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SULIT 3472/1 
3472/1 Additional Mathematics Paper 1 
SULIT 
1 
Additional Mathematics Paper 1 
Ogos, 2014 
MODUL PENINGKATAN PRESTASI TINGKATAN 5 TAHUN 2014 
ANJURAN MAJLIS PENGETUA SEKOLAH MALAYSIA (KEDAH) 
ADDITIONAL MATHEMATICS 
MARKING SCHEME 
Paper 1 
MODUL 2 
.
SULIT 3472/1 
3472/1 Additional Mathematics Paper 1 
SULIT 
2 
PROGRAM PENINGKATAN PRESTASI AKADEMIK SPM 2014 Marking Scheme Module 2 Additional Mathematics Paper 1 
Question 
Solution/ Marking Scheme 
Answer 
Marks 
1 
(a) B1 : 32morn== 
(a) 3m= AND 2n= (b) many – to – one 
21 
2 
B2 : ()66312forpp  ==  B1 : 163fp− =  
12p= 
3 
3 
(a) B1 : 233y−= (b) B1 : ()2338k−−= 
(a) ()133g=− (b) 5k= 
22 
4 
B2 : ()()12012pporporp−−= == B1 : ()()()224132pp−− 
12pANDp== 
3 
5 
(a) B1 : 35porq=−=− 
(a) 3p=− AND 5q=− (b) 3x=− 
21
SULIT 3472/1 
3472/1 Additional Mathematics Paper 1 
SULIT 
3 
Question 
Solution/ Marking Scheme 
Answer 
Marks 
6 
B2 : 
or 52x= , 3x=− B1: (25)(3)xx−+ 532x−≤≤ 
3 
7 
B2 : 32222log16logloglog8hk++ B1 : 32222log16logloglog8orhorkor 
433ab++ 
3 
8 
B2: 6221−=−+x B1 : ()22(1)37(7)7xor−− 25− 
3 
9 
B3 : ()2143+ B2 : ()()261822252217532223ddord +−+= = B1 : ()()26182225221722dord++ 
44 
4 
52 
3−
SULIT 3472/1 
3472/1 Additional Mathematics Paper 1 
SULIT 
4 
Question 
Solution/ Marking Scheme 
Answer 
Marks 
10 
(a) B1: 193= mm (b) B1: 9119118155−          − =S 
(a) 33mANDm==− (b) 91.123 
22 
11 
B1: 13r= 
272 
2 
12 
(a) B1: 2xyaxb=+ (b) B1 : () () 137*232*2borb=+ =+ 
(a) 2 (b) 1b=− 
22 
13 
B2 : ()()()22224324xyxy−+−=+− B1 : ()()()()22223204xyorxy−+−−+− 
2233248360xyxy+−−+= 
3 
14 
B1: ()()()()()()111432883411202kk×+×+×−×+×+×= OR 84421133k−− =−− 1k=− 
2
SULIT 3472/1 
3472/1 Additional Mathematics Paper 1 
SULIT 
5 
Question 
Solution/ Marking Scheme 
Answer 
Marks 
15 
(b) B1 : 5 or 2243+ 
(a) ji43+ (b) 543ji+ 
12 
16 
B3 : 6201240mORm+=+= B2 : 3360841203m ++=  B1 : 612OB  =   
3m=− 
4 
17 
B3 : 418113819xorx=⋅=⋅ B2 : 26sin8sin802sin2sin3xxorxorx−−+= =−= B1 : ()2312sin8sin5xx−=− 
418113819xANDx=⋅ =⋅   
4 
18 
(b) B2: ()()()()21112*1.047610.39222− B1: ()()()()21112*1.047610.39222or 
(a) 1.047rad (b) 44.21 
13
SULIT 3472/1 
3472/1 Additional Mathematics Paper 1 
SULIT 
6 
Question 
Solution/ Marking Scheme 
Answer 
Marks 
19 
(b) B1: 70118k∗+ = 
(a) 70 (b) 18k= 
12 
20 
B2 : (1)248h′′=− B1 : 1812)(2+−=′xxxh 
16 
3 
21 
B2 : 2823korx−=−= B1 : 28x− 
3k= 
3 
22 
B2 : ()() 2203111491515xorx + −−− B1 : ()()2311xhxdxx+ = −∫ 
10 
3 
23 
(b) B1: 23235155757or+×−×  
(a) 25 (b) 47 
12 
24 
(b) B1 : 435323CCC×× 
(a) 495 (b) 120 
12 
25 
B2 : p( z>k ) = 0.0608 B1 : P(z > 0. 14) = 0.4443 
k = 1.548 
3 
END OF MARKING SCHEME

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Trial kedah 2014 spm add math k1 skema

  • 1. SULIT 3472/1 3472/1 Additional Mathematics Paper 1 SULIT 1 Additional Mathematics Paper 1 Ogos, 2014 MODUL PENINGKATAN PRESTASI TINGKATAN 5 TAHUN 2014 ANJURAN MAJLIS PENGETUA SEKOLAH MALAYSIA (KEDAH) ADDITIONAL MATHEMATICS MARKING SCHEME Paper 1 MODUL 2 .
  • 2. SULIT 3472/1 3472/1 Additional Mathematics Paper 1 SULIT 2 PROGRAM PENINGKATAN PRESTASI AKADEMIK SPM 2014 Marking Scheme Module 2 Additional Mathematics Paper 1 Question Solution/ Marking Scheme Answer Marks 1 (a) B1 : 32morn== (a) 3m= AND 2n= (b) many – to – one 21 2 B2 : ()66312forpp  ==  B1 : 163fp− =  12p= 3 3 (a) B1 : 233y−= (b) B1 : ()2338k−−= (a) ()133g=− (b) 5k= 22 4 B2 : ()()12012pporporp−−= == B1 : ()()()224132pp−− 12pANDp== 3 5 (a) B1 : 35porq=−=− (a) 3p=− AND 5q=− (b) 3x=− 21
  • 3. SULIT 3472/1 3472/1 Additional Mathematics Paper 1 SULIT 3 Question Solution/ Marking Scheme Answer Marks 6 B2 : or 52x= , 3x=− B1: (25)(3)xx−+ 532x−≤≤ 3 7 B2 : 32222log16logloglog8hk++ B1 : 32222log16logloglog8orhorkor 433ab++ 3 8 B2: 6221−=−+x B1 : ()22(1)37(7)7xor−− 25− 3 9 B3 : ()2143+ B2 : ()()261822252217532223ddord +−+= = B1 : ()()26182225221722dord++ 44 4 52 3−
  • 4. SULIT 3472/1 3472/1 Additional Mathematics Paper 1 SULIT 4 Question Solution/ Marking Scheme Answer Marks 10 (a) B1: 193= mm (b) B1: 9119118155−          − =S (a) 33mANDm==− (b) 91.123 22 11 B1: 13r= 272 2 12 (a) B1: 2xyaxb=+ (b) B1 : () () 137*232*2borb=+ =+ (a) 2 (b) 1b=− 22 13 B2 : ()()()22224324xyxy−+−=+− B1 : ()()()()22223204xyorxy−+−−+− 2233248360xyxy+−−+= 3 14 B1: ()()()()()()111432883411202kk×+×+×−×+×+×= OR 84421133k−− =−− 1k=− 2
  • 5. SULIT 3472/1 3472/1 Additional Mathematics Paper 1 SULIT 5 Question Solution/ Marking Scheme Answer Marks 15 (b) B1 : 5 or 2243+ (a) ji43+ (b) 543ji+ 12 16 B3 : 6201240mORm+=+= B2 : 3360841203m ++=  B1 : 612OB  =   3m=− 4 17 B3 : 418113819xorx=⋅=⋅ B2 : 26sin8sin802sin2sin3xxorxorx−−+= =−= B1 : ()2312sin8sin5xx−=− 418113819xANDx=⋅ =⋅   4 18 (b) B2: ()()()()21112*1.047610.39222− B1: ()()()()21112*1.047610.39222or (a) 1.047rad (b) 44.21 13
  • 6. SULIT 3472/1 3472/1 Additional Mathematics Paper 1 SULIT 6 Question Solution/ Marking Scheme Answer Marks 19 (b) B1: 70118k∗+ = (a) 70 (b) 18k= 12 20 B2 : (1)248h′′=− B1 : 1812)(2+−=′xxxh 16 3 21 B2 : 2823korx−=−= B1 : 28x− 3k= 3 22 B2 : ()() 2203111491515xorx + −−− B1 : ()()2311xhxdxx+ = −∫ 10 3 23 (b) B1: 23235155757or+×−×  (a) 25 (b) 47 12 24 (b) B1 : 435323CCC×× (a) 495 (b) 120 12 25 B2 : p( z>k ) = 0.0608 B1 : P(z > 0. 14) = 0.4443 k = 1.548 3 END OF MARKING SCHEME