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Wind Energy I




                    Control strategies


Michael Hölling, WS 2010/2011   slide 1
Wind Energy I                              Class content
                                                            5 Wind turbines in
                                                              general                 6/7 Wind - blades
                                2 Wind measurements                                     interaction

                                                                                 8 Power losses at
                                                                                 the rotor blade

                                                                        9 Control strategies
                                  3 Wind field
                                    characterization
    4 Wind power                                                     10 Generator

                                                                     11 Electrics / grid




Michael Hölling, WS 2010/2011                     slide 2
Wind Energy I Control objectives and strategies
  Development of a wind turbine control system can be divided
                    into four major steps:

    define clearly control objectives

    selection of suitable control strategies which determines the operation point
    of the wind turbine for each wind speed

    decide how the control strategy will be realized --> selection of the control
    schemes, the controlled variables, the reference signals, the switching
    procedure between different controllers, etc.

    design of the input-output map, meaning the characteristics of the
    controller according to the specifications




Michael Hölling, WS 2010/2011           slide 3
Wind Energy I                       Control objectives

                          Control objectives for wind turbines

       Energy capture: Maximization of energy capture taking into
       account safe operation restrictions such as rated power, rated
       speed and cut-out wind speed, etc.

       Mechanical loads: Preventing WECS from excessive dynamic
       mechanical loads. This general goal includes reduction of transient
       loads, reduction of high frequency loads and resonance avoidance.

       Power quality: Conditioning the generated power to comply with
       interconnection standards.




Michael Hölling, WS 2010/2011              slide 4
Wind Energy I                        Operation point

                Where / what is the steady-state of operation ?

     the steady-state of operation is reached when the aerodynamic torque
     developed by the rotor equals the reaction torque of the generator

         net torque applied to the system is zero


 At the steady-state operation point the aerodynamical power
 equals the converted power (minus losses at the generator):
                        Pae = Pgen
                   Tae · ω = Tgen · ω

  ω · (Tae − Tgen ) = 0 ⇒ Tae − Tgen = 0

Michael Hölling, WS 2010/2011              slide 5
Wind Energy I                      Torque and power coefficient
            How does the aerodynamic torque change with u1 ?

Aerodynamic torque Tae:

                          Tae = Fae · R · cT

                                   1
                           Tae    = · ρ · π · R2 · u2 · R · cT
                                   2                1


The power converted by the WEC is given by:

                           PW EC = Tae · ω = Pair · cp

                                            1
                                ⇒ cT = cp ·
                                            λ
Michael Hölling, WS 2010/2011                   slide 6
Wind Energy I                         Aerodynamic torque
 The torque coefficient can be determined from the power
 coefficient. Until now we determined the maximum power
 coefficient by taking into consideration:
          Betz limit with the expansion by Schmitz

          losses at the rotor blades (drag losses and tip losses)

           0.6                                         cpSchmitz
                                                       cpSchmitz, z=3,"(#)=60

           0.4
                                                    These curve represents the
 cpr(!)




                                                    maximum power coefficient
           0.2
                                                    for each tip speed ratio BUT
                            λ0
                                                    design is only possible for one
           0.0
              0       5          10    15     20    tip speed ratio λ0!
                                 !

Michael Hölling, WS 2010/2011                slide 7
Wind Energy I                               Aerodynamic torque
   Without control system the WEC is designed and optimized
                     for one u1 and one ω.
                                     0.6



                            cpr(!)   0.4


                                     0.2

                                                  λ0
                                     0.0
                                        0     5          10           15        20
                                                         !
              u2= 2/3.u1                                                      u2= 2/3.u*1
                                                                                            the angle of
      urot                                                             urot               attack changes
             β ures      by changing u1                                       β* u*res   and cl(α) to cl(α*)
                         to u*1 and with                                                 and cd(α) to cd(α*)
          α                 it λ το λ*                                                         as well
                                                                 α*

Michael Hölling, WS 2010/2011                          slide 8
Wind Energy I                    Aerodynamic torque

     0.6                         cp       From Betz we know that there is one
                                          optimum ratio between u3 and u1.
     0.4
                                          The WEC meets this at the design for
cp




     0.2                                  λ0.
                     λ0
     0.0
       0.0              0.5      1.0
                        u3/u1

 The cp coming from Betz in                                                             cpSchmitz
                                                0.6
 combination with the                                                                   cpSchmitz,
 changing angle of attack                       0.4                                     z=3,"(#)=60
 for different u1, we get a                                                             cp! (!,#)
                                       cpr(!)



                                                                                           0
 power coefficient that                         0.2
 depends on λ and α -                                               λ0
 cp(λ,α)                                        0.0
                                                   0            5        10   15   20
                                                                         !

 Michael Hölling, WS 2010/2011                        slide 9
Wind Energy I                   Aerodynamic torque
    Note: In reality λmax and λ0 must NOT necessarily coincide !!
                  1
    With cT = cp · cp(λ) and cT(λ) can be plotted:
      ⇒
                  λ
                        0.6                                  0.15
                                                     cp(!)
                                                     cT(!)
                        0.4                                  0.10




                                                                    cT(!)
                cp(!)




                        0.2                                  0.05



                        0.0                                  0.00
                           0    4          8         12
                                       !

Michael Hölling, WS 2010/2011          slide 10
Wind Energy I                               Aerodynamic torque
   How does the torque change with changing ω for different but
   fixed u1?           1               ω·R   1
                                  Tae =       · ρ · π · R2 · u3 · cp        ·
                                          2                   1
                                                                       u1       ω
                                                                       λ

        0.6
                                              cp(!)

        0.4
cp(!)




                                                          cp(!)
        0.2



        0.0
           0        4             8           12
                              !                                                 !




  Michael Hölling, WS 2010/2011                          slide 11
Wind Energy I                               Aerodynamic torque
   How does the torque change with changing ω for different but
   fixed u1?           1               ω·R   1
                                  Tae =       · ρ · π · R2 · u3 · cp                 ·
                                          2                   1
                                                                             u1          ω
                                                                             λ



                                                                                             u1 = 25m/s



                                                    torque [Nm]
cp(!)




                            !                                                    !




  Michael Hölling, WS 2010/2011                                   slide 12
Wind Energy I                               Aerodynamic torque
   How does the torque change with changing ω for different but
   fixed u1?           1               ω·R   1
                                  Tae =       · ρ · π · R2 · u3 · cp                 ·
                                          2                   1
                                                                             u1          ω
                                                                             λ



                                                                                             u1 = 25m/s
                                                                                             u1 = 22m/s


                                                    torque [Nm]
cp(!)




                            !                                                    !




  Michael Hölling, WS 2010/2011                                   slide 13
Wind Energy I                               Aerodynamic torque
   How does the torque change with changing ω for different but
   fixed u1?           1               ω·R   1
                                  Tae =       · ρ · π · R2 · u3 · cp                 ·
                                          2                   1
                                                                             u1          ω
                                                                             λ



                                                                                             u1 = 25m/s
                                                                                             u1 = 22m/s


                                                    torque [Nm]
                                                                                             u1 = 20m/s
cp(!)




                            !                                                    !




  Michael Hölling, WS 2010/2011                                   slide 14
Wind Energy I                               Aerodynamic torque
   How does the torque change with changing ω for different but
   fixed u1?           1               ω·R   1
                                  Tae =       · ρ · π · R2 · u3 · cp                 ·
                                          2                   1
                                                                             u1          ω
                                                                             λ



                                                                                             u1 = 25m/s
                                                                                             u1 = 22m/s


                                                    torque [Nm]
                                                                                             u1 = 20m/s
                                                                                             u1 = 17m/s
cp(!)




                            !                                                    !




  Michael Hölling, WS 2010/2011                                   slide 15
Wind Energy I                               Aerodynamic torque
   How does the torque change with changing ω for different but
   fixed u1?           1               ω·R   1
                                  Tae =       · ρ · π · R2 · u3 · cp                 ·
                                          2                   1
                                                                             u1          ω
                                                                             λ



                                                                                             u1 = 25m/s
                                                                                             u1 = 22m/s


                                                    torque [Nm]
                                                                                             u1 = 20m/s
                                                                                             u1 = 17m/s
cp(!)




                                                                                             u1 = 14m/s




                            !                                                    !




  Michael Hölling, WS 2010/2011                                   slide 16
Wind Energy I                               Aerodynamic torque
   How does the torque change with changing ω for different but
   fixed u1?           1               ω·R   1
                                  Tae =       · ρ · π · R2 · u3 · cp                 ·
                                          2                   1
                                                                             u1          ω
                                                                             λ



                                                                                             u1 = 25m/s
                                                                                             u1 = 22m/s


                                                    torque [Nm]
                                                                                             u1 = 20m/s
                                                                                             u1 = 17m/s
cp(!)




                                                                                             u1 = 14m/s
                                                                                             u1 = 12m/s




                            !                                                    !




  Michael Hölling, WS 2010/2011                                   slide 17
Wind Energy I                               Aerodynamic torque
   How does the torque change with changing ω for different but
   fixed u1?           1               ω·R   1
                                  Tae =       · ρ · π · R2 · u3 · cp                 ·
                                          2                   1
                                                                             u1          ω
                                                                             λ



                                                                                             u1 = 25m/s
                                                                                             u1 = 22m/s


                                                    torque [Nm]
                                                                                             u1 = 20m/s
                                                                                             u1 = 17m/s
cp(!)




                                                                                             u1 = 14m/s
                                                                                             u1 = 12m/s
                                                                                             u1 = 10m/s



                            !                                                    !




  Michael Hölling, WS 2010/2011                                   slide 18
Wind Energy I                               Aerodynamic torque
   How does the torque change with changing ω for different but
   fixed u1?           1               ω·R   1
                                  Tae =       · ρ · π · R2 · u3 · cp                 ·
                                          2                   1
                                                                             u1          ω
                                                                             λ



                                                                                             u1 = 25m/s
                                                                                             u1 = 22m/s


                                                    torque [Nm]
                                                                                             u1 = 20m/s
                                                                                             u1 = 17m/s
cp(!)




                                                                                             u1 = 14m/s
                                                                                             u1 = 12m/s
                                                                                             u1 = 10m/s
                                                                                             u1 = 8m/s


                            !                                                    !




  Michael Hölling, WS 2010/2011                                   slide 19
Wind Energy I                               Aerodynamic torque
   How does the torque change with changing ω for different but
   fixed u1?           1               ω·R   1
                                  Tae =       · ρ · π · R2 · u3 · cp                 ·
                                          2                   1
                                                                             u1          ω
                                                                             λ



                                                                                             u1 = 25m/s
                                                                                             u1 = 22m/s


                                                    torque [Nm]
                                                                                             u1 = 20m/s
                                                                                             u1 = 17m/s
cp(!)




                                                                                             u1 = 14m/s
                                                                                             u1 = 12m/s
                                                                                             u1 = 10m/s
                                                                                             u1 = 8m/s
                                                                                             u1 = 6m/s
                            !                                                    !




  Michael Hölling, WS 2010/2011                                   slide 20
Wind Energy I                               Aerodynamic torque
   How does the torque change with changing ω for different but
   fixed u1?           1               ω·R   1
                                  Tae =       · ρ · π · R2 · u3 · cp                 ·
                                          2                   1
                                                                             u1          ω
                                                                             λ



                                                                                             u1 = 25m/s
                                                                                             u1 = 22m/s


                                                    torque [Nm]
                                                                                             u1 = 20m/s
                                                                                             u1 = 17m/s
cp(!)




                                                                                             u1 = 14m/s
                                                                                             u1 = 12m/s
                                                                                             u1 = 10m/s
                                                                                             u1 = 8m/s
                                                                                             u1 = 6m/s
                                                                                             u1 = 4m/s
                            !                                                    !




  Michael Hölling, WS 2010/2011                                   slide 21
Wind Energy I                               Aerodynamic torque
   How does the torque change with changing ω for different but
   fixed u1?           1               ω·R   1
                                  Tae =       · ρ · π · R2 · u3 · cp                 ·
                                          2                   1
                                                                             u1          ω
                                                                             λ



                                                                                             u1 = 25m/s
                                                                                             u1 = 22m/s


                                                    torque [Nm]
                                                                                             u1 = 20m/s
                                                                                             u1 = 17m/s
cp(!)




                                                                                             u1 = 14m/s
                                                                                             u1 = 12m/s
                                                                                             u1 = 10m/s
                                                                                             u1 = 8m/s
                                                                                             u1 = 6m/s
                                                                                             u1 = 4m/s
                            !                                                    !
                                                                                             Tcpmax



  Michael Hölling, WS 2010/2011                                   slide 22
Wind Energy I                               Aerodynamic torque
   How does the torque change with changing ω for different but
   fixed u1?           1               ω·R   1
                                  Tae =       · ρ · π · R2 · u3 · cp                 ·
                                          2                   1
                                                                             u1          ω
                                                                             λ



                                                                                             u1 = 25m/s
                                                                                             u1 = 22m/s


                                                    torque [Nm]
                                                                                             u1 = 20m/s
                                                                                             u1 = 17m/s
cp(!)




                                                                                             u1 = 14m/s
                                                                                             u1 = 12m/s
                                                                                             u1 = 10m/s
                                                                                             u1 = 8m/s
                                                                                             u1 = 6m/s
                                                                                             u1 = 4m/s
                            !                                                    !
                                                                                             Tcpmax
                                                                                             Trated power


  Michael Hölling, WS 2010/2011                                   slide 23
Wind Energy I                   Control strategies
 Points in this torque-rotational speed plane (Tae-ω plane) that
 intersect with the generator torque define the steady-state
 operating conditions of the WEC. Different WEC control
 strategies results in different power curves P(u1), power
 coefficients cp(u1) and dynamical behavior.

 Different strategies are:
    fixed-speed, fixed-pitch (FS-FP)

    variable-speed, fixed-pitch (VS-FP)

    fixed-speed, variable-pitch (FS-VP)

    variable speed, variable-pitch (VS-VP)



Michael Hölling, WS 2010/2011             slide 24
Wind Energy I                   Control strategies
The interesting region for the control system is marked in the
red box.

                                                     u1 = 25m/s
                                                     u1 = 22m/s
              torque [Nm]




                                                     u1 = 20m/s
                                                     u1 = 17m/s
                                                     u1 = 14m/s
                                                     u1 = 12m/s
                                                     u1 = 10m/s
                                                     u1 = 8m/s
                                                     u1 = 6m/s
                                                     u1 = 4m/s
                                    !
                                                     Tcpmax
                                                     Trated power

Michael Hölling, WS 2010/2011           slide 25
Wind Energy I                        Fixed-speed, fixed-pitch
    Fixed rotational-speed ω0 is realized by coupling an
    asynchronous generator directly to the grid.



        0.6
                            B                                                                u1 = 17m/s
                                       cp(!)                                        u1max    u1 = 8m/s
                   C


                                               torque [Nm]
        0.4                                                                          C       u1 = 4m/s
cp(!)




                                                                                             Trated power
                                                                                         D
                                                                                             Tcpmax
        0.2
               D
                                                                                     B
        0.0
                                       12 A                                         Aω
           0           4
                             !
                                   8
                                                                        u1min   !
                                                                                       0




   Michael Hölling, WS 2010/2011                             slide 26
Wind Energy I                                    Fixed-speed, fixed-pitch
         For the characterization of the WEC power curve P(u1) and
         cp(u1) are of interest. For FS-FP the P(u1) curve looks in principle
         like:

                                        C
                                                                                                             u1 = 17m/s
                                                      D
                                                                                                    u1max    u1 = 8m/s



                                                               torque [Nm]
P(u1)/Prated




                                                                                                     C       u1 = 4m/s
                                                                                                             Trated power
                                                                                                         D
                                                                                                             Tcpmax
                        B
                                 ideal power curve                                                   B
                                 power curve
                   A5                                                                               Aω
               0            10     15       20   25       30
                                                                                        u1min   !
                                                                                                         0
                                 u1 [m/s]




      Michael Hölling, WS 2010/2011                                          slide 27
Wind Energy I                              Fixed-speed, fixed-pitch
     For the characterization of the WEC power curve P(u1) and
     cp(u1) are of interest. For FS-FP the cp(u1) curve looks in
     principle like:


                     B                                                                              u1 = 17m/s
                                                                                           u1max    u1 = 8m/s



                                                      torque [Nm]
                                                                                            C       u1 = 4m/s
cp(u1)




                                   C                                                                Trated power
                                                                                                D
                                                                                                    Tcpmax
                          ideal cp
                          real cp            D                                              B
             A                                                                             Aω
         0       5   10      15        20   25   30
                                                                               u1min   !
                                                                                                0
                           u1 [m/s]




   Michael Hölling, WS 2010/2011                                    slide 28
Wind Energy I                         Fixed-speed, fixed-pitch

                                Power regulation by passive stall




Michael Hölling, WS 2010/2011                   slide 29
Wind Energy I                   Variable-speed, fixed-pitch
 For a variable-speed, fixed.pitch machine the rotational speed
 ωrot can be adapted to meet the optimum tip speed ratio λ0.

                                             λ0 · u1
                                    ωrot   =
                                               R

 The rotational speed ωrot changes linearly with the ambient
 wind speed u1.
 This is applied in the region below rated wind speed.




Michael Hölling, WS 2010/2011               slide 30
Wind Energy I                        Variable-speed, fixed-pitch
    Variable rotational-speed ωrot is realized by adding AC/DC-DC/
    AC converter before feeding into the grid.



        0.6
                           A-E          cp(!)

        0.4
                   D
cp(!)




        0.2
               G
        0.0
           0           4           8    12
                             !




   Michael Hölling, WS 2010/2011                  slide 31
Wind Energy I                   Variable-speed, fixed-pitch
 For the characterization of the WEC power curve P(u1) and
 cp(u1) are of interest. For VS-FP the P(u1) curve looks in
 principle like:




Michael Hölling, WS 2010/2011              slide 32
Wind Energy I                   Variable-speed, fixed-pitch
 For the characterization of the WEC power curve P(u1) and
 cp(u1) are of interest. For VS-FP the cp(u1) curve looks in
 principle like:




Michael Hölling, WS 2010/2011              slide 33
Wind Energy I                   Fixed-speed, variable-pitch
 There are two different ways to adjust the pitch to keep the
 power above rated wind speed constant:


pitch to feather                                       pitch to stall




Michael Hölling, WS 2010/2011               slide 34
Wind Energy I                   Fixed-speed, variable-pitch
 By adjusting the angle of attack the cp(λ) curves are different
 for each pitch angle:




                                                              tip speed ratio


Michael Hölling, WS 2010/2011               slide 35
Wind Energy I                   Fixed-speed, variable-pitch
 These modified cp(λ) curves result in modified torque above
 rated wind speed to meet the rated power:




Michael Hölling, WS 2010/2011               slide 36
Wind Energy I                   Fixed-speed, variable-pitch
 For the characterization of the WEC power curve P(u1) and
 cp(u1) are of interest. For FS-VP the P(u1) curve looks in
 principle like:




Michael Hölling, WS 2010/2011               slide 37
Wind Energy I                   Fixed-speed, variable-pitch
 For the characterization of the WEC power curve P(u1) and
 cp(u1) are of interest. For FS-VP the cp(u1) curve looks in
 principle like:




Michael Hölling, WS 2010/2011               slide 38
Wind Energy I                   Variable-speed, variable-pitch




Michael Hölling, WS 2010/2011                slide 39

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Wind energy I. Lesson 9. Control strategies

  • 1. Wind Energy I Control strategies Michael Hölling, WS 2010/2011 slide 1
  • 2. Wind Energy I Class content 5 Wind turbines in general 6/7 Wind - blades 2 Wind measurements interaction 8 Power losses at the rotor blade 9 Control strategies 3 Wind field characterization 4 Wind power 10 Generator 11 Electrics / grid Michael Hölling, WS 2010/2011 slide 2
  • 3. Wind Energy I Control objectives and strategies Development of a wind turbine control system can be divided into four major steps: define clearly control objectives selection of suitable control strategies which determines the operation point of the wind turbine for each wind speed decide how the control strategy will be realized --> selection of the control schemes, the controlled variables, the reference signals, the switching procedure between different controllers, etc. design of the input-output map, meaning the characteristics of the controller according to the specifications Michael Hölling, WS 2010/2011 slide 3
  • 4. Wind Energy I Control objectives Control objectives for wind turbines Energy capture: Maximization of energy capture taking into account safe operation restrictions such as rated power, rated speed and cut-out wind speed, etc. Mechanical loads: Preventing WECS from excessive dynamic mechanical loads. This general goal includes reduction of transient loads, reduction of high frequency loads and resonance avoidance. Power quality: Conditioning the generated power to comply with interconnection standards. Michael Hölling, WS 2010/2011 slide 4
  • 5. Wind Energy I Operation point Where / what is the steady-state of operation ? the steady-state of operation is reached when the aerodynamic torque developed by the rotor equals the reaction torque of the generator net torque applied to the system is zero At the steady-state operation point the aerodynamical power equals the converted power (minus losses at the generator): Pae = Pgen Tae · ω = Tgen · ω ω · (Tae − Tgen ) = 0 ⇒ Tae − Tgen = 0 Michael Hölling, WS 2010/2011 slide 5
  • 6. Wind Energy I Torque and power coefficient How does the aerodynamic torque change with u1 ? Aerodynamic torque Tae: Tae = Fae · R · cT 1 Tae = · ρ · π · R2 · u2 · R · cT 2 1 The power converted by the WEC is given by: PW EC = Tae · ω = Pair · cp 1 ⇒ cT = cp · λ Michael Hölling, WS 2010/2011 slide 6
  • 7. Wind Energy I Aerodynamic torque The torque coefficient can be determined from the power coefficient. Until now we determined the maximum power coefficient by taking into consideration: Betz limit with the expansion by Schmitz losses at the rotor blades (drag losses and tip losses) 0.6 cpSchmitz cpSchmitz, z=3,"(#)=60 0.4 These curve represents the cpr(!) maximum power coefficient 0.2 for each tip speed ratio BUT λ0 design is only possible for one 0.0 0 5 10 15 20 tip speed ratio λ0! ! Michael Hölling, WS 2010/2011 slide 7
  • 8. Wind Energy I Aerodynamic torque Without control system the WEC is designed and optimized for one u1 and one ω. 0.6 cpr(!) 0.4 0.2 λ0 0.0 0 5 10 15 20 ! u2= 2/3.u1 u2= 2/3.u*1 the angle of urot urot attack changes β ures by changing u1 β* u*res and cl(α) to cl(α*) to u*1 and with and cd(α) to cd(α*) α it λ το λ* as well α* Michael Hölling, WS 2010/2011 slide 8
  • 9. Wind Energy I Aerodynamic torque 0.6 cp From Betz we know that there is one optimum ratio between u3 and u1. 0.4 The WEC meets this at the design for cp 0.2 λ0. λ0 0.0 0.0 0.5 1.0 u3/u1 The cp coming from Betz in cpSchmitz 0.6 combination with the cpSchmitz, changing angle of attack 0.4 z=3,"(#)=60 for different u1, we get a cp! (!,#) cpr(!) 0 power coefficient that 0.2 depends on λ and α - λ0 cp(λ,α) 0.0 0 5 10 15 20 ! Michael Hölling, WS 2010/2011 slide 9
  • 10. Wind Energy I Aerodynamic torque Note: In reality λmax and λ0 must NOT necessarily coincide !! 1 With cT = cp · cp(λ) and cT(λ) can be plotted: ⇒ λ 0.6 0.15 cp(!) cT(!) 0.4 0.10 cT(!) cp(!) 0.2 0.05 0.0 0.00 0 4 8 12 ! Michael Hölling, WS 2010/2011 slide 10
  • 11. Wind Energy I Aerodynamic torque How does the torque change with changing ω for different but fixed u1? 1 ω·R 1 Tae = · ρ · π · R2 · u3 · cp · 2 1 u1 ω λ 0.6 cp(!) 0.4 cp(!) cp(!) 0.2 0.0 0 4 8 12 ! ! Michael Hölling, WS 2010/2011 slide 11
  • 12. Wind Energy I Aerodynamic torque How does the torque change with changing ω for different but fixed u1? 1 ω·R 1 Tae = · ρ · π · R2 · u3 · cp · 2 1 u1 ω λ u1 = 25m/s torque [Nm] cp(!) ! ! Michael Hölling, WS 2010/2011 slide 12
  • 13. Wind Energy I Aerodynamic torque How does the torque change with changing ω for different but fixed u1? 1 ω·R 1 Tae = · ρ · π · R2 · u3 · cp · 2 1 u1 ω λ u1 = 25m/s u1 = 22m/s torque [Nm] cp(!) ! ! Michael Hölling, WS 2010/2011 slide 13
  • 14. Wind Energy I Aerodynamic torque How does the torque change with changing ω for different but fixed u1? 1 ω·R 1 Tae = · ρ · π · R2 · u3 · cp · 2 1 u1 ω λ u1 = 25m/s u1 = 22m/s torque [Nm] u1 = 20m/s cp(!) ! ! Michael Hölling, WS 2010/2011 slide 14
  • 15. Wind Energy I Aerodynamic torque How does the torque change with changing ω for different but fixed u1? 1 ω·R 1 Tae = · ρ · π · R2 · u3 · cp · 2 1 u1 ω λ u1 = 25m/s u1 = 22m/s torque [Nm] u1 = 20m/s u1 = 17m/s cp(!) ! ! Michael Hölling, WS 2010/2011 slide 15
  • 16. Wind Energy I Aerodynamic torque How does the torque change with changing ω for different but fixed u1? 1 ω·R 1 Tae = · ρ · π · R2 · u3 · cp · 2 1 u1 ω λ u1 = 25m/s u1 = 22m/s torque [Nm] u1 = 20m/s u1 = 17m/s cp(!) u1 = 14m/s ! ! Michael Hölling, WS 2010/2011 slide 16
  • 17. Wind Energy I Aerodynamic torque How does the torque change with changing ω for different but fixed u1? 1 ω·R 1 Tae = · ρ · π · R2 · u3 · cp · 2 1 u1 ω λ u1 = 25m/s u1 = 22m/s torque [Nm] u1 = 20m/s u1 = 17m/s cp(!) u1 = 14m/s u1 = 12m/s ! ! Michael Hölling, WS 2010/2011 slide 17
  • 18. Wind Energy I Aerodynamic torque How does the torque change with changing ω for different but fixed u1? 1 ω·R 1 Tae = · ρ · π · R2 · u3 · cp · 2 1 u1 ω λ u1 = 25m/s u1 = 22m/s torque [Nm] u1 = 20m/s u1 = 17m/s cp(!) u1 = 14m/s u1 = 12m/s u1 = 10m/s ! ! Michael Hölling, WS 2010/2011 slide 18
  • 19. Wind Energy I Aerodynamic torque How does the torque change with changing ω for different but fixed u1? 1 ω·R 1 Tae = · ρ · π · R2 · u3 · cp · 2 1 u1 ω λ u1 = 25m/s u1 = 22m/s torque [Nm] u1 = 20m/s u1 = 17m/s cp(!) u1 = 14m/s u1 = 12m/s u1 = 10m/s u1 = 8m/s ! ! Michael Hölling, WS 2010/2011 slide 19
  • 20. Wind Energy I Aerodynamic torque How does the torque change with changing ω for different but fixed u1? 1 ω·R 1 Tae = · ρ · π · R2 · u3 · cp · 2 1 u1 ω λ u1 = 25m/s u1 = 22m/s torque [Nm] u1 = 20m/s u1 = 17m/s cp(!) u1 = 14m/s u1 = 12m/s u1 = 10m/s u1 = 8m/s u1 = 6m/s ! ! Michael Hölling, WS 2010/2011 slide 20
  • 21. Wind Energy I Aerodynamic torque How does the torque change with changing ω for different but fixed u1? 1 ω·R 1 Tae = · ρ · π · R2 · u3 · cp · 2 1 u1 ω λ u1 = 25m/s u1 = 22m/s torque [Nm] u1 = 20m/s u1 = 17m/s cp(!) u1 = 14m/s u1 = 12m/s u1 = 10m/s u1 = 8m/s u1 = 6m/s u1 = 4m/s ! ! Michael Hölling, WS 2010/2011 slide 21
  • 22. Wind Energy I Aerodynamic torque How does the torque change with changing ω for different but fixed u1? 1 ω·R 1 Tae = · ρ · π · R2 · u3 · cp · 2 1 u1 ω λ u1 = 25m/s u1 = 22m/s torque [Nm] u1 = 20m/s u1 = 17m/s cp(!) u1 = 14m/s u1 = 12m/s u1 = 10m/s u1 = 8m/s u1 = 6m/s u1 = 4m/s ! ! Tcpmax Michael Hölling, WS 2010/2011 slide 22
  • 23. Wind Energy I Aerodynamic torque How does the torque change with changing ω for different but fixed u1? 1 ω·R 1 Tae = · ρ · π · R2 · u3 · cp · 2 1 u1 ω λ u1 = 25m/s u1 = 22m/s torque [Nm] u1 = 20m/s u1 = 17m/s cp(!) u1 = 14m/s u1 = 12m/s u1 = 10m/s u1 = 8m/s u1 = 6m/s u1 = 4m/s ! ! Tcpmax Trated power Michael Hölling, WS 2010/2011 slide 23
  • 24. Wind Energy I Control strategies Points in this torque-rotational speed plane (Tae-ω plane) that intersect with the generator torque define the steady-state operating conditions of the WEC. Different WEC control strategies results in different power curves P(u1), power coefficients cp(u1) and dynamical behavior. Different strategies are: fixed-speed, fixed-pitch (FS-FP) variable-speed, fixed-pitch (VS-FP) fixed-speed, variable-pitch (FS-VP) variable speed, variable-pitch (VS-VP) Michael Hölling, WS 2010/2011 slide 24
  • 25. Wind Energy I Control strategies The interesting region for the control system is marked in the red box. u1 = 25m/s u1 = 22m/s torque [Nm] u1 = 20m/s u1 = 17m/s u1 = 14m/s u1 = 12m/s u1 = 10m/s u1 = 8m/s u1 = 6m/s u1 = 4m/s ! Tcpmax Trated power Michael Hölling, WS 2010/2011 slide 25
  • 26. Wind Energy I Fixed-speed, fixed-pitch Fixed rotational-speed ω0 is realized by coupling an asynchronous generator directly to the grid. 0.6 B u1 = 17m/s cp(!) u1max u1 = 8m/s C torque [Nm] 0.4 C u1 = 4m/s cp(!) Trated power D Tcpmax 0.2 D B 0.0 12 A Aω 0 4 ! 8 u1min ! 0 Michael Hölling, WS 2010/2011 slide 26
  • 27. Wind Energy I Fixed-speed, fixed-pitch For the characterization of the WEC power curve P(u1) and cp(u1) are of interest. For FS-FP the P(u1) curve looks in principle like: C u1 = 17m/s D u1max u1 = 8m/s torque [Nm] P(u1)/Prated C u1 = 4m/s Trated power D Tcpmax B ideal power curve B power curve A5 Aω 0 10 15 20 25 30 u1min ! 0 u1 [m/s] Michael Hölling, WS 2010/2011 slide 27
  • 28. Wind Energy I Fixed-speed, fixed-pitch For the characterization of the WEC power curve P(u1) and cp(u1) are of interest. For FS-FP the cp(u1) curve looks in principle like: B u1 = 17m/s u1max u1 = 8m/s torque [Nm] C u1 = 4m/s cp(u1) C Trated power D Tcpmax ideal cp real cp D B A Aω 0 5 10 15 20 25 30 u1min ! 0 u1 [m/s] Michael Hölling, WS 2010/2011 slide 28
  • 29. Wind Energy I Fixed-speed, fixed-pitch Power regulation by passive stall Michael Hölling, WS 2010/2011 slide 29
  • 30. Wind Energy I Variable-speed, fixed-pitch For a variable-speed, fixed.pitch machine the rotational speed ωrot can be adapted to meet the optimum tip speed ratio λ0. λ0 · u1 ωrot = R The rotational speed ωrot changes linearly with the ambient wind speed u1. This is applied in the region below rated wind speed. Michael Hölling, WS 2010/2011 slide 30
  • 31. Wind Energy I Variable-speed, fixed-pitch Variable rotational-speed ωrot is realized by adding AC/DC-DC/ AC converter before feeding into the grid. 0.6 A-E cp(!) 0.4 D cp(!) 0.2 G 0.0 0 4 8 12 ! Michael Hölling, WS 2010/2011 slide 31
  • 32. Wind Energy I Variable-speed, fixed-pitch For the characterization of the WEC power curve P(u1) and cp(u1) are of interest. For VS-FP the P(u1) curve looks in principle like: Michael Hölling, WS 2010/2011 slide 32
  • 33. Wind Energy I Variable-speed, fixed-pitch For the characterization of the WEC power curve P(u1) and cp(u1) are of interest. For VS-FP the cp(u1) curve looks in principle like: Michael Hölling, WS 2010/2011 slide 33
  • 34. Wind Energy I Fixed-speed, variable-pitch There are two different ways to adjust the pitch to keep the power above rated wind speed constant: pitch to feather pitch to stall Michael Hölling, WS 2010/2011 slide 34
  • 35. Wind Energy I Fixed-speed, variable-pitch By adjusting the angle of attack the cp(λ) curves are different for each pitch angle: tip speed ratio Michael Hölling, WS 2010/2011 slide 35
  • 36. Wind Energy I Fixed-speed, variable-pitch These modified cp(λ) curves result in modified torque above rated wind speed to meet the rated power: Michael Hölling, WS 2010/2011 slide 36
  • 37. Wind Energy I Fixed-speed, variable-pitch For the characterization of the WEC power curve P(u1) and cp(u1) are of interest. For FS-VP the P(u1) curve looks in principle like: Michael Hölling, WS 2010/2011 slide 37
  • 38. Wind Energy I Fixed-speed, variable-pitch For the characterization of the WEC power curve P(u1) and cp(u1) are of interest. For FS-VP the cp(u1) curve looks in principle like: Michael Hölling, WS 2010/2011 slide 38
  • 39. Wind Energy I Variable-speed, variable-pitch Michael Hölling, WS 2010/2011 slide 39