The document is a lecture on derivatives of exponential and logarithmic functions. It begins with announcements about homework and an upcoming midterm. It then provides objectives and an outline for sections on exponential and logarithmic functions. The body of the document defines exponential functions, establishes conventions for exponents of all types, discusses properties of exponential functions, and graphs various exponential functions. It focuses on setting up the necessary foundations before discussing derivatives of these functions.
Transcript: New from BookNet Canada for 2024: Loan Stars - Tech Forum 2024
NYU Calculus Class Notes on Exponential and Logarithmic Functions
1. Sections 3.1–3.3
Derivatives of Exponential and
Logarithmic Functions
V63.0121.002.2010Su, Calculus I
New York University
June 1, 2010
Announcements
Today: Homework 2 due
Tomorrow: Section 3.4, review
Thursday: Midterm in class
. . . . . .
2. Announcements
Today: Homework 2 due
Tomorrow: Section 3.4,
review
Thursday: Midterm in class
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 2 / 54
3. Objectives for Sections 3.1 and 3.2
Know the definition of an
exponential function
Know the properties of
exponential functions
Understand and apply the
laws of logarithms,
including the change of
base formula.
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 3 / 54
4. Objectives for Section 3.3
Know the derivatives of the
exponential functions (with
any base)
Know the derivatives of the
logarithmic functions (with
any base)
Use the technique of
logarithmic differentiation
to find derivatives of
functions involving roducts,
quotients, and/or
exponentials.
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 4 / 54
5. Outline
Definition of exponential functions
Properties of exponential Functions
The number e and the natural exponential function
Compound Interest
The number e
A limit
Logarithmic Functions
Derivatives of Exponential Functions
Exponential Growth
Derivative of the natural logarithm function
Derivatives of other exponentials and logarithms
Other exponentials
Other logarithms
Logarithmic Differentiation
The power rule for irrational powers
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 5 / 54
6. Derivation of exponential functions
Definition
If a is a real number and n is a positive whole number, then
an = a · a · · · · · a
n factors
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 6 / 54
7. Derivation of exponential functions
Definition
If a is a real number and n is a positive whole number, then
an = a · a · · · · · a
n factors
Examples
23 = 2 · 2 · 2 = 8
34 = 3 · 3 · 3 · 3 = 81
(−1)5 = (−1)(−1)(−1)(−1)(−1) = −1
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 6 / 54
8. Fact
If a is a real number, then
ax+y = ax ay
ax
ax−y = y
a
(ax )y = axy
(ab)x = ax bx
whenever all exponents are positive whole numbers.
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 7 / 54
9. Fact
If a is a real number, then
ax+y = ax ay
ax
ax−y = y
a
(ax )y = axy
(ab)x = ax bx
whenever all exponents are positive whole numbers.
Proof.
Check for yourself:
ax+y = a · a · · · · · a = a · a · · · · · a · a · a · · · · · a = ax ay
x + y factors x factors y factors
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 7 / 54
10. Let's be conventional
The desire that these properties remain true gives us conventions
for ax when x is not a positive whole number.
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 8 / 54
11. Let's be conventional
The desire that these properties remain true gives us conventions
for ax when x is not a positive whole number.
For example:
!
an = an+0 = an a0
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 8 / 54
12. Let's be conventional
The desire that these properties remain true gives us conventions
for ax when x is not a positive whole number.
For example:
!
an = an+0 = an a0
Definition
If a ̸= 0, we define a0 = 1.
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 8 / 54
13. Let's be conventional
The desire that these properties remain true gives us conventions
for ax when x is not a positive whole number.
For example:
!
an = an+0 = an a0
Definition
If a ̸= 0, we define a0 = 1.
Notice 00 remains undefined (as a limit form, it’s indeterminate).
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 8 / 54
14. Conventions for negative exponents
If n ≥ 0, we want
an · a−n = an+(−n) = a0 = 1
!
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 9 / 54
15. Conventions for negative exponents
If n ≥ 0, we want
an · a−n = an+(−n) = a0 = 1
!
Definition
1
If n is a positive integer, we define a−n = .
an
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 9 / 54
16. Conventions for negative exponents
If n ≥ 0, we want
an · a−n = an+(−n) = a0 = 1
!
Definition
1
If n is a positive integer, we define a−n = .
an
Fact
1
The convention that a−n = “works” for negative n as well.
an
am
If m and n are any integers, then am−n = n .
a
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 9 / 54
17. Conventions for fractional exponents
If q is a positive integer, we want
!
(a1/q )q = a1 = a
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 10 / 54
18. Conventions for fractional exponents
If q is a positive integer, we want
!
(a1/q )q = a1 = a
Definition
√
If q is a positive integer, we define a1/q = q
a. We must have a ≥ 0 if q
is even.
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 10 / 54
19. Conventions for fractional exponents
If q is a positive integer, we want
!
(a1/q )q = a1 = a
Definition
√
If q is a positive integer, we define a1/q = q a. We must have a ≥ 0 if q
is even.
√q
( √ )p
Notice that ap = q a . So we can unambiguously say
ap/q = (ap )1/q = (a1/q )p
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 10 / 54
20. Conventions for irrational powers
So ax is well-defined if x is rational.
What about irrational powers?
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 11 / 54
21. Conventions for irrational powers
So ax is well-defined if x is rational.
What about irrational powers?
Definition
Let a > 0. Then
ax = lim ar
r→x
r rational
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 11 / 54
22. Conventions for irrational powers
So ax is well-defined if x is rational.
What about irrational powers?
Definition
Let a > 0. Then
ax = lim ar
r→x
r rational
In other words, to approximate ax for irrational x, take r close to x but
rational and compute ar .
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 11 / 54
24. Graphs of various exponential functions
y
.
. = 1x
y
. x
.
. . . . . .
25. Graphs of various exponential functions
y
.
. = 2x
y
. = 1x
y
. x
.
. . . . . .
26. Graphs of various exponential functions
y
.
. = 3x. = 2x
y y
. = 1x
y
. x
.
. . . . . .
27. Graphs of various exponential functions
y
.
. = 10x= 3x. = 2x
y y
. y
. = 1x
y
. x
.
. . . . . .
28. Graphs of various exponential functions
y
.
. = 10x= 3x. = 2x
y y
. y . = 1.5x
y
. = 1x
y
. x
.
. . . . . .
29. Graphs of various exponential functions
y
.
. = (1/2)x
y . = 10x= 3x. = 2x
y y
. y . = 1.5x
y
. = 1x
y
. x
.
. . . . . .
30. Graphs of various exponential functions
x
y
.
. = (1/2)x (1/3)
y y
. = . = 10x= 3x. = 2x
y y
. y . = 1.5x
y
. = 1x
y
. x
.
. . . . . .
31. Graphs of various exponential functions
y
.
y . = x
. = (1/2)x (1/3)
y . = (1/10)x. = 10x= 3x. = 2x
y y y
. y . = 1.5x
y
. = 1x
y
. x
.
. . . . . .
32. Graphs of various exponential functions
y
.
y yx
.. = ((1/2)x (1/3)x
y = 2/. )=
3 . = (1/10)x. = 10x= 3x. = 2x
y y y
. y . = 1.5x
y
. = 1x
y
. x
.
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 12 / 54
33. Outline
Definition of exponential functions
Properties of exponential Functions
The number e and the natural exponential function
Compound Interest
The number e
A limit
Logarithmic Functions
Derivatives of Exponential Functions
Exponential Growth
Derivative of the natural logarithm function
Derivatives of other exponentials and logarithms
Other exponentials
Other logarithms
Logarithmic Differentiation
The power rule for irrational powers
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 13 / 54
34. Properties of exponential Functions
.
Theorem
If a > 0 and a ̸= 1, then f(x) = ax is a continuous function with domain R and
range (0, ∞). In particular, ax > 0 for all x. If a, b > 0 and x, y ∈ R, then
ax+y = ax ay
ax
ax−y = y
a
(ax )y = axy
(ab)x = ax bx
Proof.
This is true for positive integer exponents by natural definition
Our conventional definitions make these true for rational exponents
Our limit definition make these for irrational exponents, too
.
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 14 / 54
35. Properties of exponential Functions
.
Theorem
If a > 0 and a ̸= 1, then f(x) = ax is a continuous function with domain R and
range (0, ∞). In particular, ax > 0 for all x. If a, b > 0 and x, y ∈ R, then
ax+y = ax ay
ax
ax−y = y negative exponents mean reciprocals.
a
(ax )y = axy
(ab)x = ax bx
Proof.
This is true for positive integer exponents by natural definition
Our conventional definitions make these true for rational exponents
Our limit definition make these for irrational exponents, too
.
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 14 / 54
36. Properties of exponential Functions
.
Theorem
If a > 0 and a ̸= 1, then f(x) = ax is a continuous function with domain R and
range (0, ∞). In particular, ax > 0 for all x. If a, b > 0 and x, y ∈ R, then
ax+y = ax ay
ax
ax−y = y negative exponents mean reciprocals.
a
(ax )y = axy fractional exponents mean roots
(ab)x = ax bx
Proof.
This is true for positive integer exponents by natural definition
Our conventional definitions make these true for rational exponents
Our limit definition make these for irrational exponents, too
.
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 14 / 54
37. Simplifying exponential expressions
Example
Simplify: 82/3
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 15 / 54
38. Simplifying exponential expressions
Example
Simplify: 82/3
Solution
√
3 √
82/3 = 82 =
3
64 = 4
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 15 / 54
42. Limits of exponential functions
Fact (Limits of exponential y
.
functions) . = (= 2()1/32/3)x
y . 1/ =x( )x
y .
y y y = x . 3x y
. = (. /10)10x= 2x. =
1 . =
y y
If a > 1, then lim ax = ∞
x→∞
and lim ax = 0
x→−∞
If 0 < a < 1, then
lim ax = 0 and y
. =
x→∞
lim a = ∞ x . x
.
x→−∞
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 16 / 54
43. Outline
Definition of exponential functions
Properties of exponential Functions
The number e and the natural exponential function
Compound Interest
The number e
A limit
Logarithmic Functions
Derivatives of Exponential Functions
Exponential Growth
Derivative of the natural logarithm function
Derivatives of other exponentials and logarithms
Other exponentials
Other logarithms
Logarithmic Differentiation
The power rule for irrational powers
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 17 / 54
44. Compounded Interest
Question
Suppose you save $100 at 10% annual interest, with interest
compounded once a year. How much do you have
After one year?
After two years?
after t years?
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 18 / 54
45. Compounded Interest
Question
Suppose you save $100 at 10% annual interest, with interest
compounded once a year. How much do you have
After one year?
After two years?
after t years?
Answer
$100 + 10% = $110
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 18 / 54
46. Compounded Interest
Question
Suppose you save $100 at 10% annual interest, with interest
compounded once a year. How much do you have
After one year?
After two years?
after t years?
Answer
$100 + 10% = $110
$110 + 10% = $110 + $11 = $121
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 18 / 54
47. Compounded Interest
Question
Suppose you save $100 at 10% annual interest, with interest
compounded once a year. How much do you have
After one year?
After two years?
after t years?
Answer
$100 + 10% = $110
$110 + 10% = $110 + $11 = $121
$100(1.1)t .
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 18 / 54
48. Compounded Interest: quarterly
Question
Suppose you save $100 at 10% annual interest, with interest
compounded four times a year. How much do you have
After one year?
After two years?
after t years?
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 19 / 54
49. Compounded Interest: quarterly
Question
Suppose you save $100 at 10% annual interest, with interest
compounded four times a year. How much do you have
After one year?
After two years?
after t years?
Answer
$100(1.025)4 = $110.38,
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 19 / 54
50. Compounded Interest: quarterly
Question
Suppose you save $100 at 10% annual interest, with interest
compounded four times a year. How much do you have
After one year?
After two years?
after t years?
Answer
$100(1.025)4 = $110.38, not $100(1.1)4 !
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 19 / 54
51. Compounded Interest: quarterly
Question
Suppose you save $100 at 10% annual interest, with interest
compounded four times a year. How much do you have
After one year?
After two years?
after t years?
Answer
$100(1.025)4 = $110.38, not $100(1.1)4 !
$100(1.025)8 = $121.84
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 19 / 54
52. Compounded Interest: quarterly
Question
Suppose you save $100 at 10% annual interest, with interest
compounded four times a year. How much do you have
After one year?
After two years?
after t years?
Answer
$100(1.025)4 = $110.38, not $100(1.1)4 !
$100(1.025)8 = $121.84
$100(1.025)4t .
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 19 / 54
53. Compounded Interest: monthly
Question
Suppose you save $100 at 10% annual interest, with interest
compounded twelve times a year. How much do you have after t
years?
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 20 / 54
54. Compounded Interest: monthly
Question
Suppose you save $100 at 10% annual interest, with interest
compounded twelve times a year. How much do you have after t
years?
Answer
$100(1 + 10%/12)12t
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 20 / 54
55. Compounded Interest: general
Question
Suppose you save P at interest rate r, with interest compounded n
times a year. How much do you have after t years?
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 21 / 54
56. Compounded Interest: general
Question
Suppose you save P at interest rate r, with interest compounded n
times a year. How much do you have after t years?
Answer
( r )nt
B(t) = P 1 +
n
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 21 / 54
57. Compounded Interest: continuous
Question
Suppose you save P at interest rate r, with interest compounded every
instant. How much do you have after t years?
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 22 / 54
58. Compounded Interest: continuous
Question
Suppose you save P at interest rate r, with interest compounded every
instant. How much do you have after t years?
Answer
( ( )
r )nt 1 rnt
B(t) = lim P 1 + = lim P 1 +
n→∞ n n→∞ n
[ ( )n ]rt
1
=P lim 1 +
n→∞ n
independent of P, r, or t
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 22 / 54
59. The magic number
Definition
( )
1 n
e = lim 1 +
n→∞ n
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 23 / 54
60. The magic number
Definition
( )
1 n
e = lim 1 +
n→∞ n
So now continuously-compounded interest can be expressed as
B(t) = Pert .
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 23 / 54
61. Existence of e
See Appendix B
( )
1 n
n 1+
n
1 2
2 2.25
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 24 / 54
62. Existence of e
See Appendix B
( )
1 n
n 1+
n
1 2
2 2.25
3 2.37037
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 24 / 54
63. Existence of e
See Appendix B
( )
1 n
n 1+
n
1 2
2 2.25
3 2.37037
10 2.59374
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 24 / 54
64. Existence of e
See Appendix B
( )
1 n
n 1+
n
1 2
2 2.25
3 2.37037
10 2.59374
100 2.70481
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 24 / 54
65. Existence of e
See Appendix B
( )
1 n
n 1+
n
1 2
2 2.25
3 2.37037
10 2.59374
100 2.70481
1000 2.71692
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 24 / 54
66. Existence of e
See Appendix B
( )
1 n
n 1+
n
1 2
2 2.25
3 2.37037
10 2.59374
100 2.70481
1000 2.71692
106 2.71828
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 24 / 54
67. Existence of e
See Appendix B
( )
1 n
n 1+
We can experimentally n
verify that this number 1 2
exists and is 2 2.25
3 2.37037
e ≈ 2.718281828459045 . . .
10 2.59374
100 2.70481
1000 2.71692
106 2.71828
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 24 / 54
68. Existence of e
See Appendix B
( )
1 n
n 1+
We can experimentally n
verify that this number 1 2
exists and is 2 2.25
3 2.37037
e ≈ 2.718281828459045 . . .
10 2.59374
e is irrational 100 2.70481
1000 2.71692
106 2.71828
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 24 / 54
69. Existence of e
See Appendix B
( )
1 n
n 1+
We can experimentally n
verify that this number 1 2
exists and is 2 2.25
3 2.37037
e ≈ 2.718281828459045 . . .
10 2.59374
e is irrational 100 2.70481
1000 2.71692
e is transcendental
106 2.71828
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 24 / 54
70. Meet the Mathematician: Leonhard Euler
Born in Switzerland, lived
in Prussia (Germany) and
Russia
Eyesight trouble all his life,
blind from 1766 onward
Hundreds of contributions
to calculus, number theory,
graph theory, fluid
mechanics, optics, and
astronomy
Leonhard Paul Euler
Swiss, 1707–1783
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 25 / 54
71. A limit
.
Question
eh − 1
What is lim ?
h→0 h
. . . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 26 / 54
72. A limit
.
Question
eh − 1
What is lim ?
h→0 h
Answer
If h is small enough, e ≈ (1 + h)1/h . So
eh − 1
≈1
h
. . . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 26 / 54
73. A limit
.
Question
eh − 1
What is lim ?
h→0 h
Answer
If h is small enough, e ≈ (1 + h)1/h . So
eh − 1
≈1
h
eh − 1
In fact, lim = 1.
h→0 h
2h − 1
This can be used to characterize e: lim = 0.693 · · · < 1 and
h→0 h
3h − 1
lim = 1.099 · · · > 1
h→0 h
. . . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 26 / 54
74. Outline
Definition of exponential functions
Properties of exponential Functions
The number e and the natural exponential function
Compound Interest
The number e
A limit
Logarithmic Functions
Derivatives of Exponential Functions
Exponential Growth
Derivative of the natural logarithm function
Derivatives of other exponentials and logarithms
Other exponentials
Other logarithms
Logarithmic Differentiation
The power rule for irrational powers
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 27 / 54
75. Logarithms
Definition
The base a logarithm loga x is the inverse of the function ax
y = loga x ⇐⇒ x = ay
The natural logarithm ln x is the inverse of ex . So
y = ln x ⇐⇒ x = ey .
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 28 / 54
76. Logarithms
Definition
The base a logarithm loga x is the inverse of the function ax
y = loga x ⇐⇒ x = ay
The natural logarithm ln x is the inverse of ex . So
y = ln x ⇐⇒ x = ey .
Facts
(i) loga (x · x′ ) = loga x + loga x′
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 28 / 54
77. Logarithms
Definition
The base a logarithm loga x is the inverse of the function ax
y = loga x ⇐⇒ x = ay
The natural logarithm ln x is the inverse of ex . So
y = ln x ⇐⇒ x = ey .
Facts
(i) loga (x · x′ ) = loga x + loga x′
(x)
(ii) loga ′ = loga x − loga x′
x
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 28 / 54
78. Logarithms
Definition
The base a logarithm loga x is the inverse of the function ax
y = loga x ⇐⇒ x = ay
The natural logarithm ln x is the inverse of ex . So
y = ln x ⇐⇒ x = ey .
Facts
(i) loga (x · x′ ) = loga x + loga x′
(x)
(ii) loga ′ = loga x − loga x′
x
(iii) loga (xr ) = r loga x
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 28 / 54
79. Logarithms convert products to sums
Suppose y = loga x and y′ = loga x′
′
Then x = ay and x′ = ay
′ ′
So xx′ = ay ay = ay+y
Therefore
loga (xx′ ) = y + y′ = loga x + loga x′
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 29 / 54
80. Example
Write as a single logarithm: 2 ln 4 − ln 3.
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 30 / 54
81. Example
Write as a single logarithm: 2 ln 4 − ln 3.
Solution
42
2 ln 4 − ln 3 = ln 42 − ln 3 = ln
3
ln 42
not !
ln 3
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 30 / 54
82. Example
Write as a single logarithm: 2 ln 4 − ln 3.
Solution
42
2 ln 4 − ln 3 = ln 42 − ln 3 = ln
3
ln 42
not !
ln 3
Example
3
Write as a single logarithm: ln + 4 ln 2
4
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 30 / 54
83. Example
Write as a single logarithm: 2 ln 4 − ln 3.
Solution
42
2 ln 4 − ln 3 = ln 42 − ln 3 = ln
3
ln 42
not !
ln 3
Example
3
Write as a single logarithm: ln + 4 ln 2
4
Answer
ln 12
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 30 / 54
84. “ .
. lawn”
.
. . . . . .
.
Image credit: Selva
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 31 / 54
85. Graphs of logarithmic functions
y
.
. = 2x
y
y
. = log2 x
. . 0, 1)
(
..1, 0) .
( x
.
. . . . . .
86. Graphs of logarithmic functions
y
.
. = 3x= 2x
y . y
y
. = log2 x
y
. = log3 x
. . 0, 1)
(
..1, 0) .
( x
.
. . . . . .
87. Graphs of logarithmic functions
y
.
. = .10x 3x= 2x
y y= . y
y
. = log2 x
y
. = log3 x
. . 0, 1)
(
y
. = log10 x
..1, 0) .
( x
.
. . . . . .
88. Graphs of logarithmic functions
y
.
. = .10=3x= 2x
y xy
y y. = .ex
y
. = log2 x
y
. = ln x
y
. = log3 x
. . 0, 1)
(
y
. = log10 x
..1, 0) .
( x
.
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 32 / 54
89. Change of base formula for exponentials
Fact
If a > 0 and a ̸= 1, then
ln x
loga x =
ln a
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 33 / 54
90. Change of base formula for exponentials
Fact
If a > 0 and a ̸= 1, then
ln x
loga x =
ln a
Proof.
If y = loga x, then x = ay
So ln x = ln(ay ) = y ln a
Therefore
ln x
y = loga x =
ln a
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 33 / 54
91. Outline
Definition of exponential functions
Properties of exponential Functions
The number e and the natural exponential function
Compound Interest
The number e
A limit
Logarithmic Functions
Derivatives of Exponential Functions
Exponential Growth
Derivative of the natural logarithm function
Derivatives of other exponentials and logarithms
Other exponentials
Other logarithms
Logarithmic Differentiation
The power rule for irrational powers
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 34 / 54
92. Derivatives of Exponential Functions
Fact
If f(x) = ax , then f′ (x) = f′ (0)ax .
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 35 / 54
93. Derivatives of Exponential Functions
Fact
If f(x) = ax , then f′ (x) = f′ (0)ax .
Proof.
Follow your nose:
f(x + h) − f(x) ax+h − ax
f′ (x) = lim = lim
h→0 h h→0 h
a x ah − ax a h−1
= lim = ax · lim = ax · f′ (0).
h→0 h h→0 h
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 35 / 54
94. Derivatives of Exponential Functions
Fact
If f(x) = ax , then f′ (x) = f′ (0)ax .
Proof.
Follow your nose:
f(x + h) − f(x) ax+h − ax
f′ (x) = lim = lim
h→0 h h→0 h
a x ah − ax a h−1
= lim = ax · lim = ax · f′ (0).
h→0 h h→0 h
To reiterate: the derivative of an exponential function is a constant
times that function. Much different from polynomials!
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 35 / 54
95. The funny limit in the case of e
Remember the definition of e:
( )
1 n
e = lim 1 + = lim (1 + h)1/h
n→∞ n h→0
Question
eh − 1
What is lim ?
h→0 h
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 36 / 54
96. The funny limit in the case of e
Remember the definition of e:
( )
1 n
e = lim 1 + = lim (1 + h)1/h
n→∞ n h→0
Question
eh − 1
What is lim ?
h→0 h
Answer
If h is small enough, e ≈ (1 + h)1/h . So
[ ]h
eh − 1 (1 + h)1/h − 1 (1 + h) − 1 h
≈ = = =1
h h h h
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 36 / 54
97. The funny limit in the case of e
Remember the definition of e:
( )
1 n
e = lim 1 + = lim (1 + h)1/h
n→∞ n h→0
Question
eh − 1
What is lim ?
h→0 h
Answer
If h is small enough, e ≈ (1 + h)1/h . So
[ ]h
eh − 1 (1 + h)1/h − 1 (1 + h) − 1 h
≈ = = =1
h h h h
eh − 1
So in the limit we get equality: lim =1
h→0 h
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 36 / 54
98. Derivative of the natural exponential function
From ( )
d x ah − 1 eh − 1
a = lim ax and lim =1
dx h→0 h h→0 h
we get:
Theorem
d x
e = ex
dx
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 37 / 54
99. Exponential Growth
Commonly misused term to say something grows exponentially
It means the rate of change (derivative) is proportional to the
current value
Examples: Natural population growth, compounded interest,
social networks
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 38 / 54
100. Examples
Examples
Find these derivatives:
e3x
2
ex
x2 ex
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 39 / 54
101. Examples
Examples
Find these derivatives:
e3x
2
ex
x2 ex
Solution
d 3x
e = 3e3x
dx
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 39 / 54
102. Examples
Examples
Find these derivatives:
e3x
2
ex
x2 ex
Solution
d 3x
e = 3e3x
dx
d x2 2 d 2
e = ex (x2 ) = 2xex
dx dx
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 39 / 54
103. Examples
Examples
Find these derivatives:
e3x
2
ex
x2 ex
Solution
d 3x
e = 3e3x
dx
d x2 2 d 2
e = ex (x2 ) = 2xex
dx dx
d 2 x
x e = 2xex + x2 ex
dx
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 39 / 54
104. Outline
Definition of exponential functions
Properties of exponential Functions
The number e and the natural exponential function
Compound Interest
The number e
A limit
Logarithmic Functions
Derivatives of Exponential Functions
Exponential Growth
Derivative of the natural logarithm function
Derivatives of other exponentials and logarithms
Other exponentials
Other logarithms
Logarithmic Differentiation
The power rule for irrational powers
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 40 / 54
105. Derivative of the natural logarithm function
Let y = ln x. Then x = ey
so
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 41 / 54
106. Derivative of the natural logarithm function
Let y = ln x. Then x = ey
so
dy
ey =1
dx
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 41 / 54
107. Derivative of the natural logarithm function
Let y = ln x. Then x = ey
so
dy
ey=1
dx
dy 1 1
=⇒ = y =
dx e x
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 41 / 54
108. Derivative of the natural logarithm function
Let y = ln x. Then x = ey
so
dy
ey=1
dx
dy 1 1
=⇒ = y =
dx e x
So:
Fact
d 1
ln x =
dx x
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 41 / 54
109. Derivative of the natural logarithm function
y
.
Let y = ln x. Then x = ey
so
dy
ey=1
dx l
.n x
dy 1 1
=⇒ = y =
dx e x
. x
.
So:
Fact
d 1
ln x =
dx x
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 41 / 54
110. Derivative of the natural logarithm function
y
.
Let y = ln x. Then x = ey
so
dy
ey=1
dx l
.n x
dy 1 1 1
=⇒ = y = .
dx e x x
. x
.
So:
Fact
d 1
ln x =
dx x
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 41 / 54
111. The Tower of Powers
y y′
x3 3x2 The derivative of a power
2 1 function is a power function
x 2x
of one lower power
x1 1x0
x0 0
? ?
x−1 −1x−2
x−2 −2x−3
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 42 / 54
112. The Tower of Powers
y y′
x3 3x2 The derivative of a power
2 1 function is a power function
x 2x
of one lower power
x1 1x0 Each power function is the
x 0
0 derivative of another power
function, except x−1
? x−1
x−1 −1x−2
x−2 −2x−3
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 42 / 54
113. The Tower of Powers
y y′
x3 3x2 The derivative of a power
2 1 function is a power function
x 2x
of one lower power
x1 1x0 Each power function is the
x 0
0 derivative of another power
function, except x−1
ln x x−1
ln x fills in this gap
x−1 −1x−2 precisely.
x−2 −2x−3
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 42 / 54
114. Outline
Definition of exponential functions
Properties of exponential Functions
The number e and the natural exponential function
Compound Interest
The number e
A limit
Logarithmic Functions
Derivatives of Exponential Functions
Exponential Growth
Derivative of the natural logarithm function
Derivatives of other exponentials and logarithms
Other exponentials
Other logarithms
Logarithmic Differentiation
The power rule for irrational powers
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 43 / 54
115. Other logarithms
Example
d x
Use implicit differentiation to find a .
dx
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 44 / 54
116. Other logarithms
Example
d x
Use implicit differentiation to find a .
dx
Solution
Let y = ax , so
ln y = ln ax = x ln a
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 44 / 54
117. Other logarithms
Example
d x
Use implicit differentiation to find a .
dx
Solution
Let y = ax , so
ln y = ln ax = x ln a
Differentiate implicitly:
1 dy dy
= ln a =⇒ = (ln a)y = (ln a)ax
y dx dx
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 44 / 54
118. Other logarithms
Example
d x
Use implicit differentiation to find a .
dx
Solution
Let y = ax , so
ln y = ln ax = x ln a
Differentiate implicitly:
1 dy dy
= ln a =⇒ = (ln a)y = (ln a)ax
y dx dx
Before we showed y′ = y′ (0)y, so now we know that
2h − 1 3h − 1
ln 2 = lim ≈ 0.693 ln 3 = lim ≈ 1.10
h→0 h h→0 h
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 44 / 54
119. Other logarithms
Example
d
Find loga x.
dx
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 45 / 54
120. Other logarithms
Example
d
Find loga x.
dx
Solution
Let y = loga x, so ay = x.
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 45 / 54
121. Other logarithms
Example
d
Find loga x.
dx
Solution
Let y = loga x, so ay = x. Now differentiate implicitly:
dy dy 1 1
(ln a)ay = 1 =⇒ = y =
dx dx a ln a x ln a
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 45 / 54
122. Other logarithms
Example
d
Find loga x.
dx
Solution
Let y = loga x, so ay = x. Now differentiate implicitly:
dy dy 1 1
(ln a)ay = 1 =⇒ = y =
dx dx a ln a x ln a
Another way to see this is to take the natural logarithm:
ln x
ay = x =⇒ y ln a = ln x =⇒ y =
ln a
dy 1 1
So = .
dx ln a x
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 45 / 54
123. More examples
Example
d
Find log2 (x2 + 1)
dx
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 46 / 54
124. More examples
Example
d
Find log2 (x2 + 1)
dx
Answer
dy 1 1 2x
= 2+1
(2x) =
dx ln 2 x (ln 2)(x2 + 1)
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 46 / 54
125. Outline
Definition of exponential functions
Properties of exponential Functions
The number e and the natural exponential function
Compound Interest
The number e
A limit
Logarithmic Functions
Derivatives of Exponential Functions
Exponential Growth
Derivative of the natural logarithm function
Derivatives of other exponentials and logarithms
Other exponentials
Other logarithms
Logarithmic Differentiation
The power rule for irrational powers
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 47 / 54
126. A nasty derivative
Example
√
(x2 + 1) x + 3
Let y = . Find y′ .
x−1
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 48 / 54
127. A nasty derivative
Example
√
(x2 + 1) x + 3
Let y = . Find y′ .
x−1
Solution
We use the quotient rule, and the product rule in the numerator:
[ √ ] √
(x − 1) 2x x + 3 + (x2 + 1) 1 (x + 3)−1/2 − (x2 + 1) x + 3(1)
2
y′ =
(x − 1)2
√ √
2x x + 3 (x2 + 1) (x2 + 1) x + 3
= + √ −
(x − 1) 2 x + 3(x − 1) (x − 1)2
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 48 / 54
128. Another way
√
(x2 + 1) x + 3
y=
x−1
1
ln y = ln(x2 + 1) + ln(x + 3) − ln(x − 1)
2
1 dy 2x 1 1
= 2 + −
y dx x + 1 2(x + 3) x − 1
So
( )
dy 2x 1 1
= + − y
dx x2+1 2(x + 3) x − 1
( ) √
2x 1 1 (x2 + 1) x + 3
= + −
x2 + 1 2(x + 3) x − 1 x−1
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 49 / 54
129. Compare and contrast
Using the product, quotient, and power rules:
√ √
′ 2x x + 3 (x2 + 1) (x2 + 1) x + 3
y = + √ −
(x − 1) 2 x + 3(x − 1) (x − 1)2
Using logarithmic differentiation:
( ) 2 √
′ 2x 1 1 (x + 1) x + 3
y = + −
x2 + 1 2(x + 3) x − 1 x−1
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 50 / 54
130. Compare and contrast
Using the product, quotient, and power rules:
√ √
′ 2x x + 3 (x2 + 1) (x2 + 1) x + 3
y = + √ −
(x − 1) 2 x + 3(x − 1) (x − 1)2
Using logarithmic differentiation:
( ) 2 √
′ 2x 1 1 (x + 1) x + 3
y = + −
x2 + 1 2(x + 3) x − 1 x−1
Are these the same?
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 50 / 54
131. Compare and contrast
Using the product, quotient, and power rules:
√ √
′ 2x x + 3 (x2 + 1) (x2 + 1) x + 3
y = + √ −
(x − 1) 2 x + 3(x − 1) (x − 1)2
Using logarithmic differentiation:
( ) 2 √
′ 2x 1 1 (x + 1) x + 3
y = + −
x2 + 1 2(x + 3) x − 1 x−1
Are these the same?
Which do you like better?
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 50 / 54
132. Compare and contrast
Using the product, quotient, and power rules:
√ √
′ 2x x + 3 (x2 + 1) (x2 + 1) x + 3
y = + √ −
(x − 1) 2 x + 3(x − 1) (x − 1)2
Using logarithmic differentiation:
( ) 2 √
′ 2x 1 1 (x + 1) x + 3
y = + −
x2 + 1 2(x + 3) x − 1 x−1
Are these the same?
Which do you like better?
What kinds of expressions are well-suited for logarithmic
differentiation?
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 50 / 54
133. Derivatives of powers
Let y = xx . Which of these is true?
(A) Since y is a power function, y′ = x · xx−1 = xx .
(B) Since y is an exponential function, y′ = (ln x) · xx
(C) Neither
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 51 / 54
134. Derivatives of powers
Let y = xx . Which of these is true?
(A) Since y is a power function, y′ = x · xx−1 = xx .
(B) Since y is an exponential function, y′ = (ln x) · xx
(C) Neither
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 51 / 54
135. It's neither! Or both?
If y = xx , then
ln y = x ln x
1 dy 1
= x · + ln x = 1 + ln x
y dx x
dy
= xx + (ln x)xx
dx
Each of these terms is one of the wrong answers!
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 52 / 54
136. Derivative of arbitrary powers
Fact (The power rule)
Let y = xr . Then y′ = rxr−1 .
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 53 / 54
137. Derivative of arbitrary powers
Fact (The power rule)
Let y = xr . Then y′ = rxr−1 .
Proof.
y = xr =⇒ ln y = r ln x
Now differentiate:
1 dy r
=
y dx x
dy y
=⇒ = r = rxr−1
dx x
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 53 / 54
138. Summary
. . . . . .
V63.0121.002.2010Su, Calculus I (NYU) Exponential and Logarithmic June 1, 2010 54 / 54