1. SHARING GASOLINE
COSTS

2. The Problem…

3. The Problem…

4. HOW MUCH SHOULD EACH
PERSON PAY?
TRY TO FIND THE FAIREST
POSSIBLE METHOD. SHOW
ALL YOUR WORK.

5. My Method to Solve the ProblemLara
10
Blocks
to
School
20
Blocks
to
School
&
Back

6. My Method to Solve the ProblemChan
8
Blocks
to
School
16
Blocks
to
School
&
Back

7. My Method to Solve the ProblemJason
5
Blocks
to
School
10
Blocks
to
School
&
Back

8. My Method to Solve the ProblemMarla
2
Blocks
to
School
4
Blocks
to
School
&
Back

9. My Method to Solve the Problem…
Student
Blocks
to School
Blocks
to School
& Back
Lara 10 20
Chan 8 16
Jason 5 10
Marla 2 4

10. 20 (LARA) + 16 (CHAN) + 10 (JASON) + 4
(MARLA) = 50 TOTAL BLOCKS
LARA = 20/50 = 2/5 (SIMPLIFIED)
CHAN = 16/50 = 8/25 (SIMPLIFIED)
JASON = 10/50 = 1/5 (SIMPLIFIED)
MARLA = 4/50 = 2/25 (SIMPLIFIED)
My Method to Solve the Problem

11. 2
-------- X $300 = $120
5
(LARA) (TOTAL) (MONEY OWED)
My Method to Solve the ProblemLara

12. 8
-------- X $300 = $96
25
(CHAN) (TOTAL) (MONEY OWED)
My Method to Solve the ProblemChan

13. 1
-------- X $300 = $60
5
(JASON) (TOTAL) (MONEY OWED)
My Method to Solve the ProblemJason

14. 2
-------- X $300 = $24
25
(MARLA) (TOTAL) (MONEY OWED)
My Method to Solve the ProblemMarla

15. My Method to Solve this
Problem
 As I started this problem I determined how many
blocks each person was in the car. I figured it out
for a one way trip and a to school and back. I
compared this problem to the fraction unit we did
earlier in the year and also the ratio and
proportion unit. I figured out the part for each of
the students in the car compared to the whole. I
created fractions for each of the students to
represent their time in the car. I simplified each of
the fractions. I knew that the total cost was $300
so I used $300 and multiplied it by the fraction of
each student to get my total cost per kid. I figured
this is a fair to split the cost because if you are in
the car longer you should pay more and if you are
in the car less you should pay less.