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4.4 Exponential &
     Logarithmic Equations
                      Day 3



Romans 15:13  May the God of hope fill you with
all joy and peace in believing, so that by the power
of the Holy Spirit you may abound in hope.
$2000 is invested at an interest rate of 3.5% per year.
Find the time for the money to double if the interest is
compounded monthly.
$2000 is invested at an interest rate of 3.5% per year.
Find the time for the money to double if the interest is
compounded monthly.
                     nt
         ⎛   r ⎞
   A = P ⎜ 1+ ⎟
         ⎝ n ⎠
$2000 is invested at an interest rate of 3.5% per year.
Find the time for the money to double if the interest is
compounded monthly.
                      nt
          ⎛   r ⎞
    A = P ⎜ 1+ ⎟
          ⎝ n ⎠

                           12t
            ⎛ .035 ⎞
4000 = 2000 ⎜ 1+    ⎟
            ⎝    12 ⎠
$2000 is invested at an interest rate of 3.5% per year.
Find the time for the money to double if the interest is
compounded monthly.
                      nt
          ⎛   r ⎞
    A = P ⎜ 1+ ⎟
          ⎝ n ⎠

                           12t
            ⎛ .035 ⎞
4000 = 2000 ⎜ 1+    ⎟
            ⎝    12 ⎠

                ⎛ .035 ⎞
log 2 = 12t log ⎜ 1+    ⎟
                ⎝    12 ⎠
$2000 is invested at an interest rate of 3.5% per year.
Find the time for the money to double if the interest is
compounded monthly.
                      nt
          ⎛   r ⎞
    A = P ⎜ 1+ ⎟
          ⎝ n ⎠                      log 2
                                                    =t
                                        ⎛ .035 ⎞
                           12t   12 log ⎜ 1+    ⎟
            ⎛ .035 ⎞                  ⎝    12 ⎠
4000 = 2000 ⎜ 1+    ⎟
            ⎝    12 ⎠

                ⎛ .035 ⎞
log 2 = 12t log ⎜ 1+    ⎟
                ⎝    12 ⎠
$2000 is invested at an interest rate of 3.5% per year.
Find the time for the money to double if the interest is
compounded monthly.
                      nt
          ⎛   r ⎞
    A = P ⎜ 1+ ⎟
          ⎝ n ⎠                      log 2
                                                    =t
                                        ⎛ .035 ⎞
                           12t   12 log ⎜ 1+    ⎟
            ⎛ .035 ⎞                  ⎝    12 ⎠
4000 = 2000 ⎜ 1+    ⎟
            ⎝    12 ⎠
                                   t ≈ 19.8 years
                ⎛ .035 ⎞
log 2 = 12t log ⎜ 1+    ⎟
                ⎝    12 ⎠
A sum of money invested at a fixed rate with continuous
compounding tripled in 19 years. Find the rate.
A sum of money invested at a fixed rate with continuous
compounding tripled in 19 years. Find the rate.
                           rt
                  A = Pe
A sum of money invested at a fixed rate with continuous
compounding tripled in 19 years. Find the rate.
                           rt
                  A = Pe
                         19r
                  3 = 1e
A sum of money invested at a fixed rate with continuous
compounding tripled in 19 years. Find the rate.
                           rt
                  A = Pe
                         19r
                  3 = 1e
               ln 3 = 19r ln e
A sum of money invested at a fixed rate with continuous
compounding tripled in 19 years. Find the rate.
                           rt
                  A = Pe
                         19r
                  3 = 1e
               ln 3 = 19r ln e
                   ln 3
                        =r
                   19
A sum of money invested at a fixed rate with continuous
compounding tripled in 19 years. Find the rate.
                           rt
                  A = Pe
                         19r
                   3 = 1e
               ln 3 = 19r ln e
                   ln 3
                        =r
                   19
                  r ≈ 5.8%
If I o and I denote the intensity of light before and
after going through a material, and x is the distance in
feet the light travels in the material, then
                 −1 ⎛ I ⎞
                   ln ⎜ ⎟ = x
                 k ⎝ I o ⎠
where k is a constant depending on the type of material.
If I o and I denote the intensity of light before and
after going through a material, and x is the distance in
feet the light travels in the material, then
                 −1 ⎛ I ⎞
                   ln ⎜ ⎟ = x
                 k ⎝ I o ⎠
where k is a constant depending on the type of material.

            This is the Beer-Lambert Law
If I o and I denote the intensity of light before and
after going through a material, and x is the distance in
feet the light travels in the material, then
                 −1 ⎛ I ⎞
                   ln ⎜ ⎟ = x
                 k ⎝ I o ⎠
where k is a constant depending on the type of material.

            This is the Beer-Lambert Law

                Solve the equation for I
−1 ⎛ I ⎞
  ln ⎜ ⎟ = x
k ⎝ I o ⎠
−1 ⎛ I ⎞
  ln ⎜ ⎟ = x
k ⎝ I o ⎠

   ⎛ I ⎞
ln ⎜ ⎟ = −kx
   ⎝ I o ⎠
−1 ⎛ I ⎞
  ln ⎜ ⎟ = x
k ⎝ I o ⎠

   ⎛ I ⎞
ln ⎜ ⎟ = −kx
   ⎝ I o ⎠

      − kx     I
  e          =
               Io
−1 ⎛ I ⎞
  ln ⎜ ⎟ = x
k ⎝ I o ⎠

   ⎛ I ⎞
ln ⎜ ⎟ = −kx
   ⎝ I o ⎠

      − kx     I
  e          =
               Io
        − kx
 I oe          =I
−1 ⎛ I ⎞
  ln ⎜ ⎟ = x
k ⎝ I o ⎠

   ⎛ I ⎞
ln ⎜ ⎟ = −kx
   ⎝ I o ⎠

      − kx     I
  e          =
               Io
        − kx
 I oe          =I
         or
               − kx
 I = I oe
−1 ⎛ I ⎞
  ln ⎜ ⎟ = x        This is just a variation of
k ⎝ I o ⎠
                                            rt
                              A = Ao e
   ⎛ I ⎞
ln ⎜ ⎟ = −kx                   or
   ⎝ I o ⎠
                                       rt
      − kx     I              y = Pe
  e          =
               Io
        − kx
 I oe          =I     (This is part of Example 10
         or                   on page 364)
               − kx
 I = I oe
HW #9

It is literally true that you can succeed best and
quickest by helping others to succeed.
                                  Napoleon Hill

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0410 ch 4 day 10

  • 1. 4.4 Exponential & Logarithmic Equations Day 3 Romans 15:13  May the God of hope fill you with all joy and peace in believing, so that by the power of the Holy Spirit you may abound in hope.
  • 2. $2000 is invested at an interest rate of 3.5% per year. Find the time for the money to double if the interest is compounded monthly.
  • 3. $2000 is invested at an interest rate of 3.5% per year. Find the time for the money to double if the interest is compounded monthly. nt ⎛ r ⎞ A = P ⎜ 1+ ⎟ ⎝ n ⎠
  • 4. $2000 is invested at an interest rate of 3.5% per year. Find the time for the money to double if the interest is compounded monthly. nt ⎛ r ⎞ A = P ⎜ 1+ ⎟ ⎝ n ⎠ 12t ⎛ .035 ⎞ 4000 = 2000 ⎜ 1+ ⎟ ⎝ 12 ⎠
  • 5. $2000 is invested at an interest rate of 3.5% per year. Find the time for the money to double if the interest is compounded monthly. nt ⎛ r ⎞ A = P ⎜ 1+ ⎟ ⎝ n ⎠ 12t ⎛ .035 ⎞ 4000 = 2000 ⎜ 1+ ⎟ ⎝ 12 ⎠ ⎛ .035 ⎞ log 2 = 12t log ⎜ 1+ ⎟ ⎝ 12 ⎠
  • 6. $2000 is invested at an interest rate of 3.5% per year. Find the time for the money to double if the interest is compounded monthly. nt ⎛ r ⎞ A = P ⎜ 1+ ⎟ ⎝ n ⎠ log 2 =t ⎛ .035 ⎞ 12t 12 log ⎜ 1+ ⎟ ⎛ .035 ⎞ ⎝ 12 ⎠ 4000 = 2000 ⎜ 1+ ⎟ ⎝ 12 ⎠ ⎛ .035 ⎞ log 2 = 12t log ⎜ 1+ ⎟ ⎝ 12 ⎠
  • 7. $2000 is invested at an interest rate of 3.5% per year. Find the time for the money to double if the interest is compounded monthly. nt ⎛ r ⎞ A = P ⎜ 1+ ⎟ ⎝ n ⎠ log 2 =t ⎛ .035 ⎞ 12t 12 log ⎜ 1+ ⎟ ⎛ .035 ⎞ ⎝ 12 ⎠ 4000 = 2000 ⎜ 1+ ⎟ ⎝ 12 ⎠ t ≈ 19.8 years ⎛ .035 ⎞ log 2 = 12t log ⎜ 1+ ⎟ ⎝ 12 ⎠
  • 8. A sum of money invested at a fixed rate with continuous compounding tripled in 19 years. Find the rate.
  • 9. A sum of money invested at a fixed rate with continuous compounding tripled in 19 years. Find the rate. rt A = Pe
  • 10. A sum of money invested at a fixed rate with continuous compounding tripled in 19 years. Find the rate. rt A = Pe 19r 3 = 1e
  • 11. A sum of money invested at a fixed rate with continuous compounding tripled in 19 years. Find the rate. rt A = Pe 19r 3 = 1e ln 3 = 19r ln e
  • 12. A sum of money invested at a fixed rate with continuous compounding tripled in 19 years. Find the rate. rt A = Pe 19r 3 = 1e ln 3 = 19r ln e ln 3 =r 19
  • 13. A sum of money invested at a fixed rate with continuous compounding tripled in 19 years. Find the rate. rt A = Pe 19r 3 = 1e ln 3 = 19r ln e ln 3 =r 19 r ≈ 5.8%
  • 14. If I o and I denote the intensity of light before and after going through a material, and x is the distance in feet the light travels in the material, then −1 ⎛ I ⎞ ln ⎜ ⎟ = x k ⎝ I o ⎠ where k is a constant depending on the type of material.
  • 15. If I o and I denote the intensity of light before and after going through a material, and x is the distance in feet the light travels in the material, then −1 ⎛ I ⎞ ln ⎜ ⎟ = x k ⎝ I o ⎠ where k is a constant depending on the type of material. This is the Beer-Lambert Law
  • 16. If I o and I denote the intensity of light before and after going through a material, and x is the distance in feet the light travels in the material, then −1 ⎛ I ⎞ ln ⎜ ⎟ = x k ⎝ I o ⎠ where k is a constant depending on the type of material. This is the Beer-Lambert Law Solve the equation for I
  • 17. −1 ⎛ I ⎞ ln ⎜ ⎟ = x k ⎝ I o ⎠
  • 18. −1 ⎛ I ⎞ ln ⎜ ⎟ = x k ⎝ I o ⎠ ⎛ I ⎞ ln ⎜ ⎟ = −kx ⎝ I o ⎠
  • 19. −1 ⎛ I ⎞ ln ⎜ ⎟ = x k ⎝ I o ⎠ ⎛ I ⎞ ln ⎜ ⎟ = −kx ⎝ I o ⎠ − kx I e = Io
  • 20. −1 ⎛ I ⎞ ln ⎜ ⎟ = x k ⎝ I o ⎠ ⎛ I ⎞ ln ⎜ ⎟ = −kx ⎝ I o ⎠ − kx I e = Io − kx I oe =I
  • 21. −1 ⎛ I ⎞ ln ⎜ ⎟ = x k ⎝ I o ⎠ ⎛ I ⎞ ln ⎜ ⎟ = −kx ⎝ I o ⎠ − kx I e = Io − kx I oe =I or − kx I = I oe
  • 22. −1 ⎛ I ⎞ ln ⎜ ⎟ = x This is just a variation of k ⎝ I o ⎠ rt A = Ao e ⎛ I ⎞ ln ⎜ ⎟ = −kx or ⎝ I o ⎠ rt − kx I y = Pe e = Io − kx I oe =I (This is part of Example 10 or on page 364) − kx I = I oe
  • 23. HW #9 It is literally true that you can succeed best and quickest by helping others to succeed. Napoleon Hill

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