1. Unit 3 - Homework 2
Solving 1-Step Equations

2. Solving Equations
Solving means to get the variable alone.
Think OPPOSITE SIDE = OPPOSITE
OPERATION

3. Solve for x.
x+3= 5

4. Solve for x.
Circle the term with the
x+3= 5 variable you need to isolate.

5. Solve for x.
Circle the term with the
x+3= 5 variable you need to isolate.

6. Solve for x.
Circle the term with the
x+3= 5 variable you need to isolate.
Anything outside the circle
needs to move to the other
side by doing the opposite
operation.

7. Solve for x.
Circle the term with the
x+3= 5 variable you need to isolate.
Anything outside the circle
needs to move to the other
side by doing the opposite
operation.
Opposite of addition is
Subtraction.

8. Solve for x.
Circle the term with the
x+3= 5 variable you need to isolate.
−3 −3 Anything outside the circle
needs to move to the other
side by doing the opposite
operation.
Opposite of addition is
Subtraction.

9. Solve for x.
Circle the term with the
x+3= 5 variable you need to isolate.
−3 −3 Anything outside the circle
needs to move to the other
side by doing the opposite
x=2 operation.
Opposite of addition is
Subtraction.

10. Solve for x.
Circle the term with the
x+3= 5 variable you need to isolate.
−3 −3 Anything outside the circle
needs to move to the other
side by doing the opposite
x=2 operation.
Opposite of addition is
Subtraction.
x is alone so you are done.

11. Solve for x.
x − 8 = −2

12. Solve for x.
Circle the term with the
x − 8 = −2 variable you need to
isolate.

13. Solve for x.
Circle the term with the
x − 8 = −2 variable you need to
isolate.

14. Solve for x.
Circle the term with the
x − 8 = −2 variable you need to
isolate.
Move 8 by opposite
operation.

15. Solve for x.
Circle the term with the
x − 8 = −2 variable you need to
isolate.
Move 8 by opposite
operation.
Opposite of subtraction is
addition.

16. Solve for x.
Circle the term with the
x − 8 = −2 variable you need to
+8 +8 isolate.
Move 8 by opposite
operation.
Opposite of subtraction is
addition.

17. Solve for x.
Circle the term with the
x − 8 = −2 variable you need to
+8 +8 isolate.
Move 8 by opposite
x=6 operation.
Opposite of subtraction is
addition.

18. Solve for x.
Circle the term with the
x − 8 = −2 variable you need to
+8 +8 isolate.
Move 8 by opposite
x=6 operation.
Opposite of subtraction is
addition.
x is alone so you are done.

19. Solve for x.
−3x = −8

20. Solve for x.
Circle the term with the
−3x = −8 variable you need to isolate.

21. Solve for x.
Circle the term with the
−3x = −8 variable you need to isolate.

22. Solve for x.
Circle the term with the
−3x = −8 variable you need to isolate.
There is nothing outside
the circle so look inside
now.

23. Solve for x.
Circle the term with the
−3x = −8 variable you need to isolate.
There is nothing outside
the circle so look inside
now.
Opposite of multiplication is
division.

24. Solve for x.
Circle the term with the
−3x = −8 variable you need to isolate.
− 3 −3 There is nothing outside
the circle so look inside
now.
Opposite of multiplication is
division.

25. Solve for x.
Circle the term with the
−3x = −8 variable you need to isolate.
− 3 −3 There is nothing outside
the circle so look inside
8 now.
x= Opposite of multiplication is
3 division.

26. Solve for x.
Circle the term with the
−3x = −8 variable you need to isolate.
− 3 −3 There is nothing outside
the circle so look inside
8 now.
x= Opposite of multiplication is
3 division.
x is alone so you are done.

27. Solve for x.
x
=7
5

28. Solve for x.
x Circle the term with the
=7 variable you need to
5 isolate.

29. Solve for x.
x Circle the term with the
=7 variable you need to
5 isolate.

30. Solve for x.
x Circle the term with the
=7 variable you need to
5 isolate.
There is nothing outside
the circle so look inside.

31. Solve for x.
x Circle the term with the
=7 variable you need to
5 isolate.
There is nothing outside
the circle so look inside.
Opposite of division is
multiplication.

32. Solve for x.
x Circle the term with the
5 ⋅ = 7⋅ 5 variable you need to
5 isolate.
There is nothing outside
the circle so look inside.
Opposite of division is
multiplication.

33. Solve for x.
x Circle the term with the
5 ⋅ = 7⋅ 5 variable you need to
5 isolate.
There is nothing outside
x = 35 the circle so look inside.
Opposite of division is
multiplication.

34. Solve for x.
x Circle the term with the
5 ⋅ = 7⋅ 5 variable you need to
5 isolate.
There is nothing outside
x = 35 the circle so look inside.
Opposite of division is
multiplication.
x is alone so you are done.

35. Solve for x.
7 − x = −1

36. Solve for x.
Circle the term with the
7 − x = −1 variable you need to isolate.

37. Solve for x.
Circle the term with the
7 − x = −1 variable you need to isolate.

38. Solve for x.
Circle the term with the
7 − x = −1 variable you need to isolate.
Anything outside the circle
needs to move to the other
side by doing the opposite
operation.

39. Solve for x.
Circle the term with the
7 − x = −1 variable you need to isolate.
Anything outside the circle
needs to move to the other
side by doing the opposite
operation.
The 7 is positive so Subtract.

40. Solve for x.
Circle the term with the
7 − x = −1 variable you need to isolate.
−7 −7 Anything outside the circle
needs to move to the other
side by doing the opposite
operation.
The 7 is positive so Subtract.

41. Solve for x.
Circle the term with the
7 − x = −1 variable you need to isolate.
−7 −7 Anything outside the circle
needs to move to the other
−x = −8 side by doing the opposite
operation.
The 7 is positive so Subtract.

42. Solve for x.
Circle the term with the
7 − x = −1 variable you need to isolate.
−7 −7 Anything outside the circle
needs to move to the other
−x = −8 side by doing the opposite
operation.
The 7 is positive so Subtract.
x is NOT alone. Divide by
negative one.

43. Solve for x.
Circle the term with the
7 − x = −1 variable you need to isolate.
−7 −7 Anything outside the circle
needs to move to the other
−x = −8 side by doing the opposite
operation.
−1 −1 The 7 is positive so Subtract.
x is NOT alone. Divide by
negative one.

44. Solve for x.
Circle the term with the
7 − x = −1 variable you need to isolate.
−7 −7 Anything outside the circle
needs to move to the other
−x = −8 side by doing the opposite
operation.
−1 −1 The 7 is positive so Subtract.
x is NOT alone. Divide by
x=8 negative one.

45. Solve for x.
Circle the term with the
7 − x = −1 variable you need to isolate.
−7 −7 Anything outside the circle
needs to move to the other
−x = −8 side by doing the opposite
operation.
−1 −1 The 7 is positive so Subtract.
x is NOT alone. Divide by
x=8 negative one.
x is alone so you are done.