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Joint mechanics

   Lennard Funk
Joint mechanics


Hundreds of articulations in the human
 body
Many injuries occur to these joint
 structures
No two joints are structurally identical
Joint Lubrication

Synovial fluid
  – Reduction of friction
  – Distribution of force
  – Nutrition for tissues
Injury implication: joint wear
Joint
Joint Lubrication
Synovial fluid produced by
  Synoviocytes
Arthritis => damaged synoviocytes
Articular Cartilage

Type II collagen
Different fibres
  orientation
   – Shear forces
   – tensile resistance
     to swelling
Creep
   – constant load
   – compression load
Cyclic loading
   – Benefits vs. damage
Articular Cartilage
              lubrication
Synovial joints
   – Low coefficients of friction .
     01-.04
                                        molecules
Theories of lubrication
   – Boundary
      • "lubricin" from synovial fluid
   – Fluid film
      • hydrodynamic (non
        deformable)                     Fluid
      • Squeeze Film
          – right angle movement
          – short duration
   – Mixed
Articular Cartilage:
            Adaptation
Active loading &
  unloading
Degenerative changes
  (OA)
Aging
   – ↓ water content
   – ↓ PG
   – ↓ collagen content
Joint Mobility and
Mobility sometimes has very distinct
 endpoints
  – Elbow or knee hyperextension
In other cases variable soft tissue
  properties and other factors limit ROM
Some see stability as the joint’s ability to
  resist dislocation.

                                      Stability
Joint Mobility and
Mobility sometimes has very distinct
 endpoints
  – Elbow or knee hyperextension
In other cases variable soft tissue
  properties and other factors limit ROM
Some see stability as the joint’s ability to
  resist dislocation.

                                        Stability
                              hi   p!
                       pt the
                   e
                Exc
Lever Systems

Most motion at the major joints results
 from the body’s structures acting as a
 system of levers
  – Multiple “classes” of lever systems
Functions:
  – Increase the effect of an applied force
    • Moment arms
  – Increase the effective velocity of
    movement
    • v=rω
Levers
Levers

• Levers are used to alter the resulting
  direction of the applied force
Levers

• Levers are used to alter the resulting
  direction of the applied force
• A lever is a rigid bar (bone) that turns
  about an axis of rotation or fulcrum (joint)
Levers

• Levers are used to alter the resulting
  direction of the applied force
• A lever is a rigid bar (bone) that turns
  about an axis of rotation or fulcrum (joint)
• The lever rotates about the axis as a result
  of a force (from muscle contraction)
Levers

• Levers are used to alter the resulting
  direction of the applied force
• A lever is a rigid bar (bone) that turns
  about an axis of rotation or fulcrum (joint)
• The lever rotates about the axis as a result
  of a force (from muscle contraction)
• The force acts against a resistance
  (weight, gravity, opponent, etc.)
Levers
Levers


The relationship of the points
 determines the type of lever
Levers


The relationship of the points
 determines the type of lever
The axis (joint), force (muscle
 insertion point), and the resistance
 (weight, etc.)
First Class

F                 R




             A


        F
 A
 R
First Class
First Class
     A


         R



 F
Neck extension
First Class
     A


         R



 F
Neck extension
First Class   Erector spinae
                and Splenius
     A


         R



 F
First Class
First Class




F




    A
         R
First Class

             Elbow extension




F




    A
         R
First Class

             Elbow extension
             Triceps


F




    A
         R
First Class




F                         R




    A                 A
First Class
Designed for speed and range of motion
 when the axis is closer to the force



F                         R




    A                 A
First Class
Designed for speed and range of motion
 when the axis is closer to the force
Designed for strength when the axis is
 closer to the resistance

F                         R




    A                 A
Second Class


       R           F




A


        A
 R
 F
Second Class
Second Class




R


         F

    A
Second Class

                 Plantar flexion




R


         F

    A
Second Class

                 Plantar flexion
                 Gastrocnemius
                   and Soleus



R


         F

    A
Second Class
Second Class

Designed more for force
Third Class

     F               R




A


         A
 F
   R
Third Class
Third Class


     F



 A
          R
Elbow flexion
Third Class


     F



 A
          R
Elbow flexion
Third Class   Biceps brachii and
                Brachialis


     F



 A
          R
Third Class
FUNCTIONAL   RELATIONSHIP     PRACTICAL         HUMAN
CLASS   ARRANGEMENT    ARM MOVEMENT       DESIGN        TO AXIS        EXAMPLE         EXAMPLE

1ST      F-A-R        Resistance arm   Balanced      Axis near      Seesaw           Erector
                      and force arm    movements     middle                          spinae neck
                      in opposite                                                    extension
                      direction
                                       Speed and     Axis near      Scissors         Triceps
                                       range of      force
                                       motion
                                       Force         Axis near      Crow bar
                                       (Strength)    resistance


2ND      A-R-F        Resistance arm   Force         Axis near      Wheel            Gatroc and
                      and force arm    (Strength)    resistance     barrow,          soleus
                      in same                                       nutcracker
                      direction


3RD      A-F-R        Resistance arm   Speed and     Axis near      Shoveling        Biceps
                      and force arm    range of      force          dirt, catapult   brachii
                      in same          motion
                      direction
Factors In Use of
Anatomical Levers




         F
Factors In Use of
       Anatomical Levers


A lever system
 can be balanced
 if the F and FA
 equal the R and
 RA                F
Factors In Use of
       Anatomical Levers


A lever system
 can be balanced
 if the F and FA
 equal the R and
 RA                F
Factors In Use of
               Anatomical Levers


A lever system
 can be balanced
 if the F and FA
 equal the R and
 RA                           F



(A = Arm - distance from A)
Balanced

    Force Arm       Resistance Arm



                                 R
F




                A
Balance with More

Force Arm       Resistance Arm



                                 R
F




            A
Balanced with Less

    Force Arm   Resistance Arm



                         R
F




                A
Factors In Use of
Anatomical Levers
Factors In Use of
          Anatomical Levers
A lever system can become unbalance when
  enough torque is produced
Factors In Use of
           Anatomical Levers
A lever system can become unbalance when
  enough torque is produced
Torque is the turning effect of a force; inside
  the body it caused rotation around a joint.
Factors In Use of
           Anatomical Levers
A lever system can become unbalance when
  enough torque is produced
Torque is the turning effect of a force; inside
  the body it caused rotation around a joint.
Torque = Force (from the muscle) x Force
  Arm (distance from muscle insertion from
  the joint)
Practical Application




                        Resistance
               Force
Practical Application

Force is produced by the
  muscle




                                    Resistance
                           Force
Practical Application

Force is produced by the
  muscle
FA the distance from




                                     Resistance
                             Force

  joint (i.e. axis or
  folcrum) to insertion of
  the force
Practical Application

Force is produced by the
  muscle
FA the distance from




                                     Resistance
                             Force

  joint (i.e. axis or
  folcrum) to insertion of
  the force
Resistance could be a
  weight, gravity, etc.
Practical Application

Force is produced by the
  muscle
FA the distance from




                                     Resistance
                             Force

  joint (i.e. axis or
  folcrum) to insertion of
  the force
Resistance could be a
  weight, gravity, etc.
RA the distance from
  joint to the center of
  the resistance
Examples




                   Resistance
           Force
Examples

1. How much torque needs
  to be produced to move
  45 kg when the RA is 0.25
  m and the FA is 0.1




                                      Resistance
                              Force

  meters?
Examples

1. How much torque needs
  to be produced to move
  45 kg when the RA is 0.25
  m and the FA is 0.1




                                      Resistance
                              Force

  meters?
Use the formula F x FA = R
  x RA
Examples

1. How much torque needs
  to be produced to move
  45 kg when the RA is 0.25
  m and the FA is 0.1




                                                 Resistance
                                         Force

  meters?
Use the formula F x FA = R
  x RA
Note: A Newton is the unit of force
  required to accelerate a mass of one
  kilogram one meter per second per
  second.
Example 1




               RA = 0.25
FA = 0.1
           ?




                           45




A
Example 1

F x 0.1 meters = 45 Kg x 0.25 meters




                       RA = 0.25
        FA = 0.1
                   ?




                                   45




      A
Example 1

F x 0.1 meters = 45 Kg x 0.25 meters
F x 0.1 kg = 11.25 Kg-meters


                       RA = 0.25
        FA = 0.1
                   ?




                                   45




      A
Example 1

F x 0.1 meters = 45 Kg x 0.25 meters
F x 0.1 kg = 11.25 Kg-meters
F = 112.5 Kg

                       RA = 0.25
        FA = 0.1
                   ?




                                   45




      A
Example 2: Increasing the
    FA




                RA = 0.25
FA = 0.15
            ?



                            45




A
Example 2: Increasing the
           FA
2. What if the FA was increased to 0.15 meters?




                           RA = 0.25
        FA = 0.15
                    ?



                                        45




       A
Example 2: Increasing the
           FA
2. What if the FA was increased to 0.15 meters?
F x 0.15 meters = 45 Kg x 0.25 meters




                           RA = 0.25
        FA = 0.15
                    ?



                                        45




       A
Example 2: Increasing the
           FA
2. What if the FA was increased to 0.15 meters?
F x 0.15 meters = 45 Kg x 0.25 meters
F x 0.15 = 11.25 Kg-meters


                           RA = 0.25
        FA = 0.15
                    ?



                                        45




       A
Example 2: Increasing the
           FA
2. What if the FA was increased to 0.15 meters?
F x 0.15 meters = 45 Kg x 0.25 meters
F x 0.15 = 11.25 Kg-meters
F = 75 Kg

                           RA = 0.25
        FA = 0.15
                    ?



                                        45




       A
Example 3: Decreasing the
    RA




               RA = 0.2
FA = 0.1
           ?




                          45




A
Example 3: Decreasing the
            RA
3. What if the RA was decreased to 0.2 meters?




                           RA = 0.2
         FA = 0.1
                    ?




                                      45




        A
Example 3: Decreasing the
            RA
3. What if the RA was decreased to 0.2 meters?
F x 0.1 meters = 45 Kg x 0.2 meters




                           RA = 0.2
         FA = 0.1
                    ?




                                      45




        A
Example 3: Decreasing the
            RA
3. What if the RA was decreased to 0.2 meters?
F x 0.1 meters = 45 Kg x 0.2 meters
F x 0.1 = 9 Kg-meters


                           RA = 0.2
         FA = 0.1
                    ?




                                      45




        A
Example 3: Decreasing the
            RA
3. What if the RA was decreased to 0.2 meters?
F x 0.1 meters = 45 Kg x 0.2 meters
F x 0.1 = 9 Kg-meters
F = 90 Kg

                           RA = 0.2
         FA = 0.1
                    ?




                                      45




        A
Summary
Summary


• The actual torque needed to move a
  given resistance depends on the
  length of the FA and RA
Summary


• The actual torque needed to move a
  given resistance depends on the
  length of the FA and RA
• As the FA increases or RA
  decreases, the required torque
  decreases.
Summary


• The actual torque needed to move a
  given resistance depends on the
  length of the FA and RA
• As the FA increases or RA
  decreases, the required torque
  decreases.
• As the FA decreases or RA
  increases, the required torque
Levers Continued
Levers Continued


Inside the body, several joints can be
  “added” together to increase
  leverage (e.g. shoulder, elbow, and
  wrist.
Levers Continued


Inside the body, several joints can be
  “added” together to increase
  leverage (e.g. shoulder, elbow, and
  wrist.
An increase in leverage can increase
  velocity
Lever Length


               Z’



      S’




           S        Z
Lever Length

Where is the velocity or speed the
 greatest; at S’ or Z’?         Z’



                  S’




                       S         Z
Lever Length

Where is the velocity or speed the
 greatest; at S’ or Z’?         Z’



                  S’




                       S         Z
Lever Length

Where is the velocity or speed the
 greatest; at S’ or Z’?         Z’



                  S’




                       S         Z
Lever Length

Where is the velocity or speed the
 greatest; at S’ or Z’?         Z’



                  S’




                       S         Z
Lever Length

Where is the velocity or speed the
 greatest; at S’ or Z’?         Z’



                  S’




                       S         Z
Lever Length

Where is the velocity or speed the
 greatest; at S’ or Z’?         Z’



                  S’




                       S         Z
Lever Length

Where is the velocity or speed the
 greatest; at S’ or Z’?         Z’



                  S’




                       S         Z

How can this principle be applied to
 tennis?
Lever
Length
Lever
        Length
A longer lever would
 increase speed at
 the end of the
 racquet unless the
 extra weight was
 too great. Then the
 speed may actually
 be slower.
Wheels and Axles


                   R = 3”




                      R = 1”
Wheels and Axles

Wheels and axles can
 enhance speed and
                            R = 3”
 range of motion




                               R = 1”
Wheels and Axles

Wheels and axles can
 enhance speed and
                             R = 3”
 range of motion
They function as a form of
 lever



                                R = 1”
Wheels and Axles

Wheels and axles can
 enhance speed and
                             R = 3”
 range of motion
They function as a form of
 lever
Mechanical advantage 
 = radius of wheel /
 radius of axle
                                R = 1”
Wheels and Axles




               H
Wheels and Axles

Consider the humerus as an
  axle and the forearm/hand
  as the wheel




                              H
Wheels and Axles

Consider the humerus as an
  axle and the forearm/hand
  as the wheel
The rotator cuff muscles
  inward rotate the humerus
  a small amount




                              H
Wheels and Axles

Consider the humerus as an
  axle and the forearm/hand
  as the wheel
The rotator cuff muscles
  inward rotate the humerus
  a small amount
The hand will travel a large
  amount




                               H
Wheels and Axles

Consider the humerus as an
  axle and the forearm/hand
  as the wheel
The rotator cuff muscles
  inward rotate the humerus
  a small amount
The hand will travel a large
  amount
A little effort to rotate the
  humerus, results in a
  significant amount of
  movement at the hand
                                H
Joints and
          moments
Note, as a joint moves through its
 ROM, two things change:
  – Instantaneous Center of Rotation
    • Rotation
    • Sliding
    • Rolling
  – Muscle Line of Action
These combine to change the moment
 arm
lenfunk@shoulderdoc.co.uk

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Joint biomechanics

  • 1. Joint mechanics Lennard Funk
  • 2. Joint mechanics Hundreds of articulations in the human body Many injuries occur to these joint structures No two joints are structurally identical
  • 3. Joint Lubrication Synovial fluid – Reduction of friction – Distribution of force – Nutrition for tissues Injury implication: joint wear
  • 5. Joint Lubrication Synovial fluid produced by Synoviocytes Arthritis => damaged synoviocytes
  • 6. Articular Cartilage Type II collagen Different fibres orientation – Shear forces – tensile resistance to swelling Creep – constant load – compression load Cyclic loading – Benefits vs. damage
  • 7. Articular Cartilage lubrication Synovial joints – Low coefficients of friction . 01-.04 molecules Theories of lubrication – Boundary • "lubricin" from synovial fluid – Fluid film • hydrodynamic (non deformable) Fluid • Squeeze Film – right angle movement – short duration – Mixed
  • 8. Articular Cartilage: Adaptation Active loading & unloading Degenerative changes (OA) Aging – ↓ water content – ↓ PG – ↓ collagen content
  • 9. Joint Mobility and Mobility sometimes has very distinct endpoints – Elbow or knee hyperextension In other cases variable soft tissue properties and other factors limit ROM Some see stability as the joint’s ability to resist dislocation. Stability
  • 10. Joint Mobility and Mobility sometimes has very distinct endpoints – Elbow or knee hyperextension In other cases variable soft tissue properties and other factors limit ROM Some see stability as the joint’s ability to resist dislocation. Stability hi p! pt the e Exc
  • 11. Lever Systems Most motion at the major joints results from the body’s structures acting as a system of levers – Multiple “classes” of lever systems Functions: – Increase the effect of an applied force • Moment arms – Increase the effective velocity of movement • v=rω
  • 13. Levers • Levers are used to alter the resulting direction of the applied force
  • 14. Levers • Levers are used to alter the resulting direction of the applied force • A lever is a rigid bar (bone) that turns about an axis of rotation or fulcrum (joint)
  • 15. Levers • Levers are used to alter the resulting direction of the applied force • A lever is a rigid bar (bone) that turns about an axis of rotation or fulcrum (joint) • The lever rotates about the axis as a result of a force (from muscle contraction)
  • 16. Levers • Levers are used to alter the resulting direction of the applied force • A lever is a rigid bar (bone) that turns about an axis of rotation or fulcrum (joint) • The lever rotates about the axis as a result of a force (from muscle contraction) • The force acts against a resistance (weight, gravity, opponent, etc.)
  • 18. Levers The relationship of the points determines the type of lever
  • 19. Levers The relationship of the points determines the type of lever The axis (joint), force (muscle insertion point), and the resistance (weight, etc.)
  • 20. First Class F R A F A R
  • 22. First Class A R F
  • 24. Neck extension First Class Erector spinae and Splenius A R F
  • 27. First Class Elbow extension F A R
  • 28. First Class Elbow extension Triceps F A R
  • 29. First Class F R A A
  • 30. First Class Designed for speed and range of motion when the axis is closer to the force F R A A
  • 31. First Class Designed for speed and range of motion when the axis is closer to the force Designed for strength when the axis is closer to the resistance F R A A
  • 32. Second Class R F A A R F
  • 35. Second Class Plantar flexion R F A
  • 36. Second Class Plantar flexion Gastrocnemius and Soleus R F A
  • 39. Third Class F R A A F R
  • 41. Third Class F A R
  • 43. Elbow flexion Third Class Biceps brachii and Brachialis F A R
  • 45. FUNCTIONAL RELATIONSHIP PRACTICAL HUMAN CLASS ARRANGEMENT ARM MOVEMENT DESIGN TO AXIS EXAMPLE EXAMPLE 1ST F-A-R Resistance arm Balanced Axis near Seesaw Erector and force arm movements middle spinae neck in opposite extension direction Speed and Axis near Scissors Triceps range of force motion Force Axis near Crow bar (Strength) resistance 2ND A-R-F Resistance arm Force Axis near Wheel Gatroc and and force arm (Strength) resistance barrow, soleus in same nutcracker direction 3RD A-F-R Resistance arm Speed and Axis near Shoveling Biceps and force arm range of force dirt, catapult brachii in same motion direction
  • 46. Factors In Use of Anatomical Levers F
  • 47. Factors In Use of Anatomical Levers A lever system can be balanced if the F and FA equal the R and RA F
  • 48. Factors In Use of Anatomical Levers A lever system can be balanced if the F and FA equal the R and RA F
  • 49. Factors In Use of Anatomical Levers A lever system can be balanced if the F and FA equal the R and RA F (A = Arm - distance from A)
  • 50. Balanced Force Arm Resistance Arm R F A
  • 51. Balance with More Force Arm Resistance Arm R F A
  • 52. Balanced with Less Force Arm Resistance Arm R F A
  • 53. Factors In Use of Anatomical Levers
  • 54. Factors In Use of Anatomical Levers A lever system can become unbalance when enough torque is produced
  • 55. Factors In Use of Anatomical Levers A lever system can become unbalance when enough torque is produced Torque is the turning effect of a force; inside the body it caused rotation around a joint.
  • 56. Factors In Use of Anatomical Levers A lever system can become unbalance when enough torque is produced Torque is the turning effect of a force; inside the body it caused rotation around a joint. Torque = Force (from the muscle) x Force Arm (distance from muscle insertion from the joint)
  • 57. Practical Application Resistance Force
  • 58. Practical Application Force is produced by the muscle Resistance Force
  • 59. Practical Application Force is produced by the muscle FA the distance from Resistance Force joint (i.e. axis or folcrum) to insertion of the force
  • 60. Practical Application Force is produced by the muscle FA the distance from Resistance Force joint (i.e. axis or folcrum) to insertion of the force Resistance could be a weight, gravity, etc.
  • 61. Practical Application Force is produced by the muscle FA the distance from Resistance Force joint (i.e. axis or folcrum) to insertion of the force Resistance could be a weight, gravity, etc. RA the distance from joint to the center of the resistance
  • 62. Examples Resistance Force
  • 63. Examples 1. How much torque needs to be produced to move 45 kg when the RA is 0.25 m and the FA is 0.1 Resistance Force meters?
  • 64. Examples 1. How much torque needs to be produced to move 45 kg when the RA is 0.25 m and the FA is 0.1 Resistance Force meters? Use the formula F x FA = R x RA
  • 65. Examples 1. How much torque needs to be produced to move 45 kg when the RA is 0.25 m and the FA is 0.1 Resistance Force meters? Use the formula F x FA = R x RA Note: A Newton is the unit of force required to accelerate a mass of one kilogram one meter per second per second.
  • 66. Example 1 RA = 0.25 FA = 0.1 ? 45 A
  • 67. Example 1 F x 0.1 meters = 45 Kg x 0.25 meters RA = 0.25 FA = 0.1 ? 45 A
  • 68. Example 1 F x 0.1 meters = 45 Kg x 0.25 meters F x 0.1 kg = 11.25 Kg-meters RA = 0.25 FA = 0.1 ? 45 A
  • 69. Example 1 F x 0.1 meters = 45 Kg x 0.25 meters F x 0.1 kg = 11.25 Kg-meters F = 112.5 Kg RA = 0.25 FA = 0.1 ? 45 A
  • 70. Example 2: Increasing the FA RA = 0.25 FA = 0.15 ? 45 A
  • 71. Example 2: Increasing the FA 2. What if the FA was increased to 0.15 meters? RA = 0.25 FA = 0.15 ? 45 A
  • 72. Example 2: Increasing the FA 2. What if the FA was increased to 0.15 meters? F x 0.15 meters = 45 Kg x 0.25 meters RA = 0.25 FA = 0.15 ? 45 A
  • 73. Example 2: Increasing the FA 2. What if the FA was increased to 0.15 meters? F x 0.15 meters = 45 Kg x 0.25 meters F x 0.15 = 11.25 Kg-meters RA = 0.25 FA = 0.15 ? 45 A
  • 74. Example 2: Increasing the FA 2. What if the FA was increased to 0.15 meters? F x 0.15 meters = 45 Kg x 0.25 meters F x 0.15 = 11.25 Kg-meters F = 75 Kg RA = 0.25 FA = 0.15 ? 45 A
  • 75. Example 3: Decreasing the RA RA = 0.2 FA = 0.1 ? 45 A
  • 76. Example 3: Decreasing the RA 3. What if the RA was decreased to 0.2 meters? RA = 0.2 FA = 0.1 ? 45 A
  • 77. Example 3: Decreasing the RA 3. What if the RA was decreased to 0.2 meters? F x 0.1 meters = 45 Kg x 0.2 meters RA = 0.2 FA = 0.1 ? 45 A
  • 78. Example 3: Decreasing the RA 3. What if the RA was decreased to 0.2 meters? F x 0.1 meters = 45 Kg x 0.2 meters F x 0.1 = 9 Kg-meters RA = 0.2 FA = 0.1 ? 45 A
  • 79. Example 3: Decreasing the RA 3. What if the RA was decreased to 0.2 meters? F x 0.1 meters = 45 Kg x 0.2 meters F x 0.1 = 9 Kg-meters F = 90 Kg RA = 0.2 FA = 0.1 ? 45 A
  • 81. Summary • The actual torque needed to move a given resistance depends on the length of the FA and RA
  • 82. Summary • The actual torque needed to move a given resistance depends on the length of the FA and RA • As the FA increases or RA decreases, the required torque decreases.
  • 83. Summary • The actual torque needed to move a given resistance depends on the length of the FA and RA • As the FA increases or RA decreases, the required torque decreases. • As the FA decreases or RA increases, the required torque
  • 85. Levers Continued Inside the body, several joints can be “added” together to increase leverage (e.g. shoulder, elbow, and wrist.
  • 86. Levers Continued Inside the body, several joints can be “added” together to increase leverage (e.g. shoulder, elbow, and wrist. An increase in leverage can increase velocity
  • 87. Lever Length Z’ S’ S Z
  • 88. Lever Length Where is the velocity or speed the greatest; at S’ or Z’? Z’ S’ S Z
  • 89. Lever Length Where is the velocity or speed the greatest; at S’ or Z’? Z’ S’ S Z
  • 90. Lever Length Where is the velocity or speed the greatest; at S’ or Z’? Z’ S’ S Z
  • 91. Lever Length Where is the velocity or speed the greatest; at S’ or Z’? Z’ S’ S Z
  • 92. Lever Length Where is the velocity or speed the greatest; at S’ or Z’? Z’ S’ S Z
  • 93. Lever Length Where is the velocity or speed the greatest; at S’ or Z’? Z’ S’ S Z
  • 94. Lever Length Where is the velocity or speed the greatest; at S’ or Z’? Z’ S’ S Z How can this principle be applied to tennis?
  • 96. Lever Length A longer lever would increase speed at the end of the racquet unless the extra weight was too great. Then the speed may actually be slower.
  • 97. Wheels and Axles R = 3” R = 1”
  • 98. Wheels and Axles Wheels and axles can enhance speed and R = 3” range of motion R = 1”
  • 99. Wheels and Axles Wheels and axles can enhance speed and R = 3” range of motion They function as a form of lever R = 1”
  • 100. Wheels and Axles Wheels and axles can enhance speed and R = 3” range of motion They function as a form of lever Mechanical advantage = radius of wheel / radius of axle R = 1”
  • 102. Wheels and Axles Consider the humerus as an axle and the forearm/hand as the wheel H
  • 103. Wheels and Axles Consider the humerus as an axle and the forearm/hand as the wheel The rotator cuff muscles inward rotate the humerus a small amount H
  • 104. Wheels and Axles Consider the humerus as an axle and the forearm/hand as the wheel The rotator cuff muscles inward rotate the humerus a small amount The hand will travel a large amount H
  • 105. Wheels and Axles Consider the humerus as an axle and the forearm/hand as the wheel The rotator cuff muscles inward rotate the humerus a small amount The hand will travel a large amount A little effort to rotate the humerus, results in a significant amount of movement at the hand H
  • 106. Joints and moments Note, as a joint moves through its ROM, two things change: – Instantaneous Center of Rotation • Rotation • Sliding • Rolling – Muscle Line of Action These combine to change the moment arm

Hinweis der Redaktion

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  7. Synovial joint lubrication: in spite of the massive loads generated in them, synovial joints are efficient bearings with very low friction. The coefficient of friction of a synovial joint is around 0.02. This compares to 0.03 for ice sliding on ice. A coefficient of friction of 0.01 means that a load of 100 lb could be made to slide by applying a force of 1lb. Joint lubrication is the key to reduced friction. So, it is helpful to understand them in order to better understand and treat joint wear. It is still unclear how lubrication works, but there are many theories, based on man-made ball-bearings. What is clear is that no single mechanism is responsible and different modes of lubrication work at different stages of joint function. The joint is lined by wear resistant hyaline cartilage and is bathed by synovial fluid. Unlike a typical newtonian fluid synovial fluid has a viscosity that decreases with increasing shear rate. The function of a lubricant is to provide an intermediate layer with low shear resistance in between the two sliding surfaces to reduce friction. A thixotropic fluid would fit the bill perfectly.\nBasic lubrication is of two types: fluid-film, boundary and mixed.\nFluid film : a thin fluid film separates the bearing surfaces. Of two types: hydrodynamic and squeeze film. Hydrodynamic lubrication is unlikely to be feasible in vivo as the sliding velocity of joints are too low to generate a substantial fluid film. Squeeze film lubrication takes place by the production of a fluid film under pressure as the two bearing surfaces move perpendicularly towards each other. Fluid film and resultant load bearing capacity depends on fluid viscosity. It could explain lubrication under sudden loading but is not suitable for prolong loading conditions.\nBoundary: the bearing surfaces come to contact with each other, but "lubricin" from synovial fluid is attached to the cartilage surface and offers an interposed layer which when rubbed provides less resistance to shear.\nMixed: weeping lubrication: on load application synovial fluid is released or "wept" from articular cartilage. It separates the two bearing surfaces and reduces friction due to the hydrostatic pressure. On unloading the fluid is squeezed back in. This mechanism is not dependent on sliding speed .\n
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