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March
18th

              Today:

              Warm-Up
             Test Review
   Khan Academy Results/Schedule
  Begin Unit on Quadratic Equations
Khan Academy:

  Saturday/Sunday -- 1409 minutes
           = 23.48 Hours
       Topics for March 24th:
Graphing Parabolas in Standard Form
 Solving Quadratics by Factoring 1
Number Sense: Space   & Volume
Number Sense: Space   & Volume
Number Sense: Space   & Volume
Number Sense: Space   & Volume
Number Sense: Space   & Volume

3D Sphere
Number Sense: Space   & Volume
Test Review:

  Top 4 missed questions from Friday's test: v.1
 4th; (44% correct) #8. 32x2 = 50

  3rd; (42% correct) #10. x3 - 121x = 0

  2nd; (40% correct) #4. -3x3 - 12x2 = 0

1st; (37%) #3. The product of (9 - 4t)(9 + 4t) results in:
Quadratic Equations:

  Today's Objectives:

1. Understand the characteristics of Quadratic Equations,
   (What they are, and what they aren't).
2. Recognize the Graph of a Quadratic Equation
3. Describe the Differences between Quadratic & Linear
   Equations
4. Solve Quadratic Equations by factoring
5. Listen Carefully, take notes, ask questions when needed.
Quadratic Equations:
 1. What is a Quadratic Equation? From the Latin 'quad',
 as in quaduplets, quadrilaterals, and quarters...
Quad means 4. A square has four sides. A variable in a
quadratic equation can have an exponent of 2, but no higher.
An exponent of 2 is a number 'squared'....
  The following are all examples of quadratic equations:
x2 = 25,   4y2 + 2y - 1 = 0,   y2 + 6y = 0,   x2 + 2x - 4 = 0
    The standard form of a quadratic is written as:
     ax2 + bx + c = 0, where only a cannot = 0
Quadratic Equations:

   We have been solving quadratic equations recently
   without actually calling them Quadratics.
        Let's review. Solve: x2 - 13x = 0

   x( x - 13) = 0 x = 0, or x = 13
  One more example. Solve: y = x2 - 4x - 5. To find the
  x-intercepts, we set the equation to x2 - 4x - 5 = 0
 ( x - 5)( x + 1) = 0 x = 5 or x = -1
Which brings us to: What do Quadratic Equations look like
and how are they different from linear equations?
Linear Equations:
 Y = 2x + 0 is a linear equation.
Linear Equations are straight
lines and cross the x and y axis
only one time. For each
'y', there is only one 'x'.

 The greatest degree of any
exponent in a linear equation
is 1. The relationship
between x and y is constant;
the slope stays the same.
Linear vs. Quadratic Equations
                               A. The graphs of quadratics
                               are not straight lines, they
                               are always in the shape of a
                               Parabola.
                               B. Parabolas can cross an
                               axis more than once.

C. Unlike linear equations, each value of Y in a quadratic
equation has more than one value of x. Because Y is 0 at the
X-intercept, when we set the equation = to 0, we get the
values of the x-intercepts.
 D. The slope of a quadratic is not constant. The slope-
 intercept formula will not work with parabolas.
Parabolas: ...In Sports
Parabolas: ...In Archeticture
Parabolas: ...In Nature
Parabolas: ...Everywhere

Finally, the most important
       Parabola of all
Objective 4: Solving Quadratic Equations by Factoring

 There are 2 ways to factor Quadratic Equations and we
 have done both already. Let's review:

    Method 1: Set the equation = to 0 and solve:
    Example A. x2 + 6x + 9

x2 + 6x + 9 = 0; (x + 3) (x + 3) = 0, x = -3.This is a perfect square
trinomial, and the parabola only crosses the x axis at -3 and
would be in this shape:
Objective 4: Solving Quadratic Equations by Factoring

                 Example B. x2 + 16x + 48 = 0
(x + 12) (x + 4) = 0; x = -12, x = -4. This parabola is to
                   the left of the Y axis
 Method 2: Solve x2 = 64. Remember the standard form?
      ax2 + bx + c = 0, where only a cannot = 0
 In this case, b is 0, and c is 64.
   We can solve by taking the square root of both sides.
   The result is x = + 8; x = 8, and x = -8
Factoring Quadratic Equations

From the warm-up exercises, we have seen the various
ways to factor quadratic equations. The solutions, or
roots, tell us where the graph crosses the x axis.

Given this information, we can begin to plot the graph.
However, there is still more information we need to
complete the graph.
Graphing Parabolas & Parabola Terminology
Remember, all Quadratic Equations are in the form of
a Parabola. Parabolas are in one of these forms:

                  To solve and graph a quadratic
                  equation, we need to know where
                  the graph crosses the x and y axis:
Graphing Parabolas & Parabola Terminology
  Important points on a Parabola:

1.Axis of Symmetry:The axis of symmetry is the verticle
or horizontal line which runs through the exact center
of the parabola.
Graphing Parabolas & Parabola Terminology
Important points on a Parabola:
2. Vertex: The vertex is the highest point (the
maximum), or the lowest point (the minimum) on a
parabola.
                           Notice that the axis of
                           symmetry always runs
                           through the vertex.
Finding the Axis of Symmetry and Vertex
 1. Finding the Axis of Symmetry: The formula is: x = - b/2a
              Plug in and solve for y = x2 + 12x + 32
We get - 12/2; = -6. The center of the parabola crosses the x
axis at -6. Since the axis of symmetry always runs through
the vertex, the x coordinate for the vertex is -6 also.
Finding the Axis of Symmetry and Vertex

There is one more point left to find and that is the
y-coordinate of the vertex. To find this, plug in the
value of the x-coordinate back into the equation and
find y. y = -12 + 12(4) + 32. Y = 1 + 48 + 32. Y = 81.

 The bottom of the parabola is at -1 on the x axis, and
way up at 81 on the y axis.
Warm- Up Exercises

                     The slope is 2,
                       which is
                        positive
                      and the Y-
                       intercept
                             is -2

                       Therefore,
                           the
                         correct
                        graph is
                            A
Warm- Up Exercises


                                 The Y-intercept is:0

                                  The slope is: 2
                             The equation of the line is:
                                   Y = 2x + 0



Write the equation for the line above
Warm- Up Exercises
3. Write the inequality for the graph below

                               The Y-intercept is: 2
                                The slope is: -3
                               The line is solid,
                               not dotted. The
                               equation is:

                                   Y < -3x + 2
Class Work:
90% of 90 girls and 80% of 110 boys have
shown up in the concert hall on time.

How many children are late?
Parabolas




A parabola with -x2

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March 18

  • 1. March 18th Today: Warm-Up Test Review Khan Academy Results/Schedule Begin Unit on Quadratic Equations
  • 2. Khan Academy: Saturday/Sunday -- 1409 minutes = 23.48 Hours Topics for March 24th: Graphing Parabolas in Standard Form Solving Quadratics by Factoring 1
  • 7. Number Sense: Space & Volume 3D Sphere
  • 9. Test Review: Top 4 missed questions from Friday's test: v.1 4th; (44% correct) #8. 32x2 = 50 3rd; (42% correct) #10. x3 - 121x = 0 2nd; (40% correct) #4. -3x3 - 12x2 = 0 1st; (37%) #3. The product of (9 - 4t)(9 + 4t) results in:
  • 10. Quadratic Equations: Today's Objectives: 1. Understand the characteristics of Quadratic Equations, (What they are, and what they aren't). 2. Recognize the Graph of a Quadratic Equation 3. Describe the Differences between Quadratic & Linear Equations 4. Solve Quadratic Equations by factoring 5. Listen Carefully, take notes, ask questions when needed.
  • 11. Quadratic Equations: 1. What is a Quadratic Equation? From the Latin 'quad', as in quaduplets, quadrilaterals, and quarters... Quad means 4. A square has four sides. A variable in a quadratic equation can have an exponent of 2, but no higher. An exponent of 2 is a number 'squared'.... The following are all examples of quadratic equations: x2 = 25, 4y2 + 2y - 1 = 0, y2 + 6y = 0, x2 + 2x - 4 = 0 The standard form of a quadratic is written as: ax2 + bx + c = 0, where only a cannot = 0
  • 12. Quadratic Equations: We have been solving quadratic equations recently without actually calling them Quadratics. Let's review. Solve: x2 - 13x = 0 x( x - 13) = 0 x = 0, or x = 13 One more example. Solve: y = x2 - 4x - 5. To find the x-intercepts, we set the equation to x2 - 4x - 5 = 0 ( x - 5)( x + 1) = 0 x = 5 or x = -1 Which brings us to: What do Quadratic Equations look like and how are they different from linear equations?
  • 13. Linear Equations: Y = 2x + 0 is a linear equation. Linear Equations are straight lines and cross the x and y axis only one time. For each 'y', there is only one 'x'. The greatest degree of any exponent in a linear equation is 1. The relationship between x and y is constant; the slope stays the same.
  • 14. Linear vs. Quadratic Equations A. The graphs of quadratics are not straight lines, they are always in the shape of a Parabola. B. Parabolas can cross an axis more than once. C. Unlike linear equations, each value of Y in a quadratic equation has more than one value of x. Because Y is 0 at the X-intercept, when we set the equation = to 0, we get the values of the x-intercepts. D. The slope of a quadratic is not constant. The slope- intercept formula will not work with parabolas.
  • 18. Parabolas: ...Everywhere Finally, the most important Parabola of all
  • 19. Objective 4: Solving Quadratic Equations by Factoring There are 2 ways to factor Quadratic Equations and we have done both already. Let's review: Method 1: Set the equation = to 0 and solve: Example A. x2 + 6x + 9 x2 + 6x + 9 = 0; (x + 3) (x + 3) = 0, x = -3.This is a perfect square trinomial, and the parabola only crosses the x axis at -3 and would be in this shape:
  • 20. Objective 4: Solving Quadratic Equations by Factoring Example B. x2 + 16x + 48 = 0 (x + 12) (x + 4) = 0; x = -12, x = -4. This parabola is to the left of the Y axis Method 2: Solve x2 = 64. Remember the standard form? ax2 + bx + c = 0, where only a cannot = 0 In this case, b is 0, and c is 64. We can solve by taking the square root of both sides. The result is x = + 8; x = 8, and x = -8
  • 21. Factoring Quadratic Equations From the warm-up exercises, we have seen the various ways to factor quadratic equations. The solutions, or roots, tell us where the graph crosses the x axis. Given this information, we can begin to plot the graph. However, there is still more information we need to complete the graph.
  • 22. Graphing Parabolas & Parabola Terminology Remember, all Quadratic Equations are in the form of a Parabola. Parabolas are in one of these forms: To solve and graph a quadratic equation, we need to know where the graph crosses the x and y axis:
  • 23. Graphing Parabolas & Parabola Terminology Important points on a Parabola: 1.Axis of Symmetry:The axis of symmetry is the verticle or horizontal line which runs through the exact center of the parabola.
  • 24. Graphing Parabolas & Parabola Terminology Important points on a Parabola: 2. Vertex: The vertex is the highest point (the maximum), or the lowest point (the minimum) on a parabola. Notice that the axis of symmetry always runs through the vertex.
  • 25. Finding the Axis of Symmetry and Vertex 1. Finding the Axis of Symmetry: The formula is: x = - b/2a Plug in and solve for y = x2 + 12x + 32 We get - 12/2; = -6. The center of the parabola crosses the x axis at -6. Since the axis of symmetry always runs through the vertex, the x coordinate for the vertex is -6 also.
  • 26. Finding the Axis of Symmetry and Vertex There is one more point left to find and that is the y-coordinate of the vertex. To find this, plug in the value of the x-coordinate back into the equation and find y. y = -12 + 12(4) + 32. Y = 1 + 48 + 32. Y = 81. The bottom of the parabola is at -1 on the x axis, and way up at 81 on the y axis.
  • 27.
  • 28.
  • 29. Warm- Up Exercises The slope is 2, which is positive and the Y- intercept is -2 Therefore, the correct graph is A
  • 30. Warm- Up Exercises The Y-intercept is:0 The slope is: 2 The equation of the line is: Y = 2x + 0 Write the equation for the line above
  • 31. Warm- Up Exercises 3. Write the inequality for the graph below The Y-intercept is: 2 The slope is: -3 The line is solid, not dotted. The equation is: Y < -3x + 2
  • 33. 90% of 90 girls and 80% of 110 boys have shown up in the concert hall on time. How many children are late?