1. ELECTRICAL SYSTEM
DESIGN 1
EE- 53
ELECTRICAL PLAN
SUBMITTED BY:
ANGELIE M. MOROSCALLO
MARK ANTHONY B. ENOY
SUBMITTED TO:
ENGR. URSINO TABILIRAN

2. 2
TABLE OF CONTENTS
PAGE
ILLUMINATION DESIGN………………………………………………………...………
3
FIRST FLOOR……………………………………………………………………….
3
SECOND FLOOR……………………………………………………………………
7
POWER LOAD……………………………………………………………………………..
10
CONVENIENCE OUTLET………………………………………………………….
10
SPECIAL OUTLETS………………………………………………………………...
11
LIGHTING LOAD………......................................................................................................
13
SUB-FEEDER……………………………………………………………………………….
14
MAIN FEEDER…………………………………………………………………………….
17

3. 3
ILLUMINATION DESIGN
FIRST FLOOR
A. GARAGE
AREA= 25.5 sq.m.
LUX= 150
COEFFICIENT OF UTILIZATION= 0.35
MAINTENANCE FACTOR= 0.7
1. Total lamp lumens
LAMP LUMENS=
2. Using TT-40W; 40W; 3150 LUMENS
No. of Lamps=
B. PORCH
AREA= 20.375 sq.m.
LUX= 150
COEFFICIENT OF UTILIZATION= 0.35
MAINTENANCE FACTOR= 0.6
1. Total lamp lumens
LAMP LUMENS=
2. Using TT-40W; 40W; 3150 LUMENS
No. of Lamps=
C. LIVING ROOM
AREA= 26.375 sq.m.
LUX= 150
COEFFICIENT OF UTILIZATION= 0.45
MAINTENANCE FACTOR= 0.8
1. Total lamp lumens
LAMP LUMENS=
2. Using TT-40W; 40W; 3150 LUMENS
No. of Lamps=

4. 4
D. DINING ROOM
AREA= 16.75 sq.m.
LUX= 150
COEFFICIENT OF UTILIZATION= 0.45
MAINTENANCE FACTOR= 0.8
1. Total lamp lumens
LAMP LUMENS=
2. Using TT-40W; 40W; 3150 LUMENS
No. of Lamps=
E. KITCHEN
AREA= 10.5 sq.m.
LUX= 300
COEFFICIENT OF UTILIZATION= 0.45
MAINTENANCE FACTOR= 0.8
1. Total lamp lumens
LAMP LUMENS=
2. Using TT-40W; 40W; 3150 LUMENS
No. of Lamps=
F.
BEDROOM 1
AREA= 14 sq.m.
LUX= 250
COEFFICIENT OF UTILIZATION= 0.35
MAINTENANCE FACTOR= 0.8
1. Total lamp lumens
LAMP LUMENS=
2. Using TT-40W; 40W; 3150 LUMENS
No. of Lamps=
G. BEDROOM 2
AREA= 14.5 sq.m.
LUX= 250

5. 5
COEFFICIENT OF UTILIZATION= 0.35
MAINTENANCE FACTOR= 0.8
1. Total lamp lumens
LAMP LUMENS=
2. Using TT-40W; 40W; 3150 LUMENS
No. of Lamps=
H. TOILET & BATH (T & B)
AREA= 5 sq.m.
LUX= 150
COEFFICIENT OF UTILIZATION= 0.25
MAINTENANCE FACTOR= 0.7
1. Total lamp lumens
LAMP LUMENS=
2. Using TT-36W; 36W; 2900 LUMENS
No. of Lamps=
I.
LAUNDRY AREA
AREA= 8 sq.m.
LUX= 150
COEFFICIENT OF UTILIZATION= 0.35
MAINTENANCE FACTOR= 0.7
1. Total lamp lumens
LAMP LUMENS=
2. Using TT-40W; 40W; 3150 LUMENS
No. of Lamps=
J.
LOFT/ HALLWAY
AREA= 5.4 sq.m.
LUX= 150
COEFFICIENT OF UTILIZATION= 0.35
MAINTENANCE FACTOR= 0.8

6. 6
1. Total lamp lumens
LAMP LUMENS=
2. Using TT-18W; 1150 LUMENS
No. of Lamps=
K. STORAGE ROOM
AREA= 2.6 sq.m.
LUX= 150
COEFFICIENT OF UTILIZATION= 0.25
MAINTENANCE FACTOR= 0.6
1. Total lamp lumens
LAMP LUMENS=
3. Using TT-40W; 40W; 3150 LUMENS
No. of Lamps=
SECOND FLOOR
A. LIVING ROOM
AREA= 24.9 sq.m.
LUX= 150
COEFFICIENT OF UTILIZATION= 0.45

7. 7
MAINTENANCE FACTOR= 0.8
1. Total lamp lumens
LAMP LUMENS=
2. Using TT-40W; 40W; 3150 LUMENS
No. of Lamps=
STAIRCASES
AREA= 3.6 sq.m.
LUX= 150
COEFFICIENT OF UTILIZATION= 0.35
MAINTENANCE FACTOR= 0.8
1. Total lamp lumens
LAMP LUMENS=
2. Using TT-40W; 40W; 3150 LUMENS
No. of Lamps=
B. LOFT
AREA= 5 sq.m.
LUX= 150
COEFFICIENT OF UTILIZATION= 0.35
MAINTENANCE FACTOR= 0.8
1. Total lamp lumens
LAMP LUMENS=
2. Using TT-40W; 40W; 3150 LUMENS
No. of Lamps=
C. MASTER’S BEDROOM
AREA= 25 sq.m.
LUX= 250
COEFFICIENT OF UTILIZATION= 0.35
MAINTENANCE FACTOR= 0.8
1. Total lamp lumens
LAMP LUMENS=

8. 8
2. Using TT-40W; 40W; 3150 LUMENS
No. of Lamps=
D. MASTER’S T&B AND COMMON T&B
AREA= 5 sq.m.
LUX= 150
COEFFICIENT OF UTILIZATION= 0.25
MAINTENANCE FACTOR= 0.7
1. Total lamp lumens
LAMP LUMENS=
2. Using TT-36W; 36W; 2900 LUMENS
No. of Lamps=
E. MASTER’S BALCONY
AREA= 6 sq.m.
LUX= 150
COEFFICIENT OF UTILIZATION= 0.35
MAINTENANCE FACTOR= 0.6
1. Total lamp lumens
LAMP LUMENS=
2. Using TT-40W; 3150 LUMENS
No. of Lamps=
F.
BEDROOM 3 & 4
AREA= 20 sq.m.
LUX= 250
COEFFICIENT OF UTILIZATION= 0.35
MAINTENANCE FACTOR= 0.8
1. Total lamp lumens
LAMP LUMENS=
2. Using TT-40W; 40W; 3150 LUMENS
No. of Lamps=

9. 9
G. LIBRARY & COMPUTER ROOM
AREA= 19.25 sq.m.
LUX= 300
COEFFICIENT OF UTILIZATION= 0.45
MAINTENANCE FACTOR= 0.8
1. Total lamp lumens
LAMP LUMENS=
2. Using TT-40W; 40W; 3150 LUMENS
No. of Lamps=
H. BALCONY
AREA= 16.25 sq.m.
LUX= 150
COEFFICIENT OF UTILIZATION= 0.35
MAINTENANCE FACTOR= 0.6
1. Total lamp lumens
LAMP LUMENS=
2. Using TT-40W; 40W; 3150 LUMENS
No. of Lamps=
POWER LOAD
CONVENIENCE OUTLET:
A. For circuit (1, 4 & 5) with 10 outlets
Maximum load for convenience outlet= 180W
1. Total load
2. Total expected current load

10. 10
3. Size of the branch circuit wire
Referring to Table 2-5
Use 2 pcs. of 3.5 mm2 TW copper wire
4. Size of conduit pipe
Referring to Table 2-9
Use 13 mm diameter conduit pipe
5. Size of the Overcurrent Protection Device
Referring to Table 4-1
Use 1 pc. 30 Ampere trip breaker
B. For circuit (2) with 6 outlets
1.
2.
3. Use 2 pcs. of 3.5 mm2 TW copper wire
4. Use 13 mm diameter conduit pipe
5. Use 1 pc. 30 Ampere trip breaker
C. For circuit (3) with 7 outlets
1.
2.
3. Use 2 pcs. of 3.5 mm2 TW copper wire
4. Use 13 mm diameter conduit pipe
5. Use 1 pc. 30 Amp trip breaker
SPECIAL PURPOSE OUTLET
D. For circuit (6) laundry circuit at 1500 W per circuit (PEC)
Total load x demand factor (df)
1. Total Expected Current Load

11. 11
2. Size of the Branch Circuit wire
Referring to Table 2-5
Use 2pcs. of 3.5 mm2 TW copper wire
3. Size of conduit pipe
Referring to Table 2-9
Use 13 mm diameter conduit pipe
4. Size of the Overcurrent Protection Device
Referring to Table 4-1
Use 1 pc. 30 Amperes trip breaker
SPECIAL PURPOSE OUTLET
E. For circuit (7 & 8) with 1 unit of air condition at 2.5 HP each
1. Total load
2.5
2. Total Expected current Load
“Branch circuit conductor supplying a motor shall have an ampacity not less than 125% of the
full load current”
3. Size of the branch circuit wire
Referring to Table 2-5
Use 2 pcs. of 5.5 mm2 TW copper wire
4. Size of conduit pipe
Referring to Table 2-5
Use 20 mm diameter conduit pipe
5. Size of the Overcurrent Protection Device
8.11 x 2.5= 20.275 A
Referring to Table 4-1
Use 1pc. 60 Amperes trip breaker
F. For circuit (9, 10, 11 & 12) with 1 unit of air conditioner at 3 HP each
1. Total load
3 x 746= 2238 W
2.
“Branch circuit conductor supplying a motor shall have an ampacity not less than 125% of the
full load current”
3. Use 2 pcs. of 8.0 mm2 THW copper wire

12. 12
4. Use 30 mm diameter conduit pipe
5. 9.73 x 2.5= 24.33 A
Referring to Table 4-1
Use 1pc. 70 Amperes trip breaker
SPECIAL PURPOSE OUTLET
G. For circuit (13) cooking unit at 5,100 W
Total load x Demand Factor (df); 5,100 x 0.8= 4,080 W
1. Total Expected Current Load
2. Size of the branch circuit wire
Referring to Table 2-5
Use 2 pcs. of 5.5 mm2
3. Size of conduit pipe
Referring to Table 2-9
Use 20 mm diameter conduit pipe
4. Size of the Overcurrent Protection Device
Referring to Table 4-1
Use 1 pc. 30 Amperes trip
LIGHTING LOAD
H. For circuit (14, 19 & 20) with 11 lighting outlets
Maximum Load for lighting outlet= 100 W
1. Total load
11 x 100= 1100 W
2. Total Expected Current Load
3. Size of the branch circuit wire

13. 13
Referring to Table 2-5
Use 2 pcs. of 2.0 mm2 TW copper wire
4. Size of conduit pipe
Referring to Table 5-7
Use 13 mm diameter conduit pipe
5. Size of the Overcurrent Protection Device
Referring to Table 5-2
Use 1 pc. 15 Amperes trip breaker
I.
For circuit (15, 16 & 20) with 8 lighting outlets
1. 8 x 100= 800 W
2.
3. Use 2 pcs. of 2.0 mm2 TW copper wire
4. Use 13 mm diameter conduit pipe
5. Use 1 pc. 15 amperes trip breaker
J.
For circuit (17) with 9 lighting outlets
1. 9 x 100= 900W
2.
3. Use 2 pcs. of 2.0 mm2 TW copper wire
4. Use 13 mm diameter conduit pipe
5. Use 1 pc. 15 amperes trip breaker
K. For circuit (18) with 10 lighting outlets
1. 10 x 100= 1000 W
2.
3. Use 2 pcs. of 2.0 mm2 TW copper wire
4. Use 13 mm diameter conduit pipe
5. Use 1 pc. 15 amperes trip breaker
SUB-FEEDER
For circuits 1 to 21:
1. Total connected load
For circuits 1, 4 & 5------------------------------------------------------------------------10800 W
For circuits 2---------------------------------------------------------------------------------3240 W
For circuits 3---------------------------------------------------------------------------------2520 W
For circuits 6---------------------------------------------------------------------------------1500 W
For circuits 13--------------------------------------------------------------------------------5100 W
For circuits 14, 19 & 21---------------------------------------------------------------------3300 W

14. 14
For circuits 15, 16 & 20---------------------------------------------------------------------2400 W
For circuits 17--------------------------------------------------------------------------------900 W
For circuits 18--------------------------------------------------------------------------------1000 W
TOTAL (excluding the Aircon Unit)-----------------------30.760 W
From Table 4-4, optional calculation for Dwelling Unit, apply Demand Factor (df)
For the first 10,000 Watts at 100% df--------------------------------------------------------10,000 Watts
For the remaining load apply 40% df
30,760- 10,000= 20, 760 Watts at 40% (df)----------------------------------------- 8304 Watts
For circuit 7 to 8: Aircon units at 100% Demand Factor (df)
2- units at 1865 Watts-------------------------------------------------------------------3730 Watts
For circuit 9 to 12: Aircon units at 100% Demand Factor (df)
4- units at 2238 Watts-------------------------------------------------------------------8952 Watts
TOTAL=
30,986 Watt
2. Total Line Current
3. Size of sub-feeder wire
Referring to Table 4-2
Use 2 pcs. of 80 mm2 TW copper wire
4. Size of conduit pipe
Referring to Table 2-9
Use 32 mm diameter conduit pipe
5. Size of the Overcurrent Device
Referring to Table 4-1
Use 1pc. 175 amperes trip breaker
SPECIAL PURPOSE OUTLET
For circuit (22) with 1 unit of Motor Pump @ 3 HP
Total Load
3 x 746= 2238 Watts
Total expected Current Load
“ Branch circuit conductor supplying a motor shall have an ampacity not less than 125% of full
load current”

15. 15
9.73 x 125%= 12.16 A
1. Size of the branch circuit wire
Referring to Table 2.5
Use 2pcs. of 8.0 mm2 TW copper wire
2. Size of conduit pipe
Referring to Table 2-9
Use 30 mm diameter conduit pipe
3. Size of the Overcurrent Protection Device
9.73 x 2.5= 24.33 A
Referring to Table 4-1
Use 1 pc. 70 amperes trip breaker
MAIN FEEDER
Total current load of 2 dwelling units at 134.72 A----------------------------------------------269.44 A
Motor unit at 100% Demand Factor (df)
1-unit at 9.73 A-------------------------------------------------------------------------9.73 A
TOTAL-----------------------------------------------------------------------------279.17 A
At 125% of Full Load Current
279.17 x 1.25= 348.96 A

16. 16
1. Size of the branch circuit wire
Referring to Table 2-5
Use 2 pcs. of No. 600 AWG MCM
2. Size of Conduit Pipe
Referring to Table 2-9
Use 80 mm diameter conduit pipe
3. Size of the Overcurrent Protection Device
Referring to Table 4-1
Use 1 pc. 450 amperes trip breaker