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Volumes by Cylindrical Shells
The volume of a right circular cylindrical shell with radius r, height h,
and infinitesimal thickness dx, is given by:

Vshell = 2πrh dx
If one slits the cylinder down a side and unrolls it into a rectangle,
the height of the rectangle is the height of the cylinder, h, and the
length of the rectangle is the circumference of a circular end of
the cylinder, 2πr. So the area of the rectangle (and the surface of
the cylinder) is 2πrh. Multiply this by a (slight) thickness dx to get
the volume.
In the diagram, the yellow region is revolved about the
y-axis. Two of the shells are shown. For each value of x
between 0 and a (in the graph), a cylindrical shell is
obtained, with radius x and height f(x). Thus, the
volume of one of these shells (with thickness dx) is given
by

Vshell = 2π x f(x) dx.
Summing up the volumes of all these
infinitely thin shells, we get the total volume
of the solid of revolution:

V=

a

a

0

0

ĂČ 2p xf (x)dx = 2p ĂČ xf (x)dx
Example 1: Find the volume of the solid of revolution formed
by rotating the region bounded by the x-axis and the graph of
y = x from x=0 to x=1, about the y-axis.

Ăč
V = ĂČ 2p x x dx = 2p ĂČ x dx = 2p × 2x Ăș =
1
0
5 Ăș
Ăș0
1
Ă»
5
5 öĂč
4p
4p ĂŠ 2
ç1 - 0 2 Ă·Ăș =
5
5 Ăš
ĂžĂș0
Ă»
2

1

3
2

5 1
2
Example 2: Find the volume of the solid of revolution formed by
rotating the finite region bounded by the graphs of
y = x -1
2
and y = ( x -1) about the y-axis.
2

V = ĂČ 2p x
1

(

x -1 - ( x -1)

2

)

2
ĂŠ2
ö
2
dx = 2p ç ĂČ x x -1 dx - ĂČ x ( x -1) dx Ă· =
Ăš1
Ăž
1

ĂŠ
ö
2
2p ç ĂČ ( u +1) u du - ĂČ ( u +1) u duĂ· =
Ăš
Ăž
Ê Ê 3 1ö
ö
3
2
2p ç ĂČ Ă§ u 2 + u 2 Ă· du - ĂČ ( u + u ) duĂ· =
ç
Ă·
Ăš
Ăž
Ăš
Ăž

u = x – 1 so x = u + 1
du = dx
3
Ă© 5
Ăč
4
3
2
2
ĂȘ 2u 2u u u Ăș
2p ĂȘ
+
- - Ăș=
5
3
4 3
ĂȘ
Ăș
Ă«
Ă»

5
3
Ă©
4
3Ăč
2
2
ĂȘ 2 ( x -1) + 2 ( x -1) - ( x -1) - ( x -1) Ăș =
2p
ĂȘ
5
3
4
3 Ăș
ĂȘ
Ăș1
Ă«
Ă»
2

Ă© 2 2 1 1Ăč
29 29p
=
2p ĂȘ + - - Ăș = 2p
60 30
Ă« 5 3 4 3Ă»
Time to Practice !!!
EXAMPLE Find the volume of the solid
obtained by rotating the region bounded by
y = x - x 2 and y = 0 about the line x = 2 .
One More Example

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7.3 volumes by cylindrical shells

  • 2. The volume of a right circular cylindrical shell with radius r, height h, and infinitesimal thickness dx, is given by: Vshell = 2πrh dx If one slits the cylinder down a side and unrolls it into a rectangle, the height of the rectangle is the height of the cylinder, h, and the length of the rectangle is the circumference of a circular end of the cylinder, 2πr. So the area of the rectangle (and the surface of the cylinder) is 2πrh. Multiply this by a (slight) thickness dx to get the volume.
  • 3. In the diagram, the yellow region is revolved about the y-axis. Two of the shells are shown. For each value of x between 0 and a (in the graph), a cylindrical shell is obtained, with radius x and height f(x). Thus, the volume of one of these shells (with thickness dx) is given by Vshell = 2π x f(x) dx.
  • 4. Summing up the volumes of all these infinitely thin shells, we get the total volume of the solid of revolution: V= a a 0 0 ĂČ 2p xf (x)dx = 2p ĂČ xf (x)dx
  • 5. Example 1: Find the volume of the solid of revolution formed by rotating the region bounded by the x-axis and the graph of y = x from x=0 to x=1, about the y-axis. Ăč V = ĂČ 2p x x dx = 2p ĂČ x dx = 2p × 2x Ăș = 1 0 5 Ăș Ăș0 1 Ă» 5 5 öĂč 4p 4p ĂŠ 2 ç1 - 0 2 Ă·Ăș = 5 5 Ăš ĂžĂș0 Ă» 2 1 3 2 5 1 2
  • 6. Example 2: Find the volume of the solid of revolution formed by rotating the finite region bounded by the graphs of y = x -1 2 and y = ( x -1) about the y-axis.
  • 7. 2 V = ĂČ 2p x 1 ( x -1 - ( x -1) 2 ) 2 ĂŠ2 ö 2 dx = 2p ç ĂČ x x -1 dx - ĂČ x ( x -1) dx Ă· = Ăš1 Ăž 1 ĂŠ ö 2 2p ç ĂČ ( u +1) u du - ĂČ ( u +1) u duĂ· = Ăš Ăž ĂŠ ĂŠ 3 1ö ö 3 2 2p ç ĂČ Ă§ u 2 + u 2 Ă· du - ĂČ ( u + u ) duĂ· = ç Ă· Ăš Ăž Ăš Ăž u = x – 1 so x = u + 1 du = dx 3 Ă© 5 Ăč 4 3 2 2 ĂȘ 2u 2u u u Ăș 2p ĂȘ + - - Ăș= 5 3 4 3 ĂȘ Ăș Ă« Ă» 5 3 Ă© 4 3Ăč 2 2 ĂȘ 2 ( x -1) + 2 ( x -1) - ( x -1) - ( x -1) Ăș = 2p ĂȘ 5 3 4 3 Ăș ĂȘ Ăș1 Ă« Ă» 2 Ă© 2 2 1 1Ăč 29 29p = 2p ĂȘ + - - Ăș = 2p 60 30 Ă« 5 3 4 3Ă»
  • 8. Time to Practice !!! EXAMPLE Find the volume of the solid obtained by rotating the region bounded by y = x - x 2 and y = 0 about the line x = 2 .