The SRE Report 2024 - Great Findings for the teams
2 stress and strain intro
1. Week 2: Stress and Strain
…what is essential is invisible to the eye.
~Antoine de Saint-Exupery, The Little Prince
BIOE 3200 - Fall 2015
2. Learning Objectives
Define internal forces and stresses on
a rigid body
Calculate internal stresses from
internal forces
Define strain and Poisson’s ratio
Relate stress to strain through
constitutive equations
BIOE 3200 - Fall 2015
3. Terminology of Stress and Strain
σ = Normal Stress
τ = Shear Stress
ε = Normal Strain
γ= Shear Strain
E = Young’s Modulus (Modulus of
Elasticity)
G = Shear Modulus (Modulus of Rigidity)
ν = Poisson’s Ratio
A = Cross-sectional area
http://www.pbs.org/wgbh/nova/tech/makin
g-stuff.html#making-stuff-stronger
BIOE 3200 - Fall 2015
4. Internal forces: Keeping stuff
together
Consider a body in equilibrium under the action of forces: why
isn’t it pulled apart?
Internal forces develop in the body to keep it together
Recall the mandible in the jaw, eating candy: Where in the bone
is the stress highest?
BIOE 3200 - Fall 2015
From Szűcs, A., Bujtár, P., Sándor, G. K. B., Barabás, J. Finite Element
Analysis of the Human Mandible to Assess the Effect of Removing an
Impacted Third Molar. J Can Dent Assoc 2010;76:a72
5. Internal forces: Keeping stuff
together
Consider a body in equilibrium under the action of forces: why
isn’t it pulled apart?
Internal forces develop in the body to keep it together.
Decrease size of A to a point P
◦ As A 0, F 0, but F/ A ≠0
Define normal stress: σ = lim A 0 Fn / A
◦ Gives change in size
Define shear stress τ = lim A 0 Ft/ A
◦ Gives change in shape
BIOE 3200 - Fall 2015
6. Stress: Is it as simple as
force/area?
If the cut was made in a different direction, the force
and area would be different stresses would
change
A vector (like force) is associated with the direction in which it
acts
A tensor (like stress) is associated with 2 directions:
Direction in which it acts
Plane upon which it acts
Stress is written in terms of its 9 components.
BIOE 3200 - Fall 2015
7. Stress components are
associated with two directions.
BIOE 3200 - Fall 2015
The stress tensor is symmetric: we can show that τxy =
τyx
8. How many independent components of
stress are there at any point in a body?
BIOE 3200 - Fall 2015
9. Strain: Deformation due to
loading
Normal strain: change in size (change
in length/original length)
BIOE 3200 - Fall 2015
10. Strain: Deformation due to
loading
Shear strain: change in shape (change in
angle between lines that were originally
perpendicular)
BIOE 3200 - Fall 2015
13. Constitutive Equations: relating
stress and strain
For isotropic materials (material properties
the same in all directions), at small strains:
◦ σ = E * ε
◦ Τ = G * ϒ
For linear elastic materials:
◦ G = E/(2*(1+ν)
BIOE 3200 - Fall 2015
Hinweis der Redaktion
To discuss material and mechanical properties, we need a common understanding of terminology.
For a 3D body under load (multiple forces F1, F2, F3, F4), if a cut is made through it to form a surface, forces on body are no longer under equilibrium. Internal forces on the cut surface are required to balance the body forces.
For an incrementally small area A on the cut surface, let F = resultant F on A. F has components in the x, y and z directions (Fx, Fy and Fz).
Normal and tangential components of F are defined as Fn and Ft
Stress components are associated with two directions: direction in which it is acting and the plane that the area it acts on lies within
- The direction of stress has components in the x, y and z directions
- The incrementally small area A could lie on the x face, y face or z face
- 3 directions x 3 planes = 9 components
A point in an object subjected to normal and shear stresses, defined in a cartesian coordinate system (i.e. in orthogonal directions).
Subscript “i” refers to direction normal to the plane on which it acts – the “face” of the stress element
Subscript “j” refers to the direction the shear stress is applied.
Sum moments about a line AA (along the z-axis) due to each force on each face; force = stress*area; for an incrementally small volume, the area on each face is dx*dy, dy*dz, and dz*dx.
Stresses parallel to AA do not create moments about AA (σzz , τ yz, τ xz )
Stresses σxx , σyy , τ zy, τ zx have counterparts on opposite faces of the volume that cancel each other out (acting in opposite directions about AA)
Summing moments for remaining stresses: multiply stress by area over which it is acting (dy*dz for τ xy, dx*dz for τ yx) to calculate force, and multiply by moment arm (dx for τ xy, dy for τ yx ) - results in τ xy =τ yx
Can repeat for moments about line along x- and y-axes to show that τ zy =τ yz and τ xz =τ zx
Example: body under load, with lines AB and A’B’ (new position due to loading)
Average normal strain over AB: εN = (A’B’ – AB )/ AB; at pt A εNA = lim BA ((A’B’ – AB) / AB)
εxx, εyy, εzz – normal strains in Cartesian directions
Example: a body under load, with points that form a rt angle between AB and AC, and acute angle φ formed by AB and AC’ (C’ is new position of point C after deformation)
Average shear strain: ϒave = π/2 – φ (has to be in radians so it’s unitless); ϒ A = lim BA, CA (π/2 – φ)
εxx, εyy, εzz – normal strains in Cartesian directions
For small angles, ϒ = tan ϒ; ϒ=Deformation = side opp/side adj
When a material is compressed in one direction, it usually tends to expand in the other two directions perpendicular to the direction of compression.
Conversely, if the material is stretched rather than compressed, it usually tends to contract in the directions transverse to the direction of stretching.
Consider bar under axial load – it elongates and narrows.
In certain rare cases, a material will actually shrink in the transverse direction when compressed (or expand when stretched) which will yield a negative value of the Poisson ratio. Narrowing term (ε lat) is negative due to reduction in one of the dimensions;
Most natural materials are not negative, but some artificial materials will expand when stretched - mostly polymer foams.
If ν (Nu) is 0.5, material is incompressible (water, soft tissues)
Rubber: .55
Metals: .2 - .4
Glass: .2 - .3
Cortical bone: .2 - .5 (average = .3)
Cancellous bone: .01 - .35 (average = .12)
Elastic region, E = slope (stiffness); Hooke’s Law (elastic materials like springs);
Beyond yield point = plastic deformation; elastic ε + plastic ε = total ε
In plastic zone, “yield point” increases with increased plastic deformation (strain hardening)
LEHI material from the textbook definition: Linear stress-strain behavior; Elastic (no dissipation of energy; load/unload curve are the same); Homogeneous (same material behavior throughout body; Isotropic (same material properties in all directions)
Trabecular bone E = 15 GPa; Cortical bone E = 20 GPa; Esteel = 200 GPa; polymers, E < 1
Example tensile test video: https://www.youtube.com/watch?v=67fSwIjYJ-E
Constitutive equations relate stress to strain; for isotropic materials, under linear or elastic deformation conditions; ok for non-linear materials at small strains: σ =Eε; τ = Gϒ – in 1D
E = Elastic modulus (Young’s modulus); G = Shear modulus or modulus of rigidity
Trabecular bone E = 15 GPa; Cortical bone E = 20 GPa; Esteel = 200 GPa; polymers, E < 1 GPa
Approximation of stress and strain for an axially loaded system made of a linear elastic isotropic material: σ = P/A; for σ =Eε and ε=L/L, L = PL/AE