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WHAT IS VEDIC MATHS Vedic mathematics is the name given to the ancient system of mathematics which was rediscovered from the Vedas. It’s a unique technique of calculations based on simple principles and rules, with which any mathematical problem - be it arithmetic, algebra, geometry or trigonometry can be solved mentally.
WHY VEDIC MATHS ,[object Object]
It reduces burden (Need to learn tables up to nine only)
It provides one line answer.
It is a magical tool to reduce scratch work and finger   counting.
It increases concentration.
 Time saved can be used to answer more questions.
Improves concentration.
Logical thinking process gets enhanced.,[object Object],[object Object]
SQUARING OF NUMBERS  ENDING WITH 5 Conventional Method 65 X 65   6 5 X 6 5  3 2 5 3 9 0 X  4 2 2 5 ,[object Object],65 X 65 = 4225 ( 'multiply the previous digit 6 by one more than itself 7. Than write 25 )
NIKHILAM NAVATASHCARAMAM DASHATH ,[object Object],The Sutra (formula) NIKHILAM NAVATAS’CHARAMAM DASATAH  means : “all from 9 and the last from 10”
I : . CASE1 .WHEN BOTH THE NUMBERS  ARE LOWER THAN THE BASE ,[object Object], 	 97		3  X 94		6 9 1 1 8                  Conventional Method 97 X 94   9 7 X 9 4  3 8 8 8 7 3 X   9 1 1 8
Case ( ii) : When both the numbers are higher than the base Conventional Method 103 X 105    103 X 105  5 1 5             0 0 0 X  1 0 3 X X 1 0, 8 1 5 ,[object Object],For Example103 X 105  	 103	3  X 105	5 1 0, 8 1 5
Case III: When one number is more and the other is less than the base. Conventional Method 103 X 98    103 X   98   8 2 4 9 2 7 X 1 0, 0 9 4 ,[object Object], 	 103	 3  X   98 	-2 1 0, 0 9 4
ĀNURŨPYENA The Sutra (formula) ĀNURŨPYENA means : 'proportionality '  or  'similarly '  ,[object Object],[object Object]
ĀNURŨPYENA Conventional Method 58 X 48    5 8 X 4 8  4 6 4 2 4  2 X  2  8  8 4 ,[object Object], 	 	58	 8  X 	48	-2 2 8 8 4
URDHVA TIRYAGBHYAM The Sutra (formula)  	URDHVA TIRYAGBHYAM 	means : “Vertically and cross wise”  ,[object Object],[object Object]
Step 2: 7×2 + 5×3 = 14+15=29, add to it previous carry over value 1, so we have 30, now write down 0 and carry 3
Step 3: 7×3=21, add previous carry over value of 3 to get 24, write it down.
So we have 2400 as the answer.,[object Object]
Three digit multiplication byURDHVA TIRYAGBHYAM ,[object Object],   103 X 105  1 0, 8 1 5
YAVDUNAM TAAVDUNIKRITYA VARGANCHA YOJAYET This sutra means whatever the extent of its deficiency, lessen it still further to that very extent; and also set up the square of that deficiency.  ,[object Object],[object Object]
 Since 98 is 2 less than 100, we call 2 as the deficiency.
 Decrease the given number further by an amount equal to the deficiency. i.e., perform ( 98 -2 ) = 96. This is the left side of our answer!!.
 On the right hand side put the square of the deficiency, that is square of 2 = 04.
 Append the results from step 4 and 5 to get the result. Hence the answer is 9604.98 2	=    9604 Note   :	While calculating step 5, the number of digits in the squared number (04)  	should be equal to number of zeroes in the base(100).
YAVDUNAM TAAVDUNIKRITYA VARGANCHA YOJAYET  ,[object Object]
 Since 103 is 3 more than 100 (base), we call 3 as the surplus.
 Increase the given number further by an amount equal to the surplus. i.e., perform ( 103 + 3 ) = 106. This is the left side of our answer!!.
 On the right hand side put the square of the surplus, that is square of 3 = 09.

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Vedic maths

  • 1.
  • 2. WHAT IS VEDIC MATHS Vedic mathematics is the name given to the ancient system of mathematics which was rediscovered from the Vedas. It’s a unique technique of calculations based on simple principles and rules, with which any mathematical problem - be it arithmetic, algebra, geometry or trigonometry can be solved mentally.
  • 3.
  • 4. It reduces burden (Need to learn tables up to nine only)
  • 5. It provides one line answer.
  • 6. It is a magical tool to reduce scratch work and finger counting.
  • 8. Time saved can be used to answer more questions.
  • 10.
  • 11.
  • 12.
  • 13.
  • 14.
  • 15.
  • 16.
  • 17.
  • 18.
  • 19. Step 2: 7×2 + 5×3 = 14+15=29, add to it previous carry over value 1, so we have 30, now write down 0 and carry 3
  • 20. Step 3: 7×3=21, add previous carry over value of 3 to get 24, write it down.
  • 21.
  • 22.
  • 23.
  • 24. Since 98 is 2 less than 100, we call 2 as the deficiency.
  • 25. Decrease the given number further by an amount equal to the deficiency. i.e., perform ( 98 -2 ) = 96. This is the left side of our answer!!.
  • 26. On the right hand side put the square of the deficiency, that is square of 2 = 04.
  • 27. Append the results from step 4 and 5 to get the result. Hence the answer is 9604.98 2 = 9604 Note : While calculating step 5, the number of digits in the squared number (04) should be equal to number of zeroes in the base(100).
  • 28.
  • 29. Since 103 is 3 more than 100 (base), we call 3 as the surplus.
  • 30. Increase the given number further by an amount equal to the surplus. i.e., perform ( 103 + 3 ) = 106. This is the left side of our answer!!.
  • 31. On the right hand side put the square of the surplus, that is square of 3 = 09.
  • 32. Append the results from step 4 and 5 to get the result.Hence the answer is 10609.103 2 = 10609 Note :while calculating step 5, the number of digits in the squared number (09) should be equal to number of zeroes in the base(100).
  • 33. YAVDUNAM TAAVDUNIKRITYA VARGANCHA YOJAYET 1009 2 = 1018081
  • 34.
  • 35.
  • 36.
  • 37.
  • 39.
  • 40. The simple point to remember is to multiply each product by 10, 100, 1000, - - as the case may be .
  • 41.
  • 42.
  • 43.
  • 44. Similarly eliminate y and retain x and z and factorize the quadratic in x and z.
  • 45.
  • 46. Similarly eliminate y and retain x and z and factorize the quadratic in x and z.
  • 47.