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Section 10-6
                       Secants, Tangents, and Angle Measures




Monday, May 21, 2012
Essential Questions

                       How do you find measures of angles
                       formed by lines intersecting on or inside
                       a circle?


                       How do you find measure of angles
                       formed by lines intersecting outside the
                       circle?

Monday, May 21, 2012
Vocabulary & Theorems

     1. Secant:


     Theorem 10.12 - Two Secants:




Monday, May 21, 2012
Vocabulary & Theorems

     1. Secant: A line that intersects a circle in exactly
        two points

     Theorem 10.12 - Two Secants:




Monday, May 21, 2012
Vocabulary & Theorems

     1. Secant: A line that intersects a circle in exactly
        two points

     Theorem 10.12 - Two Secants: If two secants or
      chords intersect in the interior of a circle, then
      the measure of an angle formed is half of the
      sum of the measure of the arcs intercepted by
      the angle and its vertical angle

Monday, May 21, 2012
Vocabulary & Theorems


      Theorem 10.13 - Secant and Tangent:




Monday, May 21, 2012
Vocabulary & Theorems


      Theorem 10.13 - Secant and Tangent: If a
       secant and a tangent intersect at the point of
       tangency, then the measure of each angle
       formed is half of the measure of its intercepted
       arc



Monday, May 21, 2012
Vocabulary & Theorems


      Theorem 10.14 - Exterior Intersection:




Monday, May 21, 2012
Vocabulary & Theorems


      Theorem 10.14 - Exterior Intersection: If two
       secants, a secant and a tangent, or two
       tangents intersect in the exterior of a circle,
       then the measure of the angle formed is half
       the difference of the measures of the
       intercepted arcs


Monday, May 21, 2012
Example 1
                         Find x.
           a.




Monday, May 21, 2012
Example 1
                         Find x.
           a.
                        m∠FDE = 180 − m∠EDH




Monday, May 21, 2012
Example 1
                           Find x.
           a.
                          m∠FDE = 180 − m∠EDH
                               76 + 88
                       m∠EDH =
                                  2




Monday, May 21, 2012
Example 1
                           Find x.
           a.
                          m∠FDE = 180 − m∠EDH
                               76 + 88 164
                       m∠EDH =        =
                                  2     2




Monday, May 21, 2012
Example 1
                           Find x.
           a.
                          m∠FDE = 180 − m∠EDH
                               76 + 88 164
                       m∠EDH =        =    = 82°
                                  2     2




Monday, May 21, 2012
Example 1
                           Find x.
           a.
                          m∠FDE = 180 − m∠EDH
                               76 + 88 164
                       m∠EDH =        =    = 82°
                                  2     2

                          m∠FDE = 180 − 82


Monday, May 21, 2012
Example 1
                           Find x.
           a.
                          m∠FDE = 180 − m∠EDH
                               76 + 88 164
                       m∠EDH =        =    = 82°
                                  2     2

                          m∠FDE = 180 − 82 = 98°


Monday, May 21, 2012
Example 1
                           Find x.
           a.
                          m∠FDE = 180 − m∠EDH
                               76 + 88 164
                       m∠EDH =        =    = 82°
                                  2     2

                          m∠FDE = 180 − 82 = 98°

                                     x = 98
Monday, May 21, 2012
Example 1
                         Find x.
           b.




Monday, May 21, 2012
Example 1
                         Find x.
           b.
                           x = 180 − m∠VZW




Monday, May 21, 2012
Example 1
                         Find x.
           b.
                           x = 180 − m∠VZW
                                  96 + 62
                          m∠VZW =
                                     2




Monday, May 21, 2012
Example 1
                         Find x.
           b.
                           x = 180 − m∠VZW
                                  96 + 62
                          m∠VZW =
                                     2
                              158
                            =
                               2



Monday, May 21, 2012
Example 1
                         Find x.
           b.
                           x = 180 − m∠VZW
                                   96 + 62
                          m∠VZW =
                                      2
                              158
                            =     = 79°
                               2



Monday, May 21, 2012
Example 1
                         Find x.
           b.
                           x = 180 − m∠VZW
                                   96 + 62
                          m∠VZW =
                                      2
                              158
                            =     = 79°
                               2

                           x = 180 − 79
Monday, May 21, 2012
Example 1
                         Find x.
           b.
                           x = 180 − m∠VZW
                                   96 + 62
                          m∠VZW =
                                      2
                              158
                            =     = 79°
                               2

                           x = 180 − 79 = 101
Monday, May 21, 2012
Example 1
                         Find x.
           c.




Monday, May 21, 2012
Example 1
                         Find x.
           c.
                                   x + 25
                              60 =
                                      2




Monday, May 21, 2012
Example 1
                         Find x.
           c.
                                   x + 25
                              60 =
                                      2
                              120 = x + 25




Monday, May 21, 2012
Example 1
                         Find x.
           c.
                                   x + 25
                              60 =
                                      2
                              120 = x + 25
                                   x = 95



Monday, May 21, 2012
Example 2
                       Find each measure.
                           = 250°
           a. m∠QPS when mPTS




Monday, May 21, 2012
Example 2
                       Find each measure.
                           = 250°
           a. m∠QPS when mPTS

                                     1 
                              m∠QPS = mPTS
                                     2




Monday, May 21, 2012
Example 2
                       Find each measure.
                           = 250°
           a. m∠QPS when mPTS

                                     1 
                              m∠QPS = mPTS
                                     2
                                1
                               = (250)
                                2

Monday, May 21, 2012
Example 2
                       Find each measure.
                           = 250°
           a. m∠QPS when mPTS

                                     1 
                              m∠QPS = mPTS
                                     2
                                1
                               = (250) = 125°
                                2

Monday, May 21, 2012
Example 2
                       Find each measure.
               
           b. mBD




Monday, May 21, 2012
Example 2
                       Find each measure.
               
           b. mBD

                              = 360 − 2m∠ADB
                            mBD




Monday, May 21, 2012
Example 2
                       Find each measure.
               
           b. mBD

                              = 360 − 2m∠ADB
                            mBD
                                 = 360 − 2(108)




Monday, May 21, 2012
Example 2
                       Find each measure.
               
           b. mBD

                              = 360 − 2m∠ADB
                            mBD
                                 = 360 − 2(108)
                                  = 360 − 216


Monday, May 21, 2012
Example 2
                       Find each measure.
               
           b. mBD

                              = 360 − 2m∠ADB
                            mBD
                                 = 360 − 2(108)
                                  = 360 − 216
                                     = 144°
Monday, May 21, 2012
Example 3
                       Find each measure.
                when m∠AED = 62°
           a. mBC




Monday, May 21, 2012
Example 3
                       Find each measure.
                when m∠AED = 62°
           a. mBC
                                     − mBC
                                   mABD  
                           m∠AED =
                                       2




Monday, May 21, 2012
Example 3
                       Find each measure.
                when m∠AED = 62°
           a. mBC
                                         − mBC
                                       mABD  
                           m∠AED =
                                           2
                               141 − x
                          62 =
                                 2


Monday, May 21, 2012
Example 3
                       Find each measure.
                when m∠AED = 62°
           a. mBC
                                         − mBC
                                       mABD      
                           m∠AED =
                                            2
                               141 − x
                          62 =          124 = 141 − x
                                 2


Monday, May 21, 2012
Example 3
                       Find each measure.
                when m∠AED = 62°
           a. mBC
                                         − mBC
                                       mABD      
                           m∠AED =
                                            2
                               141 − x
                          62 =          124 = 141 − x
                                 2
                         −17 = −x

Monday, May 21, 2012
Example 3
                       Find each measure.
                when m∠AED = 62°
           a. mBC
                                         − mBC
                                       mABD      
                           m∠AED =
                                            2
                               141 − x
                          62 =          124 = 141 − x
                                  2
                         −17 = −x
                           x = 17
Monday, May 21, 2012
Example 3
                       Find each measure.
                when m∠AED = 62°
           a. mBC
                                         − mBC
                                       mABD      
                           m∠AED =
                                            2
                               141 − x
                          62 =          124 = 141 − x
                                  2
                         −17 = −x          = 17°
                                         mBC
                           x = 17
Monday, May 21, 2012
Example 3
                       Find each measure.
                
           b. m XYZ




Monday, May 21, 2012
Example 3
                       Find each measure.
                
           b. m XYZ
                                    − m XZ
                                 m XYZ   
                           m∠W =
                                       2




Monday, May 21, 2012
Example 3
                       Find each measure.
                
           b. m XYZ
                                     − m XZ
                                  m XYZ   
                           m∠W =
                                        2
                                    − 140
                                 m XYZ
                            40 =
                                      2




Monday, May 21, 2012
Example 3
                       Find each measure.
                
           b. m XYZ
                                     − m XZ
                                  m XYZ   
                           m∠W =
                                        2
                                    − 140
                                 m XYZ
                            40 =
                                      2
                                    − 140
                            80 = m XYZ


Monday, May 21, 2012
Example 3
                       Find each measure.
                
           b. m XYZ
                                     − m XZ
                                  m XYZ   
                           m∠W =
                                        2
                                    − 140
                                 m XYZ
                            40 =
                                      2
                                    − 140
                            80 = m XYZ
                                  = 220°
                               m XYZ
Monday, May 21, 2012
Check Your Understanding



                               p. 731 #1-7




Monday, May 21, 2012
Problem Set




Monday, May 21, 2012
Problem Set



                       p. 732 #9-29 odd, 41, 47




             "I hate quotations. Tell me what you know."
                       – Ralph Waldo Emerson
Monday, May 21, 2012

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Secants, Tangents and Angle Measures

  • 1. Section 10-6 Secants, Tangents, and Angle Measures Monday, May 21, 2012
  • 2. Essential Questions How do you find measures of angles formed by lines intersecting on or inside a circle? How do you find measure of angles formed by lines intersecting outside the circle? Monday, May 21, 2012
  • 3. Vocabulary & Theorems 1. Secant: Theorem 10.12 - Two Secants: Monday, May 21, 2012
  • 4. Vocabulary & Theorems 1. Secant: A line that intersects a circle in exactly two points Theorem 10.12 - Two Secants: Monday, May 21, 2012
  • 5. Vocabulary & Theorems 1. Secant: A line that intersects a circle in exactly two points Theorem 10.12 - Two Secants: If two secants or chords intersect in the interior of a circle, then the measure of an angle formed is half of the sum of the measure of the arcs intercepted by the angle and its vertical angle Monday, May 21, 2012
  • 6. Vocabulary & Theorems Theorem 10.13 - Secant and Tangent: Monday, May 21, 2012
  • 7. Vocabulary & Theorems Theorem 10.13 - Secant and Tangent: If a secant and a tangent intersect at the point of tangency, then the measure of each angle formed is half of the measure of its intercepted arc Monday, May 21, 2012
  • 8. Vocabulary & Theorems Theorem 10.14 - Exterior Intersection: Monday, May 21, 2012
  • 9. Vocabulary & Theorems Theorem 10.14 - Exterior Intersection: If two secants, a secant and a tangent, or two tangents intersect in the exterior of a circle, then the measure of the angle formed is half the difference of the measures of the intercepted arcs Monday, May 21, 2012
  • 10. Example 1 Find x. a. Monday, May 21, 2012
  • 11. Example 1 Find x. a. m∠FDE = 180 − m∠EDH Monday, May 21, 2012
  • 12. Example 1 Find x. a. m∠FDE = 180 − m∠EDH 76 + 88 m∠EDH = 2 Monday, May 21, 2012
  • 13. Example 1 Find x. a. m∠FDE = 180 − m∠EDH 76 + 88 164 m∠EDH = = 2 2 Monday, May 21, 2012
  • 14. Example 1 Find x. a. m∠FDE = 180 − m∠EDH 76 + 88 164 m∠EDH = = = 82° 2 2 Monday, May 21, 2012
  • 15. Example 1 Find x. a. m∠FDE = 180 − m∠EDH 76 + 88 164 m∠EDH = = = 82° 2 2 m∠FDE = 180 − 82 Monday, May 21, 2012
  • 16. Example 1 Find x. a. m∠FDE = 180 − m∠EDH 76 + 88 164 m∠EDH = = = 82° 2 2 m∠FDE = 180 − 82 = 98° Monday, May 21, 2012
  • 17. Example 1 Find x. a. m∠FDE = 180 − m∠EDH 76 + 88 164 m∠EDH = = = 82° 2 2 m∠FDE = 180 − 82 = 98° x = 98 Monday, May 21, 2012
  • 18. Example 1 Find x. b. Monday, May 21, 2012
  • 19. Example 1 Find x. b. x = 180 − m∠VZW Monday, May 21, 2012
  • 20. Example 1 Find x. b. x = 180 − m∠VZW 96 + 62 m∠VZW = 2 Monday, May 21, 2012
  • 21. Example 1 Find x. b. x = 180 − m∠VZW 96 + 62 m∠VZW = 2 158 = 2 Monday, May 21, 2012
  • 22. Example 1 Find x. b. x = 180 − m∠VZW 96 + 62 m∠VZW = 2 158 = = 79° 2 Monday, May 21, 2012
  • 23. Example 1 Find x. b. x = 180 − m∠VZW 96 + 62 m∠VZW = 2 158 = = 79° 2 x = 180 − 79 Monday, May 21, 2012
  • 24. Example 1 Find x. b. x = 180 − m∠VZW 96 + 62 m∠VZW = 2 158 = = 79° 2 x = 180 − 79 = 101 Monday, May 21, 2012
  • 25. Example 1 Find x. c. Monday, May 21, 2012
  • 26. Example 1 Find x. c. x + 25 60 = 2 Monday, May 21, 2012
  • 27. Example 1 Find x. c. x + 25 60 = 2 120 = x + 25 Monday, May 21, 2012
  • 28. Example 1 Find x. c. x + 25 60 = 2 120 = x + 25 x = 95 Monday, May 21, 2012
  • 29. Example 2 Find each measure.  = 250° a. m∠QPS when mPTS Monday, May 21, 2012
  • 30. Example 2 Find each measure.  = 250° a. m∠QPS when mPTS 1  m∠QPS = mPTS 2 Monday, May 21, 2012
  • 31. Example 2 Find each measure.  = 250° a. m∠QPS when mPTS 1  m∠QPS = mPTS 2 1 = (250) 2 Monday, May 21, 2012
  • 32. Example 2 Find each measure.  = 250° a. m∠QPS when mPTS 1  m∠QPS = mPTS 2 1 = (250) = 125° 2 Monday, May 21, 2012
  • 33. Example 2 Find each measure.  b. mBD Monday, May 21, 2012
  • 34. Example 2 Find each measure.  b. mBD  = 360 − 2m∠ADB mBD Monday, May 21, 2012
  • 35. Example 2 Find each measure.  b. mBD  = 360 − 2m∠ADB mBD = 360 − 2(108) Monday, May 21, 2012
  • 36. Example 2 Find each measure.  b. mBD  = 360 − 2m∠ADB mBD = 360 − 2(108) = 360 − 216 Monday, May 21, 2012
  • 37. Example 2 Find each measure.  b. mBD  = 360 − 2m∠ADB mBD = 360 − 2(108) = 360 − 216 = 144° Monday, May 21, 2012
  • 38. Example 3 Find each measure.  when m∠AED = 62° a. mBC Monday, May 21, 2012
  • 39. Example 3 Find each measure.  when m∠AED = 62° a. mBC  − mBC mABD  m∠AED = 2 Monday, May 21, 2012
  • 40. Example 3 Find each measure.  when m∠AED = 62° a. mBC  − mBC mABD  m∠AED = 2 141 − x 62 = 2 Monday, May 21, 2012
  • 41. Example 3 Find each measure.  when m∠AED = 62° a. mBC  − mBC mABD  m∠AED = 2 141 − x 62 = 124 = 141 − x 2 Monday, May 21, 2012
  • 42. Example 3 Find each measure.  when m∠AED = 62° a. mBC  − mBC mABD  m∠AED = 2 141 − x 62 = 124 = 141 − x 2 −17 = −x Monday, May 21, 2012
  • 43. Example 3 Find each measure.  when m∠AED = 62° a. mBC  − mBC mABD  m∠AED = 2 141 − x 62 = 124 = 141 − x 2 −17 = −x x = 17 Monday, May 21, 2012
  • 44. Example 3 Find each measure.  when m∠AED = 62° a. mBC  − mBC mABD  m∠AED = 2 141 − x 62 = 124 = 141 − x 2 −17 = −x  = 17° mBC x = 17 Monday, May 21, 2012
  • 45. Example 3 Find each measure.  b. m XYZ Monday, May 21, 2012
  • 46. Example 3 Find each measure.  b. m XYZ  − m XZ m XYZ  m∠W = 2 Monday, May 21, 2012
  • 47. Example 3 Find each measure.  b. m XYZ  − m XZ m XYZ  m∠W = 2  − 140 m XYZ 40 = 2 Monday, May 21, 2012
  • 48. Example 3 Find each measure.  b. m XYZ  − m XZ m XYZ  m∠W = 2  − 140 m XYZ 40 = 2  − 140 80 = m XYZ Monday, May 21, 2012
  • 49. Example 3 Find each measure.  b. m XYZ  − m XZ m XYZ  m∠W = 2  − 140 m XYZ 40 = 2  − 140 80 = m XYZ  = 220° m XYZ Monday, May 21, 2012
  • 50. Check Your Understanding p. 731 #1-7 Monday, May 21, 2012
  • 52. Problem Set p. 732 #9-29 odd, 41, 47 "I hate quotations. Tell me what you know." – Ralph Waldo Emerson Monday, May 21, 2012