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BBMP 1103
   Mathematic Management
Exam Preparation Workshop Sept 2011
  Part 5 - Application of Integration

        Presented By: Dr Richard Ng

               26 Nov 2011
                 2ptg – 4ptg
5. Focus on Application of Integration

     Question: 12 (May 2010)




Prepared by Dr Richard Ng (2011)              Page 2
Suggested Answers:


           i) Given                C' 30x

                Hence, C              30x.dx
                                          x2
                                       30      c
                                          2
                                      15x 2 c

                When x = 0, c = 15000

                Hence, C 15x 2 15000


Prepared by Dr Richard Ng (2011)                   Page 3
ii) When x = 100:

                            C 15(100) 2 15000
                                   150000 15000
                                   165000

                 When x = 150:
                            C 15(150) 2 15000
                                   15(22500) 15000
                                   352500
             Hence, increase in cost = 352500 - 165000 = RM187,500

Prepared by Dr Richard Ng (2011)                              Page 4
Question: 13 (Jan 2010)




Prepared by Dr Richard Ng (2011)   Page 5
Suggested Answers:

                                   80000
           i) Given C '
                                    x2
                                   80000
                Hence, C              2
                                        .dx
                                    x

                                    80000x 2 .dx

                                             1
                                    80000x
                                                 c
                                        1
                                     80000
                                           c
                                       x

Prepared by Dr Richard Ng (2011)                     Page 6
When x = 0, c = 27000

                                        80000
                Hence, C                      27000
                                          x

          ii) When x = 200

                                        80000
                                   C          27000
                                        (200)

                                       400 27000

                                       26600

Prepared by Dr Richard Ng (2011)                      Page 7
When x = 400

                                        80000
                                   C          27000
                                        (400)

                                       200 27000

                                       26800

           Hence, increase in cost = 26800 - 26600 = RM200




Prepared by Dr Richard Ng (2011)                             Page 8
End of
Part 5

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BBMP1103 - Sept 2011 exam workshop - part 5

  • 1. BBMP 1103 Mathematic Management Exam Preparation Workshop Sept 2011 Part 5 - Application of Integration Presented By: Dr Richard Ng 26 Nov 2011 2ptg – 4ptg
  • 2. 5. Focus on Application of Integration Question: 12 (May 2010) Prepared by Dr Richard Ng (2011) Page 2
  • 3. Suggested Answers: i) Given C' 30x Hence, C 30x.dx x2 30 c 2 15x 2 c When x = 0, c = 15000 Hence, C 15x 2 15000 Prepared by Dr Richard Ng (2011) Page 3
  • 4. ii) When x = 100: C 15(100) 2 15000 150000 15000 165000 When x = 150: C 15(150) 2 15000 15(22500) 15000 352500 Hence, increase in cost = 352500 - 165000 = RM187,500 Prepared by Dr Richard Ng (2011) Page 4
  • 5. Question: 13 (Jan 2010) Prepared by Dr Richard Ng (2011) Page 5
  • 6. Suggested Answers: 80000 i) Given C ' x2 80000 Hence, C 2 .dx x 80000x 2 .dx 1 80000x c 1 80000 c x Prepared by Dr Richard Ng (2011) Page 6
  • 7. When x = 0, c = 27000 80000 Hence, C 27000 x ii) When x = 200 80000 C 27000 (200) 400 27000 26600 Prepared by Dr Richard Ng (2011) Page 7
  • 8. When x = 400 80000 C 27000 (400) 200 27000 26800 Hence, increase in cost = 26800 - 26600 = RM200 Prepared by Dr Richard Ng (2011) Page 8