2. The volume of a right circular cylindrical shell with radius r, height h,
and infinitesimal thickness dx, is given by:
Vshell = 2Ïrh dx
If one slits the cylinder down a side and unrolls it into a rectangle,
the height of the rectangle is the height of the cylinder, h, and the
length of the rectangle is the circumference of a circular end of
the cylinder, 2Ïr. So the area of the rectangle (and the surface of
the cylinder) is 2Ïrh. Multiply this by a (slight) thickness dx to get
the volume.
3. In the diagram, the yellow region is revolved about the
y-axis. Two of the shells are shown. For each value of x
between 0 and a (in the graph), a cylindrical shell is
obtained, with radius x and height f(x). Thus, the
volume of one of these shells (with thickness dx) is given
by
Vshell = 2Ï x f(x) dx.
4. Summing up the volumes of all these
infinitely thin shells, we get the total volume
of the solid of revolution:
V=
a
a
0
0
ĂČ 2p xf (x)dx = 2p ĂČ xf (x)dx
5. Example 1: Find the volume of the solid of revolution formed
by rotating the region bounded by the x-axis and the graph of
y = x from x=0 to x=1, about the y-axis.
Ăč
V = ĂČ 2p x x dx = 2p ĂČ x dx = 2p Ă 2x Ăș =
1
0
5 Ăș
Ăș0
1
Ă»
5
5 öĂč
4p
4p ĂŠ 2
ç1 - 0 2 Ă·Ăș =
5
5 Ăš
ĂžĂș0
Ă»
2
1
3
2
5 1
2
6. Example 2: Find the volume of the solid of revolution formed by
rotating the finite region bounded by the graphs of
y = x -1
2
and y = ( x -1) about the y-axis.