1. Equilibre d’un corps solide soumis à deux
forces

.1
.2
.I



300
4.0
250
3.5
200
3.0
150
2.5
100
2.0
50
1.5
0
1
P=T
3.0
3.0
2.5
2.5
2.0
2.0
1.5
1.5
m (g)
l (cm)
(S)
1.0
1.0
0.5
0.5
0
0
T (N)
∆l (cm)
.1
.2

2. .3
T = K.∆l
K
.II
∆l
T
.1
∆l
T = K.∆l
N.m-1
(S.I)
K
T = K.∆l

(S)
T2 = 1.4N
.1
T1 = 2N
Fa = T1 – T2 = 0.6N
(S)
.2

3. V = 58cm3 (S)
Pliquide = ρ.V.g
Fa ≈ Pliquide
V
Pliquide = 0.58N
.III
.1
.2




F = ρ.V.g
Kg.m-3
m3
N.Kg-1
ρ
V
g