IE TECHNICAL TRAINING

2. ON IE

3. Discussion topics/ Av
‡
j v
P
¨ w
el q:
 Efficiency/Kg©
`¶Zvw
K?
 How can you calculate Target?
 How can you balance the line?
 How can you calculate capacity of
an operator?

4. •Efficiency Gi mv‡_ Manpower, Production I Time Gi
m¤úK©
•How can you increase/Efficiency wKfv‡e e„w× Kiv hvq ?
What is SMV???
Standard time of a average worker will take to do a job.
In idle environment in predetermined speed a general
operator needs time to do a process.

5. SMV=Standard Minute Value
SMV = Cycle time + allowances
Allowances = personal + machine+ bundle handling
Personal 2%
Machine O/L = 10%, SN = 3%, FL = 8%
Bundle = 2%

6. GKRb kªwgK Gi mvavib Kv‡Ri MwZ‡K 100% †iwUs wnmv‡e MY¨ Kiv nq|
hw` †Kvb kªwgK mvfvweK MwZi †Pq axi MwZ‡Z KvR m¤cbœ K‡i Zvn‡j
Zvi †iwUs 100% Gi †P‡q Kg A_©vr 90% ev
% n‡Z cv‡i|
hw` †Kvb kªwgK mvfvweK MwZi †Pq `ª“Z MwZ‡Z KvR m¤cbœ K‡i Zvn‡j
Zvi †iwUs 100% Gi †P‡q †ewk A_v©r 110% ev
% n‡Z cv‡i|

7. Pick up Sewing
Dispose
Cycle Time

8.  Mv‡g©›Um
†Zvjv
 Ae¯’vb wVK Kiv
 mvRv‡
bv
 †mjvB Kiv
 myZv
KvUv
 †i‡L †`qv
mvB‡Kj UvBg
Pick-up
Position
ing
Aligning
Sewing
Trimmin
g
Dispose

9. Gm,Gg,wf MYbv
mvB‡Kj UvBg = 36, 42, 39,36, 39 sec
= 192 sec =192/60 min =3.2 min cÖvß mgq = 3.2 / 5
= 0.64
†iwUs = 85%
†ewmK UvBg = cÖvß mgq x †iwUs
= 0.64 X 85/100
= 0.54
Gm,Gg,wf = †ewmK UvBg + AwZwi³ mgq

10. = 0.54+15%
= 0.54+(0.54
15/100)
= 0.54+ (0.54*0.15)
= 0.54(1+0.15) =0.54*1.15
= 0.62
wK Kvi‡b AwZwi³ mgq †`qv
nq
cvwb LvIqv
ev_i“g G hvIqv
Kv‡Ri GK‡N‡qwg `~i Kiv
†gwkb mgm¨v

11. myZv †K‡U hvIqv
ev‡Ûj †Lvjv I eÜ Kiv BZvw`
wK Kvi‡b AwZwi³ mgq †`qv nq

12. How can you calculate efficiency?
Efficiency = hv Kv‡R jvMv‡bv
n†”Qhv
Av‡Q
X 100

13. Efficiency
Output x SMV
Efficiency =
Total M/P x W/H x 60
SMV = 1wcP Output Gi Rb¨ †h mgq jv‡M
Example, Bella Hipster
X 100%

14. 2000 x 7.07
Efficiency =
32 x 11 x 60
14140
=
21120
X
100%
= 0.6695 X 100%
= 66.95%
X
100%

15. Efficiency Gi mv‡_ m¤úwK©Z
Output evo‡j Efficiency ev‡o
Manpower Kg‡j Efficiency ev‡o
Time Kg‡j Efficiency ev‡o
We can handle
Output/Total Production

16. Manpower/(Operator+Helper)
Working Hour

17. GOOD
EFFICIENCY
MAN
POWER
WORKING
HOUR
SMV
OUTPUT

18. How????
 Output
Condition 01:
Let output=1400
,SMV=8.0,Manpower =35, Working
hour=10 Then
Efficiency=(1400 x 8 x 100)/(35 x 10 x 60)
=53 %
Condition 02:
Let output=2000
,SMV=8.0,Manpower =35, Working
hour=10 Then
Efficiency=(2000 x 8 x 100)/(35 x 10 x 60)
=76 %
Out put increase efficiency ????
Out put decrease efficiency???

19. Manpower
Let output=1400,SMV=8.0,Manpower
=35,
Working hour=10 Then
Efficiency=(1400 x 8 x 100)/(35 x 10 x 60)
=53%
Condition 02:
Let output=1400,SMV=8.0,Manpower=28,
Working hour=10 Then

20. Efficiency=(1400 x 8 x 100)/(28 x 10 x 60)
=67%
Manpower increase efficiency ???
Manpower decrease efficiency ???
Working hours
Let output=1400,SMV=8.0,Manpower =35, Working
hour=10 Then
Efficiency=(1400 x 8 x 100)/(35 x 10 x 60)
=53%
Condition 02:
Let output=1400,SMV=8.0,Manpower =35,
Working hour=8 Then

21. Efficiency=(1400 x 8 x 100)/(35 x 8 x 60)
=67%
Working time increase efficiency ???
Working time decrease efficiency ???

22. GOOD
EFFICIENCY
MAN
POWER
????????
WORKING
HOUR
???????
SMV
Unchanged
OUTPUT ??????

23. You can check mobile stop watch& easily calculate…..
How many minutes makes One Hour?
1 Hour = ……………..Minutes?
 How many seconds makes a minutes?
1 Minutes=………….Seconds?

24. TARGET CALCULATION
TARGET FOR A LINE = M/P X W/H X 60
SMV
SUPPOSE, LINE 25+26 (MIKE BOXER)
SMV=5.97, W/H=11,M/P=26
SO…. TARGET AT 100% EFF = (60/5.97) X 11 X 26
=2874 PCS
TARGET AT 55% EFF = 2874 X 0.55=1581 PCS

25. Capacity
If a worker takes 1 min to complete a
process then how many pieces he/she
can complete in an hour?
Answer:60 Pcs????? 30Pcs???
If a worker takes 30 sec complete a
process then how many pieces he/she
can complete in an hour?
Answer:120Pcs???? 200 Pcs???

26. Bottleneck?
Capacity
190 197
98
200 195
0
100
200
300
Rehen maksud Nazma Niha Selina

27. Capacity
190
197
196
200
195
184
186
188
190
192
194
196
198
200
202
Rehana Maksuda Nazma+Kajol Nihar Selina

29. Feeding report Line-37+38 L-25+26
450
1200
1800 2000 2000 2000 2000 2000 2000
450
800
1600
2000 2000 2000 2000 2000 2000
0
1000
2000
3000
4000
5000
1st 2nd 3rd 4th 5th 6th 7th 8th 9th
Capacity
Day
1
st
output time for L 25+ 26
- = 3.5 hrs 1st output time for L-37+38=3.9 hrs

30. ?
?
?
Loss Time Report
L-1-Machine problem
L-10-Elastic N/A
L-15-Label problem
L-25-Input problem
L-33-Quality problem
L-38-Air problem
L-23-Meeting
L-1-Power problem
L-4-Manpower problem
L-2-Merchendiser problem

31. How can You Report?
L-3+4
M/c problem
2.5 hr
Flat lock machine
Process: Leg Hem 28

32. WHICH 1 IS BETTER???
150
90
90
150
Output Output

33. Question
?
?
?

34. Thank You