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Basic quantity is defined as a quantity which  cannot be derived from any physical quantities ,[object Object],[object Object],cd candela Luminous Intensity mol mole N Amount of substance A ampere I Electric current K kelvin T/  Temperature s second t Time kg kilogram m Mass m metre l Length Symbol SI Unit Symbol Quantity
d.  29 cm = ? in e.  12 mi h -1  = ? m s -1
Learning Outcome: At the end of this chapter, students should be able to:  ,[object Object],[object Object]
Dimensional Analysis ,[object Object],[object Object],[object Object],[object Object],mole N [amount of substance] or [ N ] K  [temperature] or [ T ] A A @ I [electric current] or [ I ] s T [time] or [ t ] m L [length] or [ l ] kg M [mass] or [ m ] Unit Symbol  [Basic Quantity]
[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],Dimension on the L.H.S. = Dimension on the R.H.S
Determine a dimension and the S.I. unit for the following quantities: a. Velocity b. Acceleration c. Linear momentum d. Density e. Force Solution : a. The S.I. unit of velocity is  m s  1 . Example 1.2 : or
b. Its unit is  m s  2 . d. S.I. unit :  kg m  3 . c. S.I. unit :  kg m s  1 . e. S.I. unit :  kg m s  2 .
Determine Whether the following expressions are dimensionally correct or not. a.   where  s ,  u ,  a  and  t  represent the displacement, initial velocity, acceleration and the time of an object respectively.  b.   where  t ,  u ,  v  and  g  represent the time, initial velocity, final velocity and the gravitational acceleration respectively.  c.   where  f ,  l  and  g  represent the frequency of a  simple pendulum , length of the simple pendulum and the gravitational acceleration respectively.  Example 1.3 :
Solution : a. Dimension on the LHS  : Dimension on the RHS : Dimension on the LHS = dimension on the RHS  Hence the equation above is  homogeneous  or  dimensionally correct. b. Dimension on the LHS  :  Dimension on the RHS : Thus Therefore the equation above is  not homogeneous  or  dimensionally  incorrect. and and
Solution : c. Dimension on the LHS  : Dimension on the RHS : Therefore the equation above is  homogeneous  or  dimensionally  correct.
The period,  T  of a simple pendulum depends on its length  l ,  acceleration due to gravity,  g  and mass,  m . By using dimensional analysis,  obtain an equation for period of the simple pendulum. Solution : Suppose that : Then where  k ,  x ,  y  and  z  are dimensionless constants. Example 1.4 : ………………… (1)
By equating the indices on the left and right sides of the equation, thus By substituting eq. (3) into eq. (2), thus Replace the value of  x ,  y  and  z  in eq. (1), therefore The value of  k  can be determined experimentally. ………………… (2) ………………… (3)
Determine the unit of    in term of basic unit by using the equation below: where  P i  and  P o  are pressures of the air bubble and  R  is the radius of the bubble. Solution : Example 1.5 :
Since    thus Therefore the unit of    is  kg s -2
[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],Exercise 1.1 :
[object Object],[object Object],[object Object],[object Object],[object Object],Exercise 1.1 :
[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],Exercise 1.1 :
 
 

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C1h2

  • 1.
  • 2. d. 29 cm = ? in e. 12 mi h -1 = ? m s -1
  • 3.
  • 4.
  • 5.
  • 6. Determine a dimension and the S.I. unit for the following quantities: a. Velocity b. Acceleration c. Linear momentum d. Density e. Force Solution : a. The S.I. unit of velocity is m s  1 . Example 1.2 : or
  • 7. b. Its unit is m s  2 . d. S.I. unit : kg m  3 . c. S.I. unit : kg m s  1 . e. S.I. unit : kg m s  2 .
  • 8. Determine Whether the following expressions are dimensionally correct or not. a. where s , u , a and t represent the displacement, initial velocity, acceleration and the time of an object respectively. b. where t , u , v and g represent the time, initial velocity, final velocity and the gravitational acceleration respectively. c. where f , l and g represent the frequency of a simple pendulum , length of the simple pendulum and the gravitational acceleration respectively. Example 1.3 :
  • 9. Solution : a. Dimension on the LHS : Dimension on the RHS : Dimension on the LHS = dimension on the RHS Hence the equation above is homogeneous or dimensionally correct. b. Dimension on the LHS : Dimension on the RHS : Thus Therefore the equation above is not homogeneous or dimensionally incorrect. and and
  • 10. Solution : c. Dimension on the LHS : Dimension on the RHS : Therefore the equation above is homogeneous or dimensionally correct.
  • 11. The period, T of a simple pendulum depends on its length l , acceleration due to gravity, g and mass, m . By using dimensional analysis, obtain an equation for period of the simple pendulum. Solution : Suppose that : Then where k , x , y and z are dimensionless constants. Example 1.4 : ………………… (1)
  • 12. By equating the indices on the left and right sides of the equation, thus By substituting eq. (3) into eq. (2), thus Replace the value of x , y and z in eq. (1), therefore The value of k can be determined experimentally. ………………… (2) ………………… (3)
  • 13. Determine the unit of  in term of basic unit by using the equation below: where P i and P o are pressures of the air bubble and R is the radius of the bubble. Solution : Example 1.5 :
  • 14. Since thus Therefore the unit of  is kg s -2
  • 15.
  • 16.
  • 17.
  • 18.  
  • 19.