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taylor’s series
taylor’s series

 If f(z) is a complex function analytic inside & on a simple
  closed curve C (usually a circle) in the z-plane, then the higher
  derivatives of f(z) also exist inside C. If z0 & z0+h are two
  fixed points inside C then…..


F(z0+h) = f(z0) + hf (1) (z0) + h2/2! f (2) (z0)
  +…..+ hn /n! f (n) (z0)+….
Where f(k)(z0) is the kth derivative of f(z) at z=z0
taylor’s series

Putting z0+h=z, the series becomes….


F(z) = f(z0) + (z-z0) f (1) (z0) + (z-z0)2/2! f (2) (z0) +
  …..+ (z-z0)n /n! f n (z0) +…….
   =               f (n) (z0).

This series is known as Taylor’s series expansion of f(z) about
 z=z0.The radius of converges of this series is | z – z0 | < R, a
 disk centered on z=z0 & of radius R.
taylor’s series

When z0=0, in previous equation then we get,


F(z) = f(0) + zf (1) (0) + z2/2! f (2) (0) +…..+ zn/n!
  f (n) (0) +…..

  The obtained series is Maclaurin’s Series expansion, In the
  case of function of real variables.
taylor’s series

 Some Standard power series expansion :-

1.                ;|z|<∞

2.                         ;|z|<∞



3.                         ;|z|<∞
taylor’s series


4.                       ;|z|<∞



5.                      ;|z|<∞



6. (Geometric Series)
taylor’s series


7.                            ;|z|<1


                      ;|z|<1

8. ( Binomial series for any positive integer m )

                                    ;|z|<1
taylor’s series

Illustration 5.2: Find the Taylor’s series expansion of
   f(z)=a/(bz+c) about z=z0. Also determine about the region of
   convergence.



Illustration 5.3: Determine the Taylor’s series expansion of the
   function f(z)=1/z( z - 2i ) above the point z=i.
  (a)directly upto the term (z – i)4 , (b) using the binomial
   expansion. Also determine about the radius of convergence.
taylor’s series

Illustration 5.4: Find the Taylor’s series expansion of f(z) = 1/( z2
   - z – 6 ) about z=1.




Illustration 5.5: Expand f(z) = (z - 1)/(z + 1) as Taylor’s series
  (a) about the point z=0 , and (b) about the point z=1.
   determine also the result the radius of convergence.
taylor’s series

Illustration 5.6: (Geometric series) Expand f(z) = 1/(1 – z).




Illustration 5.7: Find the Maclaurin’s series of ln[(1 + z)/(1 – z)].




Illustration 5.8: Find the Maclaurin’s series of f(z) = 1/(1 – z2).
taylor’s series

Illustration 5.9: Find the Maclaurin’s series of f(Z) = tan-1 z.



Illustration 5.10: (Development by using the geometric series)
   Develop 1/(c – z) in powers of z – z0, where c – z0 ≠ 0.



Illustration 5.11: (Reduction by partial fractions) Find the

  Taylor’s series of f(z)=                      with center z0 = 1.
taylor’s series


Illustration 5.12: Develop f(z) = sin2 z in a Maclaurin’s series and
   find the radius of convergence.




Note: This example can also be solved using the formula
  sin2 z = ( 1 – cos2z) / 2 & then using the standard power series
  expansion for cos z with z replaced by 2z.
taylor’s series

 In the above discussion of power series and in particular
  Taylor’s series with illustrations, we have seen that inside the
  radius of convergence, the given function and its Taylor’s
  series expansion are identically equal. Now the points at which
  a function fails to be analytic are called Singularities.

 No Taylor’s series exp. Is possible about singularity.
  So, Taylor’s exp. About a point z0, at which a function is
  analytic is only valid within a circle centered z0.

 Thus all the singularities must be excluded in Taylor’s
  Expansion.
Thank you


            Prepared By
       BHARGAV GODHANI

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Taylor’s series

  • 2. taylor’s series  If f(z) is a complex function analytic inside & on a simple closed curve C (usually a circle) in the z-plane, then the higher derivatives of f(z) also exist inside C. If z0 & z0+h are two fixed points inside C then….. F(z0+h) = f(z0) + hf (1) (z0) + h2/2! f (2) (z0) +…..+ hn /n! f (n) (z0)+…. Where f(k)(z0) is the kth derivative of f(z) at z=z0
  • 3. taylor’s series Putting z0+h=z, the series becomes…. F(z) = f(z0) + (z-z0) f (1) (z0) + (z-z0)2/2! f (2) (z0) + …..+ (z-z0)n /n! f n (z0) +……. = f (n) (z0). This series is known as Taylor’s series expansion of f(z) about z=z0.The radius of converges of this series is | z – z0 | < R, a disk centered on z=z0 & of radius R.
  • 4. taylor’s series When z0=0, in previous equation then we get, F(z) = f(0) + zf (1) (0) + z2/2! f (2) (0) +…..+ zn/n! f (n) (0) +….. The obtained series is Maclaurin’s Series expansion, In the case of function of real variables.
  • 5. taylor’s series  Some Standard power series expansion :- 1. ;|z|<∞ 2. ;|z|<∞ 3. ;|z|<∞
  • 6. taylor’s series 4. ;|z|<∞ 5. ;|z|<∞ 6. (Geometric Series)
  • 7. taylor’s series 7. ;|z|<1 ;|z|<1 8. ( Binomial series for any positive integer m ) ;|z|<1
  • 8. taylor’s series Illustration 5.2: Find the Taylor’s series expansion of f(z)=a/(bz+c) about z=z0. Also determine about the region of convergence. Illustration 5.3: Determine the Taylor’s series expansion of the function f(z)=1/z( z - 2i ) above the point z=i. (a)directly upto the term (z – i)4 , (b) using the binomial expansion. Also determine about the radius of convergence.
  • 9. taylor’s series Illustration 5.4: Find the Taylor’s series expansion of f(z) = 1/( z2 - z – 6 ) about z=1. Illustration 5.5: Expand f(z) = (z - 1)/(z + 1) as Taylor’s series (a) about the point z=0 , and (b) about the point z=1. determine also the result the radius of convergence.
  • 10. taylor’s series Illustration 5.6: (Geometric series) Expand f(z) = 1/(1 – z). Illustration 5.7: Find the Maclaurin’s series of ln[(1 + z)/(1 – z)]. Illustration 5.8: Find the Maclaurin’s series of f(z) = 1/(1 – z2).
  • 11. taylor’s series Illustration 5.9: Find the Maclaurin’s series of f(Z) = tan-1 z. Illustration 5.10: (Development by using the geometric series) Develop 1/(c – z) in powers of z – z0, where c – z0 ≠ 0. Illustration 5.11: (Reduction by partial fractions) Find the Taylor’s series of f(z)= with center z0 = 1.
  • 12. taylor’s series Illustration 5.12: Develop f(z) = sin2 z in a Maclaurin’s series and find the radius of convergence. Note: This example can also be solved using the formula sin2 z = ( 1 – cos2z) / 2 & then using the standard power series expansion for cos z with z replaced by 2z.
  • 13. taylor’s series  In the above discussion of power series and in particular Taylor’s series with illustrations, we have seen that inside the radius of convergence, the given function and its Taylor’s series expansion are identically equal. Now the points at which a function fails to be analytic are called Singularities.  No Taylor’s series exp. Is possible about singularity. So, Taylor’s exp. About a point z0, at which a function is analytic is only valid within a circle centered z0.  Thus all the singularities must be excluded in Taylor’s Expansion.
  • 14. Thank you Prepared By BHARGAV GODHANI