2. Intro To Population
Predictor
• To begin to predict a population you must first
get your numbers of previous years. In this
project I used the years 1850, 1900, 1950, 1960,
1980, 1990, 2000 and 2010. We used all of these
numbers to predict the year 2060
4. Work
Point One:
• First you pick two (110, 45,684,000)
points that best Point Two:
represent your (130, 53, 880,000)
growth.
• The you plug the
two points into the After plugging it in I got
Slope equation. the answer 409, 800
5. Work
• You then take your
first point and plug When plugging it into
Point Slope Formula the
it into Point Slope
answer I got was 606,000
Form.
• Your Slope answer
is M and your Point When plugging into
Slope answer is Y=Mx + B I got
your B.. Plug into Y=409,800x+606,000
Y=Mx+B
6. Finishing up your work
• Solve your 409,800(210)+606,000-
equation by
860,580,000+606,000=
placing you
861,186,000
number of years
in the place of X Y=861,186,000
Population Prediction of france in 2060 is
861,186,000
7. Intro
• Another way to predict your future
population is to plug it into a quadratic
equation.
8. Work
• Choose three points
Points:
from your chart on
(X1,Y1)=(0,36)
slide three. Round
(X2,Y2)=(50,41)
the to the nearest
(X3,Y3)=(100,42)
millionth.
• First plug in your
first point into the 36=ao2+bo+c
equation c=36
Y1+ax12+bx1+c
9. Work
• Then plug in C to 41=a(50)+b(50)+36
the equation and solve for A
plug in your next A=-0.008
set of points.
• Now that you have
42=a(100)2+b(100)+c
a and c use
B=-0.0292
elmination to find
your b
10. More Work
• After you have found all of your
points plug your numbers into
Y=Ax 2+Bx+C. The answer is what
you get after you plug in
everything and you plug in one of
your three points into X and Y.
11. Intro
• This next equation that we will solve
for will give us a log graph. You will
need two points.
13. Work
• The equation that
you will need for
this is Y=abx
• Then plug X and
41=ab50 and 42=ab100
Y into the
equation. You
should have two
equations so you
can plug in both
points.
14. Work
• After you have 41b50/=ab50/b50
your problem 41/b100=ab 100 /b100
divide b and your
exponent on both 41/b50=a and 42/b100=a
sides of each
equation
• Then place A in
the place of A 41/b50=42/b100
15. • Then Cross Answer=
Multiply 41b100 =42b 50
• Then divide by
b50 41b50=42
• Divide 41 on each 41b50/41=42/41
side b50=1.0243
• Get rid of the
exponent 50 b=1.0004803
16. Work
• Now plug in b
into the
equation and
solve 41=a(1.0004803)50
41/1.0242998=
• And then after a(1.0242998)/
plug in your 1.0242888
points to check a=40.02734
your math. You
got it right if it
is close to 41