Tcs 2011with solutions

TCS
SAMPLE QUESTIONS
For student’s preparation
(New Test Pattern 2010 onwards)

TCS pattern since year 2010 has
changed. From this year onwards the new
pattern has been followed .In the new
pattern 35 questions have to be answered
in 60 minutes time. However the
significant difference is that the English
part (verbal, synonyms) has been deleted
in the new test pattern; though reading
comprehension is likely to continue – the
test is named “TOUCHSTONE”.

Some notable points
 TCS test is computer based test.
 Each student will get unique questions – as
random questions will pop-up- on computer
screen - so do not copy.
 There will be negative marking – so do not
guess. Answer the question only if you are more
than 80% sure of the correctness of the answer.
 You are allowed to use calculators, but not
mobile phones.
 Carry HB pencils, eraser, coloured pencils etc.
for answering analytical reasoning questions –
rough work.

In the new test pattern questions are equally
divided amongst the three/ four types as listed
below:
a) Quantitative Ability about 15 questions.
b) Logical Reasoning about 10 questions.
c) Analytical Reasoning about 5 questions.
d) Reading comprehension about 5 questions.

Some sample questions are
discussed in this presentation
to facilitate the preparation of
students. First let us take the
quantitative questions which
can be typified to some extent.

Quantitative 1: Simple Trigonometry

Q1) If cosec 18°= sec A, then the measure of A
is________

a) 18° b) 108°
c) 72° d) None of these

Ans: c) 72°

SOLUTION

Cosec 18° = Cosec (90° – 72°)
As, Cosec (90 – Ѳ) = Sec Ѳ
Cosec (90° – 72°) = Sec 72°
Sec 72° = Sec A
Hence, A = 72°

Quantitative 2 : Problem of Ages

Q2) After 2 years, Paul will be 2 times as old as
Alice. Presently he is 4 times as old. What is
the present age of Paul?
a) 1 year b) 4 years

c) 2 years d) None of these

Ans: b) 4 years

SOLUTION

Let present age of Paul be x yrs
and that of Alice be y yrs
According to condition no. 1
x + 2 = 2 (y + 2)
x – 2y = 4 – 2
x – 2y = 2 -----(i)

According to condition no. 2
x = 4y
Substituting x in equation (i)
4y – 2y = 2
2y = 2
Hence, y = 1 years
x= 4 years

Quantitative 3 : Mensuration
Q3) A vessel is in the form of a hollow cylinder
mounted on a hollow hemisphere. The
diameter of the hemisphere is 14 cms and the
total height of the vessel is 30 cms . Find the
outer surface area of the vessel. (take π = 22/7)
a) 1628 cm² b) 1528 cm²
c) 1474 cm² d) None of these

Ans: c) 1474 cm²

SOLUTION d = 14 cm
r = 7 cm
Height of the cylinder = 30 – 7 = 23 cm
Outer Surface Area of the Vessel = curved
surface area of hemisphere+ curved
surface area of cylinder + πr² (top
surface)
= 2 πr² + 2πrh + πr²
= πr (2π + 2h + r)
= 22/7 * 7 ( 2*7 +2*23 + 7)
= 22 (14 + 46 + 7)
= 22 * 67
= 1474 cm²

Quantitative 4 : Linear Equation
Q4) A telephone company charges 80 paisa/ min
for first 80 min of talk , 70 paisa/ min
subsequently up to 130 min and 55 paisa/min
beyond 130 min. What would be the amount
paid by a subscriber who has used a total of
110 min of talk time?
a) Rs. 85 b) Rs. 108.
c) Rs. 64 d) None of these
Ans: Rs. 85

SOLUTION

Total Charges
= (80 min x 80p) + (30 min x 70p)
= 6400p + 2100p
= 8500p = Rs. 85

Quantitative 5: Linear Equation
Q5) (2/3rd) of a number is 4 more than (1/6th) of
the same number. What is the number?

a) 6 b)8
c)36 d)24

Ans: b) 8

SOLUTION

Let number be x
Then 2/3x = 1/6x + 4
2/3x – 1/6x = 4
[(4-1)/6] x = 4
3x/6 = 4
x = 4x6/3 = 8

Quantitative 6 : Probability
Q6) Paul the octopus who has been forecasting the
outcome of FIFA world cup matches with tremendous
accuracy has now been invited to predict ICC world cup
matches in 2011. We will assume that the world cup
contenders have been divided into 2 groups of 9 teams
each. Each team in a group plays with the other teams
in the group. The top two teams from each group enter
the semi finals ( after which the winner is decided by
knockout).
However, Paul has a soft spot for India and when India
plays with any team, Paul always backs India. Alas, his
predictions on matches involving India are right only 2
out of 3 times. In order to qualify for the semi finals, it is
sufficient for India to win 7 of its group matches. What
is the probability that India will win the ICC world cup?

6(b)
a) (2/3)^10
b) (2/3)^9 + 8/3 * (2/3)^9
c) 1/3 * (2/3)^9
d) (2/3)^10 + 8/3*(2/3)^9

Ans: c) 1/3 * (2/3)^9

SOLUTION
1. To win semifinals India needs to win 7 matches and
can loose one.
2. To win a match probability = 2/3
3. Probability of loosing a match = 1/3
4. To qualify for semifinals India needs to win 7 matches
the probability of which is (2/3)⁷
5. For India to reach the semifinals the probability is
(2/3)⁷ x 1/3.
6. Now, to further win semifinals and final both
probability is 2/3 X 2/3.
7. Therefore overall probability of India wining =
(2/3) ⁷ x 1/3 x 2/3 x 2/3 = (2/3)⁹ x 1/3.

Note:
I. If India wins all the matches i.e. 8+2=10
matches, probability = (2/3)10
2.
The key is that for reaching semi finals India
has to win only 7 matches out of 8 and can
afford to loose one.

Q7) A toy train produces 10 different tunes when
it moves around a circular toy track of radius 5
meters at 10 meters per minute. However ,
the toy train is defective and it now produces
only two different tunes at random. What are
the odds that the toy train produces 4
consecutive music tunes of the same type?

a) 1 in 16 b) 1 in 4
c) 1 in 8 d) None of these

SOLUTION

• A toy train produces 10 different tunes in the
normal course
• But now as the toy train has become
defective, it produces only 2 different tunes;
so the probability of producing any one tune is
½.
• Probability of producing 4 consecutives same
tunes = ½ x ½ x ½ x ½ = 1/16 or 1 in 16

Q8) Six friends decide to share a big cake. Since all of
them like the cake, they begin quarreling who gets
to cut the cake first and have a piece of the cake.
One friend suggests that they can make a blindfold
friend choose from well shuffled set of cards
numbered one to six. You check and find that this
method works as it should simulating a fair throw of
a die. You check by performing multiple
simultaneous trials of picking the cards blindfold
and throwing a die. You note that the number
shown by the method of picking up a card and
throwing a real world die, sums to a number
between 2 and 12. Which total would be likely to
appear more often – 8,9 or 10?

8(b)
a) 8 b) 10
c) 9 d) All are equally likely

Ans: a) 8

SOLUTION
Sum making up to number 8 in one set of throw
of die and picking up the card, probable sets
are = (2,6), (6,2), (4,4), (5,3), (3,5) = Total 5 sets
Sums making up to number 9, probable sets are =
(4,5), (5,4), (6,3), (3,6) = Total 4 sets
Sums making up to number 10, probable sets are
= (5,5), (6,4), (4,6) = Total 3 sets
So probability of 8 would be the maximum
appearing more often than others

Q9) A lady has fine gloves and hats in her
closet- 18 blue- 32 red and 25 yellow gloves are
there. The lights are out and it is totally dark .
Inspite of the darkness she can make out the
difference between a hat and a glove. She
takes out an item out of the closet only if she is
sure that it is a glove. How many gloves must
she take out to make sure that she has a pair of
each colour?
a) 50 b) 8
c) 59 d) 42

SOLUTION
We have to consider the worst case scenario for
being sure.
Suppose 1st she takes out all 32 Red gloves (the
maximum number possible for one colour)
Then all yellow gloves which are 25 in number
And then next 2 gloves she takes out that will
definitely be of blue color
In this way to make sure that she has a pair of
each color, she has to take out = 32 + 25 + 2 =
59 gloves.


Q10) There are 7 children in a family and the
youngest child is a boy. What is the
probability that all of them are boys ?

a) 1/2! b) 1/64
c) 1/128 d) 1/8

Ans: b) 1/64

SOLUTION :
The probability of a child being boy or girl is ½
(assuming it is random)
The probability that all children in the family are
boys when the youngest child is a boy

= ½ x ½ x ½ x ½ x ½ x ½ x 1 = (1/2)^6
= 1/64

Quantitative 11 : Number System
Q11) A number when divided by D leaves a
remainder of 3 and when divided by 3D leaves
a remainder of 21 . What is the remainder,
when twice the number is divided by 3D?
a) 15 b) 42
c) 3 d) cannot be determined

Ans: a) 15

• SOLUTION-
1. As the remainder is 21 when divided by 3D
Therefore, 3 D >21 or D>7
2. Let us take the next higher value
i.e. D=8 & 3D = 24
(a). The first option is number 45 (=24+21)
Divided by 24 it leaves a remainder of 21
Divided by 8 it leaves a remainder of 5
So it does not fulfill the conditions
(b). Let us try the next possibility i.e. 45+24 = 69
Divided by 24 (3D) it leaves 21 as remainder
But divided by D = 8, it leaves 7 as the remainder –
so it does not fulfill the condition

3. Let us make next trial with ‘D=9’
3D = 27
(a). Let first number be 48
Divided by 3D = 27 it leaves 21 as
remainder
Divided by D=9 it leaves 3 as remainder
So 9 is the desired number ‘D’
Let us now divide double the number i.e.
96 by 3D = 27 remainder is 15
So a= 15 is the correct answer

Quantitative 12 : Permutation and
Combination
Q12) Alok is attending a workshop “How to do more
with less” and today's theme is Working with fewer
digits. The speakers discuss how a lot of miraculous
mathematics can be achieved if mankind (as well as
womankind) had only worked with fewer digits.
The problem posed at the end of the workshop is
How many four digit numbers can be formed using
the digits 1, 2,3,4 ,5 ( but with repetition) that are
divisible by 4?
Can you help Alok find the answer?

12 (B)
a)100 b) 125
c) 75 d) 85

Ans: b) 125

SOLUTION
A number to be divisible by 4 the last 2 digits
should be divisible by 4

To fill the last two digits that are divisible by 4
are (1,2), (2,4), (3,2), (4,4), (5,2)
Therefore there are 5 possibilities.
And the rest 2 digits can be filled in ⁵P₅ ways.
So total there are 5*5*5 ways = 125 ways

Combination
Q13) A research lab in Chennai requires 100 mice and 75
sterilized cages for a certain set of laboratory
experiments. To identify the mice, the lab has
prepared labels with numbers 1 to 100 , by combining
tags numbered 0 to 9. The SPCA requires that the tags
be made of toxin-free material and that the
temperature of the cages be maintained at 27 degree
Celsius. Also , not more than 2 mice can be caged
together and each cage must be at least 2 sq. ft in
area. The 5 experiments to be conducted by lab are to
be thoroughly documented and performed only after a
round of approval by authorities. The approval
procedure takes around 48 hours. How many times a
tag having number '4' is used by the lab in numbering
these mice?

13(b)

a) 9 b) 19
c) 20 d) 21

Ans: b) 19

SOLUTION
• Tag having number '4‘ are as follows
• 4, 14, 24, 34, 44, 54, 64, 74, 84, 94
• 40, 41, 42, 43, 45, 46, 47, 48, 49
• So a total of 19 times.

combination
Q14) 20 people meet and shake hands. What is the
maximum number of hand shakes possible if there
is to be one ‘cycle’ of handshakes { a cycle of
handshake is a sequence of people (a1,a2,…..ak)
such that people (a1,a2),(a2,a3)…..(a(k-1),ak),
(a20,a1) shake hand}

a) 18 b) 19
c) 20 d) 21

Ans: c) 20

SOLUTION 20
1 2
3
19 4

5
18

6
17

16 7
8
15
9
14
10
13 12 11

To make a complete cycle number of
handshakes required is 20

Quantitative 15 : Time and Distance
Q15) On planet korba, a solar blast has melted the ice
caps on its equator. 9 years after the ice melts, tiny
planetoids called Echina start growing on the rocks.
Echina grows in the form of a circle ,and the
relationship between the diameter of this circle and
the age of echina is given by the formula
d = 4*√ (t-9) for t ≥ 9
where d represents the diameter in mm and t the
number of years since the solar blast.
Jagan recorded the radius of some echina at a
particular spot as 7mm. How many years back did
the solar blast occur?

15(b)

a) 17 b) 21.25
c) 12.25 d) 12.06

Ans: b) 21.25

SOLUTION

The relationship between the diameters of the circle
and the age of Echina is given by the formula
D = 4 x √(t – 9) for t>=9
If radius r is 7 mm then diameter = 7 x 2 = 14 mm
14 = 4 x √(t – 9)
14/4 = √(t – 9)
7/2 = √(t – 9)
squaring both sides
49/4 = (t – 9)
So t = 21.25

Quantitative 16 : Time and
Distance
Q16) Ferrari S.P.A is an Italian sports car
manufacturer based in Maranello, Italy. Founded by
Enzo Ferrari in 1928 as Scuderia Ferrari , the
company sponsored drivers and manufactured race
cars before moving into production of street-legal
vehicles in 1947 as Ferrari S.P.A. Throughout its
history, the company has been noted for its
continued participation in racing, especially in
Formula One where it has enjoyed great success .
Rohit once bought a Ferrari . It could go 4 times as
fast as Mohan's old Mercedes. If the speed of
Mohan's Mercedes is 46 km/hr and the distance
traveled by the Ferrari is 953 km, find the total time
taken for Rohit to drive that distance.

16(b)

a) 20.72 hr b) 5.18 hr
c) 238.25 hr d) 6.18 hr

Ans: b) 5.18 hr

SOLUTION
Speed of Mohan's Mercedes = 46 km/hr
Speed of Rohit’s Ferrari = 4 times of Mohan's Mercedes
= 4 * 46 km/hr
= 184 km / hr
Distance = 953 km
Time taken by Rohit’s Ferrari = Distance / Speed
= 953 km/ 184 km/hr
= 5.18 hrs
The total time taken for Rohit to drive that distance will
be 5.18 hrs

Quantitative 17 : Pipes and Cisterns
Q17) There are two water tanks A and B, A is much
smaller than B. While water fills at the rate of one litre
every hour in A, it gets filled up like 10, 20, 40, 80, 160...
Litres per hour in tank B.( At the end of first hour, B gets
10 litres , second hour it gets 20 litres more, and so on).
If tank B is 1/33 filled after 5 hours, what is the time still
required (in hours) to fill it completely?

a) 26 hrs b) 25 hrs
c) 5 hrs d) 27 hrs

Ans: c) 5 hrs

SOLUTION
The data has been shown in the form of a table

Hours Water filled in B Cumulative Water filled
in that hr (in lts) in B (in lts)
1 10 10
2 20 30
3 40 70
4 80 150
5 160 310

After 5 hrs the tank is 1/33 filled which is 310
liters
So applying unitary method
When 1/33 is equal to 310 lts
Therefore, the total capacity of tank B will be
= 310 lts * 33
= 10230 lts

Let us construct the chart further
Hours Water filled in B Cumulative Water filled
in that hr (in lts) in B (in lts)
1 10 10
2 20 30
3 40 70
4 80 150
5 160 310
6 320 630
7 640 1270
8 1270 2550
9 2560 5110
10 5120 10230
Therefore, after 5 more hours the tank B will be
completely filled

Quantitative 18 : Ratio and Proportion
Q18) A researcher at Sony Computer Science
laboratories is also a jazz musician. He decided to
build a robot able to improvise like a pro. Named
“Continuator”, the robot can duet with a live
musician in real- time. It listens to a musical phrase
and then computes a complementary phrase with
the same playing style. If the cost of making the
robot is divided between materials , labour and
overheads in the ratio of 4:6:2 and if the materials
cost $108. What is the cost of the robot?

18(b)

a) $270 b) $324
c) $216 d) $ 648

Ans: b) $ 324

SOLUTION
Ratio = 4:6:2
Let x be the total cost
Since, the cost of material = 108$
Which was equal to
4/(4+6+2) * x = 108 $
Therefore, x = 324 $

Quantitative 19 : Ratio and Proportion
with Linear Equations
Q19) In the year 2002, Britain was reported
to have had 4.3million closed – circuit
television (CCTV) cameras – one for every
14 people in the country . This scrutiny is
supposed to deter and detect crime. In one
criminal case, the police interrogates two
suspects . The ratio between the ages of
the two suspects is 6:5 and the sum of their
ages is 55 years. After how many years will
the ratio be 8:7.?

19(b)

a) 11 b) 6
c) 10 d) 5

Ans: c) 10

SOLUTION
Since, the ratio of ages is 6:5
Therefore, ages can be 6x and 5x
6x+5x= 55 years
x= 5
The two ages will be 30 years and 25 years
New ratio = 8:7
No. of years required = 30+y = 8
25 +y 7
On solving y = 10 years
After 10 years the ratio between their ages will be
8:7.

Quantitative 20 : Average speed

Q20) A man jogs at 6 mph over a certain
journey and walks back the same route at 4
mph. What is his average speed for the
journey?

a) 4 mph b) 5 mph
c) 2.4 mph d) 4.8 mph

Ans: d) 4.8 mph

SOLUTION
• Average speed = 2xy or (Total Distance)
x+y Total Time
x = 6 mph
y= 4 mph

• Average speed = 2*6*4
6+4
= 4.8 mph

Quantitative 21 : Simplification
Q21) Spores of a fungus, called late blight, grow and
spread infection rapidly. These pathogens were
responsible for the Irish potato famine of the mid-
19th century. These seem to have attacked the
tomato crops in England this year. The tomato crops
have reduced and the price of the crop has risen up .
The price has already gone up to $45 a box from $27
a box a month ago. How much more would a
vegetable vendor need to pay to buy 27 boxes this
month over what he would have paid last month?

21(b)

a) $27 b) $ 18
c) $45 d) $ 486

Ans: d) $ 486

SOLUTION
• Difference in two prices = $ 45 - $ 27
= $ 18
Amount that the vendor needs to pay to buy 27
boxes this month over what he would have
paid last month = $ 18 * 27
= $ 486

Quantitative 22 : Simplification
Q22) (40*40*40 – 31*31*31) = ?
(40*40+40*31+31*31)
a) 8 b) 9
c) 71 d) 51

Ans: b) 9

SOLUTION
• Let x be 40 and y be 31
(40*40*40 – 31*31*31) / (40*40+40*31+31*31)

Is in the form of x3 - y 3
x2 + xy + y2
= (x2 + xy + y2 ) ( x – y)
x2 + xy + y2
= ( x – y)
= 40 – 31
= 9

Quantitative 23 : Cubes
Q23) Susan made a block with small cubes of 8
cubic cm volume to make a block 3 small
cubes long, 9 small cubes wide and 5 small
cubes deep. She realizes that she has used
more small cubes than she really needed. She
realized that she could have glued a fewer
number of cubes together to look like a block
with same dimensions, if it were made hollow.
What is the minimum number of cubes that
she needs to make the block?

23(b)

a) 114 b) 135
c) 21 d) 71

Ans: a) 114

3
SOLUTION
9
1
7

3
5

Total number of cubes used = 3 * 9 * 5 = 135
Number of cubes required to make a hollow
cube
= (3*9*5)- (1*7*3)
= 135 -21
= 114

Note: Only two outer cubes on either end face
will make the faces, so inner blocks can be
removed to make a hollow or 1*7*3= (3-2)(9-
2)(5-2) blocks can be removed from inside to
make it hollow.

Quantitative 24 : Co-ordinate Geometry

Q24) Determine the distance between x-
intercept and z-intercept of the plane where
equation is 6x+8y-3z=72.

a)3 b)26.83
c)9 d)25.63

Ans: b) 26.83

SOLUTION
• 6x+8y-3z=72
x + y - z = 1
72/6 72/8 72/3
X- intercept = (72/6, 0, 0)
= (12, 0, 0)
Y- intercept = (0, 0, -72/3)
= (0, 0, -24)
Distance between x-intercept and z-intercept of the
plane = √[( x1- x2)2 + (y1-y2)2 + (z1-z2)2]
=√[( 12- 0)2 + (0-0)2 + (0+24)2]
= 26.83
Or simplify √(x²+z² )= √(12²+ 24²) = 26.83

Quantitative 25 : Co-ordinate
Geometry
Q25) The vertices of Δ ABC are point A (1,2),
B(4,6), C(-4,12). Which of the following is true?

a) ABC is not a right angled Δ
b) It is a right angled Δ with right angle at C
c) It is a right angled Δ with right angle at B
d) It is a right angled Δ with right angle at A

Ans: c) It is a right angled Δ with right angle at B

SOLUTION

Side AB = √ [(4-1)2 + (6-2)2 ]
= 5 units
Side BC = √[ (-4-4)2 + (12-6)2 ]
= 10 units
Side CA = √[ (1+4)2 + (12-2)2 ]
= √125 units
For a right-angled triangle
H2=p2+b2
(√125)2=102 +52
CA2 = AB 2+BC2
Hence it is right angled at B

Quantitative 26 :Time and Work
Q26) A seamstress buys a certain amount of Gingham
cloth which comes in rolls that are exactly 56 inches
wide. She has also bought a certain length of Seek
sucker cloth which is 35 inches wide. The seamstress
first focuses on the Gingham roll and discovers that
she has 116 yards of Gingham and she wants to
divide the gingham into 116 lengths of 1 yard each.
She wants to have twice as many pieces of seek
sucker as she does of the Gingham. It takes 4
seconds to cut each length of Gingham. Working
non-stop, how long (in seconds) will it take her to cut
all the 116 pieces?

26(b)

a) 464 secs b) 460 secs
c) 463 secs d) 465 secs

Ans: b) 460 secs

SOLUTION

• It takes 4 seconds to cut each length of
Gingham
• So to cut 116 pieces, total time required
= (116-1) * 4
= 460 sec

Quantitative 27 : Arithmetic
Progression
Q27) A long thin strip of width 7 cm is kept on a
flat surface. Another identical strip is kept on
it in an overlapping manner such that the
combined width of the two is 11 cm. What is
the width of 55 such strips kept like this?
a) 224 b) 223
c) 225 d) None of these

Ans: b) 223

SOLUTION

4 7 4 7

7+4+4+4+……….+4 = 4*54+7 = 223

Quantitative 28 : Averages
Q28) Six persons with different ages are
standing in a queue. After two years their
average age will be 43 years. A seventh
person joins them. The current average age
has now become 45 years. Find the age of
seventh person (in years)?
a) 55 years b) 59 years
c) 69 years d) None of these
Ans: c) 69 years

SOLUTION

• Present average age of group = 43-2 = 41 years
• When 7th person joins the average = 45 years
• Total age of 7 people = 41*6 + x
• Where x is the age of the 7th person joining the
group
• Average = total/ number of observations
• 45 = (246 +x) / 7
• On solving
• X= 69 years

Quantitative 29 : Heights & distance

Q29) Two vertical poles of heights 6m and 11m stand
on a plane ground. The distance between their feet is
12m. A rope is tied tightly from the top of one pole
to the top of the other. Find the length of the rope
(round off)?
a) 14m b)13m
c) 15m d) None of these

Ans: b) 13m

SOLUTION

5m

11 m
12 m
6m

12 m
A 2 + B 2 = H2

144 + 25 = 169
H = 13 m
Therefore, Length of rope = 13 m

Quantitative 30 : Heights & distance
with Trigonometry
Q 30) Standing on top of a high building, I measure
an angle of elevation of a building 25 metres away as
45 degrees. The angle of depression of the ground
level of the same building is also measured as 45
degrees. How tall is that building?
a) 10m b) 20m
c) 25m d) 50m
Ans: d) 50m

C
Solution
Since Angle of Elevation =
45o
Tan 45 = p / b = BC/OB = 1
45o
p/25= 1 25 45o
B ---------------------------------- O
Therefore, P = 25m Similarly ----
--
25 ----
-
AB = 25m --
----
-
----
Total Height of the taller --- ----
-
- --
building = AB + BC = 25m + A --- ----
25m = 50m
25

Logical reasoning-1
Q31) One day Alice meets Pal and Byte in
fairyland. She knows that Pal lies on Mondays,
Tuesdays and Wednesdays and tells the truth
on the other days of the week .Byte, on the other
hand, lies on Thursdays, Fridays and
Saturdays, but tells the truth on the other days of
the week. Now they make the following
statements to Alice – Pal: “Yesterday was one of
those days when I lie”.
Byte: “Yesterday was one of those days when I
lie too”.
What day is it ?

1(b)

a) Thursday b) Tuesday

c) Monday d) Sunday

Ans: a) Thursday

SOLUTION

Mon Tues Wed Thurs Fri Sat Sun

Alice √ √ √

Pal √ √ √

Logical Reasoning-2
Q32) Rearrange the following letters to make a
meaningful word and choose from the options
given, the category in which it lies. “RAPETEKA”

a) Bird b) Vegetable

c) City d) Fruit

Ans: ‘PARAKEET’. a) Bird

Logical Reasoning-3

Q33) In the reading room of a library, there are 23
reading spots. Each reading spot consists of a
round table with 9 chairs placed around it. There
are some readers such that in each occupied
reading spot there are different numbers of
readers. If in all there are 36 readers, how many
reading spots do not have even a single
reader?

a) 8 b) 15
c) 16 d) None of these

Ans: b) 15

SOLUTION
 23 reading spots
 Each reading spot consists of 9 chairs placed
around it so there are some readers such that in
each occupied reading spot there are different
number of readers.
 Soon first table 1 person will sit.
 On second table 2 person will sit
 If there are 36 readers then
 1+2+3+4+5+6+7+8=36
 Only 8 tables will be occupied.
 Therefore, 23-8=15 reading spots will not have
even a single reader.

Logical reasoning-4
Q34) Middle – earth is a fictional land inhabited
by Hobbits, Elves, dwarves and men. The
Hobbits and the Elves are peaceful creatures
who prefer slow, silent lives and appreciate
nature and art. The dwarves and the men
engage in physical games. The game is as
follows . A tournol is one where out of the two
teams that play a match, the one that loses get
eliminated. The matches are played in different
rounds where in every round , half of the teams
get eliminated from the tournament. If there are
8 rounds played in a knock-out tournol how
many matches were played?

4(b)

a) 257 b) 256
c) 72 d) 255

Ans: d) 255

SOLUTION
Round No. of matches No. of
played contestants
8 1 2
7 2 4
6 4 8
5 8 16
4 16 32
3 32 64
2 64 128
1 128 256
Total 255

Logical Reasoning-5
Q35) Consider two tumblers, the first
containing Water and second containing
coffee. Suppose you take one spoon of
water out of the first tumbler and pour it
into the second tumbler. After stirring well
you take one spoon of the mixture from
the second tumbler and pour it back into
the first tumbler. Which one of the
following statement holds now?

5(b)
a) There is less coffee in the first tumbler than
water in the second tumbler.

b) There is more coffee in the first tumbler than
water in the second tumbler.

c) There is as much coffee in the first tumbler as
there is water in the second tumbler.

d) None of the statements holds true.

Ans: d) None of the statements holds true.

Logical reasoning-6
Q36) A taxi driver commenced his journey from a
point and he drove 10 km towards north and
turned to his left and drove another 20 km. After
meeting a friend here, he turned to his right and
continued to drive another 10 km. In which
direction is he now with respect to the starting
point?
a)West b)South
c)North d)East

Ans: c) North

SOLUTION

North

10 KM
20 KM
10 KM

Logical reasoning-7

Q37) A school yard contains only bicycles
and 4 wheeled wagons. On Tuesday, the
total number of wheels in the schoolyard
was 114. What would be the possible
number of bicycles?
a)18 b)17
c)16 d) 8

Ans: b) 17

SOLUTION

 Number of wheels in a bicycle = 2
 Number of wheels in a wagon = 4
 Total number of wheels =114
a) 18
 If bicycles are 18 then the number of wheels in
bicycle = 36
 Remaining wheels = 114-36=78
 Now this should be divisible by four because the
remaining wheels are of wagons 78/4 = 19.5
 Solution not feasible.

b)17
 Number of wheels in bicycle = 17×2=34
 Now 114 – 34=80/4 = 20

c) 16
16×2 = 32 114-32 = 82/4 =20.5

d) 8
8×2 = 16 114-16 =98 = 24.5

Logical reasoning-8

Q38) A pie is to be divided among 20
people. A man eats 3 pieces, a woman
eats 2 pieces and a child eats ½ a piece
of pie. There are 20 pieces of pie in all.
What is the number of men, women &
children, so that 20 people in total and
everyone gets pie as per his/her
requirement and there is no shortage or
excess of pie at the end?

8(b)
a) 7 women, 1 man, 12 children
b) 5 women, 1 man, 14 children
c) 4 women, 2 men, 12 children
d) None of these

Ans: b) 5 women, 1 man, 14 children

SOLUTION
Number of People = 20

Pieces eaten by men = 3

Pieces eaten by women = 2

Pieces eaten by children = ½

Options Women Men Children Total no. of Total no. of
Pieces People
a 7(7×2=14) 1(1×3=3) 12(12×1/2=6) 23 20
b 5(5×2=10) 1(1×3=3) 14(14×1/2=7) 20 20
c 4(4×2=8) 2(2×3=6) 12(12×1/2=6) 20 18

Logical reasoning-9 (Direction)
Q39) A scientist was researching on animal
behavior in his lab. He was very interested in
analyzing the behavior of bears. For some
reason he traveled 1mile in north direction &
reached at North Pole. There he saw a bear. He
then followed the bear around 1 hr with a speed
of 2km/hr in east direction. After that he traveled
in south direction & reached at his lab in 2 hrs.
Then what is the color of the bear?
a) Black b) Brown
c) White d) None of these

Logical Reasoning-10(Series)
Q40) When Lucy was young her father would take his
daughter to the terrace and explain about constellations
to his daughter and then he leaves her alone in the
terrace to find few of them all by herself. Lucy finds
around 25 groups of stars that appear to her as
constellations. She draws 7 patterns of the constellations
in her notebook and notes down the number of stars in
each of them. She counts 5 stars in first constellation
and 15 in next. She counts a number the third time and
forgets to note it down. The next four constellations she
counts are 51,53,159,161. Next day her father looks at
the notebook and wants to know the number of stars in
the third constellation. Lucy only remembers that number
of starts counted in each of the constellation followed a
pattern 5, 15, x, 51, 53, 159, 161.

10(b)
What is the value of x?

a) 19 b) 45
c) 16 d) 17

Ans: d) 17

SOLUTION
5 15 x 51 53 159 161

×3 +2 ×3 +2 ×3 +2

Analytical reasoning-1
Q41) Bob, Peter, Oliver and 2 girls –Raven and
Chelsey are to be seated in a row. Raven often
sits to left of Bob. No girl sits at extreme
positions and middle positions. Peter always
sits at the extreme position. Who sits to the
right of Chelsey?

a)Oliver b)Bob
c)Peter/Oliver d)Peter
Ans: c)Peter/Oliver

SOLUTION

There are two possible solutions:

Peter Chelsey Oliver Raven Bob

Peter Raven Bob Chelsey Oliver

Oliver Peter

Q42) A man is standing in front of a painting of a
man, and he tells us the following: “ Brothers
and sisters have I none, but this man’s father is
my father’s son”. Who is on the painting?
a) The man himself
b) The man’s son
c) The man’s father
d) Can’t be determined

SOLUTION
Father

Man’s Father

Man

Q43) There are 5 materials to make a perfume: Lilac,
Balsalmic, Lemon, Woody and Mimosaic. To make a
perfume that is in demand the following conditions
are to be followed: Lilac and Balsalmic go together.
Woody and Mimosaic go together but one of any
one group does not go with any other of the other
group together. Lemon can be added with any
material. All of the following combinations are
possible to make a perfume EXCEPT:

3(b)
a) Balsalmic and Lilac
b) Woody and Lemon
c) Mimosaic and Woody
d) Mimosaic and Lilac

Ans: Mimosaic and Lilac.

SOLUTION
LILAC ----------------BALSAMIC

WOODY--------------MIMOSAIC

LEMON CAN BE ADDED TO ALL

LILAC ----------------BALSAMIC x WOODY--------------MIMOSAIC

Directions for question 43: Read the passage
given below and answer the questions that
follow.

Analytical Reasoning-4
Q44) In a certain society, there are 2 marriage groups,
red and brown. No marriage is permitted within a
group. On marriage, males become part of their
wife’s group; women remain in their own group.
Children belong to the same group as their parents.
Widowers and divorced males revert to the group of
their birth. Marriage to more than one person at the
same time and marriage to a direct descendant are
forbidden.

4(b)
i) A male born into the brown group may have

a) an uncle in either group
b) a brown daughter
c) a brown son
d) a son-in-law born into the red group
e) a daughter-in-law in the red group

Ans: a)

MOTHER MOTHER’S
FATHER
FATHER’S BROTHER FATHER BROTHER
MALE

4(c)
ii) Which of the following is not permitted under
the rules as stated?
a) a brown male marrying his father’s sister
b) A red female marrying her mother’s brother
c) a man born red, who is now a widower,
marrying his brother’s widow
d) a widower marrying his wife’s sister
Ans: b)

MOTHER FATHER
FATHER’S SISTER FATHER
MALE

MOTHER MOTHER’S BROTHER

FEMALE

Reading Comprehension-1
Q45)The recent news, that local hospitals have had to reroute seriously ill
patients because the community's critical-care beds are full, is worrisome.
Earlier this week, four of the six local hospitals ran out of space for the
critically ill and had to turn people away.
Federal law requires hospitals to treat anyone who walks in. As a result of
having to treat large number of uninsured patients, the emergency rooms
often become an economic drain on their hospitals. Doctors now want to set
up their own free-standing ambulatory surgical facilities and diagnostic
centers. Critics contend this would leave hospitals with less revenue and the
same number of indigents to treat. A bill was recently introduced to phase
out the need for a "certificate of public need" for non-hospital-based
facilities, provided those facilities met stringent regulations and
requirements. This would have made it easier to set up alternative facilities
to help indigent patients. The finance committee balked at the hefty price
and killed the bill, another casualty of a failed legislative session.
Unfortunately, the problem of access to medical care for those of limited
means is not going to go away anytime soon and, despite the well-intended
regulations, full hospitals compromise everyone's welfare. Healthy
competition with small neighborhood surgical and diagnostic centers may be
what is necessary to help dampen rising medical costs. But under no
circumstances should the hospitals be forced to care for everybody without
health insurance while competitors operate free of the burden of caring for
those unable to pay.

1(b)
Which of the following best describes the
tone of the passage?
a) neutral
b) positive
c) persuasive
d) angry
e) Reverential

Ans : c) persuasive

1(c)
Which of the following is cited as a factor which has
contributed to the overburdening of hospitals?
I Failure to pass legislation which would have mitigated
the problem
II Limited access to medical care for the poor
III Federal law
a) I only
b) II only
c) III only
d) I and II
e) I, II, and III

Ans : e) I, II, and III

1(d)
The author cites the failed legislation in order to show
that
a) the legislature will never resolve this issue.
b) the finance committee does not care about the uninsured
citizens.
c) there will continue to be uninsured hospital patients for a
long time to come.
d) the legislature does not have the decision to resolve this
issue.
e) the doctors successfully lobbied the finance committee.

Ans : c) there will continue to be uninsured hospital patients
for a long time to come.

1(e)
Which of the following is a conclusion supported by the
passage?
a) If doctors want to run their own facilities, they should be
required to take in at least some of the indigents.
b) The government should provide health insurance for
those unable to buy their own.
c) Voters should tell the finance committee members that
they will not be reelected if they do not pass some new
legislation.
d) Emergency rooms that turn patients away due to
overcrowding are derelict in their duty .
e) The fundamental problem facing hospitals now is that
health care costs have risen dramatically in recent years

Ans : a) If doctors want to run their own facilities, they
should be required to take in at least some of the
indigents.

SUMMARY
The pattern of the paper can be
summarized as follows:

1. In Quantitative ability the following
topics are to be covered-
Simple trigonometry( sin-cosine, cot-
tan, cos-cosec)
Problem of ages
Heights & distances
Mensuration ( rings, spheres etc.)
Simple Geometry
Co-ordinate Geometry
Number System ( simplification,
factorization based on (a+b)2, (a+b)3)
Arithmetic & Geometric Progression

Pipes & Cisterns
Ratio & Proportion
Averages
Average Speed
Profit & Loss
Cubes (volume & surface area)
Simple linear equations
Time & Work
Time & Distance
Probability (atleast 3 questions will
come in each paper)
Permutation & Combination (atleast 2
questions will come in each paper)

2. In logical Reasoning
Simple series ( at least one question)
Directions
Small puzzles
3 You may get one or two passages on
Analytical Reasoning.
4 A passage on Reading Comprehension
may appear with 3 or 4 questions.

THANK YOU
&
WISH ALL OF YOU

ALL THE BEST

Tcs 2011with solutions

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