Quadratic applications ver b

Quadratic Applications Maximum and Minimum values of Quadratic Functions

h=initial height, v=initial velocity, and t = time ,[object Object],[object Object],[object Object],[object Object],[object Object]

Solution: Find the vertex of the parabola. (Use your graphing calculator to find the coordinates of the vertex.) The x value will be the time it takes to reach the maximum height and the y value will be the height. To find when the ball reaches the ground again, use the calculator to find the second zero or root. (The x value will be the time.) In this problem the ball has no initial height. Sometimes there will be a height and sometimes there will not be initial velocity if the object is at rest. Read the problem very carefully .

The maximum is the point (1,16). Using the graphing calculator you might need to round to the nearest integer at times. The maximum height is 16 after 1 second.

Quadratic Function Applications Area Problem ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]

Quadratic Function Applications ,[object Object],[object Object],[object Object],[object Object]

Topics to be covered on Module 7 Test Factoring, Vertex form, identifying quadratic equation, applications of quadratic equations, and finding quadratic best-fit equation ,[object Object],[object Object],[object Object]

Module 8 Complex Numbers ,[object Object],DEFINITION OF i And

Example # 1 = Example # 2 = = = Example # 3 = = = =

Solving Quadratic Equations by Factoring ,[object Object],=0 Now set each set of ( ) equal to zero and solve. x=5 and x=5 Example # 2

Quadratic applications ver b

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