Question 4

Question 4 Will the bacteria fill the dish?

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DO NOT MOVE ON UNTIL YOU HAVE ANSWERED THE QUESTION OR YOU NEED HELP!

Things You Should Know ,[object Object],[object Object],[object Object],[object Object]

Population Count (Logs and Exp.) ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]

Population Count (Logs and Exp.) ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]

Population Count (Logs and Exp.) ,[object Object],[object Object],[object Object],[object Object]

Population Count (Logs and Exp.) ,[object Object],[object Object],[object Object],[object Object],[object Object]

Population Count (Logs and Exp.) ,[object Object],You could actually pick ‘log’ instead of ‘ln’ when you take the log of both sides. Both of these are programmed into your calculator. Don’t clear the value from your calculator. The number here is just rounded off but your calculator will store all the decimal places

Population Count (Logs and Exp.) This value is in terms of hours meaning it will take around 35.6151 hours but we want our time in the form Day Hour:Min:Sec. So let’s break this down. The whole number is how many hours there are. There are 35 hours. There are enough hours in here for a day so let’s subtract 24 hours for the day. Now there are 11 hours left. So far we have this: 1 day 11:xx:xx.x Now we should have a decimal value less than one (0.8150803798). This value represents the fraction of an hour we have left. So let’s move down one unit of measurement. The next step down from an hour is a minute. Let’s find out how many minutes this is shall we? * All the value typed out here are rounded off. Do not round off in your calculator. Press [2 nd ][(-)] and Ans will appear on your screen. This means that the last answer you came up with will be used and you keep all the decimal places. 0.8151 hours(60 min/hour)≈48.9048 minutes Now we have 1 day 11:48:xx.x

Population Count (Logs and Exp.) Now we have 1 day 11:48:xx.x. Now we subtract 48 so we are left with the decimal value less than one again (0.9048227887). This value represents the fraction of a minute that we have. So let’s take another step down and go to seconds! *Remember: [2 nd ][(-)] to keep the decimal places! 0.9048(60 seconds/minute)≈54.3 seconds Now we have the complete time to the nearest tenth second: 1 day 11:48:54.3 So how do we find when (date) the population will approximately be 7 billion? We add it to the date it started!

First we convert the time into military time so that we can add it. Next we add the seconds. Now we add the minutes. Remember that there are 60 minutes in an hour so for every 60 minutes, you add 1 to the hours and start back at 0 for the minutes.

Now we add the hours. Remember that there are 24 hours in a day so for every 24 hours, add 1 to the days and start back at 0 for the hours. Next we add the days. Great! So now we have the approximate time at which the population of the bacteria will reach 7 billion. Saturday June 6 at 6:23:58.3 am

Population Count (Logs and Exp.) ,[object Object],[object Object],[object Object]

Population Count (Logs and Exp.) ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]

Population Count (Logs and Exp.) ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]

OH NO! THERE WILL BE A BACTERIAL OVERFLOW!!!!!!!

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