10 Reduction And Oxidation

Oxidation Numbers ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]

[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],Mn = +7 O = -2

[object Object],[object Object],N = -2 Cr = +6 Cl = +2 N = -3 V = +5

[object Object],[object Object],[object Object],[object Object]

[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]

[object Object],(loss of electrons) -3 -2 -1 0 +1 +2 +3 +4 +5 +6 +7 decrease in oxidation state (Gain of electrons)

[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],In any reaction involving oxidation and reduction there must be a species giving electrons and another species gaining electrons. Hence the term redox reaction.

[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]

[object Object],[object Object],[object Object]

[object Object],[object Object],[object Object],[object Object],[object Object],5Fe 2+ + MnO 4 -  5Fe 3+ + Mn 2+

[object Object],[object Object],[object Object],[object Object],2MnO 4 - (aq) + 6H + (aq) + 5H 2 O 2(l)  2Mn 2+ (aq) + 8H 2 O (l) + 5O 2(g)

[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],O 2 + 4e  2O 2- ox no 0 to -2 reduction Al -3e  Al 3+ ox no 0 to +3 oxidation Mg -2e  Mg 2+ ox no 0 to +2 oxidation Sn 4+ +2e  Sn 2+ ox no +4 to +2 reduction Cl 2 + 2e  2Cl - ox no 0 to -1 reduction

10 Reduction And Oxidation

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10 Reduction And Oxidation