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Distributed Computing … and introduction of Hadoop -  Ankit Minocha
Outline ,[object Object],[object Object]
Computer Speedup Moore’s Law: “ The density of transistors on a chip doubles every 18 months, for the same cost”  (1965)
Scope of problems ,[object Object],[object Object],[object Object]
Rendering multiple frames of high-quality animation
Parallelization Idea ,[object Object]
Parallelization Idea (2) In a parallel computation, we would like to have as many threads as we have processors. e.g., a four-processor computer would be able to run four threads at the same time.
Parallelization Idea (3)
Parallelization Idea (4)
Parallelization Pitfalls ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],What is the common theme of all of these problems?
Parallelization Pitfalls (2) ,[object Object],[object Object]
What is Wrong With This? ,[object Object],[object Object],[object Object],[object Object],[object Object],Thread 2: void bar() { y++; x+=3; } If the initial state is y = 0, x = 6, what happens after these threads finish running?
Multithreaded = Unpredictability ,[object Object],Thread 1: void foo() { eax = mem[x]; inc eax; mem[x] = eax; ebx = mem[x]; mem[y] = ebx; } Thread 2: void bar() { eax = mem[y]; inc eax; mem[y] = eax; eax = mem[x]; add eax, 3; mem[x] = eax; } ,[object Object]
Multithreaded = Unpredictability ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
Synchronization Primitives ,[object Object],[object Object]
Semaphores ,[object Object],[object Object],Only one side of the semaphore can ever be red! (Can both be green?)
Semaphores ,[object Object],[object Object],[object Object]
The “corrected” example Thread 1: void foo() { sem.lock(); x++; y = x; sem.unlock(); } Thread 2: void bar() { sem.lock(); y++; x+=3; sem.unlock(); } Global var “Semaphore sem = new Semaphore();” guards access to x & y
Condition Variables ,[object Object],[object Object],[object Object]
The final example Thread 1: void foo() { sem.lock(); x++; y = x; fooDone = true; sem.unlock(); fooFinishedCV.notify(); } Thread 2: void bar() { sem.lock(); if(!fooDone) fooFinishedCV.wait(sem); y++; x+=3; sem.unlock(); } Global vars: Semaphore sem = new Semaphore(); ConditionVar fooFinishedCV = new ConditionVar(); boolean fooDone = false;
Too Much Synchronization? Deadlock Synchronization becomes even more complicated when multiple locks can be used Can cause entire system to “get stuck” Thread A: semaphore1.lock(); semaphore2.lock(); /* use data guarded by  semaphores */ semaphore1.unlock();  semaphore2.unlock(); Thread B: semaphore2.lock(); semaphore1.lock(); /* use data guarded by  semaphores */ semaphore1.unlock();  semaphore2.unlock(); (Image: RPI CSCI.4210 Operating Systems notes)
The Moral: Be Careful! ,[object Object],[object Object],[object Object],[object Object],[object Object]
Hadoop to the rescue!
Prelude to MapReduce ,[object Object],[object Object],[object Object]
Prelude to MapReduce ,[object Object],[object Object],[object Object]
Thank you so much “Clickable” for your sincere efforts.

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Distributed computing presentation

  • 1. Distributed Computing … and introduction of Hadoop - Ankit Minocha
  • 2.
  • 3. Computer Speedup Moore’s Law: “ The density of transistors on a chip doubles every 18 months, for the same cost” (1965)
  • 4.
  • 5. Rendering multiple frames of high-quality animation
  • 6.
  • 7. Parallelization Idea (2) In a parallel computation, we would like to have as many threads as we have processors. e.g., a four-processor computer would be able to run four threads at the same time.
  • 10.
  • 11.
  • 12.
  • 13.
  • 14.
  • 15.
  • 16.
  • 17.
  • 18. The “corrected” example Thread 1: void foo() { sem.lock(); x++; y = x; sem.unlock(); } Thread 2: void bar() { sem.lock(); y++; x+=3; sem.unlock(); } Global var “Semaphore sem = new Semaphore();” guards access to x & y
  • 19.
  • 20. The final example Thread 1: void foo() { sem.lock(); x++; y = x; fooDone = true; sem.unlock(); fooFinishedCV.notify(); } Thread 2: void bar() { sem.lock(); if(!fooDone) fooFinishedCV.wait(sem); y++; x+=3; sem.unlock(); } Global vars: Semaphore sem = new Semaphore(); ConditionVar fooFinishedCV = new ConditionVar(); boolean fooDone = false;
  • 21. Too Much Synchronization? Deadlock Synchronization becomes even more complicated when multiple locks can be used Can cause entire system to “get stuck” Thread A: semaphore1.lock(); semaphore2.lock(); /* use data guarded by semaphores */ semaphore1.unlock(); semaphore2.unlock(); Thread B: semaphore2.lock(); semaphore1.lock(); /* use data guarded by semaphores */ semaphore1.unlock(); semaphore2.unlock(); (Image: RPI CSCI.4210 Operating Systems notes)
  • 22.
  • 23. Hadoop to the rescue!
  • 24.
  • 25.
  • 26. Thank you so much “Clickable” for your sincere efforts.

Hinweis der Redaktion

  1. There are multiple possible final states. Y is definitely a problem, because we don’t know if it will be “1” or “7”… but X can also be 7, 10, or 11!
  2. Inform students that the term we want here is “race condition”
  3. Ask: are there still any problems? (Yes – we still have two possible outcomes. We want some other system that allows us to serialize access on an event.)
  4. Go over wait() / notify() / broadcast() --- must be combined with a semaphore!