ibrar@cecos.edu.pk Ph: 03339051548 (0830 to 1300 hrs) 1
  • 2. Chapter-4 Amplitude Modulation Ā  1. Bandwidth and baseband 2. Amplitude modulation 3Ā QuadratureĀ amplitudeĀ modulation 4. SingleĀ sideĀ bandĀ Modulation 5. VestigialĀ sideĀ bandĀ Modulation 2
  • 3. Baseband and carrier Communication ā€¢ ā€¢ ā€¢ The bandwidth B represents a measure of frequency range. It is typically measured in Hz with 1 Hz = 1/sec. The bandwidth of a signal indicates the frequency range in which the signalā€˜s Fourier transform has a power above a certain threshold (typically half of the maximum power) ā€¢ Often the frequency f = Ļ‰ / 2Ļ€ is used instead of the angular frequency Ļ‰. 3
  • 4. Baseband and carrier Communication ā€¢ The term baseband designates a frequency range starting at 0 Hz ā€¢ Example of a baseband signal spectrum: ā€¢ In baseband communication baseband signals are sent without any shift in the range of frequencies ā€¢ Any communication that uses modulation of a highfrequency carrier signal is called carrier communication 4
  • 5. Amplitude Modulation (DSB) ā€¢Amplitude modulation (AM)Ā variesĀ theĀ amplitudeĀ ofĀ aĀ carrierĀ  signalĀ Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā accordingĀ toĀ aĀ modulatingĀ signalĀ m(t). A cos( wct + Īø c ) ā€¢Ā TheĀ modulatedĀ signalĀ is m(t ) cos( wct ) 5
  • 6. Amplitude Modulation (DSB) contā€¦ Frequency-Shifting Property of Fourier transform: 6
  • 7. Amplitude Modulation (DSB) contā€¦ ā€¢Ā ThisĀ typeĀ ofĀ modulationĀ shiftsĀ theĀ spectrumĀ ofĀ m(t)Ā toĀ theĀ carrierĀ  frequency. If m(t ) ā‡” M ( w) 1 m(t ) cos wc t ā‡” [ M ( w + wc ) + M ( w āˆ’ wc )] 2 7
  • 8. Amplitude Modulation (DSB) contā€¦ m(t ) cos wc t ā‡” 1 [ M (w + wc ) + M ( w āˆ’ wc )] 2 ā€¢ThisĀ modulationĀ shiftsĀ theĀ frequencyĀ spectrumĀ toĀ theĀ rightĀ andĀ theĀ  leftĀ byĀ  wc wc ā€¢Ā TheĀ modulatedĀ signalĀ isĀ composedĀ ofĀ twoĀ parts,Ā aboveĀ Ā Ā Ā Ā andĀ  belowĀ  wc wc ā€“Ā Ā theĀ upper sideband (USB)Ā containingĀ theĀ frequenciesĀ |w|Ā >Ā |Ā Ā Ā Ā Ā | wc ā€“Ā Ā theĀ lower sideband (LSB)Ā containingĀ theĀ frequenciesĀ Ā |w|Ā <Ā |Ā Ā Ā Ā Ā | ā€¢TheĀ modulatedĀ signalĀ inĀ thisĀ schemeĀ doesĀ notĀ haveĀ aĀ discreteĀ  wc componentĀ ofĀ theĀ carrierĀ frequencyĀ Ā Ā Ā Ā Ā forĀ thisĀ reasonĀ thisĀ isĀ calledĀ  double-sidebandĀ suppressedĀ carrierĀ (DSB-SC)Ā modulationĀ Ā  8
  • 9. Amplitude Modulation (DSB) contā€¦ BĀ Ā Ā VsĀ  wc ā€¢IfĀ theĀ bandwidthĀ ofĀ theĀ originalĀ signalĀ m(t)Ā isĀ 2Ā Ā Ā B,Ā thenĀ theĀ  Ļ€ Ļ€ bandwidthĀ ofĀ theĀ modulatedĀ signalĀ willĀ beĀ 4Ā Ā B,Ā consistingĀ of wc ā€“Ā Ā theĀ upper sideband (USB)Ā containingĀ theĀ frequenciesĀ |w|Ā >Ā |Ā Ā Ā Ā Ā | wc ā€“Ā Ā theĀ lower sideband (LSB)Ā containingĀ theĀ frequenciesĀ Ā |w|Ā <Ā |Ā Ā Ā Ā Ā | ToĀ avoidĀ overlapĀ ofĀ theĀ twoĀ spectralĀ parts,Ā wc >Ā 2Ļ€BĀ mustĀ beĀ fulfilled (ifĀ Ļ‰cĀ Ā <Ā 2Ļ€BĀ ,Ā theĀ informationĀ ofĀ m(t)Ā willĀ beĀ partlyĀ lostĀ inĀ theĀ processĀ ofĀ  modulation)Ā  9
  • 10. Amplitude Modulation (DSB) contā€¦ 10
  • 11. Amplitude Modulation (DSB) contā€¦ SpectrumĀ  Spectrum of the DSB-SC signal m(t)cos10,000t 1 cos Ī± cos Ī² = cos(Ī± + Ī² ) + cos(Ī± āˆ’ Ī² ) 2 11
  • 12. Amplitude Modulation (DSB) contā€¦ SpectrumĀ  Spectrum of the DSB-SC signal m(t)cos10,000t 12
  • 13. Amplitude Modulation (DSB) contā€¦ SpectrumĀ  Spectrum of the DSB-SC signal m(t)cos10,000t 13
  • 18. Modulators (contā€¦) Nonlinear modulators: Modulation is achieved by using nonlinear devices such as semiconductor diode or a transistor NL: Two identical NL: Two identical nonlinear elements nonlinear elements Let output characteristics of NL be approximated by the power series as: Where x(t) and y(t) are input & output 18
  • 20. Modulators (contā€¦) ā€¢Spectrum m(t) is centered at the origin, while of m(t)coswct is centered at +-wc ā€¢The signal is ready for transmission but we do not need the m(t) part of z(t) ā€¢Z(t) is passed through a band-pass filter tuned to wc , the signal m(t) is suppressed while 4bm(t)coswct passed unharmed. 20
  • 21. Modulators (contā€¦) Summary nonlinear modulator: ā€¢Two inputs m(t) and coswct ā€¢The summer output does not contain one of the input coswct ā€¢Circuits which have this characteristic are called balanced circuits. ā€¢The previous circuitry is an example of balanced modulators. This circuit is balanced to only one input carrier, the other input m(t) still appear at the This circuit is balanced to only one input carrier, the other input m(t) still appear at the filter input, which must reject itā€¦ā€¦.for that reason ititis called aasingle balanced modulator filter input, which must reject itā€¦ā€¦.for that reason is called single balanced modulator 21
  • 22. Modulators (contā€¦) Modulation through any periodic signal: Modulated signal can not only be obtained by a pure sinusoid but by any periodic signal.of fundamental frequency wc. E.g: Trigonometric Fourier series Trigonometric Fourier series Spectrum of the modulated signal is the spectrum M(w) shifted to If we pass this modulated signal through band-pass filter of bandwidth 2B tuned to wc 22
  • 23. Modulators (contā€¦) Modulation through any periodic signal: Modulated signal can not only be obtained by a pure sinusoid but by any periodic signal.of fundamental frequency wc. E.g: Trigonometric Fourier series Trigonometric Fourier series Spectrum of the modulated signal is the spectrum M(w) shifted to If we pass this modulated signal through band-pass filter of bandwidth 2B tuned to wc 23
  • 24. Switching Modulators Multiplication operation of modulation can be replaced by switching operation. If we a periodic signal having Fourier series as: carrier Modulated signal Now consider a periodic square pulse train with Fourier series as 1 2ļ£« 1 1 1 ļ£¶ w(t ) = + ļ£¬ cos w t āˆ’ cos 3w t + cos 5w t āˆ’ cos 7 w t + .... ļ£· 2 Ļ€ļ£­ 3 5 7 ļ£ø c c c From example 2.8 From example 2.8 c 24
  • 25. Switching Modulators The modulated signal m(t)w(t) is given by 25
  • 26. Switching Modulators Modulated signal m(t)w(t) consists of the component m(t) plus infinite numbers of modulated signals with carrier frequencies w ,3w ,5w ,..... c c c The spectrum of m(t)w(t) consists of M(w) and M(w) shifted to Ā± w ,Ā±3w ,Ā±5w ,..... c c c As we are interested in modulated component m(t ) cos w t only. To separate this component from others we pass m(t)w(t) through a bandpass filter of bandwidth 2BHz, centered at Ā± w c c gives the required modulated signal 2 m(t ) cos w t Ļ€ c Therefore the multiplication of a signal by a square pulse train is is reality a switching operation means turning off and on signal m(t) periodically and can be accomplished by switching element 26 controlled by w(t)
  • 27. Switching Modulators Diode bridge modulator: Consider the following electronic switch circuit driven by A cos w t to produce the switching action c D ,D 1 2 andD 3 , D 4 are matched pairs When terminal c is positive with respect to d, all the diodes conduct, terminal a & b are effectively shortened. During the next half cycle d is positive with respect to c, all the diodes open, terminal a & b are open. 27
  • 28. Switching Modulators Therefore the the circuit act as a desired electronic switch, where the terminal a & b open and close periodically with the carrier frequency f c . When A cos wct is applied across the terminal ab To obtain m(t)w(t) we may place terminal ab in series or in parallel as: Series-bridge diode modulator Shunt-bridge diode modulator Switching on and off m(t) for each cycle of the carrier, resulting in the switched signal m(t)w(t) and passing through bandpass filter gives the desired signal: 28
  • 29. Switching Modulators Ring modulator: Consider the following circuit During the positive half cycle of the carrier D1 & D3 conduct and D2 & D4 are open, hence terminal a is connected to c & b to d During the negative half cycle of the carrier D1 & D3 are open and D2 & D4 conduct, hence terminal a is connected to d & b to c Output is proportional to m(t) during positive cycle & -m(t) during negative cycle 29
  • 30. Switching Modulators The Fourier series of bipolar square wave is given by: Example 2.8 p-52 Example 2.8 p-52 Gives modulated signal as: Filtering this signal to bandpass filter tuned to wc gives the required modulated signal: In this circuit there are two inputs m(t) and coswcct,the input of the final In this circuit there are two inputs m(t) and cosw t, the input of the final bandpass filter does not contain either of the inputsā€¦ā€¦ bandpass filter does not contain either of the inputsā€¦ā€¦ this circuit is an example of double balanced modulator this circuit is an example of double balanced modulator 30
  • 33. Problem 4.2-4 At point b At point c 33
  • 34. Problem 4.2-4 The minimum value of wc is to avoid overlapping Will not work 34
  • 35. Problem 4.2-4 This may be verified that the identity for contains a term when n is odd. This is not true when n is even. Hence, the system works for a carrier only when n is odd. 35
  • 36. Example 4.2 Frequency mixer or converter: Frequency mixer or converter is used to change the carrier frequency of the modulated signal m(t)coswct to some other frequency wl Can be achieved by multiplying m(t)coswct by where or 36
  • 37. Example 4.2 In both cases the filter tuned to Wl will pass the term m(t)coswlt and suppress the other term and giving the required output m(t)coswct (the carrier frequency is translated to wl from wc) Frequency mixing or frequency conversion is also known as heterodyning. All the modulators discussed previously can be used for frequency mixing. Frequency selected as Frequency selected as operation called up-conversion operation called down-conversion 37
  • 38. Amplitude Modulation (AM) For DSB-SC a receiver must generate a carrier in frequency and phase synchronism with the carrier at the transmitter. Problem: Transmitter and receiver may be located thousands of miles away, this call for a sophisticated receiver and could be costly. Solution: Transmit a carrier Acoswct along with the modulated signal m(t)coswct so no need to generate a carrier at the receiver. 38
  • 39. Amplitude Modulation (AM) This type of modulation is called amplitude modulation and denoted by Ļ• (t ) and is given by: AM It has the Fourier spectrum The spectrum of Ļ• (t ) is the same as m(t)coswct plus two additional impulses atĀ± wc AM ā€¢DSB-SC signal m(t)coswct and AM signal A+m(t) as modulating signal instead of m(t) are identical with ā€¢To sketch Ļ• (t ) ,we sketch A+m(t) & -(A+m(t) ) and fill in between the carrier frequency. AM 39
  • 40. Amplitude Modulation (AM) As we sketch A+m(t) & -(A+m(t) ): Consider two cases: A + m(t ) ā‰„ 0 and A + m(t ) ā‰¤ 0 40
  • 41. Amplitude Modulation (AM) For simple envelope detection for AM signal is: A = 0, also satisfies the condition. In this case there is no need to add carrier, because the envelope of DSB-SC signal m(t)coswct is m(t) Such a DSB-SC signal can be detected by envelope detection Assume for all t Let mp is the peak amplitude (positive or negative) of m(t) Then Hence the condition is equivalent to Thus the minimum carrier amplitude required for the envelope detection is mp 41
  • 42. Amplitude Modulation (AM) We define the modulation index Āµ as: A = carrier amplitude mp = constant of m(t) As A is the carrier amplitude and there is no upper bound on A, This is the condition for the viability of demodulation of Am signal by an envelope detector 42
  • 44. Amplitude Modulation (AM) Sideband and carrier power: There is a disadvantage of envelope detection in terms of power waste, as the carrier term does not contain any information The carrier power Pc is given by The sideband power Ps is given by Hence the power efficiency is given by: Ī· 44
  • 45. Amplitude Modulation (AM) For the special case of tone modulation: m(t ) = ĀµA cos wmt and Hence With condition Thus under best condition only one third of the transmitted power is used for carrying message, for practical signals the efficiency is even worst 45
  • 46. Generation of AM signals ā€¢ Am signals can be generated by any DSB-SC modulators. ā€¢ The input should be A + m(t) instead of just m(t). ā€¢ The modulating circuit do not have to be balanced because there is no need to suppress the carrier Switching action is provided by aasingle diode Switching action is provided by single diode and controlled by c cos wc t with and controlled by with 46
  • 47. Generation of AM signals The diode opens and short periodically with The diode opens and short periodically with multiplying the input signal by w(t). multiplying the input signal by w(t). infect infect The voltage across bb / is: 47
  • 48. Demodulation of AM Signals The AM signal can be demodulated coherently by a locally generated carrier. E.g. [[ A + m(t )] cos wct ] cos wct No benefit of sending carrier on the channel No benefit of sending carrier on the channel There are two well known methods of demodulation of AM signals: 1) Rectifier detection 2) Envelope detection Rectifier detector: AM signal is applied to a diode and resistor circuit, the negative part of the the AM wave will be suppressed. The output across the resistor is the half wave rectified version of the AM signal means multiplying AM with w(t). 48
  • 49. Rectifier Detector The rectified output VR {[ ]} vR = A + m(t ) cos w t w(t ) c ļ£®1 2 ļ£« 1 1 ļ£¶ļ£¹ = [ A + m(t )] cos w t ļ£Æ + ļ£¬ cos w t āˆ’ cos 3w t + cos 5w t āˆ’ ...ļ£·ļ£ŗ c ļ£°2 Ļ€ ļ£­ c 3 c 5 c ļ£øļ£» = 1 [ A + m(t )] + otherTerms Ļ€ 49
  • 51. Envelope Detector In an envelope detector, the output follows the envelope of the modulated signal. The following circuit act as an envelope detector: ā€¢ During the positive cycle of the input signal, the diode conducts and the capacitor C charges up to the peak voltage of the input signal. ā€¢When input signal falls below this peak value, the diode is cut off. (because the diode voltage which is nearly the peak voltage is greater than the input signal voltage causing the diode to open ). ā€¢At this stage the capacitor discharge at the slew rate (with a time constant RC) ā€¢ during the next positive cycle the process repeats. 51
  • 52. Envelope Detector (contā€¦) During each positive cycle the capacitor charges up to the peak voltage of the input signal and then decays slowly until the next positive cycle. This behavior of the capacitor makes output voltage Vc(t) follow the envelope of the input signal. Capacitor discharges during each positive peaks causes a ripple signal of frequency wc at the output 52
  • 53. Envelope Detector (contā€¦) The ripple can be reduced by increasing the time constant RC so the capacitor discharges very little between positive peaks of the input signals Making RC too large, makes capacitor voltage impossible to follow the envelope. Conditions: RC should be large compared to 1/wc, but should be small compared to 1 2Ļ€B Where B is the highest frequency in m(t) Also requires a condition which is necessary for well defined envelope. 53
  • 54. Envelope Detector (contā€¦) The envelope detector output is with a ripple of frequency w c The DC term A can be blocked by a capacitor or a simple RC high pass filter, and the ripple may be reduced further by another low-pass RC filter. 54
  • 55. Quadrature Amplitude Modulation The DSB signals of AM require twice the bandwidth required for the baseband signal! Idea: Try to send two signals m1(t) and m2(t) simultaneously by modulating them with two carrier signals of same frequency but shifted in phase by ā€“Ļ€/2 The combined signal is m1 (t ) + m2 (t ) = m1 (t ) cos wc t + m2 (t ) sin wc t 55
  • 56. Quadrature Amplitude Modulation (contā€¦) Both modulated signals occupy the same band ā€¢ At the receiver the two baseband signals can be separated by using a second carrier that is shifted in phase by ā€“Ļ€/2 ā€¢ The first signal m1(t) can be detected by a multiplication with 2cos(Ļ‰ct) followed by a low-pass filter The second signal x2(t) can be detected accordingly by a multiplication with sin(Ļ‰ct) followed by a low-pass filter 56
  • 57. Quadrature Amplitude Modulation (contā€¦) ā€¢ Thus, two baseband signals, each of bandwidth B, can be simultaneously transmitted over a channel with bandwidth 2B ā€¢ This principle is called quadrature amplitude modulation (QAM), because the carrier frequencies are in phase quadrature. 57
  • 58. Amplitude Modulation (Single Sideband SSB) ā€¢ The DSB spectrum has two sidebands: USB and LSB ā€¢ Both USB and LSB contain complete information of the baseband signal. ā€¢ A scheme in which only one sideband is transmitted is known as single-sideband ( SSB) transmission. ā€¢ In SSB transmission the required bandwidth is half compared to DSB signal. ā€¢ An SSB signal can be coherently (synchronously) demodulated. E.g. For example multiplying USB signal by cos wc t shifts its spectrum to the left and right by wc 58
  • 59. Single Sideband SSB (cont..) Low pass filtering will give the required baseband signal at the receiver. 59
  • 60. Single Sideband SSB (cont..) Time domain representation of SSB signals: Ļ• SSB (t ) = m(t ) cos wct Ā± mh (t ) sin wc t mh (t ) Hilbert Transform of m(t) Hilbert Transform of m(t) Ļ€ and delays the phase of each component by 2 and delays the phase of each component by Where minus sign applies to USB and the plus sign applies to LSB 60
  • 61. Example 4.7 p-174 Tone Modulation: Find Ļ• SSB (t ) for a simple case of tone modulation, that is, when the modulating signal is a sinusoid m(t ) = cos wmt Solution: Ļ• SSB (t ) = m(t ) cos wc t Ā± mh (t ) sin wc t 61
  • 64. Generation of SSB Signals Two methods are generally used to generate SSB signals. 1) Sharp cutoff filters 2) Phase shifting networks Selective Filtering Method: ā€¢ In this method the DSB-SC signal is passed through a sharp cutoff filter to eliminate the undesired sideband. ā€¢ To obtain USB , the filter should pass all components above wc, attenuated and completely suppress all components below wc ā€¢ Such an operation requires an ideal filter that is practically not possible. 64
  • 65. Generation of SSB Signals ā€¢ This method of generating SSB signal can be used when there is some separation between the passband and stopband. ā€¢ In some application this can be achieved e.g. voice signals Voice signals spectrum shows little power content at the origin. Thus filtering the unwanted sideband is relatively easy. Tests have shown that frequency components Tests have shown that frequency components below 300Hz are not important. below 300Hz are not important. 600Hz transition region around the cutoff 600Hz transition region around the cutoff frequency w cc, ,makes filtering easy and frequency w makes filtering easy and minimize the channel interference minimize the channel interference 65
  • 66. Generation of SSB Signals(contā€¦) Phase-Shift Method: The basis of this method is the following equation Ļ• SSB (t ) = m(t ) cos wc t Ā± mh (t ) sin wc t 66
  • 67. Generation of SSB Signals(contā€¦) 67